Link OA has a constant counterclockwise angular velocity w = 13 rad/sec during a short interval of its motion. For the position shown determine the angular accelerations of AB and BC.

Answer: Non-programmable

Explanation:

A non-programmable solid-state relay is an electronic device that performs the same function as an electromechanical relay.

An SSR is an electrical switching device that turns on or off when an external voltage (AC or DC) is applied across its control terminals. They perform the same job as an electromechanical relay, but because they include no moving parts, they have a longer operational lifetime.

Solid-state relays are the semiconductor analogs of electromechanical relays and can thus control electrical loads. When energized, the solid-state relay is a fairly complex device with a simple purpose: to activate a single output load.

Therefore, a non-programmable solid-state relay is a type of electrical device that functions similarly to an electromechanical relay.

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The advanced safety features that are now standard on 2023 Z are:

The above is the short name or nickname for the All New 2023 Nissan Z coupe Sports car.

The care also features Advanced driver assist and safety technology which relieves the driver's everyday workload, allowing you to focus on what matters most.

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The demand curve is the graphical representation of the relationship between the price of a good and the quantity demanded for a given period of time.

A demand schedule is a table which shows the quantity demanded of a good or service at different price levels.

A demand schedule can be graphed as a continuous demand curve on a chart where the Y-axis represents the price and the X-axis represents quantity.

Here, a typical representation, the price will appear on the left vertical axis, the quantity demanded on the horizontal axis.

Note that the complete information wasn't found and an overview was given.

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Answer:

the carburizing time necessary to achieve a carbon concentration is 31.657 hours

Explanation:

Given the data in the question;

To determine the carburizing time necessary to achieve the given carbon concentration, we will be using the following equation:

(Cs - Cx) / (Cs - C0) = ERF( x / 2√Dt)

where Cs is Concentration of carbon at surface = 0.90

Cx is Concentration of carbon at distance x = 0.30 ; x in this case is 4 mm = ( 0.004 m )

C0 is Initial concentration of carbon = 0.10

ERF() = Error function at the given value

D = Diffusion of Carbon into steel

t = Time necessary to achieve given carbon concentration ,

so

(Cs - Cx) / (Cs - C0) = (0.9 - 0.3) / (0.9 - 0.1)

= 0.6 / 0.8

= 0.75

now, ERF(z) = 0.75; using ERF table, we can say;

Z ~ 0.81; which means ( x / 2√Dt) = 0.81

Now, Using the table of diffusion data

D = 5.35 × 10⁻¹¹ m²/sec at (1100°C) or 1373 K

now we calculate the carbonizing time by using the following equation;

z = (x/2√Dt)

t is carbonizing time

so we we substitute in our values

0.81 = ( 0.004 / 2 × √5.35 × 10⁻¹¹ × √t)

0.81 = 0.004 / 1.4628 × 10⁻⁵ × √t

0.81 × 1.4628 × 10⁻⁵ × √t = 0.004

1.184868 × 10⁻⁵ × √t = 0.004  

√t = 0.004 / 1.184868 × 10⁻⁵

√t = 337.5903

t = ( 337.5903)²  

t = 113967.21 seconds

we convert to hours

t = 113967.21 / 3600

t = 31.657 hours

Therefore, the carburizing time necessary to achieve a carbon concentration is 31.657 hours

Different lever designs can be engineered and developed to alter the brake pedal effort required of the driver by using different levels of mechanical advantage.

Mechanical advantage can be defined as a ratio of the output force of a lever to the force acting on it (input force or effort), assuming no losses due to wear, flexibility, tear or friction.

This ultimately implies that, different lever designs can be suitably engineered and developed to alter the brake pedal effort (input force) that is required of the driver, especially by using different levels of mechanical advantage.

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Water pressure principles is known to  state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

Note that  principle is shown by a vessel that is said to be having flat sides and has water. The pressure exerted by the weight of the water is therefore known to be perpendicular to the walls of the storage.

A water butt is known to be a container that is made and also used to store a lot of rainwater.

Note that Water pressure principles is known to  state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

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The maximum height that the water can rise above the jet is: 35 meters.

Given:

P = 350 kPa = 350000 Pa

We would use pressure(p)  formula to determine the maximum height that the water can rises above the jet by solving for h (height).

Using this formula

Pressure(P) = P₀ + ρgh

Where;

P₀ represent Pressure at the fluid's surface

ρ represent Density of the fluid = 1000 kg/m³

g represent acceleration due to gravity = 10 m/s².

h represent height

Solving for h (height)

350000 = 0 + (1000 × 10 ×h)

350000 = 10000h

Divide both side by  10000h

h = 350000/10000

h = 35 meters

Therefore the maximum height that the water can rise above the jet is: 35 meters.

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According to the research, research can facilitate the work of building technicians in the conception, materials to use and planning of the project.

They are experts in construction projects, supporting the design of plans, estimating costs, planning work methods, etc.

Research can facilitate the work of building technicians in the following ways:

Therefore, we can conclude that according to the research, research can facilitate the work of building technicians in the conception, materials to use and planning of the project.

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The capacitance is affected is that the capacitance increases because of the insertion of Teflon.

A capacitance is known to be a form of a device that is said to be used to save some measures of charges in any kind of an electrical circuit.

Note that the capacitor functions on the principle that the capacitance of a conductor is said to go up if an earthed conductor is  taken close to it.

Therefore, The capacitance is affected is that the capacitance increases because of the insertion of Teflon and so the teflon tends to widen the capacitance.

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Answer:

Industrial users can select from numerous pump technologies for water supply and the handling of other liquid media. A particular favorite is the centrifugal pump. How do centrifugal pumps work? What different delivery principles are there? For which applications are centrifugal pumps especially well-suited?

Here we provide you an overview of the different types of centrifugal pumps. In addition, the operating principles are explained, and typical applications are listed also.

Explanation:

Answer:

5.118 m^3/hr

Explanation:

Given data:

viscosity of cell broth = 5cP

cake resistance = 1*1011 cm/g

dry basis per volume of filtrate = 20 g/liter

Diameter = 8m ,  Length = 12m

vacuum pressure = 80 kpa

cake formation time = 20 s

cycle time = 60 s

Determine the filtration rate in volumes/hr  expected fir the rotary vacuum filter

attached below is a detailed solution of the question

Hence The filtration rate in volumes/hr expected for the rotary vacuum filter

V' = ( [tex]\frac{60}{20}[/tex] ) * 1706.0670

   = 5118.201 liters  ≈ 5.118 m^3/hr

The combination of temperatures that is expected to give the best result is option A: SCY temperature higher than electrode temp.

The answer is option A because the proton conductivity of SCY is known to be one that often goes up along with increasing temperature, and the favorability of reaction goes down or reduces with total temperature.

Hence, It is said to be good for one to to keep the SCY conductor at a higher temperature and as such, The combination of temperatures that is expected to give the best result is option A: SCY temperature higher than electrode temp.

See options below

. Which combination of temperatures is expected to give the best results?

A.

SCY temperature higher than electrode temperature

B.

SCY temperature lower than electrode temperature

C.

SCY temperature the same as electrode temperature

D.

The temperature of the components does not make a difference.

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Using the formula of comfort condition it is possible to determine the safe operating speed on the highway.

In physics, we define angular deviation as the angle resulting from the deflection of light when reflected from a prism. A prism has the ability to separate white light into several other colors, which are reflected by the object.

The comfort condition formula is given by: [tex]L=2(\frac{NV^{3} }{C} )^{\frac{1}{2} }[/tex]

Where, L is the length of the vertical curve, N is the grade, V is the safe speed operation and assuming the standart value for C (0,6 m/s3) it is possible to calculate:

[tex]C = 0,6 m/s^{3} = 1,968 ft/s^{3}\\ N= N1 - N2 = 7,5-0 = 7,5% = 0,075[/tex]

Changing the values in the formula:

[tex]L=2(\frac{NV^{3} }{C}){\frac{1}{2} } \\300 = 2(\frac{0,075.V^{3} }{1,968})^{\frac{1}{2} } \\V = 83,89 ft/s[/tex]

So, the safe operating speed on the highway is 83,89 ft/s.

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The working principle of a DC machine is when electric current flows through a coil within a magnetic field, and then the magnetic force generates a torque that rotates the dc motor. The DC machines are classified into two types such as DC generator as well as DC motor.

Answer:

acidity, time,oxygen

Explanation:

These are some conditions for the growth of bacteria

Sales represent the income statement item used in verticla analyses in order to determine the cost contribution for each expense category (Option C).

In business, a vertical analysis represents a methodology used to examine financial statements that are ordered as specific points.

A vertical analysis analyzes numbers for only one period, conversely to the horizontal analyses that generally involve many different periods.

In conclusion, sales represent the income statement item used in verticla analyses in order to determine the cost contribution for each expense category (Option C).

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The new slip rings is been  attached to the rotor core during alternator rebuilding by b. Soldered on.

Soldering serves as the way of joining  different types of metals together by melting solder.

This is been used on new slip rings to get it  attached to the rotor core during alternator rebuilding .

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CHECK THE COMPLETE QUESTION BELOW:

How are new slip rings attached to the rotor core during alternator rebuilding?

a. Machine clamped

b. Soldered on

c. Crimped on

d. epoxy glue

An example of a power consuming device would be a(n) light bulb, a computer device while an example of a non-power consuming device would be a(n) switch or button.

The quantity of energy utilized per unit of time is known as power consumption. Power use is a significant factor in digital systems.

Power consumption is a limiting factor for the battery life of portable devices like laptop computers and cell phones.

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Answer:

Camshaft

Explanation:

Based on the positive-going zero crossing at 0° of the sine wave, the instantaneous value at 15° is 7.321V.

At 15°, the instantaneous value is:

= 20√2 x Sin(angle)

Solving gives:

=  20√2 x Sin(15°)

= 7.321V

At angel 33°, the instantaneous value is:

=  20√2 x Sin(angle)

=  20√2 x Sin(33)

= 15.405V

At angle 70°:

=  20√2 x Sin(angle)

=  20√2 x Sin(70)

= 26.579V

The full question is:

A certain sine wave has a positive-going zero crossing at 0° and an rms value of 20 V. Calculate its instantaneous value at each of the following angles: a. 15° b. 33° c. 70°

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Answer: This approach is allocated 32 seconds of effective green time. The cycle length is 100 seconds. Determine the average approach delay (using Eq. 7.27). A) 34.8 s.

The heat transferred to and the work produced by the steam during this process  is 13781.618 kJ/kg

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

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Answer: True

Explanation:

Airtight plugs are installed in the ends of large sizes of PVC conduit before bending to  A. prevent the conduit from collapsing when heated.

Airtight plugs is necessary in the  PVC conduit so as to be able to avoid the collapse of conduit.

In this case, Airtight plugs are installed in the ends of large sizes of PVC conduit before bending to  A. prevent the conduit from collapsing when heated.

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Answer: Increase in minimills

Explanation:

The maximum load that may be applied to a specimen with a cross-sectional area of 130 mm² is; 35535 N

We are told that for an alloy, the yield stress is 345-MPa and the elastic modulus (E) is 103-GPa.

Now, we want to find the maximum load that may be applied to a specimen with a cross-sectional area of 130-mm² without plastic deformation. Thus;

We are given the parameters;

Yield Stress; σ = 345 Mpa = 345 * 10⁶ Pa

Elastic Modulus; E = 103 GPa = 103 * 10⁹ Pa

Cross sectional Area; A = 130 mm² = 103 * 10⁻⁶ m²

Formula for stress without Plastic deformation is;

σ = F_max/Area

where;

σ is stress

F_max is maximum force

Area is Area

Thus making maximum force the subject of the formula gives;

F_max = σ * A

Plugging in the relevant values for stress and area gives us;

F_max = 345 * 10⁶ * 103 * 10⁻⁶

F_max = 35535 N

The maximum load that may be applied to a specimen with a cross-sectional area of 130 mm² is gotten to be 35535 N

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The frequency bands that are used primarily for short-range distances include the following:

GSM is an abbreviation for global system for mobile communication and it can be defined as an open and digital cellular network technology that is designed and developed to be used for the transmission of both mobile voice and data services at the same time.

In Computer technology and networking, the global system for mobile communication (GSM) is typically designed and developed to operates at the following bands of frequencies:

In this context, we can infer and logically deduce that the frequency bands that are used primarily for short-range distances such as PAN, include the following:

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Answer:

on the façade, entrance, and column capitals