Answer:
2.92 m
Explanation:
As we know, frequency × Wavelength = Speed of light
so here frequency of 102.7 MHz can be written as 102.7× 10⁶ Hz..
So Lambda (wavelength) = 3×10⁸/ 102.7 × 10⁶ which gives 2.92 metres or 2.92 × 10¹⁰ Å
A hockey puck that has a mass of 0.170 kg travels with a speed of 42.0 m/s.
What is the momentum of the puck?
Answer:
Momentum = 7.14 Kgm/s
Explanation:
Given the following data;
Mass = 0.170 kg
Velocity = 42m/s
To find the momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
Momentum = mass * velocity
Substituting into the equation, we have;
Momentum = 0.170 * 42
Momentum = 7.14kgm/s
Therefore, the momentum of the honey puck is 7.14 Kgm/s.
How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?
Explanation:
Hey there!
Given that 4kg ball struck by 12 N force.
So, we need acceleration.
Force = Mass × Acceleration
And, so
Acceleration = Force / Mass.
Acceleration = 12/4
Acceleration is equal to 3m/s² in SI units.
Hope it helps :)
Identify an example of conformity in your school or community. Tell what makes it an example of conformity.
Answer:
One example of conformity in my school is the wide obsession of designer clothes. Because famous people wear them kids think its cool and follow their actions.
Explanation:
Which process causes the transfer of energy by air currents within the Earth's atmosphere?
Answer:
Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface
simple machines are in a mousetrap
Answer:
A mousetrap makes use of a simple machine called a lever.
Explanation:
In a second-class lever the effort force is at the other end, with the load in the middle. In a third-class lever, the load is at the end and the effort force is between the fulcrum and the load. When you set the mousetrap, you are using a second-class lever. Sorry if I get this wrong. I am in 5th grade! ♥
How do limiting factors impact Pacific Coast organisms?
Answer:
Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration. When organisms face limiting factors, they show logistic growth (S-shaped curve, curve B: Figure below). ... Limiting factors determine the carrying capacity of a population.
Explanation:
Which best describes how single-celled organisms are different from multi-celled organisms?
A.
A single-celled organism is more detailed and complex.
B.
A single-celled organism must perform all cellular functions.
С.
A single-celled organism must work with other cells to survive.
D.
A single-celled organism is specialized to perform one function.
Answer:
A single-called organism must perform all cellular functions on its own
Explanation:
i took the test
examples for types of connective tissue
Plz it very important
Answer:
SPECIALISED CONNECTIVE TISSUES
dense regular connective tissue which is found in tendons and ligaments, and is shown below. ...
cartilage - (see the topic on bone and cartilage)
adipose tissue (see adipose cells)
haemopoietic tissue (bone marrow, lymphoid tissue)
blood (see the topic on blood)
Explanation:
hope you like my ans
Answer: Types of Connective Tissue
Cartilage. Cartilage is a type of supporting connective tissue.
ex:Hyaline cartilage, Hyaline cartilage, Elastic cartilage
Bone. Bone is another type of supporting connective tissue.
ex; Spongy bone, Compact bone
Adipose. Adipose is another type of supporting connective tissue that provides cushions and stores excess energy and fat.
Blood.
ex;Lymph
Hemapoetic/Lymphatic.
Elastic.
Fibrous
A negative charge of 0.198 C exerts an attractive force of 83,506 N on a second charge that is 3,004 m away. What is the magnitude of the second charge? ( solve for one of the charges)
Answer:
-606.73C
Explanation:
According to coulombs law
F = kq1q2/r^2
Substitute the given value
83,506 = 9*10^9(-0.198)q2/(3004)^2
83,506 = -1.242*10^9q2/9,024,016
-1.242*10^9q2 = 7.54*10^11
q2 = -7.54*10^11/1.242*10^9
q2 = -606.73C
hence the magnitude of the other charge is -606.73C
select one popular music either OPM or from other countries that you like most. a.why you like this music/song? b.What is the message/s of this song that affect you most? c.if you will be the writer of this song, will you change the title or not? why?
Answer:
my favourite song is hym to the sea. That song reminds me of the innocent people who lost their lives in titanic a century ago. If I was the writer of that song ,i would not change the title of that song because I can feel the sound of ocean when I listen to that song.
28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark. From this information, calculate the density of iron.
Answer:
Density=mass/volume.
1) we have to calculate the iron volume in liters.
iron volume=second level - first level=49.10 ml-45.50 ml=3.6 ml
3.6 ml=3.6 ml(1 liter / 1000 ml)=0.0036 liters
2) we calculate the mass iron in kg.
28.5 g=28.5 g(1 kg /1000 g)=0.0285 kg.
2) we calculate the density of iron.
density=0.0285 kg / 0.0036 liters=7.92 kg/L
7.92 kg/l=7.92 kg/L(1000 g/1Kg)(1000 cm³/1 L)=7.92 g/cm³.
From this information the Iron density is 7.92 Kg/L or 7.92 g/cm³.
Explanation:
I hope this helps u! :D
Answer:
7.92 g/cm^3
Explanation:
1 mL = 1 cm^3
density = mass/volume
volume: 49.10 mL - 45.50 mL = 3.60 mL = 3.60 cm^3
mass: 28.5 g
density = (28.5 g)/(3.60 cm^3) = 7.91666... g/cm^3
Answer: 7.92 g/cm^3
An ice skater accelerates backward for 5.0 second to final speed of 12m/s. If the acceleration backward was at a a rate of 1.5m/s2 what was the skater's initial speed
Answer:
Initial velocity, U = 4.5m/s
Explanation:
Given the following data;
Final velocity, v = 12m/s
Time, t = 5 seconds
Acceleration, a = 1.5m/s²
To find the initial velocity, we would use the first equation of motion.
[tex] V = U + at[/tex]
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
12 = U + 1.5*5
12 = U + 7.5
U = 12 - 7.5
Initial velocity, U = 4.5m/s
A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5.40 m and friction is ignored, what is the kinetic energy of the fish when it hits the water?
need help someone please
Answer:
C would be the correct answer.
A cart at rest accelerates to a speed of 30 meters per second over a 3.0 second time interval. What is the average velocity of the cart during these 3.0 seconds? P.4B
Answer:
15 m/s
Explanation:
Given data
Initial velocity= 0m/s----------since the cart was at rest
Final velocity = 30m/s
time= 30 seconds
Required
the average speed
We know that the sum of the initial and final velocity is divided by 2 to find the average velocity
average velocity= 0+30/2
average velocity= 30/2
average velocity= 15 m/s
Hence the average velocity is 15 m/s
Comparing the Motion of Two Cars
Position vs Time
for Two Cars
D
Which statements describe the motion of car A and car
B? Check all that apply.
Car A and car B are both moving toward the origin.
Car A and car B are moving in opposite directions,
Car Ais moving faster than car B.
Car A and car B started at the same location.
Car A and car B are moving toward each other until
they cross over.
B
Position (m)
Time (s)
B, C, E
Hope this helps
what do you call ends of a magnet
Answer:
The end that faces the north is called the north-seeking pole, or north pole, of the magnet. The other end is called the south pole. When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another.
Explanation:
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If you have observed something about the world and want to
investigate it further, what are you seeking to do?
a Do background research
b Construct a hypothesis
C Ask a question
d Report the results
Answer: a
Explanation: :)
PLS ANSWER FAST WILL GIVE BRAINLYEST TIMED TEST!!!!
use the equation solving a= F divided by M
Also use metres per second squared [m/s2]
A Spring balance is used to launch a 0.05 kg foam ball with a force of 5N. What acceleration is produced?
A 9 V battery produces a current of 18 amps. What is the resistance?
[tex] \sf• \: Battery \: Voltage \: (V) = 9 \: v[/tex]
[tex] \sf• \: Current \: (I) = 18 \: Amps.[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find :- }}[/tex][tex] \sf• \: The \: Resistance. [/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{Solution :- }}[/tex]
[tex] \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}[/tex]
[tex] \rightarrow \sf R = \frac{9}{18} [/tex]
[tex] \rightarrow \sf R = \frac{1}{2}[/tex]
[tex] \rightarrow \sf R = 0.5[/tex]
[tex] \\ [/tex]
[tex] \bf \purple{Therefore, \: the \: \: resistance \: \: is \: \: 0.5 \: Ω \: .}[/tex]An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?
Answer:
i. 15.6 m/s
ii. I = 1.44 KNs
Explanation:
The impulse, I, on a body is the product of force applied on it and the time it acts.
i.e I = F x t
Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.
i. mass, m, of the player = 92 kg
initial velocity of the player, u = 9.4 m/s
final velocity of the player, v = 6.2 m/s
Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.
So that,
change in velocity of the player = final velocity - initial velocity
= 6.2 - (-9.4)
= 6.2 + 9.4
= 15.6 m/s
change in velocity of the player is 15.6 m/s
ii. Impulse, I = m(v - u)
= 92 x 15.6
= 1435.2
Impulse on the player is 1.44 KNs.
A trash compactor pushes down with a force of 500 N on a 3 cm2 input piston, causing a force of 30,000 N to crush the trash. What is the area of the output piston that crushes the trash
Answer:
[tex]180 cm^2[/tex]
Explanation:
We are given that
Force [tex]F_1=500 N[/tex]
[tex]A_1=3cm^2[/tex]
[tex]F_2=30000 N[/tex]
We have to find the area of the output piston that crushes the trash
Input piston=Output piston
We know that
[tex]Pressure=\frac{force}{Area}[/tex]
Using the formula
[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]
Substitute the values
[tex]\frac{500}{3}=\frac{30000}{A_2}[/tex]
[tex]A_2=\frac{30000\times 3}{500}[/tex]
[tex]A_2=180 cm^2[/tex]
Hence, the area of the output piston that crushes the trash 180 square cm
A trash compactor pushes down with a force of 500 N on a 3 cm² input piston, causing a force of 30,000 N on a 180 cm² output piston.
In physics, the pressure (P) is the force (F) applied perpendicular to the surface of an object per unit area (A) over which that force is distributed.
[tex]P = \frac{F}{A}[/tex]
A trash compactor pushes down with a force of 500 N (F₁) on a 3 cm² (A₁) input piston, causing a force of 30,000 N (F₂) to crush the trash.
Since the pressure in both pistons is equal, we can use the previous expression to calculate the area of the output piston (A₂).
[tex]\frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\A_2 = \frac{A_1 \times F_2}{F_1} = \frac{3cm^{2} \times 30,000N}{500N} = 180cm^{2}[/tex]
A trash compactor pushes down with a force of 500 N on a 3 cm² input piston, causing a force of 30,000 N on a 180 cm² output piston.
Learn more: https://brainly.com/question/23603188
can someone help me please
Answer:
time
Explanation:
Answer:
hour measure time so their for it is time
When you push an object, it pushes back with an equal and opposite force
Answer:
I would say false
Explanation:
Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.
What is the final temperature of 5kg of water, with an initial temperature of 5oC, after 50kJ of energy has been transferred to it. The specific heat capacity of water is 4200 J/kgoC
Answer:
[tex]T_f=7.38^{\circ}[/tex]
Explanation:
Given that,
Mass, m = 5 kg
Initial temperature of water, [tex]T_i=5^{\circ} C[/tex]
Heat transferred, Q = 50 kJ = 50,000 J
The specific heat capacity of water is 4200 J/kg°C
We need to find the final temperature of the water. The heat transferred in the process is given by :
[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}+T_i=T_f\\\\T_f=\dfrac{50000}{5\times 4200}+5\\\\T_f=7.38^{\circ}[/tex]
So, the final temperature of water is [tex]7.38^{\circ}[/tex].
scientific notation
1. 0,000034
2. 0,0054
3. 346574
4. 0,00125
5. 348954
Answer:
1. 3.4 x10^-5
2. 5.4 x10^-3
3. 346574
4. 12.5x10^-4
5. 348954
Hope this helps, please mark me brainliest if it does! :)
An object’s distance from a converging lens is 16.1 times the focal length.
How far is the image from the lens?
Answer in units of f .
Answer:Hey I just wanted to tell you that Jesus LOVES YOU SO MUCH He died on the cross for all your sins so you won’t have to suffer the consequences of your sin He paid for ALL OF IT! He loves you SO FREAKING MUCH like unconditionally... all you have to do is confess with your mouth and believe in your heart that Jesus is Lord and God raised Him from the dead 3 days later you will be saved ;)))))))) He wants an intimate relationship with you all you have to do is reach out to Him I love you AND ABOVE ALL JESUS LOVES YOU
Have a blessed day;))
Explanation:
walks 5 meters in 5 seconds what is the average speed
Answer:
10 is the speed
Explanation:
this is y
What is the net force of a scooter acting on the road with an impulse of 550 Ns for 10s.
Answer:
55N
Explanation:
Impulse is the product of Force and Time
Impulse = Force * Time
Given
Impulse = 550Ns
Time = 10s
Force = Impulse/Time
Force = 550/10
Force = 55N
Hence the net force on the scooter is 55N
You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.
a)How long after it is launched does the walnut reach the ground?
b)How far does the walnut travel horizontally from launch point to landing point?
c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.
Answer:
a.3.51s
b.33.8m
c. 9.64,-22.9
Explanation:
(a) The time taken be "3.5083 sec".
(b) The distance will be "33.82 m".
(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".
Velocity and DirectionAccording to the question,
Speed, V₀x = 15 Cos (50.0°)
= 9.64 m/s
V₀y = 15 Sin (50.0°)
= 11.49 m/s
Vertical displacement = -20.0 m
(a) We know the relation between displacement, time and acceleration
→ y = vt + [tex]\frac{1}{2}[/tex]at²
By substituting the values,
→ -20.0 = 11.49 t - 4.9 t²
4.9 t² - 11.49 t - 20.0 = 0
t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]
= [tex]\frac{11.49 + 22.89}{9.8}[/tex]
= 3.5083 sec
(b) We know the formula,
Distance = Speed × Time
or,
→ X = 9.64 t
= 9.64 × 3.5083
= 33.82 m
(c) Again by using the above relation, we get
Vx = V₀x
= 9.64 m/s
Vy = V₀y - gt
By substituting the values,
= 11.49 - 9.8 × 3.5083
= 11.49 - 34.38
= -22.89 m/s
Thus the response above is correct.
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