sorry I didn't understand the question ask you to do
In the Lewis structure for FeF3, how many lone pairs surround the iron atom?
NEED ASAP
Select one:
a. 0
b. 1
c. 2
d. 3
Clear my choice
Answer:
b. 1
Explanation:
If we consider it carefully we will notice that the electronic configuration of iron III is; [Ar] 3d5 4s0.
Now, three electrons from the d orbital are paired with the three electrons from three F atoms according to the valence bond theory. This leaves out one pair of electrons localized on the d orbital of iron.
Hence the compound has one lone pair of electrons.
Complete the sentence. Select all that apply. The use of the term "energy levels" in the text implies:
s, p, d, f
a quantized amount of energy found at the different levels
n = 1, 2, 3, ...
orbitals
groups
The energy levels of an atom is the quantized amount of energy found at different levels n = 1,2, 3 etc. Thus option B is correct.
What is energy levels?Electrons in an atom are revolving around the nucleus through circular paths of fixed energy. These circular paths are called orbits and the different energy levels in these paths are called orbitals.
The quantized energy levels are termed as n = 1, 2, 3 that is lowest level to higher levels of energy. Electrons are able to transit between these energy levels.
Thus, a level of n=1 is the ground level or first energy level n =2 is second energy level and so on. These energy level cannot be fractions and therefore, they are said to quantised. Hence, option B is correct.
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Answer: n = 1, 2, 3,
a quantized amount of energy found at the different levels
Explanation:
which factor causes metamorphic rock to turn into igneous rock?
A. melting and then cooling
B.weathering and erosion
C.heat and pressure
D.cementation
Which group on the periodic table contains chemical elements that are usually brittle as solids, shiny, and able to conduct electricity under certain conditions? O A. Metals O B. Metalloids C. Representative metals D. Nonmetals
Answer:
Metals
Explanation:
how do we calculate standard electrode potentials
Explanation:
[tex]answer[/tex]
The overall cell potential can be calculated by using the equation E0cell=E0red−E0oxid. Step 2: Solve. Before adding the two reactions together, the number of electrons lost in the oxidation must equal the number of electrons gained in the reduction. The silver half-cell reaction must be multiplied by two.
Please help me this is a big grade please
Answer:
water
Explanation:
because the others are in compounds and can not be considered as products lonely.
Fill in the coefficients that will balance the following reaction:
(Note: Use 1 as coefficient where appropriate.)
NaCl+
FeO →
Na²O+
FeCl?
Answer:
To balance a reaction, the amount of reactants must be equal to the amount of products, as stated by the Law of Conservation of Matter. It may help you to keep track of the number of each element in a list as you try to balance. It's not able to be balanced.
Answer:
2,1,1,1
Explanation:
Hope this helped!
HURRY NEED NOW! Calcium has a charge of +2. The chart lists the charges of different ions.
Which are possible equations for an ionic compound with calcium?
CaO, CaMg, or CaF2
Ca2Cl, CaNa, or CaP
CaF, CaMg, or CaNa
CaO, CaF2, or CaCl2
Answer:
CaO, CaF2, or CaCl2
Explanation:
In an ionic compound, the charges need to balance out. This is the only set of compounds that fits this criteria.
Answer:
CaO CaF2 CaCl2 are ionic
Explanation:
Because electronegativity difference between calcium and other atom is more than 1.7
what were the reslt of aurangzeb's religion policy ? what measures did he takes
Answer: The religious fanaticism of Aurangzeb overshadowed his virtues. His reversal of Akbar's policy of religious toleration resulted in weakening the entire structure of the Mughal empire. It led to several conflicts and wars in different parts of the country.
To determine the mass of CO2 that forms from a given mass of CaCO3, which of the following must be known? Check all that apply.
To determine the mass of CO₂, the following must be known :
the molar mass of CaCO₃ the mole ratio of CaCO₃ to CO₂ the molar mass of CO₂Further explanationReaction
Decomposition of CaCO₃
CaCO₃ ⇒ CaO + CO₂
Given the mass of CaCO₃, so to determine the mass of CO₂ :
1. Find the mol of CaCO₃ from the molar mass of CaCO₃
[tex]\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}[/tex]
2. Find the mole ratio of CaCO₃ : CO₂(from equation = 1 : 1)
[tex]\tt n_{CaCO_3}\div n_{CO_2}=1\div 1[/tex]
3. Find the mass of CO₂ from the molar mass of CO₂
[tex]\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}[/tex]
Answer:
1 3 and 5
Explanation:
1. The diagram shows a box that is sliding down a ramp
F1
F4
F2
F3
Which arrow correctly indicates the direction of friction acting on the box?
A F1
B. F2
C3
D. 14
10 POINTS!!!
Answer:
F4
Explanation:
Friction is a force that opposes motion
Alice and Bob are experimenting with two moles of neon, a monatomic gas, that starts out at conditions of standard temperature and pressure (273.15 K, 105 Pa). Alice heats the gas at constant volume until its pressure is doubled, then Bob further heats the gas at constant pressure until its volume is doubled. If Alice and Bob assume that neon behaves as an ideal gas, then how much heat have they added to the gas for the entire process.
Answer:
29273.178 joules have been added to the gas for the entire process.
Explanation:
The specific heats of monoatomic gases, measured in joules per mol-Kelvin, are represented by the following expressions:
Isochoric (Constant volume)
[tex]c_{v} = \frac{3}{2}\cdot R_{u}[/tex] (1)
Isobaric (Constant pressure)
[tex]c_{p} = \frac{5}{2}\cdot R_{u}[/tex] (2)
Where [tex]R_{u}[/tex] is the ideal gas constant, measured in pascal-cubic meters per mol-Kelvin.
Under the assumption of ideal gas, we notice the following relationships:
1) Temperature is directly proportional to pressure.
2) Temperature is directly proportional to volume.
Now we proceed to find all required temperatures below:
(i) Alice heats the gas at constant volume until its pressure is doubled:
[tex]\frac{T_{2}}{T_{1}} = \frac{P_{2}}{P_{1}}[/tex] (3)
([tex]\frac{P_{2}}{P_{1}} = 2[/tex], [tex]T_{1} = 273.15\,K[/tex])
[tex]T_{2} = \frac{P_{2}}{P_{1}} \times T_{1}[/tex]
[tex]T_{2} = 2\times 273.15\,K[/tex]
[tex]T_{2} = 546.3\,K[/tex]
(ii) Bob further heats the gas at constant pressure until its volume is doubled:
[tex]\frac{T_{3}}{T_{2}} =\frac{V_{3}}{V_{2}}[/tex] (4)
([tex]\frac{V_{3}}{V_{2}} = 2[/tex], [tex]T_{2} = 546.3\,K[/tex])
[tex]T_{3} = \frac{V_{3}}{V_{2}}\times T_{2}[/tex]
[tex]T_{3} = 2\times 546.3\,K[/tex]
[tex]T_{3} = 1092.6\,K[/tex]
Finally, the heat added to the gas ([tex]Q[/tex]), measured in joules, for the entire process is:
[tex]Q = n\cdot [c_{v}\cdot (T_{2}-T_{1})+c_{p}\cdot (T_{3}-T_{2})][/tex] (5)
If we know that [tex]R_{u} = 8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K}[/tex], [tex]n = 2\,mol[/tex], [tex]T_{1} = 273.15\,K[/tex], [tex]T_{2} = 546.3\,K[/tex] and [tex]T_{3} = 1092.6\,K[/tex], the heat added to the gas for the entire process is:
[tex]c_{v} = \frac{3}{2}\cdot \left(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} \right)[/tex]
[tex]c_{v} = 12.471\,\frac{J}{mol\cdot K}[/tex]
[tex]c_{p} = \frac{5}{2}\cdot \left(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} \right)[/tex]
[tex]c_{p} = 20.785\,\frac{J}{mol\cdot K}[/tex]
[tex]Q = (2\,mol)\cdot \left[\left(12.471\,\frac{J}{mol\cdot K} \right)\cdot (536.3\,K-273.15\,K)+\left(20.785\,\frac{J}{mol\cdot K} \right)\cdot (1092.6\,K-546.3\,K )\right][/tex]
[tex]Q = 29273.178\,J[/tex]
29273.178 joules have been added to the gas for the entire process.
For the chemical reaction:
N2 (g)
+
H2(g)=
NH3 (g)
Calculate the volume of NH; that will form from 200 dm cubed of N2 at STP. (N = 14; H - 1)
[At STP. 1 mole of any gas occupies volume of 22 A dm cubed
Answer:
Volume of ammonia produced = 398.7 dm³
Explanation:
Given data:
Volume of N₂ = 200 dm³
Pressure and temperature = standard
Volume of ammonia produced = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Number of moles of N₂:
PV = nRT
1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K
n = 200 atm.L /22.41 atm.L/mol
n = 8.9 mol
Now we will compare the moles of ammonia and nitrogen.
N₂ : NH₃
1 : 2
8.9 : 2/1×8.9 = 17.8 mol
Volume of ammonia:
1 mole of any gas occupy 22.4 dm³ volume
17.8 mol ×22.4 dm³/1 mol = 398.7 dm³
Hydrogenation (H2/Pd-C) of 3,4-dimethyl-3-hexene (3,4-dimethyl hex-3-ene) would be expected to form A) an enantiomeric pair for both the (E) and (Z) isomers. B) an enantiomeric pair for the (E) isomer and one meso compound for the (Z) isomer. C) one meso compound for the (E) isomer and an enantiomeric pair for the (Z) isomer. D) will not form any stereoisomers since the product is a saturated hydrocarbon. E) None of the above provide a correct response.
Answer:
D) will not form any stereoisomers since the product is a saturated hydrocarbon.
Explanation:
Stereoisomerism, or spatial isomerism,refers to a type of isomerism in which two or more molecules have the same molecular formula and atom to atom connectivity but different three-dimensional orientations of those atoms in space.
Stereoisomerism occurs in alkenes because free rotation about the C=C bond is hindered. Thus, the molecule is "locked" in a particular orientation. In a saturated alkane, there is unrestricted free rotation about the C-C bond hence straight chain alkanes do not have steroisomers.
The product formed is 3,4-dimethyl hexane which is a straight chain saturated alkane. This compound does not exhibit stereoisomerism.
why did my dad hasn't come back with the milk for 10 years
Answer:
Milk's heavy
Explanation:
Cindy is studying how the light absorption of construction paper varies with the color of the paper.
She decides to conduct her experiment in a room that is completely closed to sunlight. She provides a single light source—a florescent light bulb and places it 1.0 meters above each sheet of construction paper for 20.0 minutes.
If Cindy wants to measure the relative absorption of each sheet of construction paper, which of the following tools would be the most useful?
A) A temperature probe
B) A hand lens
C) A light sensor
D) A prism
Answer: I think that is C, a light sensor but im not sure
Explanation:
Answer:
temperature probe
Explanation:
As a cognitive effect of consuming violent media, what may the appetite effect cause one to believe?
A. A person witnessing aggressive behavior thinks it is unusual and rare.
B. Those who witness violence in the media see the world as threatening.
C. Witnessing violent behavior in the media causes the desire for more violent media.
D. This exposure causes others to react aggressively to potential conflicts.
The appetite effect cause one to believe is those who witness violence in the media see the world as threatening.
What is an appetite effect?The appetite effect is used as a slang here, if someone is consuming violent media.
If someone is consuming violent media, then his appetite effect will be threatening from the world.
Thus, the correct option is B. Those who witness violence in the media see the world as threatening.
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Answer:
b
Explanation:
edge 2022
When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 56.11 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question.
Answer: The empirical formula is [tex]CH_2[/tex] and molecular formula is [tex]C_4H_8[/tex]
Explanation:
We are given:
Mass of [tex]CO_2[/tex] = 18.95 g
Mass of [tex]H_2O[/tex]= 7.759 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 18.59 g of carbon dioxide, =[tex]\frac{12}{44}\times 18.59=5.07g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 7.759 g of water, =[tex]\frac{2}{18}\times 7.759=0.862g[/tex] of hydrogen will be contained.
Mass of C = 5.07 g
Mass of H = 0.862 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.422}{0.422}=1[/tex]
For H =[tex]\frac{0.862}{0.422}=2[/tex]
The ratio of C : H = 1: 2
Hence the empirical formula is [tex]CH_2[/tex].
The empirical weight of [tex]CH_2[/tex] = 1(12)+2(1)= 14 g.
The molecular weight = 56.1 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4[/tex]
The molecular formula will be=[tex]4\times CH_2=C_4H_8[/tex]
Which of the following could form an ionic bond with an anion?
Hg22+
NO2–
SO32–
Ar
Answer:
the correct answer is A, Hg22+ on edge 2020
Explanation:
i took the review
The only cation that can form an ionic bond with an anion in the list is Hg22+.
The term "anion" refers to a negatively charged ion. An ionic bond is a kind of bond that is formed between an anion and a cation. As a result, ionic compounds are actually an ion pair.
If we look at the options closely, the only cation that can form an ionic bond with an anion in the list is Hg22+.
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Every summer drive to Michigan it is 2952 KM to get there. if i average 82 km/hr, how much time will i spend driving ? URGENT PLZ
Answer:
36 hrsExplanation:
The time spent in driving can be found by using the formula
[tex]t = \frac{d}{v} \\ [/tex]
d is the distance
v is the velocity
From the question we have
[tex]t = \frac{2952}{82} \\ [/tex]
We have the final answer as
36 hrsHope this helps you
PLZ HELP WITH THIS PROJECT FOR 8TH GRADE SCIENCE EDGENUTY plz send file
Answer:
yes I would
Explanation:
but I would like to advice you to add more info about project and be precise
If you have 23.8g of CaCl2, how many formula units is it
Answer:
1.3×10²³ formula unit
Explanation:
Given data:
Mass of CaCl₂ = 23.8 g
Number of formula unit = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 23.8 g/110.98 g/mol
Number of moles = 0.21 mol
1 mole of any substance contain 6.022×10²³ formula unit
0.21 mol × 6.022×10²³ formula unit / 1mol
1.3×10²³ formula unit
which type of severe weather is related to high pressure systems?
A.Hurricane
B.Heat Wave
C.Tornado
D.Thunderstorm
Answer:
Heat waves
Explanation:
Write a chemical equation showing how each behaves as an acid when dissoblbed in water.
a. H2s
b. NH4
Answer:
a. H₂S(aq) + H₂O(l) ⇄ HS⁻(aq) + H₃O⁺(aq)
b. NH₄⁺(aq) + H₂O(l) ⇄ NH₃(aq) + H₃O⁺(aq)
Explanation:
According to Bronsted-Lowry acid-base theory,
An acid is a substance that donates a H⁺.A base is a substance that accepts a H⁺.a. When dissolved in water, H₂S behaves as an acid according to the following equation.
H₂S(aq) + H₂O(l) ⇄ HS⁻(aq) + H₃O⁺(aq)
b. When dissolved in water, NH₄⁺ behaves as an acid according to the following equation.
NH₄⁺(aq) + H₂O(l) ⇄ NH₃(aq) + H₃O⁺(aq)
What is the molarity of a solution of 4.50 g
of NH4Br in enough H2O to make 213 mL of
solution?
Answer in units of M.
Answer:
M = 0.23 M
Explanation:
Given data:
Molarity of solution = ?
Mass of NH₄Br = 4.50 g
Volume of solution = 213 mL (213 mL× 1L /1000 mL = 0.213 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of NH₄Br:
Number of moles = mass/molar mass
Number of moles = 4.50 g / 97.94 g/mol
Number of moles = 0.05 mol
Molarity:
M = 0.05 mol/ 0.213 L
M = 0.23 M
1×66÷3×6666666666666
Answer: 1.4666667e+14
Explanation:
Please please please help please
The isotope 238U, which starts one of the natural radioactive series, decays first by alpha decay followed by two negative beta decays. At this point, what is the resulting isotope
Answer: The resulting isotope is [tex]^{231}_{92}\textrm {U}[/tex]
Explanation:
Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.
[tex]^{235}_{92}\textrm{U} \rightarrow ^{231}_{90}\textrm {Th}+^{4}_{2}n[/tex]
Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.
[tex]^{231}_{90}\textrm{Th}\rightarrow ^{231}_{92}\textrm {Th}+2^{0}_{-1}n[/tex]
The resulting isotope is [tex]^{231}_{92}\textrm {U}[/tex]
`Suppose you have a sample of NaOH (0.0315 L, to be exact). If this amount of NaOH is used to exactly titrate 0.0250 L of HCl that has a concentration of 0.105 M, what is the molarity of the NaOH? HINT: Remember to first get your balanced equation.
Answer:
0.0835 M
Explanation:
Step 1: Write the balanced equation
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
0.0250 L of 0.105 M HCl react.
0.0250 L × 0.105 mol/L = 2.63 × 10⁻³ mol
Step 3: Calculate the reacting moles of NaOH
The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 2.63 × 10⁻³ mol = 2.63 × 10⁻³ mol.
Step 4: Calculate the molarity of NaOH
2.63 × 10⁻³ moles of NaOH are in 0.0315 L of solution.
M = 2.63 × 10⁻³ mol / 0.0315 L = 0.0835 M
A mixture of methane and oxygen gases at a total pressure of 727 mm Hg contains methane at a partial pressure of 571 mm Hg. If the gas mixture contains 3.62 grams of methane, how many grams of oxygen are present
Answer: 1.95 g of oxygen is present.
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
[tex]p_{total}=p_{methane}+p_{oxygen}[/tex]
Given : [tex]p_{total}[/tex] =total pressure of gases = 727 mm Hg
[tex]p_{methane}[/tex] = partial pressure of methane = 571 mm Hg
[tex]p_{oxygen}[/tex] = partial pressure of oxygen = ?
[tex]727=571+p_{oxygen}[/tex]
[tex]p_{oxygen}=156mmHg[/tex]
Also [tex]p_{oxygen}=x_{oxygen}\times p_{total}[/tex]
Given : 3.62 g of methane is present
moles of methane = [tex]\frac{\text{Given mass}}{\text {Molar mass}}=\frac{3.62g}{16g/mol}=0.226moles[/tex]
[tex]x_{oxygen}[/tex] = mole fraction of oxygen
=[tex]\frac{\text {moles of oxygen}}{\text {total moles}}=\frac{y}{y+0.226}[/tex]
[tex]156=\frac{y}{y+0.226}\times 727[/tex]
[tex]y=0.061[/tex]
mass of oxygen = [tex]moles\times {\text {Molar mass}}=0.061\times 32=1.95g[/tex]
Thus 1.95 g of oxygen is present.