In rectangular park that is 63 yards by 16 yards, a dog began in the northwest corner and ran south along the length of the park. Then the dog ran east along the width to the southeast corner. Finally, the dog ran back to the northwest corner. How far did the dog run?

A unit's marginal cost, as used in economics, is the difference in total production costs that results from creating or manufacturing an extra unit.  To determine the marginal cost, divide the changes through production expenses even by quantity that has changed.

Marginal revenues are calculated by such a corporation by dividing the change in the total revenue by the total change in output quantity.

The additional cost to create a new item is known as the marginal cost. Say, for instance, that it costs $100 to produce 100 vehicle tyres. It would cost $80 to produce one extra tyre. The cost to produce one more unit of an item or service is therefore known as the marginal cost.

Marginal cost is equal to the difference between two costs (Change in quantity)

The volume of output either increases or decreases, which affects quantity.

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In economics, a unit's marginal cost is the difference in overall production costs that arise from producing or constructing an additional unit. Divide the changes in production costs even by the altered quantity to get the marginal cost.

Marginal revenues are computed by dividing the change in total income by the total variation in the output quantities.

The marginal cost is the additional expense incurred while producing a new good. Consider the example of 100 car tires costing $100 to create. One additional tire would cost $80 to create. The marginal cost is consequently the cost incurred when producing an additional unit of a good or service.

The difference between two costs (Change in quantity) is known as the marginal cost. Quantity is impacted by either an increase or decrease in output volume.

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Solve one of the equations for one of the variables as the first step in substitution method.

In order to write one of the equations as x = or y =, we must first determine which variable in the two equations is the simplest to solve for. The other equation will then have either the x or the y replaced appropriately. The outcome will be a single-unknown equation that we can solve. Isolating a variable whose coefficient is 1 or -1 is useful.

Step 1: Solve one of the equations for one of the variables.

Step 2: Enter the expression as a replacement in the remaining equation. The outcome will be a single-variable linear equation that can be solved.

Step 3: Resolve the last equation.

Step 4: To find the value of the other variable, substitute the result into the other equation.

Step 5: The intersection of the two equations, which represents the coordinates of the ordered pair, is the system's solution.

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Answer: 7 1/5

Step-by-step explanation: First convert 3 3/5 into an improper fraction which is 18/5. Then flip 1/2 which becomes 2/1. Do: 18/5 x 2/1. You get 36/5. Reduce that into a mixed number by dividing 5 into 36. 5 goes into 36 seven times. 36 minus 35 is 1. Put that over 5 and you get the answer being 7 1/5.

To find the number of people with different amounts of pets, we need to first count the number of instances each pet number occurs.The survey of forty people revealed that there were three people with four pets, seven people with three pets, nine people with two pets, seventeen people with one pet

2, 0, 3, 1, 0, 0, 4, 0, 0, 2, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 3

There are:

* 3 people with 4 pets

* 7 people with 3 pets

* 9 people with 2 pets

* 17 people with 1 pet

* 8 people with 0 pets

To find the number of people with different amounts of pets, we need to first count the number of instances each pet number occurs. To do this, we can go through the list of numbers and count how many times each number appears.

For example, the number "2" appears three times in the list, meaning that there are three people with two pets. If we do this for all the numbers in the list, we get the results listed above.

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Then the two solutions are: x = (4 + 5.66) / 8 = 11.2075  and x = (4 - 5.66) / 8 = -0.2075

The sine approximation formula of Bhaskara I is a rational equation in one variable for computing the approximations of the trigonometric sines found by Bhaskara I (c. 600–c. 680), an Indian mathematician of the seventh century.

Indian astronomer and mathematician Bhaskara II lived in the 12th century. He created a number of the same foundations and findings that are entirely attributable to Europeans and are still very helpful in modern science and forecasts, such as a basic form of calculus.

Here we have the equation:

y = 4 × x² - 4 × x - 1

And the graph should be available (you can see it below this answer)

Now, we're seeking answers to:

4 × x²- 4 × x - 1 = 0

The two x values at which the graph of our function intersects the y = 0 line, or the x-axis, will be these solutions.

The next step is to identify the two x values where our graph crosses the x-axis.

We can estimate the solutions in the graph as follows:

x = -0.2

x = 1.2

The Bhaskara's equation can be used to determine the precise solutions, and we will discover that the solutions are provided by:

[tex]$x=\frac{-(-4)+-\sqrt{(-4)^2-4 * 4 *(-1)}}{2 * 4}=\frac{4+-\sqrt{32}}{8}=\frac{4+-5.66}{8}[/tex]

Then the two solutions are:

x = (4 + 5.66) / 8 = 11.2075

x = (4 - 5.66) / 8 = -0.2075

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data collected by imposing a treatment on a sample and examining the results is data collected as a result of computer modeling. Left skewed distribution is data collected that does not fairly represent the population.

Mode [ Choose ]

x  Continuous variable

n  N

σ  σ²

r  q = 1 – p

Mode  Most frequently occurring value in the date set

Left skewed distribution  Data is collected that does not fairly represent the population

Normal distribution  Data is collected by asking a series of questions

A measure of the spread or variability of the data set  Data is collected by watching

Data is collected by imposing a treatment on a sample and examining the results  Data is collected as a result of computer modeling

x is a continuous variable, n is N, σ is σ², r is q = 1 – p, mode is the most frequently occurring value in the date set, a left skewed distribution is data collected that does not fairly represent the population, a normal distribution is data collected by asking a series of questions, a measure of the spread or variability of the data set is data collected by watching the behavior of sample, and data collected by imposing a treatment on a sample and examining the results is data collected as a result of computer modeling.

x is a continuous variable, n is N, σ is σ², r is q = 1 – p, mode is the most frequently occurring value in the date set. Data collected by asking a series of questions is a normal distribution, data collected by watching the behavior of sample is a measure of the spread or variability of the data set, and data collected by imposing a treatment on a sample and examining the results is data collected as a result of computer modeling. Left skewed distribution is data collected that does not fairly represent the population.

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Answer:

c = 10

w = -6

r = 6

b = 1.5 or 3/2

Step-by-step explanation:

1) 2c + 4 = 7c - 46

2c - 2c + 4 = 7c - 2c - 46

4 + 46 = 5c - 46 + 46

50 = 5c

c = 10

2) -3w + 8 = -6w - 10

-3w + 6w + 8 = -6w + 6w - 10

3w + 8 - 8 = -10 - 8

3w = -18

w = -6

3) (1/6)r + 1 = 3r - 16

(1/6)r - (1/6)r + 1 = 3r - (1/6)r - 16

1 + 16 = (17/6)r - 16 + 16

(17/6)r = 17

r = 17*(6/17)

r = 6

4) -7b - 1 = -5b - 4

-7b + 7b - 1 = -5b + 7b - 4

-1 + 4 = 2b - 4 + 4

2b = 3

b = 3/2 or 1.5

Hope this helps!

The methods of solving a quadratic equation are: Factoring, Quadratic Formula, Completing the Square, and Graphing.

There are several methods for solving a quadratic equation of the form ax² + bx + c = 0. The most common methods are:

1. Factoring: Factor the equation into the form (ax + b)(cx + d) = 0 and set each factor equal to zero. This will give you the solutions for x.

2. Quadratic Formula: Use the quadratic formula x = (-b ± √(b^2 - 4ac)) / 2a to find the solutions for x.

3. Completing the Square: Rewrite the equation in the form a(x + b/2a)^2 + c = 0 and then solve for x.

4. Graphing: Plot the equation on a coordinate plane and find the x-coordinates of the points where the graph crosses the x-axis (the solutions for x).

It is important to note that not all the methods are always applicable for all types of the quadratic equations.

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The three lengths that cannot be the lengths of the sides of a triangle are 21m, 6m, and 10m and it can be determined by using the triangle inequality theorem. The correct option is A.

The triangle inequality theorem can be used to determine which three lengths cannot be the lengths of the sides of a triangle.

According to the triangle inequality theorem, the sum of any two sides of a triangle must be greater than or equal to the third side of the triangle.

Option C -Sides of the triangle are: 23m, 17m, and 14m

Option C represents the sides of a triangle because the sum of any two given sides is greater than the third side.

Option B - Sides of the triangle are: 11m, 11m, 12m

Option B represents the sides of a triangle because the sum of any two given sides is greater than the third side.

Option D- Sides of the triangle are: 5m, 7m, 8m

Option D represents the sides of a triangle because the sum of any two given sides is greater than the third side.

Option A-Sides of the triangle are: 21m, 6m, and 10m

Option A- does not represent the sides of a triangle because the sum of any two given sides is not greater than or equal to the third side.

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Answer: yam

Step-by-step explanation: Tape, Twine, and Cord are all materials we use. Yam is a type of vegetable so the answer is D, Yam

Answer:  In triangle AGH, we can use the Law of Sines. The law of sines states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides of the triangle.

so, a/sin(A) = b/sin(B) = c/sin(C) = 2R where R is the circumradius of the triangle.

Given, g = 9.6 inches, m/I = 80° and m/G = 15°

AG = h, angle A = (180 - 80) = 100, angle G = (180-15) = 165

So we can use the Law of Sines to find the h,

h/sin(100) = g/sin(165) = 9.6 / sin(165) = 9.6 / sin(165) = 9.6 / 0.9659 = 9.98 inch.

Rounded to the nearest 10th of an inch, h = 9.98 inches.

Step-by-step explanation:

Answer: 85

Step-by-step explanation:

Answer:

It's exactly 1 .........

So, 175 children's tickets were sold, and 100 adult tickets were sold.

We can start solving the problem by using a system of equations. Let x be the number of children's tickets and y be the number of adult tickets. We know that:

x + y = 275 (the total number of tickets sold)

3x + 5y = 1025 (the total value of the tickets sold)

To find the number of each type of ticket sold, we can use the first equation to express one of the variables in terms of the other, and then substitute that into the second equation. For example, we can express y in terms of x:

y = 275 - x

Now we can substitute this into the second equation and solve for x:

3x + 5(275 - x) = 1025

3x + 1375 - 5x = 1025

-2x = -350

x = 175

So, 175 children's tickets were sold, and 275 - 175 = 100 adult tickets were sold.

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Answer:

You spent $39 this month on clothing

Step-by-step explanation:

Set up the proportion

[tex]\frac{x}{30} =\frac{130}{100}[/tex]

Cross multiply

130*30 = 100*x

Simplify

3900 = 100x

Solve

x = 39

We can see here that the text features that could support the ideas in the passage are :

Definition: "A satellite is an object that orbits a planet."

Examples: "Manmade satellites orbit Earth and serve many purposes. Satellites send phone calls, radio signals, and television signals from one place to another. NASA uses satellites to take pictures."

Cause and effect: "The pictures help scientists learn about conditions on Earth and other planets."

A text is a written or spoken piece of information or communication. It can take many forms such as a book, article, poem, speech, or conversation. It can contain a variety of content such as stories, information, instructions, or arguments. The purpose of a text can vary widely depending on the context in which it is created, including entertainment, education, persuasion, or documentation.

We see here that the text features likely to be seen in the passage has been identified as seen above.

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An equation that relates c and b for this problem situation is 39b - 18c = 2085.

The superposition principle is met by a linear equation. Give your function the name f(x), where x may be a vector. If f(x1 + x2) = f(x1) + f(x2) and f(αx) = αf, then the function f is linear (x). This is a very potent quality that enables you to reduce a complex situation to a collection of simple ones.

Derivatives, integrals, expectations (derived from probability), Laplace and Fourier transforms are a few examples of linear functions (the following are also referred to as operators).

Let the no, of bottles be x

Equation for Healthy Drinks

c = 0.39x + 25

[tex]\text x = \dfrac{(c - 25)}{0.39}$[/tex]

Equation for Squeeze

b = 0.18x + 65

[tex]\text x = \dfrac{(b - 65)}{0.18}$[/tex]

As x is equal x, then their values are equal too

[tex]\dfrac{(c - 25)}{0.39} = \dfrac{(b - 65)}{0.18}$[/tex]

Cross multiply

0.39(b - 65) = 0.18(c - 25)

0.39b - 25.35 = 0.18c −4.5

0.39b - 0.18c = 25.35 −4.5

0.39b - 0.18c = 20.85

multiply each by 100

39b - 18c = 2085

Thus, an equation that relates c and b for this problem situation is 39b - 18c = 2085.

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Answer:

x = 2

Step-by-step explanation:

Given equation,

→ -6x + 2 = -10

Now we have to,

→ Find the required value of x.

Then the value of x will be,

→ -6x + 2 = -10

Subtract RHS with the number 2:

→ -6x = -10 - 2

→ -6x = -12

Cancel negative sign from both sides:

→ 6x = 12

→ x = 12/6

→ [ x = 2 ]

Hence, the value of x is 2.

Pair of linear equations y = 0 and y = -5 has no solutions as the equations represents the parallel lines.

As given in the question,

Given pair of linear equations are as follow:

y = 0

y = -5

Here linear equation y = 0 represent the whole x- axis.

And the linear equation y = -5 represents the line parallel to x -axis below the origin of x- axis.

Both the linear equation y = 0 and y = -5 represents the parallel lines so they don't intersect at any point.

And has no solution.

Therefore, the given pair of linear equations y = 0 and y = -5 represents parallel lines and has no solution.

The above question is incomplete , the complete question is:

How many solutions does the pair of linear equations y = 0 and y = - 5 has?

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Value of f[g(x-1)] is 2x^2-4x+9. The solution has been obtained by applying the multiplication operation on functions and substituting the functions.

Just like we add, subtract, multiply and divide the terms in a function, the functions can also be added, subtracted, multiplied or divided in a similar way.

Suppose there are two functions f(x) and g(x). The notations are as follows:

For Addition: (f+g)(x) = f(x) + g(x)

For Subtraction: (f-g)(x) = f(x) - g(x)

For Multiplication: (f×g)(x) = f(x) × g(x)

For Division: (f/g)(x) = (f(x))/(g(x))

When we substitute one function into another, a function is generated in which one function is considered to be a part of another function.

Now, f(g) = 2g-3

We are given g = x^2+5

So, g(x-1) = (x-1)^2+5

Substituting the value of g(x-1) in f(g), we get

f(g(x-1)) = 2((x-1)^2+5)-3

= 2x^2-4x+9

Hence, the value of f[g(x-1)] is 2x^2-4x+9.

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Answer: Trinomial

Step-by-step explanation:

Tri- means three terms.

It is not possible to construct a triangle whose sides are 2cm 3cm and 5cm because the sum of two sides(2 cm and 3 cm) are equal to the third sides(5 cm).

In the given question, we have to check that it is possible to construct a triangle whose sides are 2cm 3cm and 5cm.

To check whether the given sides can make a triangle or not, we have to check that the sum of two sides always greater than the third side.

To check this we firstly add the 2 and 3

2 + 3 = 5

5 = 5

Now we add 2 and 5

2 + 5 > 3

7 > 3

Now we add 3 and 5

5 + 3 > 2

8 > 2

It is not possible to construct a triangle whose sides are 2cm 3cm and 5cm because the sum of two sides(2 cm and 3 cm) are equal to the third sides(5 cm).

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The normal distribution table appears to be slightly biased to the right. Since the values are randomly distributed, a normal distribution cannot be assumed.

An example of a continuous probability distribution is the normal distribution, in which the majority of data points cluster near the middle of the range and the remaining ones decrease symmetrically toward one of the extremes.

Maximum Value=121.9

Number of classes=5 (say)

Range=121.1-121.9=0.8

Minimum Value= 121.1

width of each class= 0.8 / 5 = 0.16 = 0.2 (approx)

Therefore, we must create classes so that the first class has the minimum value and the last class contains the highest value. The class interval will therefore be 121.1 - 121.3, 121.3 - 121.5, and so on with a class width of 0.2 volt.

Voltage (volts) Frequency

121.1 - 121.3             2

121.3 - 121.5                 5

121.5 - 121.7             10

121.7 - 121.9              6

121.9 - 122.1                  2

The normal distribution table appears to be slightly biased to the right. Since the values are randomly distributed, a normal distribution cannot be assumed.

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The only point that has the same distance from the center as the others are point (5 + 12i). Therefore, the answer is option b. (5 + 12i).

To find which point is also on the circle, we can use the distance formula to find the distance between each point and the center of the circle. The center of the circle can be found by taking the midpoint of the diameter, which has endpoints at -3+18i and 7-6i. The midpoint can be found by averaging the x-coordinates and the y-coordinates of the two endpoints:

x-coordinate: (-3 + 7)/2 = 2

y-coordinate: (18 - 6)/2 = 6

So the center of the circle is at (2, 6).

Now we can use the distance formula to find the distance between each point and the center of the circle:

Point a: |(-7 - 2) + (7 - 6)| = |-9 + 1| = 10

Point b: |(5 - 2) + (12 - 6)| = |3 + 6| = 9

Point c: |(12 - 2) + (-1 - 6)| = |10 + 7| = 17

Point d: |(14 - 2) + (11 - 6)| = |12 + 5| = 17

The distance from the center of the circle to each point is the radius of the circle, so all points on the circle should have the same distance from the center. So, the only point that has the same distance from the center as the others is point b.

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The complete question is -

A circle has a diameter with endpoints at -3 + 18i and 7 - 6i. Which point is also on the circle?

a. -7 + 7i

b. 5 + 12i

c. 12 - i

d. 14 + 11i

Answer:

y = - 3

Step-by-step explanation:

a line with a slope of zero is a horizontal line, parallel to the x- axis with equation

y = c ( where c is the value of the y- coordinates the line passes through )

the line passes through (0, - 3 ) , the y- intercept with c = - 3 , then

y = - 3 ← equation of line

note this equation cannot be expressed in slope- intercept form

The number 437.184 can be rounded or estimated as  437 if estimated to the tenths.

In mathematics, estimation implies approximating or rounding numbers. This is commonly used to make calculations simpler or to apply maths to real life. For example, 8 oranges divided by 6 people is equal to 1.33; however as calculating 0.33 when cutting oranges might be quite difficult it is better to estimate it as 1.

The general rule is that if a number is above five you should estimate it to the next unit, but if the number is below 5 you should estimate it to 0. Here is an example:

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The number of students the teacher bought for is 27.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Cost of a yogurt cup = $2.

Cost of a textbook = $13

Cost for one students = 2 + 13 = $15

Total cost = $405

The number of students.

= Total cost / Cost of one student

= 405 / 15

= 27

Thus,

The number of students is 27.

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Answer:

It's B

"Yes, the constant of proportionality is 2."

Step-by-step explanation:

The time or X shows the same numbers shown in distance or Y

it's just Time x2 for distance

We also know that the line passes through the point (6,4), so we can substitute these values into the equation of the line and solve for c:

4 = 1(6) + c

c = -2

The slope of a line is a measure of how steep the line is. It is the ratio of the change in the y-coordinate (rise) to the change in the x-coordinate (run) between two points on the line. The slope is also commonly referred as the "gradient" of a line. A line with a positive slope goes up from left to right, a line with a negative slope goes down from left to right, and a line with a slope of 0 is a horizontal line.

The formula to calculate the slope (m) with given two points (x1, y1) and (x2, y2) is:

m = (y2 - y1) / (x2 - x1)

The equation of a line in slope-intercept form is y = mx + b, where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis). Since the line has a slope of 1 and passes through the point (10, c), we know that the y-intercept is c.

We also know that the line passes through the point (6,4), so we can substitute these values into the equation of the line and solve for c:

4 = 1(6) + c

c = -2

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Round shape of the lightbulb gives advantage over any other shape for the future development of the bulb.

The round shape of the bulb scattered the light towards outside more evenly. The light source inside the lightbulb, like filament, LED, etc., kept at the focus of the round shaped bulb. round shape bulb gives the lensing(concave lens) effect to the glass that outwardly bends the light so the light cannot focus in a particular direction, but rather scattered more evenly in all directions. Any other shape like, rectangular, prismatic, or cubic shapes do not allow even scattering of light. These shapes bends the light non-uniformly through corners and walls.  

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Mrs. Moore class has the smaller interquartile range

From the question, we have the following parameters that can be used in our computation:

Dot plots

On the dotplots, we have the following readings

           Mr Kim:       Mrs. Moore

Q1        64                   62

Q3       69                   66

The difference between Q3 and Q1 is the IQR

So, we have

           Mr Kim:       Mrs. Moore

Q1        64                   62

Q3       69                   66

IQR       5                     4

4 is less than 5

Hence, Mrs Moore class has smaller IQR

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