We have that for the Question "(a) what multiple of the maximum charge is on the capacitor and (b) what multiple of the maximum current is in the inductor"
Answer:
a) maximum charge = [tex]0.366Q_{max[/tex]b) maximum current = [tex]0.931I_{max}[/tex]
From the question we are told
In an oscillating LC circuit, when 86.6% of the total energy is stored in the inductor's magnetic field
A) When 86.6\% energy is stored in inductor
[tex]\%[/tex]of energy stored in electric field = [tex]1 - 0.866 = 13.4\%[/tex]
[tex]\frac{V_E}{V} = \frac{\frac{q^2}{2c}}{\frac{Q^2}{2c}} = 0.134\\\\\frac{q}{Q} = \sqrt0.134\\\\\frac{q}{Q} = 0.366\\\\q = 0.366Q_{max[/tex]
B)
[tex]\frac{V_B}{V} = \frac{\frac{Li^2}{2}}{\frac{LI^2}{2}} = 0.866\\\\\frac{i}{I} = \sqrt0.866\\\\\frac{i}{I} = 0.931\\\\i = 0.931I_{max[/tex]
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During a picnic, you and two of your friends decide to have a three-way-tug-of-war, with three ropes in the middle tied into a knot. Roberta pulls to the west with 277 N of force; Michael pulls to the south with 603 N. a) With what force should you pull to keep the knot from moving
Answer:
Explanation:
I'm not 10% sure but i think that if you were to do:
603 + 277 = 880
1000 - 880 = 120
So to keep it from moving, i think you would need to pull with a force of 120N
The force with which it should be pulled to keep the knot from moving is 663.58 N.
What is Newton's third law ?Newton's third law states that, for every action, there is an equal and opposite reaction.
Here,
Force exerted by Roberta, F₁ = 277 N
Force exerted by Michael, F₂ = 603 N
Since, Roberta is pulling to the west and Michael is pulling towards the south, the angle between the forces applied by them is 90°.
The force needed to keep the knot from moving is the resultant force of these two forces.
Therefore, the resultant force,
Fₙ = √F₁² + F₂²
Fₙ = √(277)² + (603)²
Fₙ = 663.58 N
Hence,
The force with which it should be pulled to keep the knot from moving is 663.58 N.
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URGENTLY NEED HELP!!!!!!
the stretch of a spring and the force it exerts are inversely proportional.
Select one:
O True
O False
Answer:
False.
Explanation:
Suppose that you release a small ball from rest at a depth of 0.590 m below the surface in a pool of water. If the density of the ball is 0.370 that of water and if the drag force on the ball from the water is negligible, how high above the water surface will the ball shoot as it emerges from the water? (Neglect any transfer of energy to the splashing and waves produced by the emerging ball)
Answer:
Explanation:
The work of the buoyancy force will convert to gravity potential energy
Fresh Water has a density of 1000 kg/m³
The ball has a density of 370 kg/m³
assume the ball is 1 m³
weight of the ball is 370g
The buoyancy force is 1000g
Assume the buoyancy force drops suddenly to zero when the center of the ball clears the water level.
The Work done on the ball is
W = Fd = 1000g(0.590)
the change in potential energy is
PE = mgh = 370g(0.590 + y)
where y is the height above the water level.
1000g(0.590) = 370g(0.590 + y)
1000(0.590) = 370(0.590 + y)
y = (0.590)(1000 - 370) / 370
y = 1.004594... ≈ 1.00 m
A motorcycle, which has an initial linear speed of 9.7 m/s, decelerates to a speed of 4.0 m/s in 4.4 s. Each wheel has a radius of 0.61 m and is rotating in a counterclockwise (positive) directions.
What is (a) the constant angular acceleration (in rad/s2) and (b) the angular displacement (in rad) of each wheel?
Hi there!
We can begin by solving for the linear acceleration as we are given sufficient values to do so.
We can use the following equation:
vf = vi + at
Plug in given values:
4 = 9.7 + 4.4a
Solve for a:
a = -1.295 m/s²
We can use the following equation to convert from linear to angular acceleration:
a = αr
a/r = α
Thus:
-1.295/0.61 = -2.124 rad/sec² ⇒ 2.124 rad/sec² since counterclockwise is positive.
Now, we can find the angular displacement using the following:
θ = ωit + 1/2αt²
We must convert the initial velocity of the tire (9.7 m/s) to angular velocity:
v = ωr
v/r = ω
9.7/0.61 = 15.9 rad/sec
Plug into the equation:
θ = 15.9(4.4) + 1/2(2.124)(4.4²) = 20.56 rad
A load of 250 kg is hung by a crane's cable. The load is pulled by a horizontal force such that the cable makes a 30 angle to the vertical plane. If the load is in the equilibrium, calculate the magnitude of the tension in the cable
Answer:
1250[tex]\sqrt{3}[/tex]
Explanation:
Let's look at this in a simple manner, because it is.
The crane weights 250Kg. Okay.
Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)
Since F = m * a
F = 250 * 10
F = 2500
Now we know that the downward Force is 2500N.
To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be [tex]\frac{\sqrt{3}}{2}[/tex].
Therefore, the force pulling the box in the cable's direction is:
[tex]\frac{2500\sqrt{3} }{2} = 1250\sqrt{3}[/tex]
If you have any questions feel free to comment.
Have a great one and mark brainliest if it helped, please
How long do elephants live?
Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 1 O d) 2
I think the answer is a but I'm not sure I'm really a little confused I want to check with this app please can someone heelp me
Answer:
c
Explanation:
It really depends on what the stuff is. This should not be a math or physics question.
Having said that, I answer it by rounding it to 1. 1.04 is closest two one.
That is not entirely a satisfactory answer. Most people who take medications have pill splitters. They easily cut a pill in half. They can do this only if a the medicine's directions, or a pharmacist, or a doctor tells you can do this. Cutting it into quarters should never be done.
So a is really incorrect medically.
1.5 is too far away
C is probably the intended answer; it would annoy me no end if it was anything but c. If this was just a rounding question, it rounds to c. There is no medication that requires an intake of 1.04. No one could get that kind of accuracy.
2 is really too far away.
TRUE OR FALSE! PLZ HELP
Magnitude is a measure of how strong a force is.
A. True
B. False
Answer:
True
Explanation:
Magnitude is the "value" the greater the value the greater the force is and vice versa
Answer:
TRUE
Explanation: I did the test
Hope this helps
can you classify matter based on chemical properties
Answer:
Explanation:
Matter can be broken down into two categories: pure substances and mixtures. Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule.
Youssef and Sophia are driving in two different cars and not paying attention to their surroundings. Youssef approaches an intersection moving 11 m/s East while Sophia approaches the same intersection moving 13.5 m/s North. Both speeds are measured relative to the ground. When Youssef is 220 m from the intersection, Sophia is 275 m from the intersection. Do the two cars collide when they reach the intersection
Answer:
I think E--
Explanation:
The current in the long wire is decreasing. What is the direction of the current induced in the conducting loop below the wire
Answer:
anlatamadım herkeze ben sorulara bakamiyorum cumku analmaiyirum yardim edin
bu sorunu nasil cozebilirim
lutfsn...
The less dense areas created as a sound wave propagates are called
A. rarefactions✅
B. troughs
C. crests
D. compressions
Answer:
C. crests
don't trust me though
Answer:
The less dense areas created as a sound wave propagates are called rarefactions.
Explanation:
Hoped this helped.
If work stays the same and the distance is increased, then less force is needed to do the work.
True
False
Answer:
False
Explanation:
This is because the work is the same so the force won't change
What is friction ???
Answer:
Frictional force is produced when two bodies are rubbed against each other. It is the force that oppose the motion and therefore it stops or slow down a moving body.It depends upon the roughness or smoothness of the surface of the body in contact.Rough surface have more friction that the smooth surface. Similarly, the heavier body produces more friction than a lighter body. Frictional force acts in the opposite direction of the motion of the body.
How do mechanical waves compare with electromagnetic waves?
Answer:
Main Difference Between Mechanical and Electromagnetic waves
A wave is composed of some kind of disturbance that propagates. We can classify waves into many different types based on their properties. One of the properties of the waves depends on whether they need a medium to propagate or not. The primary difference between electromagnetic and mechanical waves is also based on this property. Mechanical waves need a medium, while electromagnetic waves do not need a medium to propagate. Electromagnetic waves can travel through a vacuum. The other differences between mechanical and electromagnetic waves are given below:
Electromagnetic waves can travel through a vacuum, that is an empty space, whereas mechanical waves cannot. They need a medium to travel such as water or air. Ripples in a pond are an example of mechanical waves whereas electromagnetic waves include light and radio signals, which can travel through the vacuum of space.
Mechanical waves can be classed as elastic waves because their transmission depends on the medium's (water, air etc.) elastic properties.
Electromagnetic waves are caused because of the varying magnetic and electric fields. They are produced by the vibration of the charged particles.
Because of these differences, the speed of each type of wave varies significantly. Electromagnetic waves travel at the speed of light but mechanical waves are far slower.
Have a wonderful day!
~Lillith of brainly~
A mass is placed at the end of a spring. It has starting velocity of V & allowed to oscillate freely. If the mass has a starting velocity of 2V, what would the period be? Half as long, remains constant, 1/4 as long , 4 times as long, or 2 times as long?
Answer:
Equation for SHM can be written
V = w A cos w t where w is the angular frequency and the velocity is a maximum at t = 0
V1 = w1 A cos w1 t
V2 = w2 A cos w2 t
V2 / V1 = w2 / w1 since cos X t = 1 if t = zero
V2 / V1 = 2 pi f2 / (2 pi f1) = f2 / f1 = T1 / T2
If the velocity is twice as large the period will be 1/2 long
help meee please please please
2. Jason rode his bike 10 miles and only rode for 2 hours how fast was he going?
Answer:
5 miles per hour.
Explanation:
10miles / 2hours = 5 mph
the push up is dynamic or static
Answer:
Dynamic exercises
Explanation:
A Projectile of mass 0.277 kf is shot from a cannon. The end of the cannon's barrel is at heiht 6.8 m. The initial velocity of the projectile has a horizontal component of 6.1 m/s. The projectile rises to a maximum height above the end of the cannon's barrel and strikes th ground a horizontal distance past the end of the cannon;s barrel. What is the time it takes for the projectile to reach its maximm height? The acceleration of gravity is 9.8 m/s^2.
The time taken by the projectile to reach its maximum height is 0.62 second.
Given parameters:
Horizontal component of initial velocity of the projectile: [tex]u_x[/tex] = 6.1 m/s.
To reach maximum height, the projectile should be throwed in 45 degree. So, vertical component of initial velocity of the projectile: [tex]u_y[/tex] = 6.1 m/s.
Given, The acceleration of gravity is 9.8 m/s².
At maximum height the vertical component of velocity of the projectile becomes zero due to acceleration due to gravity acts downwards.
So, from formula [tex]v_y[/tex] = [tex]u_y[/tex] - gt; we can write:
0 = 6.1 - 9.8t
⇒ t = 6.1/9.8 = 0.62 s.
Hence, the time taken by the projectile to reach its maximum height is 0.62 second.
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Which statement about reversible reactions is correct?(1 point)
They are always at equilibrium.
They are always at equilibrium.
The forward and reverse reactions must happen at the same rate.
The forward and reverse reactions must happen at the same rate.
They can occur in either direction.
They can occur in either direction.
They always involve gases.
They always involve gases.
Answer:
I think the answer would be C
C = They can occur in either direction.
Explanation:
the answer is C. They can occur in either directions
You apply the same force to two objects. Object 1 has mass M and object 2 has mass 5M. The acceleration of object 2 is
Select one:
a. one-fifth as that of object 1.
b. ten times that of object 1.
c. has no relation to that of object 1.
d. the same as that of object 1.
e. five times that of object 1.
five times that of object l
A baseball is hit with a speed of 30.0 m/s at an angle of 47.0 ∘ . It lands on the flat roof of a 11.0 m -tall nearby building. If the ball was hit when it was 1.4 m above the ground, what horizontal distance does it travel before it lands on the building?
Answer:
500m/s
Explanation:
ma thii nay pathe me thuda dase dangur ni puthar
A 0.015 kg marble sliding to the right at 0.225 m/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg marble moving to the left at 0.180 m/s. After the collision, the first marble moves to the left at 0.180 m/s. Find the velocity of the second marble after the collision.
Explanation:
[tex]if \: the \: masses \: of \: the \:two \: marbles\: equal \\ then \: each \: velocity \: sharing \: with \: other \: velocity[/tex]
A pumpkin is shot upwards at a speed of 15.5 m/s from the ground and lands on a 3.00m
high platform. How long before it hits and smashes?
Answer:
0.2seconds
Explanation:
Speed=distance/time
15.5m/s=3.00m/x seconds
x=3/15.5
x=0.1935
x=0.2sec
hope this helped
A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resistance
Explanation:
The power P dissipated by a heater is defined as
[tex]P = VI[/tex]
where V is the voltage and I is the current.
a) The current running through a 130-W heater is
[tex]I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}[/tex]
b) The resistance R of the heater is
[tex]P = VI = (IR)I = I^2R[/tex]
where [tex]V= IR[/tex] is our familiar Ohm's Law.
[tex]\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}[/tex]
[tex]R = 110.8\:Ω[/tex]
The current running through the heater when it is operating is 1.08 A.
The resistance of the heater is 110.8 ohm.
What is current?A current is a flow of Charges.The formula of current is , current I = power P / voltage VThe SI unit of current is ampere A.So, from the above equation we can calculate,
current I = P/V
∴ I = 130 / 120
∴ I = 1.08 A
What is resistance?The resistance is a quantity which oppose the current flow in a circuit.The formula of resistance is ( in the terms of power P and ohm's law V=IR ) resistance R = P/I^2.The SI unit of resistance is ohm.So, from the equation we can calculate,
Resistance R = P/I^2
∴ R = 130/(1.08)^2
∴ R = 110.8 ohm
Thus, the current running through the heater when it is operating is 1.08 A.
The resistance of the heater is 110.8 ohm.
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question below................
Answer:
do your work why you in class and you would know
Explanation:
50 points please help ASAP! !
What is the average velocity of an object that moves from 6 meter to 2 meter relative to origin in 2 second?
[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{Total\: Displacement }{Total\: time}[/tex]
[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{4}{2}=2m/s[/tex]
Two students were climbing stairs at school. Student 1 has a weight of 700 N. Student 2 has a weight of 650 N. How much power would each student have if each took 6 s to climb a 4 m tall flight of stairs?
Student 1 would have 4200 W, and Student 2 would have 3900 W of power.
Student 1 would have 116 W, and Student 2 would have 108 W of power.
Student 1 would have 2800 W, and Student 2 would have 2600 W of power.
Student 1 would have 467 W, and Student 2 would have 433 W of power.
Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
From the question,
We are to calculate the power each student would have to climb the flight of stairs.
Power can be calculated using the formula
[tex]P = \frac{F \times d}{t}[/tex]
Where
P is Power
F is the force
d is the distance
and t is the time
NOTE: The weight of the students represent the force
For student 1F = 700 N
d = 4 m
t = 6 s
∴ [tex]P = \frac{700 \times 4}{6}[/tex]
P = 467 W
For student 2
F = 650 N
d = 4 m
t = 6 s
∴ [tex]P = \frac{650 \times 4}{6}[/tex]
P = 433 W
Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.
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¿Por qué el origen de ciertos metales se relaciona con la dinámica terrestre?