Answer:
The sample space for given condition is
(1,8),(2,8),(3,8),(4,8),(5,8),(6,8),(7,8)
(1,7),(2,7),(3,7),(4,7),(5,7),(6,7)
(1,6),(2,6),(3,6),(4,6),(5,6)
(1,5),(2,5),(3,5),(4,5)
(1,4),(2,4),(3,4)
(1,3),(2,3)
(1,2)
Number of sample space is 28.
Number of sample space where the sum of two numbers is more than 13 is 2((6,8),(7,8)). Therefore the probability is
28
2
=
14
1
Step-by-step explanation:
please thank to all my answer and please mark as brilliant
A doctor is called to see a sick child. The doctor has prior information that
95% of sick children in that neighborhood have the flu, while the other 5%
are sick with measles. Let F stand for an event of a child being sick with flu
and M stand for an event of a child being sick with measles.
A well-known symptom of measles is a rash (the event of having which is
denoted by R). P(R|M) = 0.93. However, occasionally children with flu also
develop rash, so that P(R|F) = 0.09.Upon examining the child, the doctor
finds a rash. What is the probability that the child has measles?
0.57
0.35
0.65
0.20
The probability that the child has measles is gotten as; 0.35
How to use Baye's Theorem?F is the event of a child being sick with flu.
M is the event of a child being sick with measles.
A is the event that the doctor finds a rash.
B1 is the event that the child has measles
S is the sick children.
P(R|M) = 0.93.
P(R|F) = 0.09
P(S|F) = 0.95
P(S|M) = 0.05
Thus, the probability that the child has measles is;
P(M|R) = [(0.05 * 0.93)/[(0.05 * 0.93) + (0.95 * 0.09)]
P(M|R) = 0.35
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Expand (x – 3)^5 using the Binomial Theorem and Pascal’s triangle. Show all necessary steps.
The expansion of (x – 3)^5 is [tex]x^5-15x^4+90x^3-270x^2+405x-243[/tex]
The Binomial Theorem is the method of expanding an expression that has been raised to any finite power. A binomial Theorem is a powerful tool of expansion, which has application in Algebra, probability, etc. Binomial Expression: A binomial expression is an algebraic expression that contains two dissimilar terms.
Pascal's Triangle is a never-ending equilateral triangle in which the arrays of numbers arranged in a triangular manner. The triangle starts at 1 and continues placing the number below it in a triangular pattern
Using Binomial theorem,
=[tex]\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}\left(-3\right)^i[/tex]
=[tex]x^5-15x^4+90x^3-270x^2+405x-243[/tex]
Using Pascal Triangle for (x-1)
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
Accordingly replacing 1 with 3 we get
= [tex]x^5-15x^4+90x^3-270x^2+405x-243[/tex]
Thus the expansion of (x – 3)^5 is [tex]x^5-15x^4+90x^3-270x^2+405x-243[/tex]
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The volume of a cylinder is given by the formula , where r is the radius of the cylinder and h is the height. Which expression represents the volume of this cylinder
The Volume of cylinder represented by the option B.
According to the statement
we have given that the volume formula of cylinder is V= (pi)r^2h, and we have to find that the which expression verify the volume formula for the cylinder given in diagram.
So,
We know that height of the cylinder is given by h = 2x + 7 and
radius r = x - 3.
We know that the formula of volume of cylinder is:
Volume of a cylinder = (pi)r^2h
and Substituting the given values in the above formula
And the volume becomes
Volume = (pi)r^2h
Volume = (pi)( x-3 )^2 (2x+7)
Volume = (pi) ( x^2 + 9 - 6x ) (2x+7)
Volume = (pi) ( 2x^3 + 7x^2 +18x +63 - 42x)
So, The Volume of cylinder represented by the option B.
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Disclaimer: This question is incomplete. Please find the full content below.
Question:
The volume of a cylinder is given by the formula V= pi^2h, where r is the radius of the cylinder and h is the height: which expression represents the volume of this cylinder?
a) Volume = (pi) ( 3x^3 + 7x^2 +14x +63 - 42x)
b) Volume = (pi) ( 2x^3 + 7x^2 +18x +63 - 42x)
c) Volume = (pi) ( 7x^3 + 7x^2 +11x +63 - 42x)
d) Volume = (pi) ( 11x^3 + 7x^2 +13x +63 - 42x)
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Erin tried to evaluate an expression step by step.
8 x 2 x 5
Step 1
=8×2×5
Step 2
=8×(2×5)
Step 3
=16×10
Answer
=160
Find Erin's mistake.
Need Answer Soon As Possible Please!
Answer:
step 2
Step-by-step explanation:
Erin's mistake is in step 2 it should be 8*2 first and 16* 5 which equals to 86
Please someone help me, I don't get it
Answer:
a) x = 1.5 and x = -0.3
b) x = -8 and x = 5
Step-by-step explanation:
a)
The given equation follows the general structure: ax² + bx + c = 0.
Therefore, if a = 5, b = -6, and c = -2, you can substitute the values into the quadratic formula and solve for "x".
b)
Another way of solving polynomials is through factorization. After rearranging the equation to fit the general structure of a quadratic (as seen above), you can factor by asking yourself the question, which 2 numbers multiply to "c" (-40) and add to "b" (3)? The answers will make up your factors.
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\huge\textbf{Equation \#1. }[/tex]
[tex]\mathsf{5x^2 - 6x - 2 = 0}[/tex]
[tex]\huge\textbf{Use the quadratic formula to solve:}[/tex]
[tex]\mathsf{x = \dfrac{-(-6)\pm \sqrt{(-6)^2 - 4(5)(-2)}}{2(5)}}[/tex]
[tex]\huge\textbf{Simplify it: }[/tex]
[tex]\mathsf{x = \dfrac{6 \pm \sqrt{76}}{10}}[/tex]
[tex]\huge\textbf{Simplify that as well:}[/tex]
[tex]\mathsf{x = \dfrac{3}{5} + \dfrac{1}{5}\sqrt{19}\ or\ x = \dfrac{3}{5} + (-\dfrac{1}{5})\sqrt{19}}[/tex]
[tex]\huge\textbf{Therefore, your answer should be:}[/tex]
[tex]\huge\boxed{\mathsf{x \approx 1.5 \ or\ x\approx -0.3{}\ }}\huge\checkmark[/tex]
[tex]\huge\textbf{Equation \#2.}[/tex]
[tex]\mathsf{x^2 + 3x = 40}[/tex]
[tex]\huge\textbf{Subtract 40 to both sides:}[/tex]
[tex]\mathsf{x^2 + 3x - 40 = 40 - 40}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\mathsf{x^2+ 3x - 40 = 0}[/tex]
[tex]\huge\textbf{Factor the left side of the equation:}[/tex]
[tex]\mathsf{(x - 5)\times (x + 8) = 0}[/tex]
[tex]\mathsf{(x - 5)(x + 8) = 0}[/tex]
[tex]\huge\textbf{Set the factors to equal to 0:}[/tex]
[tex]\mathsf{x - 5 = 0 \ or\ even\ x + 8 = 0}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\mathsf{x = 5\ or\ x = -8}[/tex]
[tex]\huge\textbf{Therefore, your answer should be:}[/tex]
[tex]\huge\boxed{\mathsf{x = 5\ or \ x = -8}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
PR=
Help me please thanks so much
Formula: U*V=R*T
3*1=4*x
3=4x
x=3/4
Hope it helps!
Answer:
[tex]\sf PR =\dfrac{3}{4}[/tex]
Step-by-step explanation:
Intersecting chords theorem:It two chords or secants intersect inside the circle, then the product of the length of the segments of one chord is equal to the product of the lengths of the segments of the other chords.
TP * PR = UP * PV
4 * PR = 3 * 1
[tex]\sf PR = \dfrac{3}{4}[/tex]
A solid box is 15 cm by 10 cm by 8 cm. A new solid is formed by removing a cube 3 cm on a side from each corner of this box. What percent of the original volume is removed
Percent of the original volume that is removed is; 18%
How to find the Volume of a box?
Formula for volume of a box is;
V = lbh
where;
l is length
b is breadth
h is height
Thus;
V_original = 15 * 10 * 8
V_original = 1200 cm³
Volume for each cube removed = 3 * 3 * 3 = 27 cm³
Since there are 8 corners on the box, then 8 cubes are removed.
So the total volume removed is; 8 * 27 = 216
Thus;
Percent of the original volume that is removed is;
216/1200 * 100% = 18%
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In which of these situations do the quantities combine to make 0?
A. Kathy receives $20 as a gift. She gives half of her $20 to a friend and keeps the rest for herself.
B. A player in a game earns 4 points for getting an answer right. She then earns 4 points for making it around the board. C. In the morning, the temperature rises 30 degrees. In the evening, it falls by 30 degrees.
D. A hot air balloon rises 40 feet. It then rises another 40 feet.
Answer:
C
Step-by-step explanation:
The temperature rises by 30 degrees, so lets say that it goes from 0 to 30.
The temperature is now 30. But then, it falls by 30 degrees. It is now 0 again. The quantities even out, or make 0.
if the ordered pairs (x, -1) and (5, y) belong to the set {(a, b): b = 2a-3}, find x and y.
Prove that 41 is congruent to 21 (mod 3). Explain using words, symbols, as you wish
From the proof of modular congruence below, it has been shown that;
41 ≡ 21 (mod 3).
How to Solve Modular Arithmetic?We want to use the definition of modular congruence to prove that;
41 is congruent to 21 (mod 3) i.e if a ≡ b (mod m) then b ≡ a (mod m).
We are trying to prove that modular congruence mod 3 is a symmetric relation on the integers.
First, if we recall the definition of modular congruence:
For integers a, b and positive integer m,
a ≡ b (mod m) if and only if m|a–b
Suppose 41 ≡ 21 (mod 3).
Then, by definition, 3|41–21, so there is an integer k such that 41 – 21 = 3k.
Thus;
–(41 – 21) = –3k
So
21 – 41 = 3(–k)
This shows that 3|21 – 41.
Thus;
21 ≡ 41 (mod 3) and the proof is complete
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Translate the triangle.
Then enter the new coordinates.
Answer:
A 3 1 B 2-4 C4-3 then work x and y graph
What is the slope of the line that contains the points (4, 3) and (2, 7)?
OA-1
B. -5
C. -2
OD. -
Answer:
B. -2
Step-by-step explanation:
To find a slope of a line, you have to identify x and y variables:
(4, 3) => (x1, y1) (2, 7) => (x2, y2).We use the formula;
m = ∆y/∆x
= (y2 - y1)/(x2 - x1)
m is slopeSubstitute the values into the formula above.
m = (7 - 3)/(2-4)
= 4/-2
= -2
Therefore, the slope of the line is passing through points (4,3) and (2,
7) is -2.
A polynomial function has a root of 0 with multiplicity 1, and a root of 2 with multiplicity 4. If the function
has a negative leading coefficient, and is of odd degree, which of the following are true?
The function is positive on (-∞, 0).
The function is negative on (0, 2).
The function is negative on (2, ∞).
The function is positive on (0,0).
Using the Factor Theorem to find the function, the correct statement is:
The function is positive on (0,∞).
What is the Factor Theorem?The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:
[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]
In which a is the leading coefficient.
The described roots means that:
[tex]x_1 = 0, x_2 = x_3 = x_4 = x_5 = 2[/tex]
Hence the function is:
f(x) = x(x - 2)^4
(x - 2)^4 is always positive, hence the sign depends on the sign of x, which means that the correct statement is:
The function is positive on (0,∞).
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Grass the line with the given slope and y-intercept. slope = -4, y-intercept =-5
There will be no change to the grass because the exponential of the function remains the same.
According to the questions,
slope = -4 and y-intercept = -5
Equation of straight line y = mx + c
y = -4x - 5
In order to grass line, there will be no change to the grass because the exponential of the function remains the same.
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How many employers ask that employees be skilled in communication and handling money
Based on the Venn diagram, the number of employers who ask employees to be skilled in both communication (C) and handling money (M) is equal to 47 employers.
What is a Venn diagram?A Venn diagram is a circular graphical tool that is used to graphically show, logically compare and contrast two (2) or more finite data set or samples in a given population.
From the Venn diagram, we can deduce that the number of employers who ask employees to be skilled in both communication (C) and handling money (M) is given by:
C∩M = 22 + 25
C∩M = 47 employers.
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im not he brighest with math and i need help
Answer:
113.04 ft^2
Step-by-step explanation:
area of the circle= 3.14*(6)^2
pls help
me find the volume
Answer:
FIRST
To find the volume of rectangular prism is
Volume = Length x Width x Height
Volume = 20cm x 10cm x 13cm
= 40 x 13
= 520cm cubic or cube
520 is the volume of the rectangular prism
the you divide volume of rectangular prism and volume of solid ball.
Correct me if i am wrong guys.
Answer:
It will take approximately take 17 balls to overflow the container
Step-by-step explanation:
Volume of the rectangle = 20x13x10 = 2600[tex]cm^{3}[/tex]
Volume of the water = 20x10x11 = 2200[tex]cm^{2}[/tex]
Amount of empty space = 2600-2200 = 400[tex]cm^{3[/tex]
Solid ball volume = 23[tex]cm^{3}[/tex] each
To find how many balls can overflow the container = 400/23 = 17.39
insert a monomial so that each result is an identity( *− 3b4)(3b4 +*) = 121a10 − 9b8
Answer:
(11a^5 - 3b^4) (3b^4 + 11a^5) = 121a^10 - 9b^8
Step-by-step explanation:
I got the 11 part by doing √121 = 11
I got the a^5 by knowing that a needs to have the same exponent both times and 5+5=10. Thats how I got the a^5 part.
Answer: (11a^5 - 3b^4) (3b^4 + 11a^5) = 121a^10 - 9b^8
the bus bound for northtown departs every 15 minutes and the bus for eastown departs every 18 minutes from the central station. Both buses start at 9:30 AM each morning. When is the next time both buses will depart from the central station at the same time?
Considering the least common factor of 15 and 18, it is found that they will depart from the central station at the same time at 11 AM.
How to find the time it takes for periodic events to repeat at the same time?To find the time that passes between the events happening at the same time, we need to find the least common multiple of the periods.
In this problem, the periods are of 15 and 18, hence their lcm is found as follows:
15 - 18|2
15 - 9|3
5 - 3|3
5 - 1|5
1 - 1
Hence:
lcm(15,18) = 2 x 3 x 3 x 5 = 90 minutes.
They will depart from the central station at the same time in 90 minutes from 9:30 AM, hence at 11 AM.
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Find the indefinite integral by making a change of variables. (hint: let u be the denominator of the integrand. remember to use absolute values where appropriate. use c for the constant of integration.) 1 9 2x dx
The value of the indefinite integral is
Given:- The integration of is given whose lower limit is and upper limit is .
To Find:- We have to find the value of the integration of is given whose lower limit is and upper limit is .
By using the concept of indefinite integral it will be solved.
According to the problem,
Therefore, the value of the indefinite integral is .
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Which shows the solution to the inequality-4x >36
Answer:
x < - 9
Step-by-step explanation:
- 4x > 36
divide both sides by - 4 , reversing the symbol as a result of dividing by a negative quantity.
x < - 9
[tex]\boldsymbol{\sf{-4x > 36 }}[/tex]
Divide both sides by −4. Since −4 is <0, the inequality direction is changed.
[tex]\boldsymbol{\sf{x < \dfrac{36}{-4} }}[/tex]
Divide 36 by −4 to get −9.
[tex]\boxed{\boldsymbol{\sf{x < -9}}}[/tex]
Plis help! Will give brainliest! 5th grade math!
Answer:
(32÷(10-8)÷2)-3
Step-by-step explanation:
(32÷(10-8)÷2)-3
(32÷2÷2)-3
(16÷2)-3
8-3 = 5
✅
The image is listed below. Any help would be appreciated!
Check the picture below.
part A
since the base of the triangular base is 16, and the altitude "h" splits the base in two equal halves, half that is just 8, so we're looking at a right triangle with a hypotenuse of 17 and a side of 8, thus
[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2 - a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{17}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{h}\\ \end{cases} \\\\\\ \sqrt{17^2-8^2}=h\implies \sqrt{225}=h\implies \boxed{15=h}[/tex]
part B
well, the prism is simply two triangles and 3 rectangles, le's simply add their areas.
[tex]\stackrel{two~triangles}{2\left[ \cfrac{1}{2}(\stackrel{base}{16})(\stackrel{height}{15}) \right]}~~ + ~~\stackrel{two~rectangles}{2(20)(17)}~~ + ~~\stackrel{one~rectangle}{(20)(16)} \\\\\\ 240~~ + ~~680~~ + ~~320\implies \text{\LARGE 1240}[/tex]
Lizette wanted to see if it would be possible to use a little less materials in a tea infuser but still not be required to be at full capacity. Her rectangular pyramidal tea infuser would be 7 cm high, 3 cm long and 1.5 cm wide. The tea infuser from the example, was the same except 7.9 cm high and was filled to 80% capacity.
Would these dimensions work, if so to what percent would Lizette's infusers have to be filled to use the same amount of tea?
Considering the volume of a rectangular prism, since the new volume is greater than the filled volume, the new dimensions would work, and 90.29% of the infuser would be filled.
What is the volume of a rectangular prism?
The volume of a rectangular prism of length l, width w and height h is given by:
V = lwh.
The original dimensions are:
h = 7.9 cm, l = 3 cm, w = 1.5.
Hence the volume in cm³ was:
V = 7.9 x 3 x 1.5 = 35.55 cm³.
The infuser was filled to 80% capacity, hence:
Vf = 0.8 x 35.55 = 28.44 cm³.
For the new dimensions, we have that h = 7 cm, hence the volume is:
Vn = 7 x 3 x 1.5 = 31.5 cm³.
28.44/31.5 x 100% = 90.29%.
Since the new volume is greater than the filled volume, the new dimensions would work, and 90.29% of the infuser would be filled.
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PLS HELP>>>look at pic
Answer:
3x + 2 >= 0
Step-by-step explanation:
Since this is a 4th root, not a cubic root, the radical can only contain 0 or positive numbers. Therefore there is 3x + 2 >= 0.
Match each system of equations to the inverse of its coefficient matrix, A-1, and the matrix of its solution, X.
The system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X is shown in the figure.
Given that the system of equations are shown in given figure.
The first system of equations are
[tex]\begin{aligned}4x+2y-z&=150\\x+y-z&=-100\\-3x-y+z&=600\\\end[/tex]
By writing in matrix AX=b, we get
Coefficient matrix [tex]A=\left[\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right][/tex] and [tex]B=\left[\begin{array}{l}150&-100&600\end{array}\right][/tex]
Firstly, we will find the A⁻¹ by finding the determinant and adjoint of A and divide the adjoint with determinant, we get
[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right|\\ &=4(1-1)-2(1-3)-1(-1+3)\\&=4(0)-2(-2)-1(2)\\ &=2\neq 0\end[/tex]
[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}0&2&2\\-1&1&-2\\-2&3&2\end{array}\right]^T\\&=\left[\begin{array}{lll}0&-1&-2\\2&1&3\\2&-2&2\end{array}\right]\end[/tex]
[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0&-0.5&-0.5\\1&0.5&1.5\\1&-1&1\end{array}\right]\end[/tex]
For a solution Consider [A B] and apply row operations, we get
[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{lll1}4&2&-1&150\\1&1&-1&-100\\-3&-1&1&600\end{array}\right]\\ R_{2}&\rightarrow 4R_{2}-R_{1},R_{3}\rightarrow 4R_{3}+3R_{1}\\ &\sim \left[\begin{array}{lll1}4&2&-1&150\\0&2&-3&-550\\0&2&1&2850\end{array}\right]\\ R_{3}&\rightarrow R_{3}-R_{2}\\ &\sim \left[\begin{array}{llll}4&2&-1&150\\0&2&-3&-550\\0&0&4&3400\end{array}\right]\end[/tex]
Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}-250\\1000\\850\end{array}\right][/tex]
The second system of equations are
[tex]\begin{aligned}x+y-z&=220\\5x-5y-z&=-640\\-x+y+z&=200\\\end[/tex]
Similarly, we will find for second system of equations
[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}1&1&-1\\5&-5&-1\\-1&1&1\end{array}\right|\\ &=1(-5+1)-1(5-1)-1(5-5)\\&=1(-4)-1(4)-1(0)\\ &=-8\neq 0\end[/tex]
[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}-4&-4&0\\-2&0&-2\\-6&-4&-10\end{array}\right]^T\\&=\left[\begin{array}{lll}-4&-2&-6\\-4&0&-4\\0&-2&-10\end{array}\right]\end[/tex]
[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.5&0.25&0.75\\0.5&0&0.5\\0&0.25&1.25\end{array}\right]\end[/tex]
[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}1&1&-1&220\\5&-5&-1&-640\\-1&1&1&200\end{array}\right]\\ R_{2}&\rightarrow R_{2}-5R_{1},R_{3}\rightarrow R_{3}+R_{1}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&2&0&420\end{array}\right]\\ R_{3}&\rightarrow 5R_{3}+R_{2}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&0&4&360\end{array}\right]\end[/tex]
Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}100\\210\\90\end{array}\right][/tex]
The third system of equations are
[tex]\begin{aligned}2x+2y-z&=290\\x+y-3z&=500\\x-y+2z&=600\\\end[/tex]
Similarly, we will find for third system of equations
[tex]\begin{aligned}|A|&=\left|\begin{array}{lll}2&2&-1\\1&1&-3\\1&-1&2\end{array}\right|\\ &=2(2-3)-2(2+3)-1(-1-1)\\&=2(-1)-2(5)-1(-2)\\ &=-10\neq 0\end[/tex]
[tex]\begin{aligned}Adj A&=\left[\begin{array}{lll}-1&-5&-2\\-3&5&4\\-5&5&0\end{array}\right]^T\\&=\left[\begin{array}{lll}-1&-3&-5\\-5&5&5\\-2&4&0\end{array}\right]\end[/tex]
[tex]\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.1&0.3&0.5\\0.5&-0.5&-0.5\\0.2&-0.4&0\end{array}\right]\end[/tex]
get
[tex]\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}2&2&-1&290\\1&1&-3&500\\1&-1&2&600\end{array}\right]\\ R_{2}&\rightarrow 2R_{2}-R_{1},R_{3}\rightarrow 2R_{3}-R_{1}\\ &\sim \left[\begin{array}{llll}2&2&-1&290\\&0&-5&710\\0&-4&5&910\end{array}\right]\end[/tex]
Thus, [tex]x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}479\\-405\\-142\end{array}\right][/tex]
Hence, each system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X.
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Prove the statement using a two-column proof or paragraph proof.
M
L
Given: JKLM is a parallelogram; KL≈ LM; JL MK
Prove: JKLM is a rhombus.
Complete your proof in the box below. You will be awarded 5 points for your
statements and 5 points for your reasons.
1) JKLM is a parallelogram, [tex]\overline{KL} \cong \overline{LM}[/tex] (given)
2) JKLM is a rhombus (a parallelogram with a pair of consecutive congruent sides is a rhombus)
What is the difference? startfraction x 5 over x 2 endfraction minus startfraction x 1 over x squared 2 x endfraction
The difference between the two given fractions is [tex]\frac{x^{2} +4x-1}{x^{2} +2x}[/tex].
What is fraction?Fraction if a part of whole. It is represented in the form of numerator and denominator.
Given that,
[tex]\frac{x+5}{x+2} -\frac{x+1}{x^{2} +2x}[/tex]
= [tex]\frac{x+5}{x+2} -\frac{x+1}{x(x+2)}[/tex]
Take the LCM of the denominators is [tex]x(x+2)[/tex].
= [tex]\frac{x(x+5)-(x+1)}{x(x+2)}[/tex]
= [tex]\frac{x^{2}+5x -x-1}{x^{2} +2x}[/tex]
= [tex]\frac{x^{2}+4x-1}{x^{2} +2x}[/tex]
Thus, the difference between the two given fractions is [tex]\frac{x^{2}+4x-1}{x^{2} +2x}[/tex] .
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The given question is not in correct form.
This question is down below. The picture attached below.
Thanks.
The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Given an equation showing profits of A Christmas vendor as
P=-0.1[tex]g^{2}[/tex]+30g-1200.
We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.
To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.
665.60=-0.1[tex]g^{2}[/tex]+30g-1200
0.1[tex]g^{2}[/tex]-30g+1200+665.60=0
0.1[tex]g^{2}[/tex]-30g+1865.60=0
Divide the above equation by 0.1.
[tex]g^{2}[/tex]-300g+18656=0
Solving for g we get,
g=[300±[tex]\sqrt{(300)^{2}-4*1*18656 }[/tex]]/2*1
g=[300±[tex]\sqrt{90000-74624}]/2[/tex]
g=[300±[tex]\sqrt{15376}[/tex]]/2
g=(300±124)/2
g=(300+124)/2 , g=(300-124)/2
g=424/2, g=176/2
g=212,88
Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.
Put the value of P=1500 in equation P=-0.1[tex]g^{2}[/tex]+30g-1200.
-0.1[tex]g^{2}[/tex]+30g-1200=1500
0.1[tex]g^{2}[/tex]-30g+1500+1200=0
0.1[tex]g^{2}[/tex]-30g+2700=0
Dividing equation by 0.1.
[tex]g^{2}[/tex]-300g+27000=0
Solving the equation for finding value of g.
g=[300±[tex]\sqrt{300^{2} -4*1*27000}[/tex]]/2*1
=[300±[tex]\sqrt{90000-108000}] /2[/tex]
=[300±[tex]\sqrt{-18000}[/tex]]/2
Because [tex]\sqrt{-18000}[/tex] comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.
Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
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Drag each equation to the correct location on the table. Not all equations will be used.
Determine which equations represent lines that are parallel or perpendicular to the linear equation provided on the graph.
y = 2 + 3y = - +4y= 2z+ 2 y = 12 + 8
y=-2 + 5y =
-2z+1
4
Parallel Line
2
2
Perpendicular Line
Answer:
parallel: y = 1/2x +3perpendicular: y = -2x +1Step-by-step explanation:
A parallel line will have the same slope as the line on the graph. A perpendicular line will have a slope that is the opposite reciprocal of the slope of the graphed line.
Slope of graphed lineThe line on the graph rises 1 grid square for each run of 2 grid squares to the right. Its slope is ...
m = rise/run = 1/2
Slope of perpendicular lineThe opposite reciprocal of this slope is ...
-1/(1/2) = -2
A perpendicular line will have a slope of -2.
Slope-intercept formThe slope-intercept form of the equation for a line is ...
y = mx +b
where the slope is m and b is the y-intercept. For the purpose here, we don't care about the y-intercepts of any of the lines. We only care about the slope: the coefficient of x.
This means the equations we're looking for are of the form ...
parallel line: y = 1/2x + b
perpendicular line: y = 2x +b . . . . . for some constant b
Parallel lineOf the equations offered, the only one with an x-coefficient of 1/2 is ...
y = 1/2x +3
Perpendicular lineOf the equations offered, the only one with an x-coefficient of -2 is ...
y = -2x +1
Answer:
Step-by-step explanation:
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