Answer:
3.5kgm/s
Explanation:
We can calculate the momentum of Julieta
momentum = m(v-u)
Momentum = 0.2(20-2.5)
Momentum = 0.2(17.5)
Momentum = 3.5
Hence the momentum of Julieta is 3.5kgm/s
If two negative charges of -2 C and -2 C are put 32,692 m apart from each other how much force will push them apart?
Answer:
33.65 N
Explanation:
Force that will push them away is given from the equation;
F = Kq1•q2/r²
Where;
K is coulumbs constant = 8.99 × 10^(9) Nm²/C²
We are given;
q1 = q2 = -2 C
r = 32692 m
Thus;
F = 8.99 × 10^(9) × (-2) × (-2)/32692²
F ≈ 33.65 N
Absolute Zero is when energy / molecules stop moving.
Answer:
yes
Explanation:
When all of the molecules (or atoms) in a system stop moving completely, that's as cold as they can get
PLS ANSWER FAST WILL GIVE BRAINLEST!!!
Answer using mass m= F divided by a
And also use kilograms {kg}
A skyrocket is launched with a force of 10 N and accelerates at 20 m / s2. What is the mass of this skyrocket?
Answer:
mass=force/acceleration
m=10/20
m=0.5kg
earth's magnetic compass and its effect on birds?
The lamp has a resistance of 10Ω
Each resistor has a resistance of 10Ω (resistors are connected in parallel)
What is the total resistance of the circuit?
Tick one box
Between 20 and 30Ω?
Exactly 20Ω?
Exactly 30Ω?
Less than 20Ω?
D) Less than 20.
Explanation:
Equivalent resistance in a parallel combination is less than their individual value.
PLS HELP I NEED THIS BY TONIGHT PLS
Answer:
GET GOOD
Explanation:
25 POINTS please help!
What is average acceleration?
a. how fast a speed is changing over an interval of time
b. how fast velocity is changing at a specific instant in time
c. how fast a direction is changing at a specific instant
d. all of the above
Answer:
b
Explanation:
Answer: b
Explanation:
Thanks+ BRAINLIST only for correct answers
AM radio waves have a
a. Shorter broadcast range than FM waves
b. Longer broadcast range than FM waves
C. Better quality sound than FM waves
d. More music options
FM radio travel a shorter distance than AM radio waves.
a.true
b.false
Radio stations, police radios, and amateur radios don't interfere because they
have different
a. volumes
b. music options
C. frequencies
A string of density 0.01 kg/m is stretched with a tension of 5N and fixed at both ends. The length of the string is 0.1m. What is the first four resonance frequencies in the string?
Answer:
The first four resonance frequency in the string are;
1) 50·√50 Hz
2) 100·√50 Hz
3)150·√50 Hz
4) 200·√50 Hz
Explanation:
The given parameters of the string are;
The density of the string, ρ = 0.01 kg/m
The tension force on the string, T = 5 N
The length of the string, l = 0.1 m
Therefore the mass of the string, m = Length of string × Density of the string
∴ m = 0.01 kg/m × 0.1 m = 0.001 kg
The formula for the fundamental frequency, f₁, is given as follows;
[tex]f_1 = \dfrac{\sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{\sqrt{\dfrac{T}{\rho} } }{2 \cdot L}[/tex]
Where;
f₁ = The fundamental frequency in the string
T = The tension in the string = 5 N
m = The mass of the string = 0.001 kg
L = The length of the string = 0.1 m
ρ = The density of the string = 0.01 kg/m
By plugging in the values of the variables, we have;
[tex]f_1 = \dfrac{\sqrt{\dfrac{5}{0.01} } }{2 \times 0.1} = 50 \cdot \sqrt{5}[/tex]
The first four harmonics are;
f₁, 2·f₁, 3·f₁, 4·f₁
Therefore, we have the first four resonance frequency of the string are as follows;
1 × 50·√50 Hz = 50·√50 Hz
2 × 50·√50 Hz = 100·√50 Hz
3 × 50·√50 Hz = 150·√50 Hz
4 × 50·√50 Hz = 200·√50 Hz
A(n) _______ is a line in which waves move that are moving together all in the same phase
Light wave
Wave front
Incident beam
Dark wave
Answer:
wave front
Explanation:
wave front is an imaginary line of a wave that joins all adjacent points that are in phase,
so that's the definition, and you apply it to the question
it obviously can't be the rest
hope you get it
please mark it brainliest
Answer:
B Wave front
Explanation:
EDG 21
Joe and tim have the same mass. Tim stands on a desk that is very high in the air, while Joe stays on the ground. Who had higher potential energy?
Answer:
Tim has a higher potential energy than Joe.
Explanation:
The higher an object or an organism is, the more potential energy it has
If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain using Newton's second law
Answer:
The bike would have more acceleration
Explanation:
Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.
Eg.
F=50N
Motorbike M=200kg
F=ma
50=200 x a
50/200=a
0.25m/s/s =a
Bike M=35kg
F=ma
50=35 x a
50/35= a
1.43m/s/s=a
Answer:
the bike
Explanation:
it has less mass than the motorcycle so so it would have more acceleration
Escribir usando prefijos, en unidades del Sistema Internacional: longitud del ecuador, radios del núcleo y átomo, segundos de un milenio, edad de la Tierra, volumen de una pulga, masa del Sol, distancia de la estrella más cercana a la Tierra (después del Sol).
la característica de los elementos
A car weighing 16,170 newtons is placed on a hydraulic lift. Piston B has an area of 5,005 cm?
and piston A has an area of 65 cm². What force must be exerted on piston A to lift the car?
P = F/A where Pequals pressure, Fequals force, and A equals area
Answer:
210N
Explanation:
According to pascal principle
Fb/Ab = Fa/Aa
Given
Fb = 16,170N
Ab = 5,005cm²
Fa = ?
Aa = 65 cm².
Fa is the force that must be exerted on piston A to lift the car
Substitute
16170/5005 = Fa/65
Cross multiply
5005Fa = 65 * 16170
5005Fa = 1,051,050
Fa = 1,051,050/5005
Fa = 210N
Hence the required force is 210N
The force which must be exerted on piston A to lift the car is equal to 210 Newton.
Given the following data:
Force on piston B = 16,170 newtonsArea of piston B = 5,005 [tex]cm^2[/tex]Area of piston A = 65 [tex]cm^2[/tex]To determine the force which must be exerted on piston A to lift the car:
Mathematically, the pressure acting on an area is given by the formula:
[tex]Pressure = \frac{Force}{Area}[/tex]
Since, the weight of the car remains constant, the pressure on piston A must be equal to the pressure on piston B.
Pressure A = Pressure B
Mathematically, this given by:
[tex]\frac{F_A}{A_A} = \frac{F_B}{A_B}[/tex]
Making [tex]F_A[/tex] the subject of formula, we have:
[tex]F_A =\frac{A_AF_B}{A_B}[/tex]
Substituting the given parameters into the formula, we have;
[tex]F_A = \frac{65 \times 16170}{5005} \\\\F_A = \frac{1,051,050}{5005}\\\\F_A = 210\;Newton[/tex]
Therefore, the force which must be exerted on piston A to lift the car is equal to 210 Newton.
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Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
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A bear scratches his claws on a big pine tree. Does the bear do work on the tree? why or why not?
(btw it has to do with physics) ITS NOT A GENERAL QUESTION.
Answer:
The bear is actually sharpening his claws. That's the only reason he scratches a tree with his claws
Explanation:
Ultraviolet rays from the sun are dangerous because they can damage skin. Why do ultraviolet rays cause damage?
Answer:
Skin damage
Explanation:
exposure can lead to sunburn, and long term exposure can lead to aged skin and much more
How far must a spring with a spring constant of 64N/m be stretched to
store 0.32J of potential energy?
Answer:
0.1m
Explanation:
k = 64N/m
Ep = 0.32J
x = ?
Ep = 1/2 * kx²
make x the subject of the formula
x² = 2Ep/k
x = √(2Ep/k)
x = √(0.64/64)
x = √0.01
x = 0.1m
An electromagnetic wave transfers energy as it travels. During this process, what is the relationship between the magnetic and electric fields along its path?
Answer: A I just got it wrong because of the other person.
Explanation:
The electromagnetic waves are those waves that move through space and carry electromagnetic radiant energy. They include radio waves and microwaves. and many more.
During the transfer of energy, they are the sinusoidal fashion of movement that they are perpendicular to each other in the direction of wave motion. Show synchronized oscillations.Hence the option A is correct.
Learn more about the wave transfers energy as it travels.
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Dominique and her sister are practicing their basketball skills at the park. If both Dominique and her sister both throw their basketballs at the same time and they hit each other. What would happen to their basketballs? a) Only the basketball's speed would be changed b) Only the basketball's directions would be changed c) Both the basketball's speed and direction would change d) Neither the basketball's speed nor direction would change
Answer:
Option C, Both the basketball's speed and direction would change
Explanation:
When two objects travelling with certain speed interact with each their internal forces changes and hence their motion changes simultaneously.
In general cases it is said that momentum is conserved. Momentum is nothing but just the product of mass and velocity.
As the motion of the football changes, then momentum also changes. Since mass is a constant value, it is the velocity of the football that changes.
Hence, both speed and direction of both the football changes.
Option C is correct
Afootball is kicked at avelocity of 15 m/s at angle of 25 degree to the horizontal. What is the total flight time
Answer:
the total flight time is 1.29 s
Explanation:
The computation of the total flight time is given below:
The initial velocity is 15 m/s = v
And, the angle from horizontal is [tex]\theta = 25\ degrees[/tex]
Now the total time is
[tex]t = \frac{2\times v\times \sin \theta }{g} \\\\= \frac{2\times 15\times sin 25^{\circ}}{9.8} \\\\= 1.29 s[/tex]
Hence, the total flight time is 1.29 s
what is kinetic energy
Answer:
Kinetic energy is the movement of objects based on their mass and motion
Explanation:
A form of energy that an object or a particle has by reason of its motion. kinectic energy is a property of a moving object or particle and depends not only on its motion but also on its mass
A 1600 kg car with the brakes applied comes to a stop in 4.20 seconds. During these 4.20 seconds the force of friction slowing down the car is 3900 N. What is the change in momentum of the car?
Answer:
The change in momentum of the car is 16380.8 kg.m/s
Explanation:
Given;
mass of the car, m = 1600 kg
time of motion, t = 4.20s
force of friction on the car, F = 3900 N
final velocity of the car after the brakes were applied, v = 0
The initial velocity of the car during the motion is calculated as;
[tex]F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s[/tex]
The change in momentum of the car is calculated as;
ΔP = mu
ΔP = 1600 x 10.238
ΔP = 16380.8 kg.m/s
An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is given by v2 = 2gy. In an experiment, v and y are measured and the measured values are used to calculate g. If the percent uncertainty in the measured value of v is 3.69% and the percent uncertainty in the measured value of y is 5.00%, what is the percent uncertainty in the calculated value of g?
Answer:
8.91 %
Explanation:
Since v² = 2gy
By the relative error formula,
2Δv/v = Δg/g + Δy/y multiplying by 100%, we have
2Δv/v × 100% = Δg/g × 100 % + Δy/y × 100%
2(Δv/v × 100%) = Δg/g × 100 % + Δy/y × 100%
Δg/g × 100 % = 2(Δv/v × 100%) - Δy/y × 100%
Since Δv/v × 100% = 3.69 % and Δy/y × 100% = 5 %
Since we have a difference for the percentage error in g, we square the percentage errors and add them together. So,
[Δg/g × 100 %]² = [2(Δv/v × 100%)]² + [Δy/y × 100%]²
[Δg/g × 100 %]² = [2(3.69)]² + [5%]²
[Δg/g × 100 %]² = [4)(3.69 %)² + [5%]²
[Δg/g × 100 %]² = 54.4644 %² + 25%²
[Δg/g × 100 %]² = 79.4644 %²
taking square-root of both sides, we have
[Δg/g × 100 %] = 8.91 %
So, the percent uncertainty in the calculated value of g is 8.91 %
A piece of equipment belonging to an astronaut has a mass of 2 kg on the surface of the Moon. What is its weight on the Moon?
Answer:
brainliest plss
Explanation:
If a car is moving backward and has negative acceleration, what can be said about the speed of the car?
a. its speed is degreasing
b. its speed is increasing
c. its speed can either increase or decrease
d. its speed does not change
If a man with
with long-sighted eye want to
a' text book, what shoðld be the distance between
book and the lens? Give reason
The air pressure inside a car tire is
3.00 atm, and it creates 41,500 N
of force pushing out on the tire.
What is the surface area of the
inside of the tire?
Answer:
0.137m²
Explanation:
Pressure = Force/Area
Given
Force = 41,500N
Pressure = 3.00atm
since 1atm = 101325.00 N/m²
3atm = 3(101325.00)
3atm = 303,975N/m²
Pressure = 303,975N/m²
Get the area
Area = Force/Pressure
Area = 41500/303,975
Area = 0.137m²'
Hence the surface area of the inside of the tire is 0.137m²
The diagram below represents the movement of Earth on its axis. Which of 1 point
these four cities will receive sunlight first each.day? *
San Francisco
Phoenix
Chicago
Baltimore
Answer: Baltimore
Explanation:
There is no diagram included but the answer can be inferred from the rotation of the Earth.
The Earth rotates from east to west which is why places further to the east receive sunlight first each day. It is for this reason that Australia and New Zealand receive sunlight more than 15 hours before the United States does.
In the U.S. the furthest city to the east mentioned in the options is Baltimore. They will therefore receive sunlight before everyone else.
After 24.0 days 2.00 milligrams of an original 128.0. Milligram sample remain what is the half life of the sample
Answer:
4 days
either multiply 128 by .5 until you get to 2 counting each time or use 2 formulas ln(n2/n1)=-k(t2-t1) to get k then input k into ln(2)=k*t1/2
n2 is final amount and n1 is beginning and t is either time elapsed as in the first formula or the actual half life that is t1/2
Explanation:
The half life of the sample will be "4 days".
According to the question,
Let,
The number of half life = n→ [tex]\frac{N}{N_o} = (\frac{1}{2} )^n[/tex]
By substituting the values, we get
→ [tex]\frac{2}{128} = (\frac{1}{2} )^n[/tex]
→ [tex]\frac{1}{64} = (\frac{1}{2} )^n[/tex]
→ [tex](\frac{1}{2} )^6= (\frac{1}{2} )^n[/tex]
→ [tex]n=6[/tex]
So,
It takes 6 half life just to reduce from 128 mg - 2mg which is also "24 days".
→ [tex]6 \ half \ life = 24 \ days[/tex]
Hence,
→ [tex]Half \ life = \frac{24}{6}[/tex]
[tex]= 4 \ days[/tex]
Thus the answer above is right.
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