Is SCID a deletion mutation?

Torque =   force x distance from point of rotation

Torque is a measure of the turning effect of an applied force about a specific point or axis. It is calculated by multiplying the force applied to an object by the distance from the point of rotation to the point where the force is applied. The greater the force or the longer the distance from the point of rotation, the greater the torque. The unit of torque is typically Newton-meters (N·m) in the International System of Units (SI) or pound-feet (lb·ft) in the imperial system. Torque is essential in various fields such as physics, mechanics, engineering and robotics.

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R= 2+4=6Ω

in series connection, same current and different voltage

total voltage= total current × total resistance

6=I×6

I=6/6= 1A

voltage across 4Ω resistor= 1×4=4v

Therefore, heat dissipated by the 4Ω resistor in 5s= (v²/R)×t= (4²/4)× 5 = 16/4 × 5 = 20J

A container is said to have breached when it has been overstressed beyond its point of recovery.

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Answer:

8.3 m/s

Explanation:

Here's the answer in m/s:

(10 km)(1000 m/km) = 10000 m

(20 min)(60 s/min) = 1200 s

speed = d/t = 10000m / 1200s = 8.3 m/s

The formula that shows the relationship between the surface area (S) and volume (V) for spheres is S = 4πr² and V = (4/3)πr³ where r is the radius of the sphere.

This formula shows that the surface area of a sphere is directly proportional to the radius squared, and the volume is directly proportional to the radius cubed. This means that as the radius of a sphere increases, the surface area and volume will increase at a much faster rate. For example, a sphere with a radius of 2 will have four times the surface area and eight times the volume of a sphere with a radius of 1.

The question is incomplete, hence the answer is general.

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At t = 0, the wheel has an angular position of 2.3 rad and an angular velocity of 1.5 rad/s.

Since the wheel is rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2, we can use the equation for angular position to calculate the wheel's angular position at t = 2.0 s.

Angular position = initial angular position + (initial angular velocity × time) + (1/2 ×angular acceleration ×time²)

Angular position at t = 2.0 s = 2.3 rad + (1.5 rad/s × 2.0 s) + (1/2 ×-0.40 rad/s2 × (2.0 s)²)

Angular position at t = 2.0 s = 2.3 rad + 3.0 rad + -1.6 rad

Angular position at t = 2.0 s = 3.7 rad

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The area below the force curve on a force versus time graph is known as the impulse.

The concept of "impulse" refers to how much of an impact a force has over time. The cricket batsman striking the ball is one of the most well-known and frequently used illustrations. The bat significantly changes the ball's trajectory despite making contact with it for a relatively brief period and launching a bicycle. Everyone occasionally makes rash decisions, particularly when we're young. In general, as we get older, we learn to control our urges. It might or might not be a sign of a problem. A mental health concern may be indicated by persistently impulsive behavior.

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The work done to launch the motion of both the hammer and the bullet are 3.1×10³ Joule and 2.2×10² Joules respectively.

As we know,

Work = Kinetic Energy

         = (0.5)(mv^2)

For Work in Joules, the mass is in units of Kg, and the velocity is in units of m/s.

KE(hammer) = 1/2mv^2 = 1/2 x 7.3 x (29)^2 = 3.1 x 10^3 J

and KE(bullet) = 1/2mv^2 = 1/2 x 2.6 x 10^-3 x (410)^2 = 2.2 x 10^2 J

To solve this problem, we must assume that energy is conserved. (This isn't stated in the problem, and is not true in general in these real-world examples, however we must assume conservation of energy in order to solve the problem with the information given).

When an object moves while a force is being exerted on it, then work is being done on the object by the force. If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to W = F · d = F d cos φ where φ is the angle between d and F.

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Answer:

1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.

2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.

3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.

Laws of reflection:

(i) The angle of reflection is always equal to the angle of incidence.

(ii) The incident rays, reflected rays and the normal, all lie in the same plane.

4.)Snell’s law formula is expressed as: μ= sin i/sin r

, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.

Explanation:

Let a be the sphere of mass 10 kg and b be the sphere of mass 20 kg. According to Newton's universal law of gravitation, the gravitational force of a on b is expressed as:

F

a

b

=

G

m

M

d

2

, where:

G

=

6.67

×

10

−

11

N

m

2

/

k

g

2

is the gravitational constant

m = 2 kg is the mass of a

M = 10 kg is the mass of b

d = 0.2 m is the separation between the two spheres

So:

Fab=GmMd26.67

×

10

−

11

×

2

×

10

0.2

2

Answer:

15 seconds :)

Explanation:

The diagram for the standing wave after the tension is quadrupled while the frequency is held constant has been attached and explained below.

We already know that the frequency of a standing wave is given by,

= f = nv/2l

and

= v = [tex]\sqrt{\frac{T}{m} }[/tex]

In the given problem, the frequency of the wave after the tension is quadrupled will be -

= f2 = 2v/2l

= f2 = v/l

= f2 = 1/l  [tex]\sqrt{\frac{T}{m} }[/tex]

Now, since we have quadrupled the tension, we have -

= f = 1/l  [tex]\sqrt{\frac{4T}{m} }[/tex]

= f = 2(f2)

So, now we know that the final frequency will be of this form(the image has been attached here) and it would look like this if the tension is quadrupled while the frequency is held constant.

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To find the temperature of the warm iron, we first need to convert the reading on the thermocouple thermometer to a temperature value. To do this, we will use the formula:

Temperature = (Reading - Lower Fixed Point) / (Upper Fixed Point - Lower Fixed Point) * (Upper Temperature - Lower Temperature) + Lower Temperature

In this case, the lower fixed point is 9.00mV and the upper fixed point is 16.50mV. We also know that the lower temperature is 0°C (the freezing point of water) and the upper temperature is 100°C (the boiling point of water). So, we can plug in these values:

Temperature = (11.21mV - 9.00mV) / (16.50mV - 9.00mV) * (100°C - 0°C) + 0°C

Simplifying, we get:

Temperature = (2.21mV / 7.50mV) * 100°C

And further simplifying, we get:

Temperature = 0.2907 x 100°C

So, the temperature of the warm iron is approximately 29.07°C to the nearest whole number.

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The airplane that starts from rest and accelerates at 1 constant 3 m/s2 for 30 s before leaving the ground moved by the distance of 1350m.

Acceleration is given as 3.00 m/s2

Time is 30 sec.

The formula we can use in this case is:

s = ut + 0.5 at^2

v = at + u

where,

s is distance travelled

u is initial velocity = 0 since at rest

t is time travelled

a is acceleration

v is the final velocity when it took off

a. s = 0 + 0.5 * 3 * 30^2

s = 1350 m

The distance moved by the airplane is 1350 m.

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The acceleration of the center of mass of the two-ball system relative to Earth is equal to g after the balls have travelled for half their vertical distance to the ground, option A.

The total force acting on the system is equal to the acceleration of the center of mass multiplied by the total mass of the system. When applied to an extended object, Newton's second law, F = ma, predicts the motion of a specific reference point for this object. The center of mass is the name given to this reference point.

When we throw an object upward, gravity acts on it, and the acceleration it experiences is the inverse of the acceleration caused by gravity, i.e. deceleration. As a result, the acceleration of each ball will be g. As a result, the acceleration of the center of mass of the two balls thrown upward is g.

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32. 6 kg m/s will be the total momentum of the system before the collision.

In physics, a collision is any circumstance in which two or more bodies rapidly apply forces to one another.

Despite the fact that the most common usage of the word "collision" relates to instances in which two or more objects smash violently, the scientific usage of the word makes no such assumptions.

If most or all of the total kinetic energy from the collision is lost (dissipated as heat, sound, etc., or absorbed by the objects themselves), the collision is said to be inelastic; such collisions result in the objects coming to a complete stop. A collision involving a car serves as an example of this type of collision since cars fold inward rather than colliding with one another.

pf = Final momentum of the system = 32.6 kg m/s

According to the principle of conservation of angular momentum we have

pi = pf => pi = 32.6 kg m/s

The wall is not moving so the initial and final momentum of the system are equal.

Therefore, the total momentum of the system before the collision is 32.6 kg m/s

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The astronaut being pushed back into his seat as the rocket accelerates - this was the  example of Newton's first law of motion.

According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.

When the astronaut  worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to  Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .

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The balloon will be drawn to the wall once it has been rubbed sufficiently to build up a sufficient negative charge. Even though the wall should generally be neutrally charged, its charges can change, causing a positively charged region to pull the negatively charged balloon toward it.

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It is important to note that the dot product and cross product of any two non-zero vectors cannot both be zero therefore  A×B and A·B cannot both be zero.

In vector space, a non-zero vector. V is a vector that differs from the zero vector in V. If u is a non-zero vector in V and an is a scalar, i.e. an element of the field over which V is defined, then au=0 is only possible if a=0.

The product of any two non-zero vectors is non-zero in this vector context. It is referred to as Hamilton's Quaternions. Over the real numbers, quaternions form a four-dimensional vector space, and their multiplication is a combination of dot product and cross product.

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This is not a gamma radiation because there is a change in the atomic number of the daughter nucleus. It is rather a beta decay.

We have to note that when we talk about a decay we are talking about the manner that we can be able to break up the atom of a radioactive substance so that we can be able to produce a new substance.

We can see now that what we have here is the loss of a beta ray or an electron from the specie that is shown. This is evidenced by the change in the atomic number of the daughters nucleus.

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The time taken by the object to hit the ground is 1.8 seconds.

The attraction that draws two objects together is known as gravitational force, sometimes referred to as gravity. Every mass-containing object pulls on nearby things gravitationally in a sizable way.

The time it takes for an object to hit the ground after being dropped off a cliff can be calculated using the formula:

t = √(2*d/g)

where t is the time, d is the distance fallen, and g is the acceleration due to gravity.

In this case, we don't know the distance fell, but we can use the horizontal velocity and time of travel to find it:

d = v * t

where v is the velocity (6 m/s), and t is time (3 seconds)

d = 6 * 3 = 18 m

Now we can use the distance fallen to calculate the time it takes to hit the ground:

t = √(2*d/g)

g is approximately 9.8 m/s^2

t = √(2*18/9.8) = √ (3.6) = 1.8 seconds

So, it takes 1.8 seconds for the object to hit the ground after traveling horizontally off a cliff at 6 m/s for 3 seconds.

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The greater the mass of an object, the more particles there are in the sample and the more thermal energy it possesses at the same temperature. Assume you have some boiling hot water at 100 degrees Celsius to demonstrate this concept.

The energy contained inside a thermodynamic system is quantified as the quantity of energy required to get the system from its standard internal state to its current internal state of interest, accounting for energy gains and losses owing to changes in its internal state, including magnetization.  

It eliminates the kinetic energy of motion and the potential energy of the system's overall location in relation to its surroundings and external force fields.

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Answer: The time it took for them to fall ere the same.

Explanation:

The only difference was because of resistance, weight doesn't affect the speed of gravity, the speed of gravity stays the same (9.801 meters per second)

Answer:

it will increase the frequency of collisions between the two reactants

Explanation:

mark brainliest?

Yes, the center of the Milky Way is the most densely populated area of stars, and is therefore the most likely region to find newly formed stars.

What is the populated?

Populated refers to an area that has a large number of people residing in it. It is usually used to describe cities, towns, or other densely populated areas. Populated areas usually contain a variety of services and infrastructure to support their populations, such as schools, hospitals, transport links, and other amenities. Populated areas usually have higher rates of crime, pollution, and other problems associated with increased human activity.Populated refers to an area that has a high density of people living in it. It is usually used to describe cities and towns, but can also describe smaller areas, like neighborhoods.

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Nonsense mutations are those point mutations in the DNA where stop codons will appear before the time they should appear.

At the time of transcribing from DNA to RNA, the template needs to have both start and stop codons for the transcription to occur correctly, but sometimes mutations can occur that do not allow the protein to be produced correctly. This mutation can be permanent which causes damage to the formation of proteins.Sometimes mutations can be beneficial, allowing evolution and helping organisms to be better formed for a new environment.

It is the type of mutation in which a termination codon occurs before the time it should be, instead of giving a codon with a certain amino acid. Which gives a much shorter protein than it should be, giving a non-functional protein.

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1.54 is the acceleration of the crate. The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

That acceleration is proportional to the net force and inversely proportional to the mass of the object. It can be expressed with the formula: Where, Fn = Net force, m  = mass. The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes the motion and a horizontal net force appears causing the acceleration.

The forces in the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal: N = W = mg, The friction force can be calculated by using the coefficient of friction μ: μ*n. Calculating the normal force: N = 200 * 9.8 = 1,960 N. The friction force is f=0.2*1960, f=392. The horizontal net force is 308. Finally, the acceleration is computed: m/s^2

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The margin of error is 3.96.

The value of e, or the margin of error, can be calculated using the formula:

e = z*(s/√n)

where:

z = the critical value from a standard normal distribution table (for c = 0.99, z = 2.576)

s = the sample standard deviation (in this case, s = 2.6)

n = the sample size (in this case, n = 16)

So, to find the margin of error for this scenario, we plug the given values into the formula:

e = 2.576*(2.6/√16) = 2.576*(2.6/4) = 2.576*0.65 = 3.96

Therefore, the margin of error is 3.96.

It's worth noting that this value represents the range within which we expect the true population value to fall with a certain level of confidence

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Answer:

(a) The time interval required for the proton to travel 4.50 cm horizontally is

t = (4.50 cm) / (3.80 x 105 m/s) = 118.42 ns

(b) The vertical displacement of the proton during the time interval is

dY = (F × t2) / 2m = (9.20 x 103 N/C × (118.42 ns)2) / (2 × 1.67 x 10-27 kg) = 0.0033 mm

(c) The horizontal and vertical components of the velocity after the proton has traveled 4.50 cm horizontally are

Vx = 3.80 x 105 m/s

Vy = (F × t) / m = (9.20 x 103 N/C × 118.42 ns) / (1.67 x 10-27 kg) = 1.90 x 105 m/s

The rate of acceleration at which Matt goes down the slide is equal to 5.32 m/s².

The normal force or [tex]F_{N}[/tex] acts perpendicular to the object.

The angle of inclination = 35°

cosθ = [tex]F_{N}[/tex]/mg

 [tex]F_{N}[/tex] = mgcosθ = 85 × 10 × cos 35

= 850 × 0.819 = 696.15 N

To find the force of friction,

μ = 0.050

[tex]F_{f}[/tex] = μ × [tex]F_{N}[/tex]

= 0.050 × 696.15 = 34.80 N

To find the downward component of weight that pulls him down the slide.

sinθ = [tex]F_{d}[/tex]/mg

[tex]F_{d}[/tex] = mgsinθ

= 85 × 10 × sin35

= 850 × 0.5736 = 487.56 N

To find the acceleration,

[tex]F_{net} = F_{d} - F_{f}[/tex]

 = 487.56 - 34.80 = 452.76 N

To solve for acceleration,

F = force = 452.76 N

m = mass = 85 kg

Force = mass × acceleration

a = F/m = 452.76/85 = 5.32 m/s²

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