Answer:
Mr Myers and his son use the same force to pull the bags between the gates
Explanation:
The work done by Mr. Myers in pulling the carryon bags = The work done by his 13 year old grandson in pulling the identical bag
Let F₁ represent the force used by Mr Myers, and let F₂ represent the force F₂ used by his grandson
Let d represent the distance through the gate
Therefore, given that Work done, W = Force, F × Distance, we have;
The work done by Mr Myers between the gates, W₁ = F₁ × d
The work done by his grandson between the gates, W₂ = F₂ × d
Where, the work done by both Mr Myers and his grandson are equal, we have;
W₁ = W₂ and therefore, F₁ × d = F₂ × d, which gives;
F₁ = F₂, the force used by both Mr Myers and his son between the gates are equal.
A wagon moving down the road has 2000 kg m/s of momentum. Then a 500-kg bag of feed with no velocity is added to the wagon. What is the new momentum of the wagon with the feed bag in kg m/s?
Answer:
The new momentum of the wagon with the feed bag is (also) 2,000 kg·m/s
Explanation:
The given momentum of the wagon = 2000 kg·m/s
The mass of the added bag = 500 kg
The initial velocity of the bag of feed = 0 m/s
Therefore, by the conservation of momentum principle, we have;
The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = The new momentum of the wagon with the feed bag
Which gives;
The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = 2,000 kg·m/s + 500 kg × 0 = 2,000 kg·m/s = The new momentum of the wagon with the feed bag
Therefore, the new momentum of the wagon with the feed bag = 2,000 kg·m/s.
A graph showing the kinetic energy of a 10 kg object at different
speeds is provided:
Answer:
20 Joules
Explanation:
by seeing the Graph, we know that the graph will be curved. Then we can assume that the KE at speed 2 m/s is 20 Joules. But lets count it:
KE = ½ x m x v²
KE = ½ x 10 x 2²
KE = 5 x 4 = 20 Joules
Distance = 500 miles
Time = 10 hours
Average Speed = ?????
Scientists are studying a moving glacier. To monitor the flow of the glacier, they place a series of five markers, A, B, C, D, and E, in a straight line across the path of flow. A and E are closest to the edges of the glacier. C is in the center of the glacier. B and D are between A and C and C and E respectively. How would the scientists predict the motion of each of the markers relative to the edges of the valley down which the glacier flows? What pattern would they predict in the markers over time?
Answer: c a d b
Explanation:
Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers thus, The pattern they predict in the markers over time would be C D A B.
How would the scientists predict the moving glacier of the markers relative to the edges of the valley down which the glacier flows?In some parts of the world, glaciers are an important natural resource because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.
Due to this, Glaciologists monitor and try to predict the movement and morphology of glaciers.
One of the techniques used by "Glaciologists" in the monitoring and prediction of glaciers in the use of markers.
The movement of markers is measured relative to the edges of the valley down which the glacier flows.
Thus, The movement of the markers are then predicted using the Glen–Nye Flow Law.
The pattern they predict in the markers over time would be C D A B.
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A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.
Complete Question
A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope
Answer:
The value is [tex]F = 150 \ N[/tex]
Explanation:
From the question we are told that
The mass of the man is [tex]m_m = 75 \ kg[/tex]
The mass of the woman is [tex]m_f = 100 \ kg[/tex]
The acceleration of the man is [tex]a_m = 2.0 \ m/s ^2[/tex]
Generally the force which she used to pull the rope is mathematically represented as
[tex]F = m * a[/tex]
=> [tex]F = 75 * 2[/tex]
=> [tex]F = 150 \ N[/tex]
The variables for Part I of this experiment include whether or not the car hits the barrier and the distance that the washers travel. Use the drop-down menus to identify the independent and dependent variables.
The independent variable, the one that is intentionally manipulated, is
____.
The dependent variable, the one that you measure the response in, is
___.
Answer:
1. An encounter with the barrier
2. The distance traveled by the washer.
Explanation:
Answer:
Peep above me is correct
1.An encounter with the barrier
2.The distance traveled by the washer
Explanation:
got it right on edge2020 have a nice day peeps ^w^
Explain the significance of the thermometer, the electric heater, and the power supply.
Answer:
This question appear incomplete
Explanation:
This question appear incomplete. However, the significance/functions of the "instruments" mentioned (in the completed question) can be predicted since these "instruments" generally have specialized function.
A thermometer is used to determine the temperature of a substance or an object. The electric heater uses electricity to produce heat (which can be utilized for different purposes). The power supply is used to supply electricity for instruments/appliances that may require electricity to function.
An object has an acceleration of 6.0 m/s/s. If the net force acting upon this object were tripled , then its new acceleration would be _____ m/s/s.
Answer:
18m/s/s
Explanation:
6 times 3= 18
What is the velocity of a car with a momentum of 100 kg*m/s and a mass of 35kg?
Answer:
2.86 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{p}{m} \\ [/tex]
p is the momentum
m is the mass
From the question we have
[tex]v = \frac{100}{35} = \frac{50}{7} \\ = 2.857142...[/tex]
We have the final answer as
2.86 m/sHope this helps you
(1) A block of wood weighs 980N on earth where acceleration due to gravity is 9.8N/Kg. The
moon has acceleration times that on earth. Determine the weight of the block of wood
on the moon.
(3 marks)
Given,
Weight of a block on the Earth = 980 N
Acceleration due to gravity on Earth = 9.8 N/kg
To find,
Weight of the block on the moon.
Solution,
The moon has acceleration (1/6) times that on earth. Let m be the mass of the block on the moon.
We know that,
W = mg
[tex]m=\dfrac{W}{g}\\\\m=\dfrac{980}{9.8}\\\\=100\ kg[/tex]
As mass of an object remains the same everywhere. Weight of the block on Moon is :
W' = mg'
As g'=(g/6)
So,
[tex]W=100\times \dfrac{g}{6}\\\\=100\times \dfrac{9.8}{6}\\\\=163.33\ N[/tex]
So, the weight of the block on the moon is 163.33 N.
The type of charge on an object depends on what? Material of object quality of object force of rubbing thickness of object please tell
Explanation:
Type of charge on an object depends upon the material of the object. However, most of the material are electrically neutral. Since, they have equal number of positive and negative charges on them. So, they act as if they have no charge at all.
Hence, option A is correct.
What is a Cell?
Don't look it up PLEASE... I WILL GIVE BRAINLIEST
Answer:
well
Explanation:
A cell is the basic functional and structural unit of life
Answer:
Cells are the basic building blocks of all living things
Explanation:
An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a rate of 24 m per year at a time when the region is 300 m wide. How fast is the area changing at that point in time
Answer:
[tex]\frac{dA}{dt} = 28800 \ m^2/year[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Geometry
Area of a Rectangle: A = lwAlgebra I
Exponential Property: [tex]w^n \cdot w^m = w^{n + m}[/tex]Calculus
Derivatives
Differentiating with respect to time
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Explanation:
Step 1: Define
Area is A = lw
2w = l
w = 300 m
[tex]\frac{dw}{dt} = 24 \ m/year[/tex]
Step 2: Rewrite Equation
Substitute in l: A = (2w)wMultiply: A = 2w²Step 3: Differentiate
Differentiate the new area formula with respect to time.
Differentiate [Basic Power Rule]: [tex]\frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}[/tex]Simplify: [tex]\frac{dA}{dt} = 4w\frac{dw}{dt}[/tex]Step 4: Find Rate
Use defined variables
Substitute: [tex]\frac{dA}{dt} = 4(300 \ m)(24 \ m/year)[/tex]Multiply: [tex]\frac{dA}{dt} = (1200 \ m)(24 \ m/year)[/tex]Multiply: [tex]\frac{dA}{dt} = 28800 \ m^2/year[/tex]Answer:
28,800 m²/yr
Explanation:
This rectangle has dimensions such that:
width = wlength = 2wWe are given [tex]\displaystyle \frac{dw}{dt} = \frac{24 \ m}{yr}[/tex] and want to find [tex]\displaystyle \frac{dA}{dt} \Biggr | _{w \ = \ 300 \ m} = \ ?[/tex] when w = 300 m.
The area of a rectangle is denoted by Area = length * width.
Let's multiply the width and length (with respect to w) together to have an area equation in terms of w:
[tex]A=2w^2[/tex]Differentiate this equation with respect to time t.
[tex]\displaystyle \frac{dA}{dt} =4w \cdot \frac{dw}{dt}[/tex]Let's plug known values into the equation:
[tex]\displaystyle \frac{dA}{dt} =4(300) \cdot (24)[/tex]Simplify this equation.
[tex]\displaystyle \frac{dA}{dt} =1200 \cdot 24[/tex] [tex]\displaystyle \frac{dA}{dt} =28800[/tex]The area is changing at a rate of 28,800 m²/yr at this point in time.
what is happening to energy as a substance goes from a gas state to a liquid state
Answer:
If we give it enough energy, the atom will eventually gain enough energy to vibrate out of the body. This is the next change of state. The molecules of water gain enough energy to escape from the surface of the water. This change of state from liquid to gas is called vaporization.
Explanation:
Answer:
B
Explanation:
It is decrasing
Help pleasseeee URGENT
If a 0.16 kg 8-ball at rest is hit by the 0.17 kg cue ball that is moving at a speed of 2 m/s, what is the speed of the 8-ball if the cue ball is completely stopped after the collision?
Answer:
The speed of the 8-ball is 2.125 m/s after the collision.
Explanation:
Law Of Conservation Of Linear Momentum
The total momentum of a system of masses is conserved unless an external force is applied. The momentum of a body with mass m and velocity v is calculated as follows:
P=mv
If we have a system of masses, then the total momentum is the sum of all the individual momentums:
[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]
When a collision occurs, the velocities change to v' and the final momentum is:
[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]
In a system of two masses, the law of conservation of linear momentum is simplified to:
[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]
The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.
After the collision, the cue ball comes to rest v2'=0. It's required to find the final speed v1' after the collision.
The above equation is solved for v1':
[tex]\displaystyle v'_1=\frac{m_1v_1+m_2v_2-m_2v'_2}{m_1}[/tex]
[tex]\displaystyle v'_1=\frac{0.16*0+0.17*2-0.17*0}{0.16}[/tex]
[tex]\displaystyle v'_1=\frac{0.34}{0.16}[/tex]
[tex]v'_1=2.125\ m/s[/tex]
The speed of the 8-ball is 2.125 m/s after the collision.
Where is the epicenter of the hypothetical earthquake as shown in the illustration below?
A. Point A
B. Point B
C. Point C
D. Point D
Answer:
Point D
Explanation:
The epicenter of a hypothetical earthquake is located at the point where the earthquake begins.
(See the attached image).
Hope it helps!
A force of 10N is making an angle of 30
with the horizontal. Its vertical component
will be;
Explanation:
The vertical component = 10sin30° = 5.0N.
Free fall differs from terminal velocity, in that during free fall
A.
only air resistance is acting on an object
B.
only gravity is acting on an object
C.
air resistance and gravity are acting on an object with unequal magnitudes
D.
air resistance and gravity are acting on an object with equal magnitudes
Answer:
B
Explanation:
n=Q/e formula of this?
Answer:
Its not just a mere formula . It tells a hell lot about charges .
q = ne . As you know , q stands for charge and e stands for charge on an electron . As for n , it represents an integer.
This whole q=ne thing represents quantisation of charge. The formula tells us that charge is quantized ( in the form of small packets)
Every body on this small earth has a charge which has to be an integral multiple of ‘e’ . So , we represent charge on a body(q) as
q=ne.
Hence the formula .
I hope you got what I want to say .
Thanks for reading .
What are the forces on a feather falling down gravity normal force friction push force pull force?
Hot air balloon ( look at pic)
Answer:
I think that the answer is convection.
Explanation:
Hope this helps.
A billiard ball bangs against a side bumper, giving the ball a speed of 5 m/s. If the
ball has a mass of 0.15 kg, what is the ball's kinetic energy in joules?
Answer:
1.875 joules
Explanation:
K.E=1/2 mv²
K.E=1/2 0.15×5²
K.E=1.875 joules
a fire woman dropped a person onto the safety net. right before the person hit the net he had a velocity of 11.2m/s and 1800j of kinetic energy
Answer: 28.699
Explanation:
KE=1/2(mv²)
1800=1/2m (125.44)
14.349=2m
m=28.699
Answer:
28.699
Explanation:
does the voice from loudspeaker also get shrill when the listener reaches the sounding source?
Answer:
Yes, cause when listener is far away from music source... the listener feels it's pleasant.... but when observer approaches near loudspeaker... sound become unpleasant..........sound becomes noise when frequency crosses 85 Decibels.....so you can say that the voice from loudspeaker also get shrill when the listener reaches the surrounding source......
The stars with medium temperatures appear ______________ in color (check all that apply.)
a. red
b. orange
c. yellow
d. blue
An object has three forces acting upon it, the first force is 58.2 N to the right and the second force is 14.0 N to the left. What is the magnitude of the third force, such that the object travels at a constant velocity? Answer in units of N and be sure to include all necessary work, as well as a free body diagram.
Help Please!
Answer:
44.2 N towards left
or
-44.2 N towards right
Explanation:
pls refer attachment for detailed solution
Dawn and Timothy are sailboating in Lake Obewon. Starting from rest near the shore, they accelerate with a uniform acceleration of 0.39 m/s/s. How far are they from the shore after 18 seconds? *
Answer:
The value is [tex]s =63.18 \ m[/tex]
Explanation:
From the question we are told that
The uniform acceleration is [tex]a = 0.39 \ m/s^2[/tex]
The time considered is [tex]t = 18 \ seconds[/tex]
Generally the from kinematic equation we have that
[tex]s = ut + \frac{1}{2} at^2[/tex]
Given that the boat started from rest , the initial velocity is u = 0 m/s
So
[tex]s = 0 * 18 + \frac{1}{2} *0.39 * 18^2[/tex]
=> [tex]s =63.18 \ m[/tex]
a tiger moving with constant accleration covers the distance between two points 70 meter apart in 7 seconds . its speed as it pass the second point 15 meter per second . 1) what is the speed at the first point. 2) what us its accleration
Answer:
a = 1.428 [m/s²]
v₀ = 5 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]x=x_{o}+v_{o}*t+\frac{1}{2}*a*t^{2}[/tex]
where:
x = final point [m]
x₀ = initial point [m]
v₀ = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
But we need to use this additional equation.
[tex]v_{f}=v_{o}+a*t[/tex]
where:
vf = final velocity = 15 [m/s]
Now we can use this equation, replacing it, in the first one. We must bear in mind that the difference among x - x₀ is equal to 70 [m]
[tex]x-x_{o}=v_{o}*t+\frac{1}{2}*a*t^{2} \\x-x_{o}=(v_{f}-a*t)*t+\frac{1}{2} *a*t^{2}\\70=(15-a*t)*t+\frac{1}{2}*a*t^{2}\\70=15*t-a*t^{2} +\frac{1}{2}*a*t^{2} \\70=15*t-\frac{1}{2}*a*t^{2}\\70=15*(7)-\frac{1}{2} *a*(7)^{2}\\105-70=0.5*a*49\\35=24.5*a\\a=1.428[m/s^{2} ][/tex]
Now replacing this value in the second equation, we can find the initial velocity.
[tex]15=v_{o}+1.428*7\\v_{o}=5[m/s][/tex]
Which statement illustrates how progress in engineering has affected the natural environment? (O A. Engineers continue to make design improvements to solar panels, making them ever more efficient in providing electricity. O B. The development of new solar panel technology drives the development of battery technology. O C. Engineers have developed solar energy technology that reduces the need for other sources of energy that can pollute the atmosphere. (® D. As solar energy technology continues to improve, it is becoming a more attractive source of energy than sources that use fossil fuels.
Explanation:
sorry but Oz is the option or anything else can clarify
Engineers have developed solar energy technology that reduces the need for other sources of energy that can pollute the atmosphere. So, option C.
What is meant by solar energy ?Solar energy is defined as the solar radiation that has the potential to ignite chemical processes, produce heat, or generate electricity.
Here,
In order to protect wildlife, and ecosystems, it is imperative that greenhouse gas emissions are reduced and climate change is mitigated. Solar energy plays a significant part in this as a renewable source of energy.
Additionally, solar energy can reduce water use in energy production and enhance air quality.
An extremely crucial factor considering the scarcity of water is that solar energy does not produce waste or contaminate water. Wind energy is essential for preserving hydrological resources because it consumes among the least amounts of water compared to fossil fuels and nuclear power facilities.
Hence,
Engineers have developed solar energy technology that reduces the need for other sources of energy that can pollute the atmosphere. So, option C.
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The speed of sound is 344 m/sec when the air is 20 degrees Celsius how far is the source of the sound if it takes 8 seconds for the sound to reach you?
Answer: 2752 m
Explanation:
344*8=