It takes me 20 minutes to grade a students quit. how long in hours does it take me to grade 20

Answer:

A is a false equation broooo

Answer:

B, because 0.25 is EQUAL TO 1/4, not greater than

Step-by-step explanation:

A. 2/10 (or 1/5) is equal to 0.2 and 0.2 > 0.13 is correct

B. 1/4 is equal to 0.25, so 0.25 > 1/4 is incorrect

C. 1/6 is equal to 0.166666... and 0.125 < 0.1666 is correct

D. 2/3 is equal to 0.6666... and 0.15 < 2/3 is correct

Answer:

El raigañu cuadráu corresponder cola radicación d'índiz 2 o, equivalentemente, cola potenciación d'esponente 1/2.

Cualquier númberu real non negativu {\displaystyle x}x tien un únicu raigañu cuadráu positiva o raigañu cuadráu principal[2] y denotada como {\displaystyle {\sqrt {x}}}{\displaystyle {\sqrt {x}}} onde {\displaystyle {\sqrt {\;}}}{\displaystyle {\sqrt {\;}}} ye'l símbolu raigañu y {\displaystyle x}x ye'l aniciando.

Cuando se riquir denotar dos raigaños cuadraos una negativa, {\displaystyle -{\sqrt {x}}}{\displaystyle -{\sqrt {x}}}, y otra positiva, {\displaystyle {\sqrt {x}}}{\displaystyle {\sqrt {x}}}, suelen denotarse curioso como {\displaystyle \pm {\sqrt {x}}}{\displaystyle \pm {\sqrt {x}}} o bien como {\displaystyle \mp {\sqrt {x}}}{\displaystyle \mp {\sqrt {x}}} según l'orde precisáu.

El conceutu de raigañu cuadráu puede estendese a cualquier aniellu alxebraicu, asina ye posible definir el raigañu cuadráu d'un númberu real negativu o'l raigañu cuadráu de delles matrices. Nos númberos cuaterniónicos los reales negativos almiten un númberu infinitu de raigaños cuadraos, sicasí'l restu de cuaterniones distintos de cero almiten solu dos raigaños cuadraos. Nel aniellu non conmutativu de les funciones reales de variable real cola adición y la composición de funciones si fºf = g, puede plantegase que f ye la "raigañu cuadráu" de g.[3]

Step-by-step explanationY segun todos mis calculos es 2 :

53 sec hope this helps and meybe you could give me a brainlist?

Step-by-step explanation:

Answer:

8 Seconds

Step-by-step explanation:

0= -16t^2 + 1024

1024=16t^2

64=t^2

8= t

Answer:

ok.

1. Tanya spends exactly $30.

She can spend $15.00 each for 2 t shirts and spend $30.00

15 x 2 = 30

She can buy one $15.00 t shirt, one $10.00 t shirt and one $5.00 t shirt for exactly $30.00.

15 + 10 + 5 = 30

She can buy one $15.00 t shirt, and three $5.00 t shirts for exactly $30.00

15 + 5 + 5 +5 = 30

2. To spend exactly $25.00, Tanya can spend it :

5 of the $5.00 t shirts

5 x 5 = 25

2 of the $10 t shirts and one of the $5 t shirts

10 + 10 + 5 = 25

1 of the $15 t shirts and one of the $10 t shirts

15 + 10 = 25

1 of the $15 t shirts and 2 of the $5 t shirts

15 + 5 + 5 = 25

Answer:

What’s the answer?!? Ok

Step-by-step explanation:

Answer:

the answer is 27v- 2288/5

Answer:

Place one dot at (0,-2) and another point at (-1,-1) then draw a line through it. Then place a dot at (0,3) and (1,0) And draw a line through those two points. Wherever those two lines intercept will be your answer.

Step-by-step explanation:

Answer:

The answer is A

Step-by-step explanation:

Do on the first row, you see 1 tab of 5's

then on the left, you see 1 tab of 3's

So the answer is A!!!

Answer:

1.15m/s

Step-by-step explanation:

Given data

m1=0.025 kg

m2= 2.35kg

u1= 217 m/s

v1= 109 m/s

u2= 0

v2=???

Applying the law of conservation of linear momentum

m1u1+m2u2=m1v1+m2v2

substitute

0.025*217+2.35*0= 0.025*109+2.35*v2

5.425= 2.725+ 2.35v2

5.425-2.725=2.35v2

2.7=2.35v2

divide both sides by 2.35

v2= 2.7/2.35

v2=1.15 m/s

Hence the speed of the watermelon will be 1.15m/s

Answer:

60*

Step-by-step explanation:

because 180 -70 -50=60

Answer:

60°

Step-by-step explanation:

hmmmmmm oh yeah it is 60* I was honna wright 40° Lol

Answer:

primero sumas todas las calificaciones

posteriormente las divedes entre las materias que son y listo sacas su promedio

espero y te ayude

Answer:

C. 18x+9y

Step-by-step explanation:

Answer:

I think its the third one, C. Hope this helps!

Answer: a. Yes

              b. mean = 76.65

                  standard deviation = 10.04

              c. 76.65 ± 4.4

Step-by-step explanation:

a. Stem and leaf Plot shows the frequencies with which classes of value occur. To create this plot, we divide the set of numbers into 2 columns: stem, the left column, which contains the tens digits; leaf, the right column, which contains the unit digits.

Normal distribution is a type of distribution: it's a bell-shaped, symmetrical, unimodal distribution.

A stem and leaf plot displays the main features of the distribution. If turned on its side, we can see the shape of the data.

The figure below shows the stem and leaf plot of the 100-point test score. As we can see, when turned, the plot resembles bell-shaped distribution. So, this test scores were selected from a normal population.

b. Mean is the average number of a data set. It is calculated as the sum of all the data divided by the quantity the sample has:

mean = [tex]\frac{\Sigma x}{n}[/tex]

For the 100-point test score:

mean = [tex]\frac{71+93+91+...+65+75+84}{20}[/tex]

mean = 76.65

Standard Deviation determines how much the data is dispersed from the mean. It is calculated as:

[tex]s=\sqrt{\frac{\Sigma (x-mean)^{2}}{n-1} }[/tex]

For the 100-point test score:

[tex]s=\sqrt{\frac{[(71-76.65)+(93-76.65)+...+(84-76.65)]^{2}}{20-1} }[/tex]

s = 10.04

The mean and standard deviation of the scores are 76.65 and 10.04, respectively.

c. Confidence Interval is a range of values we are confident the real mean lies.

The calculations for the confidence interval is

mean ± [tex]z\frac{s}{\sqrt{n} }[/tex]

where

z is the z-score for the 95% confidence interval, which is equal 1.96

Calculating interval

76.65 ± [tex]1.96.\frac{10.04}{\sqrt{20} }[/tex]

76.65 ± 4.4

The 95% confidence interval for the average test score in the population of students is between 72.25 and 81.05.

Answer:

the answer is 3 miles

Step-by-step explanation:

1 +2 = 3 so 3

Answer:

The relationship between d, c and p is that [tex]p = \frac{4c^2}{9d}[/tex]

Step-by-step explanation:

Roots of a quadratic equation:

The roots [tex]r_1[/tex] and [tex]r_2[/tex] of a quadratic equation in the following format:

[tex]ax^2 + bx + c = 0[/tex]

Can be given by:

[tex]r_1 + r_2 = -\frac{b}{a}[/tex]

[tex]r_1r_2 = \frac{c}{a}[/tex]

In this question:

We have the following quadratic equation:

[tex]dx^2 - cx + p = 0[/tex]

So [tex]a = d, b = -c, c = p[/tex]

One of the roots is twice the other:

So [tex]r_2 = 2r_1[/tex]

First relation:

[tex]r_1 + r_2 = -\frac{b}{a}[/tex]

[tex]r_1 + 2r_1 = -\frac{(-c)}{d}[/tex]

[tex]3r_1 = \frac{c}{d}[/tex]

[tex]r_1 = \frac{c}{3d}[/tex]

Second relation:

[tex]r_1r_2 = \frac{c}{a}[/tex]

[tex]r_1*2r_1 = \frac{p}{d}[/tex]

[tex]2r_{1}^{2} = \frac{p}{d}[/tex]

[tex](\frac{2c}{3d})^2 = \frac{p}{d}[/tex]

[tex]\frac{4c^2}{9d^2} = \frac{p}{d}[/tex]

[tex]p = \frac{4c^2}{9d}[/tex]

The relationship between d, c and p is that [tex]p = \frac{4c^2}{9d}[/tex]

Answer:

PERDON POR HACER ESTO

Step-by-step explanation:

NO ENTIENDO

Answer:2

Step-by-step explanation:

Answer: 3.9

Step-by-step explanation:

7.8 miles x 0.5 = 3.9 miles

Answer:

1. HL

2. ASA

3. AAS

4. SSS

Step-by-step explanation:

1. The hypotenuse and right angle of one triangle is congruent to the other triangle's hypotenuse and right angle, proving the hypotenuse-leg congruency theorem (HL).

2. The two angles and their included side (the side between the two angles) of a triangle match those of the other triangle, proving the angle-side-angle congruency theorem (ASA).

3. The measures of the side and the two adjacent angles of a triangle are given. They are congruent to the corresponding parts of the other triangle, proving the angle-angle-side congruency theorem (AAS).

4. All side lengths of one triangle are given, matching the corresponding sides of the other triangle. This proves the side-side-side congruency theorem (SSS).

I hope this helped!

Answer:

what is your question

Step-by-step explanation: am not trying to steal ur points

Answer:

A

Step-by-step explanation:

The fact you need to use is 47%

47/100 * 47/100 = 2209 / 10000 = 0.221

Answer:

3+5+4=12units3

Step-by-step explanation:

A prism has a length of 3 units, height of 5 units, and width of 4 units. 3 + 5 + 4 = 12 Units cubed 3(4) + 5 = 17 Units cubed.

Answer:

He is wrong its really 60 units

Step-by-step explanation:

Answer:

8 times,

Step-by-step explanation:

4 x 8 is 32

Answer:

A) Barnsboro Bank has more variation.

Step-by-step explanation:

Coefficient of Variation:

The coefficient of variation is given by the division of the standard deviation by the mean.

In this question:

The account balance with the highest coefficient of variation has more variation.

Barnsboro National Bank shows an average account balance of $315 with a standard deviation of $87.

So

[tex]cv = \frac{87}{315} = 0.2762[/tex]

Wellington Savings and Loan shows an average account balance of $8350 with a standard deviation of $1800.

So

[tex]cv = \frac{1800}{8350} = 0.2156[/tex]

Barnsboro Bank has the higher cv, so more variation, and the answer is given by option A.

Answer:

2 hours 52 minutes

Step-by-step explanation:

11-2=9

26/9=2.87

ANSWER: I = 5

STEP BY STEP EXPLANATION:

HOPE THIS HELPS.

Answer:

a.)Q' = -kQ + r

b.)Q = [tex]\frac{r}{k} [ 1 - e^{-kt} ][/tex]

c.) Limiting long run value of Q = [tex]\frac{r}{k}[/tex]

Step-by-step explanation:

a.)

The rate of change is directly proportional to the quantity, Q

⇒[tex]\frac{dQ}{dt}[/tex] ∝ Q

⇒[tex]\frac{dQ}{dt}[/tex] = -kQ ( because it is decreasing )

Also given, quantity is increasing with a constant rate r

⇒[tex]\frac{dQ}{dt}[/tex] = -kQ + r

⇒Q' = -kQ + r

b.)

As we have

[tex]\frac{dQ}{dt}[/tex] = -kQ + r

⇒[tex]\frac{dQ}{-kQ + r}[/tex] = dt

⇒∫[tex]\frac{dQ}{-kQ + r}[/tex] = ∫dt

⇒-[tex]\frac{1}{k}log(-kQ + r) = t + C[/tex]

⇒log(-kQ + r) = -kt -kC

Taking exponential both side, we get

⇒-kQ + r = [tex]e^{-kt +A}[/tex]

⇒-kQ = -r + [tex]e^{-kt +A}[/tex]

⇒Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex][tex]e^{-kt +A}[/tex]

⇒Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex][tex]e^{-kt}.e^{A}[/tex]

⇒Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex][tex]Be^{-kt}[/tex]      .......(1)

Now,

At t = 0, Q = 0

0 = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex]B

⇒[tex]\frac{1}{k}B = \frac{r}{k}[/tex]

⇒B = r

∴ equation (1) becomes

Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{r}{k}[/tex][tex]e^{-kt}[/tex]

⇒Q = [tex]\frac{r}{k} [ 1 - e^{-kt} ][/tex]

c.)

for limiting long run value of Q

[tex]\lim_{n \to \infty} Q = \lim_{n \to \infty}[/tex]   [tex]\frac{r}{k} [ 1 - e^{-kt} ][/tex]

               =  [tex]\frac{r}{k}[/tex][tex]\lim_{n \to \infty} [ 1 - e^{-kt} ]= \frac{r}{k} [ 1 - e^{\infty} ] = \frac{r}{k}[ 1-0][/tex]

               = [tex]\frac{r}{k}[/tex]

⇒Limiting long run value of Q = [tex]\frac{r}{k}[/tex]

Q' = -kQ + r

Q = r/k (1- [tex]\rm e^{-kt}[/tex])

The limiting long-run value of Q = [tex]\rm \frac{r}{k}[/tex]

A drug is administered intravenously at a constant rate of r mg/hour and is excreted at a rate proportional to the quantity present, with a constant of proportionality k > 0.

The differential equation is an equation that contains the derivative of the unknown function.

a) It is given that the rate of change is directly proportional to the quantity Q

[tex]\rm \frac{dQ}{dt}[/tex] ∝ Q

[tex]\rm \frac{dQ}{dt}[/tex] = -kQ

So, Q' = -kQ + r

where quantity Q is increasing with constant rate r and k is unknown constant.

b) Q' = -kQ + r

[tex]\rm \frac{dQ}{dt}[/tex] = -kQ + r

[tex]\rm \frac{dQ}{-kQ+r}=dt\\[/tex]

[tex]\int\limits {\rm \frac{dQ}{-kQ+r} = \int\limits dt[/tex]

log(-kQ + r) = -kt -kC

by taking exponential both side, we get

-kQ + r = [tex]e^{-kt+A}[/tex]

-kQ = -r + [tex]e^{-kt+A}[/tex]

-Q /k= -r/k + [tex]e^{-kt+A}[/tex]/k

Q = -r/k -[tex]\rm \frac{1}{k}Be^{-kt}[/tex]

At t = 0, Q = 0

[tex]\rm \frac{1}{k} B=\frac{r}{k}[/tex]

B = r

by substituting the value in the above equation

Q = r/k (1- [tex]\rm e^{-kt}[/tex])

c) The limiting long-run value of Q

[tex]\rm \lim_{n \to \infty} Q= \lim_{n \to \infty} \frac{r}{k} [1-e^{-kt} ]\\\rm= \frac{r}{k}\lim_{n \to \infty} [1-e^{-kt} ]\\\rm =\frac{r}{k}[1-0]\\\rm=\frac{r}{k}[/tex]

The value Q =[tex]\rm \frac{r}{k}[/tex]

Learn more about differential equations here:

https://brainly.com/question/25731911

Answer:

✔️The graph contains point zero

✔️There's a closed circle on 2⁸/9

✔️The arrow points to the left

Step-by-step explanation:

The inequality, 2⁸/9 ≥ x, implies that 2⁸/9 is either equal to x or more than x. In other words, the highest value of x is 2⁸/9. Possible value of x is equal to or less than 2⁸/9.

This, on a number line, we would graph the information as follows:

✔️The graph contains point zero

Rationale: point zero is less than 2⁸/9

✔️There's a closed circle on 2⁸/9

Rationale: this indicates 2⁸/9 is included in the possible value of x

✔️The arrow points to the left

Rationale: possible value of x ranges from 2⁸/9 and below.

Answer: b c d

Step-by-step explanation:

heart it please ;) your welcome