In the figure below, this “double” nozzle discharges water (at 10°C, density= 1000 kg/m3) into the atmosphere at a rate of 0.50 m3/s. The pressure at the inlet is to be 315612 Pa. If the nozzle is lying in a horizontal plane. Jet A is 10 cm in diameter, jet B is 12 cm in diameter, and the pipe (1) is 30 cm in diameter. The x-component of force (Rx) acting through the flange bolts is required to hold the nozzle in place is:

Answer:

British East India Company

The battle was fought at Buxar, a "small fortified town" within the territory of Bihar, located on the banks of the Ganga river about 130 kilometres (81 mi) west of Patna; it was a decisive victory for the British East India Company.

Answer:

6.54 × 10⁻⁵ Pa-s

Explanation:

Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m

Since F = μAu/y

F/A = μu/y where F/A = force per unit area

Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²

So,  μ = F/A ÷ u/y

substituting the values of the variables into the equation, we have

μ = F/A ÷ u/y

μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m

μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s

μ = 6.54 × 10⁻⁵ Ns/m²

μ = 6.54 × 10⁻⁵ Pa-s

Answer:

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Answer:

the correct answer is C

Explanation:

This is a system with circular motion, there is a relationship between the linear and angular variables

         a = α r

with the cube going down the well, the tension of the leather is maintained therefore the acceleration of the cube is

          W = m a

          -mg = ma

          a = -g

this acceleration a is the same as that at the edge of the drum.

         α = a / r

where we can see that the angular acceleration is constant

consequently the correct answer is C

Answer:

A)quadruples

Explanation:

The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled

Answer:

98 J

Explanation:

Applying,

Change in kinetic energy = Final kinetic energy- initial kinetic energy

ΔK.E = mv²/2-mu²/2..............Equation 1

Where ΔK.E = Change in kinetic energy, m = mass of the box, u = initial velocity of the box, v = final velocity of the box.

From the question,

Given: m = 4.0 kg, u = 0 m/s, v = 7 ,0 m/s

Substitute these values into equation 1

ΔK.E = (4(7²)/2)-(4(0²)/2)

ΔK.E = (2×49)-0

ΔK.E = 98 J

Hence the change in kinetic energy 98 J

Answer:

Bobby Benson..........taxi driver

Dr Victor Olaiya......... omo pupa

prince Nic Mbarga.........sweet mother

sir Victor Uwaifor............. mammy water

Answer:

hey ...................................... what's up

Answer:

The moon Phobos orbits Mars (m = 6.42 x 1023 kg) at a distance of 9.38 x 106 m.

Answer:

Marine geologists learn about the rocks and geologic processes of the ocean basins.

Answer:

C. both a speed and a direction

Answer: Electromagnetic force is the force on charged particle due to both electric field and magnetic field. ... Magnetic force can be experienced by charges in motion. Hence, if a charged particle kept at rest experiences an electromagnetic force, the electric field must not be zero and the magnetic field may or may not be zero.

Explanation: Hope it help

Answer:

a) [tex]T=0.01s[/tex]

b) [tex]T=0.001s[/tex]

c) [tex]T=0.00001s[/tex]

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

[tex]T=\frac{1}{f}[/tex]

Therefore

a)

For

[tex]T=100 Hz[/tex]

[tex]T=\frac{1}{100}[/tex]

[tex]T=0.01s[/tex]

b)

For

[tex]F=1kHz[/tex]

[tex]T=\frac{1}{1000}[/tex]

[tex]T=0.001s[/tex]

c)

For

[tex]F=100kHz[/tex]

[tex]T=\frac{1}{100*100}[/tex]

[tex]T=0.00001s[/tex]

Answer: C. The case on the inclined surface had the least decrease intotal mechanical energy.

Explanation:

First and foremost, it should be noted that the mechanical energy is the addition of the potential and the kinetic energy.

From the information given, it should be known that when the block is projected with the same speed v up an incline where is slides to a stop due to friction, the box will lose its kinetic energy but there'll be na increase in the potential energy as a result of the veritcal height. This then brings about an increase in the mechanical energy.

Therefore, the total mechanical energy of the block will decrease the least when the case on the inclined surface had the least decrease intotal mechanical energy.

Answer:

The correct answer is (C), as explained below. The transpose of a matrix is created by interchanging corresponding rows and columns.

Switching Rows

You can switch the rows of a matrix to get a new matrix.

Explanation:

If A is an m × n matrix and AT is its transpose, then the result of matrix multiplication with these two matrices gives two square matrices: A AT is m × m and AT A is n × n. ... Indeed, the matrix product A AT has entries that are the inner product of a row of A with a column of AT.

Answer:

The new voltage is 17.7 V.  

Explanation:

Voltage, V = 8.85 V

The spacing is doubled.

When it is disconnected, the charge remains same,

q = C V ..... (1)

where, C is the capacitance, V is the voltage.  

The capacitance is inversely proportional to the distance between the two plates.

So, when the spacing is doubled, the capacitance is halved.

Let the new voltage is V'.

C V = C' V'

C x 8.85 = C/2 x V'

V' = 17.7 V  

Answer: A.

Lithium sulfide is the inorganic compound with the recipe Li2S. It solidifies in the antifluorite theme, depicted as the salt (Li+)2S2−. It frames a strong yellow-white deliquescent powder. In air, it effectively hydrolyses to deliver hydrogen sulfide (spoiled egg scent).

Answer:

Gamma rays

Explanation:

Gamma rays have the highest frequency in the electro magnetic spectrum

Answer:

a)   v = -4.74 m / s, b)  v = 0 m / s

Explanation:

Average speed is

          v = Δx /Δt

a) the variation of the distance on the return trip is

          Δx = -5120 km = -5120 10³ km

the negative sign is because the bird is going back

          Δt = 12.5 days (24 h / 1 day) (3600 s / 1 h) = 1.08 10⁶ s

          v = -5120 10³ / 1.08 10⁶

          v = -4.74 m / s

b) the displacement for the round trip is zero, therefore the average velocity is

         v = 0 m / s

Answer:

Explanation:

i am sorry i needed points

Answer:

x = 4.45 * 10 ^22  Note. Technically, this should be rounded to 4.5 * 10^22. There are only 2 sig digits.

Explanation:

You have to assume that the coin is pure copper, which I doubt.  What a coin is actually made of  depends on when it was minted. But for the sake of this question, we'll assume coins are pure copper.

Copper has an atomic mass of 63.546 grams / mol

So 4.7 g of copper = 4.7 / 63.545 mol

We have 0.07396 mol of copper

1 mol of anything = 6.02 * 10^23 atoms (in this case).

0.07396 mol        = x

Cross Multiply

1 * x = 0.07396 * 6.02 * 10^23

x = 4.45 * 10 ^22  atoms of copper

Answer:

WIND Is what you're looking for

Explanation:

The word is WIND

Answer:

The answer is below

Explanation:

The intensity level (B) of a sound wave is given by:

B = 10log(I/I₀);

where I₀ is the threshold intensity = 1 * 10⁻¹² W/m², I is the intensity at distance 5 m, B is the intensity level = 52 dB

Substituting gives:

[tex]52=10log(\frac{I}{10^{-12}} )\\\\log(\frac{I}{10^{-12}} )=5.2\\\\I=1.58*10^{-7}\ W/m^2[/tex]

The pressure is given by:

[tex]I=\frac{p_{max}^2}{2\rho v} \\\\\rho=air\ density=1.2\ kg/m^3,v=speed\ of\ sound\ in\ air=344\ m/s,p_{max}=pressure:\\\\p_{max}=\sqrt{2\rho vI}=\sqrt{2*1.58*10^{-7}*1.2*344} =1.14*10^{-2}Pa[/tex]

Answer:

c) The pitch of the two sirens sounds the same to you

Explanation:

The pitch does not depend on the distance of the object from the observer.

As per the given data

pitch = frequency

Frequency = [tex]f_{0}[/tex]  [tex]\frac{V +- V_{0}}{V +- V_{s}}[/tex]

[tex]f^{'}[/tex] = [tex]f_{0}[/tex]  [tex]\frac{V }{V - V_{s}}[/tex]

Hence, the pitch of the two sirens remains the same for the observer.

Answer:

c) The pitch of the two sirens sounds the same to you

Explanation:

Answer:

a = 1.55m/s²

Explanation:

a = (v_f-v_0)/t

a = (12.4m/s-3.22m/s)/5.94s

a = 1.55m/s²

Answer:

a)3pF  has the greatest charge

b) 3pF to have the greatest voltage.

Explanation:

From the question we are told that:

1pF is parallel to [tex]2pF =1pF//2pF[/tex]

And 3pF is in with series 1pF is parallel to[tex]2pF =3pF+(1pF//2pF)[/tex]

Generally the equation for Resultant capacitor is mathematically given by

[tex]C=3pF+(1pF//2pF)[/tex]

[tex]C=\frac{3}{2}pF[/tex]

Ohm's law

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points

a)

Since

The same charge flowing through [tex]1pF//2pF[/tex] flow through 3pF

Therefore

3pF  has the greatest charge

b)

Voltage drop in series according to ohms law

Therefore the parallel share same voltage

Given

3pF to have the greatest voltage.

Answer:

So the answer is B. A is wrong because negative answer = deceleration

Answer:

The spring constant = 125 N/m

Explanation:

Given that :

Force = 50 N

distance (x) = 0.40 m

Recall that, From Hooke's law

Force = kx

where;

k = spring constant.

∴

50 N = k × 0.40 m

k = 50 N/0.40m

k = 125 N/m

Answer:

c. More than 2 s

Explanation:

First, we will find the length of the pendulum:

[tex]T = 2\pi \sqrt{\frac{l}{g}}\\\\2\ s = 2\pi \sqrt{\frac{l}{9.81\ m/s^2}}\\\\4\ s^2 = 4\pi^2 (\frac{l}{9.81\ m/s^2})\\\\l = \frac{(4\ s^2)(9.81\ m/s^2)}{4\pi^2} \\\\l = 0.99\ m[/tex]

Now, the value of g becomes 1.625 m/s² on the surface of the moon. So the time period will be:

[tex]T = 2\pi \sqrt{\frac{l}{g}}\\\\T = 2\pi \sqrt{\frac{0.99\ m}{1.625\ m/s^2}}\\\\[/tex]

T = 4.9 s

Therefore, the correct option is:

c. More than 2 s

Answer:

a)  V = 45 10³ V, b) U = 4.59 J

Explanation:

a) The electric potential for a series of point charges is

         V = k ∑ [tex]\frac{q_i}{r_i}[/tex]

in this case point P is at a distance of 1 m from each charge, so the point is located perpendicular to the charges at its midpoint

         V = k ( [tex]\frac{q_1}{r} + \frac{q_2}{r}[/tex])

         V = 9 10⁹ (10 - 5/ 1) 10⁻⁶

         V = 45 10³ V

b) the potential energy is

           U = k (  [tex]\frac{q_1q}{r} + \frac{q_2q}{r} + \frac{q_1q_2}{r_2}[/tex] )

where r = 1m and r₂ is the distance between the two charges r₂ = 0.10 m

           U = 9 10⁹ (10 2 / 1 - 5 2/1 - 10 5 /0.10) 10⁻¹²

           U = 9 10⁻³  510

           U = 4.59 J