Is y 2x 3 in slope intercept form?

The graph is attached and  the point of maximum as y"(π/6) < 0 and at point of minimum y"(π/2) > 0.

An inflection point is where a graph's curvature changes, from concave up to concave down or vice versa. It is also known as a turning point, flex, inflection, or "point of diminishing returns."

A concave down graph resembles an upside-down U or a cap, while a concave up graph resembles the letter U (or a "cup"). The intersection of a "cup" and a "cap" marks the inflection point.

Given displacement of mass by function,

y = sin(3t), where 3t is in radians,

the graph for t = 0 and t = 2 sec.

2: The position of turning point,

differentiate the equation we get,

y' = 3cos(3t)

the turning points are t = π/6 and t = π/2

y'(π/6) = y'(π/2) = 0

3: inflexion points,

again differentiate the equation we get,

y" = -9sin(3t)

and inflection at π/3

because y"(π/3) = 0

Maximum and minimum points are π/6 and π/2 respectively,

as the point of maximum t = π/6 as y"(π/6) < 0,

and point of minimum at t = π/2 as y"(π/2) > 0.

Hence the graph is attached and maximum at t = π/6, and minimum at t = π/2, and inflection at π/3.

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In order to find the negation of an expression we simply put the not operator in front of them . Therefore, the negation of ∃ is that â is not ^ to f.

The term negation means opposite , that is the negation of a statement is the opposite of the given mathematical statement. If we will take the example of P , let P be a statement, then the negation of P will be represented by ~P.

There are two  symbols which are  used to represent the negation of a statement which are “~” or “¬”. Therefore, ~P is known as the negation of P.

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Answer: The Gradient of line A and B are

2 and -1

Step-by-step explanation:

For the given two points A(x1, y1) and B(x2, y2)

The gradient of the line AB is y2-y1/x2-x1

So the gradient of line A is

5-1/2-0

2

the gradient of line B is

5-0/0-5

-1

Answer:

Step-by-step explanation:

To calculate 7⋅VN−→3⋅MT−→, we need to perform scalar multiplication on the two vectors. Scalar multiplication is simply multiplying each of the components of the vector by the scalar value.

So for the first vector, we have: 7⋅VN−→ = {7⋅(-8); 7⋅3} = {-56; 21}.

For the second vector, we have: 3⋅MT−→ = {3⋅2; 3⋅10} = {6; 30}.

Then to add the two vectors, we simply add the corresponding components: {-56; 21} + {6; 30} = {-50; 51}.

Therefore, the final result is {-50; 51}.

The speed of the object is 9.14 cm per day.

A unit conversion expresses the same property as a different unit of measurement. For instance, time can be expressed in minutes instead of hours, while distance can be converted from miles to kilometers, or feet, or any other measure of length.

Given that, An object is moving at a speed of 3 yards per month. we are asked to express this speed in centimeters per day.

For this, we will have to convert the units,

1 yard = 91.44 cm

3 yards = 91.44 × 3 = 274.32 cm

Therefore, we can say the object is moving 274.32 cm per month

Now,

If it moves 274.32 cm in one month,

Therefore, in day, it will move = 274.32 / 30    [1 month = 30 days]

= 9.144

Hence, the speed of the object is 9.14 cm per day.

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Answer:

(n - 6)(n -4)

Step-by-step explanation:

Find two numbers that add to - 10 and multiply to +24.
In this case, -6 * -4 satisfies these requirements.

Answer:

25

Step-by-step explanation:

let there be x questions on the test

80% of x = 20

80% * x = 20

80% = 0.8

0.8 * x = 20

divide both sides by 0.8 to isolate x

x = 20/0.8 = 25

The function [tex]$$f(x)= \begin{cases}1-x^2 & x \leqslant 1 \\ \ln (x) & x \geqslant 1\end{cases}$$[/tex]  is continuous on (-∞, ∞).

As per the given data the function f(x) is given by:

[tex]$$f(x)= \begin{cases}1-x^2 & x \leqslant 1 \\ \ln (x) & x \geqslant 1\end{cases}$$[/tex]

Here we have to determine that the function f(x) is continuous on (-∞, ∞)

If we show that f(x) is continuous at x = 1 then f(x) is continuous on (-∞, ∞)

What are continuous function?

A continuous function in mathematics is one where changes in the parameter cause constant changes in the function's value (i.e., a change without a leap). This shows that there are no abrupt changes in value or discontinuities.

To show f(x) is continuous at x = 1

[tex]\lim _{x \rightarrow 1^{-}} f(x)=\lim _{x \rightarrow 1^{+}}[/tex] f(x)

[tex]\rightarrow \lim _{x \rightarrow 1^{-}} f(x) & =\lim _{x \rightarrow 1^{-}}\left(1-x^2\right) \\[/tex]

= 1 - 1

= 0

[tex]\lim _{x \rightarrow 1^{+}} f(x) & =\lim _{x \rightarrow 1^{+}} \ln (x) \\[/tex]

= ln 1

= 0

Therefore  [tex]\lim _{x \rightarrow 1^{+}} f(x) & =\lim _{x \rightarrow 1^{-}} f(x)-0[/tex].

Hence f(x) is continuous on (-∞, ∞)

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The formula for the third side of a triangle, given the lengths of two other sides and the angle between them, is:

side_3 = sqrt(side_1^2 + side_2^2 - 2 * side_1 * side_2 * cos(angle))

The formula for the third side of a triangle, given the lengths of two other sides and the angle between them, is:

side_3 = sqrt(side_1^2 + side_2^2 - 2 * side_1 * side_2 * cos(angle))

This formula is derived from the Law of Cosines, which states that the sum of the squares of any two sides of a triangle is equal to the square of the third side, minus twice the product of those two sides multiplied by the cosine of the angle between them.

In other words, the formula states that:

side_3^2 = side_1^2 + side_2^2 - 2 * side_1 * side_2 * cos(angle)

which is then solved for side_3 by taking the square root of both sides. Thus, the formula for the third side can be written as:

side_3 = sqrt(side_1^2 + side_2^2 - 2 * side_1 * side_2 * cos(angle))

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Rate of speed of each cyclist is:

Alisha 10mi/hr

Jose 15mi/hr

Raul 10mi/hr

Ruthie 16mi/hr

Data given of each cyclist;

Formula used: [tex]r=\frac{d}{t}[/tex]

here,

r=rate of speed

d=distance

t=time

Alisha: Distance=40mi; Time=4hr

applying the formula

[tex]r=\frac{d}{t} \\r=\frac{40}{4} =10mi/hr[/tex]

Jose: Distance=30mi; Time=2hr

applying the formula

[tex]r=\frac{d}{t}\\ r=\frac{30}{2} =15mi/hr[/tex]

Raul: Distance=40mi; Time=4hr

applying the formula

[tex]r=\frac{d}{t} \\r=\frac{40}{4}=10mi/hr[/tex]

Ruthie: Distance=80mi; Time=5hr

applying the formula

[tex]r=\frac{d}{t} \\r=\frac{80}{5} =16mi/hr[/tex]

Alisha= 10mi/hr

Jose= 15mi/hr

Raul= 10mi/hr

Ruthie= 16mi/hr

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The measure of angle ABC means, vertex B lies in between A and C, whose value is to be obtained.

Whenever two straight lines as well as rays intersect at a single endpoint, an angle is created. The vertex of the an angle is the location where two points come together.

Thus, the measure of angle ABC means, vertex B lies in between A and C, whose value is to be obtained.

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In one of the equations, separate one of the two variables. In the other equation, replace the expression with the value of the isolated variable from Step 1. Consequently, a linear equation with just one variable ought to emerge.

The one y-value in the substitution method is replaced with the other. We'll give an example to illustrate this. Since y = y, we can replace y in the second equation with y from the first equation. The linear system's solution is (1, 6).

Numerous solutions, no solutions, and a singular solution.

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There is a 60% chance that none of them will assault any of the others.

Only the likelihood that something will happen is included in probability. When we don't know how something will turn out, we could talk about the possibility of one or the likelihood of different outcomes. The scientific study of events that fit into a probability distribution is known as statistics.

It is based on the probability that something will happen. The fundamental principle of theoretical probability is the explanation of probability. For instance, when a coin is flipped, there is a 12% chance that it will land on its head.

Probability is a statistic that is used to show the possibility or likelihood that an event will happen. Probabilities can be expressed as fractions from 0 to 1 or as percentages from 0% to 100%.

  = 64/8 = 8

   =  8 - 2

    =  4

    =  64- 4

     = 60

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Answer: The function you provided describes an experiment in which a coin is tossed, a number cube is rolled, and a letter is picked from the word "framer". The outcome of the experiment is represented by the ordered triple (tails, 5, m).

P(tails, 5, m) refers to the probability of the outcome (tails, 5, m) occurring. To find this probability, you would need to know the probability of each individual event:

The probability of getting tails is 1/2,

The probability of getting a 5 on a number cube is 1/6

and probability of getting letter "m" in the word "framer" is 1/6

So P(tails, 5, m) = (1/2) * (1/6) * (1/6) = 1/72

It is to be noted that in order for the inverse function to exist, the function must be one-to-one, meaning each y value has one unique x value, meaning the random variables in question should be independent. But in this case the events are dependent on one another.

Step-by-step explanation:

The square of the radius of the given circle is [tex]$OP^2 = 703$[/tex]

A quadrilateral is a four-sided polygon in geometry that has four edges and four corners. The word is a derivative of the Latin words quadri and latus. Having four sides, four vertices, and four corners, a rectangle is a two-dimensional form. Concave and convex come in primarily two varieties.

We can use the concept of the power of a point, which states that the square of the distance of a point from a line is equal to the product of the distances of the point from the two tangents to the line that are drawn from the point.

Let [tex]$O$[/tex] be the center of the inscribed circle.

The power of point O with respect to AB and CD is [tex]$(OPOQ) = (1937) = 703$[/tex]

Since the Circle is tangent to AB and CD at P and Q respectively, so [tex]$OP = OQ$[/tex]

So, [tex]$OP^2 = 703$[/tex]

Hence, the square of the radius of the circle is [tex]$OP^2 = 703$[/tex]

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Complete question is: A circle is inscribed in quadrilateral [tex]$A B C D$[/tex], tangent to [tex]$\overline{A B}$[/tex] at [tex]$P$[/tex] and to [tex]$\overline{C D}$[/tex] at [tex]$Q$[/tex]. Given that [tex]$A P=19, P B=26, C Q=37$[/tex], and [tex]$Q D=23$[/tex], find the square of the radius of the circle.

The missing segment lengths are CD = 10√2, AC = 10√2, BC = 10 and AB = 10.

Drag each length to the correct location accordingly

Trigonometry is a branch of mathematics dealing with the relationship between the ratios of the sides of a right-angled triangle with its angles.

In ΔACD,

sin 45° = CD/20     (sin = opp/hyp)

(√2)/2 = CD/20

CD = (√2)/2 × 20

CD = 10√2

cos 45° = AC/20   (cos = adj/hyp)

(√2)/2 = AC/20

AC = (√2)/2 × 20

AC = 10√2

In ΔABC,

sin 45° = BC/10√2     (sin = opp/hyp)

(√2)/2 = BC/10√2

BC = (√2)/2 × 10√2

BC = (10 × 2)/2

BC = 10

cos 45° = AB/10√2   (cos = adj/hyp)

(√2)/2 = AB/10√2

AB = (√2)/2 × 10√2

AB = 10

Drag each length of the missing segment to the correct location

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On solving the provided question we can say that - Height(h) = h; Radius(r) = r; Length(l) = l Volume of cylinder A(V)=Volume of cylinder B(v) => [tex]4\pi R^2H = \pi r^2h[/tex]

One of the most fundamental curved geometric forms is the cylinder, which is often a three-dimensional solid. It is referred to as a prism with a circle as its base in elementary geometry. Several contemporary fields of geometry and topology also define a cylinder as an indefinitely curved surface. A three-dimensional object known as a "cylinder" consists of curving surfaces with circular tops and bottoms. A cylinder is a three-dimensional solid figure that has two bases that are both identical circles joined by a curving surface at the height of the cylinder, which is determined by the distance between the bases from the center. Examples of cylinders are cold beverage cans and toilet paper wicks.

Cylinder A

Height(h) = H; Radius(r) = 2R; Length(l) = L

Cylinder A

Height(h) = h; Radius(r) = r; Length(l) = l

Volume of cylinder A(V)=Volume of cylinder B(v)

[tex]4\pi R^2H = \pi r^2h[/tex]

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Adding the polynomial 3a³ + 8a - 6 and 4a² - 9a + 11 gets 3a³ + 4a² - a + 5.

The answer in descending powers of a is 3a³ + 4a² - a + 5.

A polynomial is a mathematical expression consisting of a sum of powers in one or more variables (indeterminates) with non-negative integer exponents.

Adding the polynomial 3a³ + 8a - 6 and 4a² - 9a + 11                                        

(3a³ + 8a - 6) + (4a² - 9a + 11) = 3a³ + 4a² - a + 5

The coefficients of  a³, a², a and 1 is 3, 4, -1 and 5 respectively.                      

Descending powers of a in the polynomial is a³, a², a. So the answer in descending powers of a is 3a³ + 4a² - a + 5.

--The question is incomplete, answering to the question below--

"Add the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending powers of a.

Add: 3a³ + 8a - 6 and 4a² - 9a + 11"

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The triangle with sides of length 5 cm 3 cm and 4 cm is a right angled triangle because (3, 4, 5) is a Pythagorean triple.

We know that if non zero real numbers a, b, c follows Pythagoras theorem  c² = a² + b², the numbers a, b, c is called as a Pythagorean triple.

And these numbers are nothing but the sides of right triangle.

Here we have been given the triangle with sides of length 5 cm 3 cm and 4 cm

Assume that p = 5 cm, q = 3 cm and r = 4 cm

p² = 25

q² = 9

and r² = 16

Consider q² + r² = 16 + 9

q² + r² = 25

q² + r² = r²

Since given numbers follows Pythagoras theorem, (3, 4, 5) is a  Pythagorean triple.

And p = 5 cm, q = 3 cm and r = 4 cm are the lengths of sides of right triangle.

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[tex] \longmapsto \: 7x + 5x + 2x = 35820 \\ \\ x = \frac{35840}{14} = 2560[/tex] length equals to 7 into 2560 = 1792

The statement that best represents the function must be identified by reading the graph.

A) When  x < 0, the function is negative.

This is accurate; as you can see, the function is negative for x < 0 because it is below the horizontal axis.

We shall see that choice A is the proper one. "When x < 0, the function is negative."

The function tends to infinity on the positive side at an x close to zero.

The function tends to negative infinity at x close to zero on the negative side.

The function tends to zero as x's absolute value grows.

So we can conclude that this is an inverse function similar to:

y = f(x) = 1/x

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If the total number of minutes used and text messages sent last month was 561 , then the number of minutes she use is  207 minutes .

The total number of minutes used and text messages is = 561 ;

the cost for per minute cost is = 8 cents ;

the cost for per text message is = 5 cents ;

Bella's total bill amount is = $34.26 = 3426 cents

let the number of minutes used be = x minutes ; and

let the number of text messages be = y ;

So ,According to the question ,

the equations representing the situations are ,

[tex]x+y=561[/tex]  and [tex]8x+5y=3426[/tex]

Substituting the values of [tex]y=561-x[/tex] in the equation [tex]8x+5y=3426[/tex] ,

we get ;

[tex]8x + 5(561-x)= 3426[/tex]

On solving ,

we get ; x = 207 minutes ;

So , the number of text messages (y) = [tex]561-207[/tex]

= 354 text messages.

Therefore , the number of minutes is = 207 minutes .

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Hello!:

Let's take this problem in steps:

   [tex]sinx-\sqrt{3-3sin^2(x)}=0\\\\\text{We know that } sin^2(x) + cos^2(x)=1 \text{ and that } cos^2x=1-sin^2(x)\\\\sin(x)-\sqrt{3(1-sin^2(x))}=0\\\\sin(x)-\sqrt{3*cos^2(x)}=0\\\\sin(x)-\sqrt{3}*cos(x)=0[/tex]

Now we need to find the value of sin(x) and cos(x) where the value becomes zero:

  --> and it so happens to be:

        [tex]sin(30)=\dfrac{1}{2} \\\\cos(120)=\dfrac{\sqrt{3}}{2}[/tex]

Thus:

 [tex]sin(30)-\sqrt{3}*cos(120)=0\\\\\dfrac{1}{2} -\sqrt{3}*\dfrac{\sqrt{3} }{2} =0\\\\\\\dfrac{1}{2} -\dfrac{1}{2} =0\\\\0=0[/tex]

Answer: (B)

x+y=10 and ax+0.50y=25 are the system of equations to compute the cost of each mechanical pencil.

Two or more expressions with an Equal sign is called as Equation.

Given that Mr. Spears was purchasing supplies for his math classroom.

He had $25 to spend.

Mechanical pencils and erasers come in bundles of 10

Let x represents the Mechanical pencils

y represents the erasers

x+y=10

y=10-x

Each eraser costs $0.50

ax+0.50y=25

a is the cost of the each mechanical pencil.

Hence, x+y=10 and ax+0.50y=25 are the system of equations to compute the cost of each mechanical pencil.

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Answer: To find the height of the goalpost, we can use the information provided in the problem and the concept of similar triangles. Since Violet is looking down at the mirror, the line of sight from her eyes to the top of the goalpost forms a right angle with the ground. This right angle creates two similar triangles, one between her eyes, the ground, and the top of the goalpost, and the other one between the mirror on the ground, the goalpost, and a point on the ground that is the same distance from the mirror as the top of the goalpost is from Violet's eyes.

Since similar triangles have the same angle measures, we can set up the following proportion:

(distance from mirror to point on the ground) / (distance from mirror to top of goalpost) = (distance from Violet's eyes to ground) / (height of goalpost)

We can now use the information provided in the problem to solve for the height of the goalpost.

(6.65+4.25)/x = 1.75 / H

x = (6.65+4.25) * (1.75/H)

Where x is the distance from mirror to top of the goalpost.

Substitute the known values and solve for H

H = 1.75*(6.65+4.25) / x = 1.75*10.9 / x

We know that x = 4.25, so

H = 1.75*10.9 / 4.25 = 4.093 m

The height of the football goalp

Step-by-step explanation:

Answer:

supplementary angles

Step-by-step explanation:

for instance, 50 + 130 = 180.

Answer: 37

Step-by-step explanation:

divide the total that she spent over how much each game is (166.50/4.50). this will give you the number of games that she played.