What is the transfer of
heat from one object to
another through direct
contact?
Answer:
condiction
Explanation:
conduction is the transfer of heat between substances that are in direct contact with each other.
fertilization of an egg to form a zygote takes place in?
A.urethra
B.uterus
C.cervix
D.fallopain tube
4. PLEASE HELP!! 25 points!!! (((Timed!!)))
The ADG1(ADP glucose pyrophosphorylase 1) is involved in flowering timing in plants. You are interested in developing a DNA probe using partial protein sequence information. Part of the amino acid sequence is Glu-Glu-His-Asp-Val-Leu 1. determine the possible antisense oligo nucleotides possible from this amino acid sequence 2. How many total unique different oligonucleotide would need to be produced to cover all possibilities
Answer:
1) UUC-AUG-AUC-AAG-UAA.
2) 48
Explanation:
1) Determine the possible antisense oligo nucleotides possible from this amino acid sequence
Given that the peptide sequence is = Glu-Glu-His-Asp-Val-Leu 1.
we will use a codon table to show the codons and Anticodons for each of the Amino acids
Amino Acid Codons Anticodons
Glu GAA, GAG UUC, CUC
His CAU, CAC AUG, GUG
Asp GAU, GAC AUC, GUC
Val GUU, GUC, GUA, GUG AAG, GAC, UAC,CAC
Leu UUA, UUG, CUU, CUC, CUA, CUG | UAA, CAA, AAG, GAG,UAG,CAG
From the table above
The possible antisense oligo nucleotide sequence is : UUC-AUG-AUC-AAG-UAA.
2) How many total unique different oligonucleotide would need to be produced to cover all possibilities
A desired peptide sequence requires 16 anticodons
Hence the total unique different oligonucleotide needed to be produced to cover all possibilities = 16 *3 = 48
The ADG1(ADP glucose pyrophosphorylase is involved in flowering timing in plants and a DNA probe is made by using partial protein sequence information. Part of the amino acid sequence is Glu-Glu-His-Asp-Val-Leu.
1. To determine the possible antisense oligonucleotides possible from this amino acid sequence:
Since, for every amino acid, there is a specific codon and anticodons are present so according to the given information, the possible antisense oligonucleotides for Glu-Glu-His-Asp-Val-Leu is UUC-AUG-AUC-AAG-UAA.
2) The total number of unique different oligonucleotides that would need to be produced to cover all possibilities is 48
since the amino acid sequence is Glu-Glu-His-Asp-Val-Leu has 16 anticodons and each anticodon have 3 nucleotides so the possible number of oligonucleotides are :
16×3 = 48.
What are codon and anticodon?A codon is a trinucleotide sequence of RNA that corresponds to a specific amino acid.
An anticodon is a trinucleotide sequence complementary to that of a corresponding codon in a messenger RNA sequence.
Thus, according to codon and anticodon, the possible antisense oligonucleotides for Glu-Glu-His-Asp-Val-Leu is UUC-AUG-AUC-AAG-UAA and a number of unique different oligonucleotides that would need to be produced to cover all possibilities is 48.
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Which is required for a bacterial cell to replicate its DNA?
a. tRNA
b. DNA polymerase
c. Rna stand with an origin of replication
Answer:
c
Explanation:
90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love u
The stage in the mentrual cycle usually lasting from 3to five days when fertilization does not occur.
A.ovulation
B.stimulation
C.menustration
D.reproduction
Explain how and why different parts of a plant are sinks for the translocation of sucrose at different times of the year in a country where there are season, such as Russia
Answer:
The sucrose is transported around the plant in phloem vessels. It needs to be able to reach all cells in the plant so that the sucrose can be converted back into glucose for respiration. The movement of sucrose and other substances like amino acids around a plant is called translocation .
Belowground organs of plants (e.g. roots and rhizomes) are sinks during plant growth since they cannot perform photosynthesis. Some organs are both a source and sink. Leaves are sinks when growing and sources when photosynthesizing
Describe the ecosystem that you live in. What other living creatures do you share it with? 5-8 sentences.
Answer:
i live in Terrestrial ecosystems ( land-based) &, i shared it with frogs,fishes,birds,snakes,insects,turtles....
Explanation:
WRONG ANSWERS ONLY!!! What is coastal runoff and what does it affect
Answer:
The sky.
(Purposely wrong.)
DeShawn wants to conduct a scientific study on how land-clearing in his city may have affected the quality of the water. Which source of information would be most valuable to his research? A. a survey given to the people of the city ten years ago on the possible effects of land-clearing on water B. the opinion of a neighbor who has some knowledge on how to test city water for impurities C. a recent city government report with data regarding how clean the water supply is D. a recent political article stating that the water of the city should be filtered and cleaned Reset Next Question
Answer: i think that the answer is C
Explanation:
The source of the information that should be most valuable to the research should be option C.
What is research?
It means that the development of the new knowledge should be done or there is the usage of the existing knowledge for generating the new conceptsm methods, and understanding. It involved the synthesis and the analysis of last research for resulting the new or the creative outcomes.
So based on this, the option c should be correct.
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Drag each statement into the appropriate bin depending on whether the event occurs in the lumen of the small intestine, in a small intestine epithelial cell, or in a lacteal.
a) Lipase breaks triglycerides down into monoglycerides and fatty acids.
b) Monoglycerides and fatty acids are reassembled to form triglycerides.
c) Chylomicrons are transported in this structure to veins.
d) This structure contains lymph.
e) Chylomicrons leave this structure by exocytosis.
f) Triglycerides are coated with phospholipids, cholesterol, and proteins to form chylomicrons.
Answer:
The correct answer is -
Lumen: a
Epithelial cell: b, e, f
Lacteal: c, d
Explanation:
The given statements are the events that occur in the particular location among the lumen of the small intestine, small intestine epithelial cell, or in a lacteal. the correct events and locations are grouped together:
in the lumen of the small intestine
a. The breakdown of TGA into monoglycerides and fatty acids takes place with the help of lipase.
In a small intestine epithelial cell:
b. Monoglycerides and fatty acids are form triglycerides again.
e. Chylomicrons leave this structure by exocytosis
f. TGAs are coated with proteins, cholesterol and phospholipids, to make chylomicrons.
in a lacteal:
c. Chylomicrons are transported here
d. Lymph is present here.
Explain what would happen if the leaf tissue is kept at high temperature during the process of cell isolation
Answer:
Wilting of leaves occur.
Explanation:
if the leaf tissue is kept at high temperature during the process of cell isolation the leaf will shrink because of loss of all water. Due to high, temperature the stomata will be open and water is removed in order to remove heat from the body. A time comes that all water that is present in the cell will be removed and as a result wilting of leaves occur.
What is homeostasis?
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\text{What is \underline{Homeostasis}?}[/tex]
[tex]\large\text{Homeostasis is the self-processing in the biotic structured which}\\\large\text{tended to perpetuate (maintain) rationally while it is modified}\\\large\text{its conditions that can be prototypical for surviving}[/tex]
[tex]\large\text{Homeostasis has.... }\\\bullet\large\text{ Controllable center(s)}\\\bullet\large\text{ Effectors}\\\bullet\large\text{Variables (aka Homeostasis)}\\\bullet\large\text{ Receptors}[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
[tex]\large\text{Here is what each of your features of homeostasis means}\downarrow[/tex]
A new trait that was never in the gene-pool before is called a
A) Adaptation
B) Mutation
C) Genetic Variation
D) normal
Answer:
B) Mutation
Explanation:
Mutation is a mistake in the Gene's I doesnt mean it's a bad thing or a good thing. It could be both
During transcription, an RNA molecule is formed
a. that is complementary to both strands of DNA.
b. that is complementary to neither strand of DNA.
c. that is double-stranded.
d. inside the nucleus.
Answer:
c. that is double stranded
Is hydrogen an atom or molecule
If the mother's actual genotype is IA i and the father's blood type is IB i, what is the probability of their child having AB blood?
Answer:
1/4
Explanation:
punnett squares!
______refers to the ability to cause change or do work.
A.friction
B.energy
C.gravity
D.distance
Answer:
B
Explanation:
Ive studied rhis before
What percent of energy is transferred from the sun to the level indicated? (3 points)
50 percent
100 percent
90 percent
10 percent
Answer:
It can
be explained with the help of ten percent law which
states that only 10 percent of the total energy available
at any trophic level is passed on the higher trophic level .
Most of the energy is lost as heat or is used in the
process of cellular respiration.
Explanation:
In order for a compound to be considered organic, what 2 elements must the compound contain
Answer:
Organic compounds contain carbon and hydrogen (which may be replaced by other atoms).
A student had medical testing and discovered that her white blood cell count is lower
than normal. Which of her systems are most likely functioning improperly?
A. nervous and immune
O B. circulatory and urinary
O C. circulatory and immune
O D. nervous and respiratory
Answer: b
Explanation: Viral infections that momentarily impair the function of bone marrow are the most common cause of a reduced white blood cell count. Certain defects with impaired bone marrow activity that are present at birth (congenital). Diseases of the bone marrow, such as cancer.
true or false the fertilized ovary develops into a seed
Answer:
true
Explanation:
I've done this it's TRUE
Phenylketonuria (PKU) is a genetic disease caused by the inability to break down the amino acid phenylalanine. If untreated it leads to severe mental disabilities. PKU is due to a recessive allele. Assume that the US population is in Hardy-Weinberg equilibrium with respect to this gene. In the US the PKU rate is 1 out of every 10,000 babies born. What percent of the US population have no alleles for PKU
Answer:
Therefore, 98% of the US population have no alleles for PKU
Explanation:
The Hardy-Weinberg equilibrium states that the amount of genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.
The Hardy-Weinberg equilibrium is expressed quantitatively using a mathematical equation known as the Hardy-Weinberg equation. the equation is given below:
p² + 2pq + q² = 1
also, p + q = 1
Given a pair of alleles, S and s with A dominant and a recessive
where p is the frequency of the dominant allele in the population,
q is the frequency of the recessive allele in the population,
p² represents the frequency of the (SS) dominant genotype,
q² represents the frequency of the (ss) recessive genotype,
2pq represents the frequency of the heterozygous genotype
From the given question,
q² = 1/10000 = 0.0001
q = 0.01
from p + q = 1
p = 1 - 0.01 = 0.99
p² = 0.98
Therefore, 98% of the US population have no alleles for PKU
the green colour pigment present in leaves chlorophyll true or false
Answer:
True
Explanation:
Chlorophyll produces a green pigment, which is why leaves look green
Answer:
true the green stuff is chlorophyll
Explanation:
If you wanted to look at a cell wall.Which type of cell would you observe?
Answer:
Plant cell
Explanation:
If you are trying to observe a cell wall, you should look at a plant cell. There are only two different types of cells, which are plant and animal cells. The plant cell is the only one which contains a cell wall. Animal cells actually only have a cell membrane.
The process of mitosis deals with?
Will mark brainliest
Answer: Gametes
Explanation:
Answer:
Gametes
Explanation:
When a cell divides by way of mitosis, it produces two clones of itself, each with the same number of chromosomes. When a cell divides by way of meiosis, it produces four cells, called gametes.
With the above paragraph one can conclude that mitosis deals with gametes.
Polymerase Chain Reaction (PCR) technology is used for
a. DNA identification
b. DNA repair
c. DNA amplification
d. DNA cleavage
Answer:
The correct answer is c.
Explanation:
Polymerase Chain Reaction (PCR) technology is an in vitro enzymatic method that allows the amplification of a specific DNA sequence, that is, it is the DNA amplification technique by means of the polymerase chain reaction (PCR) is a technique that consists of the in vitro amplification of a specific DNA fragment. To carry out the amplification experiment, it is necessary to know, at least partially, the sequence of the fragment to be amplified (a gene, a part of a gene, a non-coding region, ...). Basically, it is about replicating the same DNA fragment over and over again and, for this, we must do in vitro what cells do in vivo to replicate their DNA. Generally, PCR begins with the denaturation or separation of the DNA double helix by heating the sample to a temperature between 94 and 96 ° C to break the hydrogen bonds that joined them, in this way each chain remains as a template for the synthesis of a new complementary strand of DNA.
The first stage of the cell cycle during which the cell matures and prepares to divide and copies
its DNA; The stage the cell stays in the most?
The cell multiplies and creates a copy of its DNA during interphase. In the mitotic (M) phase, the cell divides into two new cells by dividing its cytoplasm and DNA into two sets.
What is the main role of interphase stage of cell cycle?A cell consumes the bulk of its time in what is known as interphase, where it creates, duplicates its chromosomes, and acquires available to split. The cell then moves interphase, goes direct mitosis, and completes dividing.
The cell multiplies and the nuclear DNA is duplicated during interphase. The mitotic phase immediately follows interphase.
Chromosomes that have been duplicated are separated and distributed across daughter nuclei during the mitotic phase. Usually, the cytoplasm is divided as well, producing two daughter cells.
Therefore, The first stage and the stage the cell stays in most is Interphase.
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Please help me.!!!
Lol you’ll get 100 points
Answer:
Arteries carry blood away from the heart and veins carry blood back to the heart. The circulatory system carries oxygen, nutrients, and hormones to cells, and removes waste products, like carbon dioxide. These roadways travel in one direction only, to keep things going where they should.
Explanation: dont be men to me i have autism and savant syndrom
a = lil b = p c = a d = pi add it up lil papi
Explanation:
The stems of bamboo, a tropical grass, can grow at the phenomenal rate of 0.3 m/day under optimal conditions. Given that the stems are composed almost entirely of cellulose fibers oriented in the direction of growth, calculate the number of sugar residues per second that must be added enzymatically to growing cellulose chains to account for the growth rate. Each D-glucose unit contributes ~0.5 nm to the length of a cellulose molecule.
Answer:
Approximately 6944 glucose residues are added enzymatically per second
Explanation:
Cellulose is the main structural polysaccharides in plants. It is composed of unbranched glucose monomer units linked to each other by beta 1-4 glycosidic bonds.
The cell wall and stem of plants cells are composed of cellulose fibers. They provide rigidity and support to the plant.
In the given bamboo plant, the enzymatic addition of glucose units to the growing cellulose fiber chains results in the phenomenal growth rate of the bamboo stem.
Since each glucose unit contributes ~0.5 nm to the length of a cellulose molecule, number of glucose units required for daily growth is calculated as follows:
0.5 nm = 10⁻⁹
0.3 m/0.5 x 10⁻⁹ m = 600000000 units of glucose per day
Number of seconds in a day = 24 * 60 * 60 = 86400 seconds
Number of glucose residues added per second = 600000000/86400
Number of glucose residues added per second = 6944.4 glucose molecules per second
Therefore, approximately 6944 glucose residues are added per second