List the prices for the first 8 carwashes of each package below.

Answers

Answer 1

Answer:

you might have to post a pic of the question


Related Questions

if m x and l m = 6 and l = 2 find the value of l when m = 15​

Answers

Answer:

5

Step-by-step explanation:

6 / 2 = 15 / l

3 = 15 / l

l = 15 / 3

l = 5

given the function R(x)= x+5/x-5 find the value of x that make the function greater then or equal to zero. write the solution in interval notation​

Answers

Answer:

Step-by-step explanation:

Hello,

First of all, let s take x real number different from 5, as we cannot divide by 0

[tex]\dfrac{x+5}{x-5}\geq 0 \\ \\<=> (x+5\geq 0 \ and \ x-5> 0) \ or \ (x+5\leq 0 \ and \ x-5< 0) \\ \\<=> (x\geq -5 \ and \ x> 5) \ or \ (x\leq -5 \ and \ x< 5)\\ \\<=> x> 5 \ or \ x\leq -5[/tex]

So the solution is

[tex]\Large \boxed{\sf \bf ]-\infty;-5]\cup]5;+\infty[}[/tex]

Thanks

Answer:

(−∞,−5]∪(5,∞)

What is the first step in solving In(x - 1) = In6 - Inx for x?

Answers

Answer:

x=3

Step-by-step explanation:

In(x-1) = In(6) - In(x)

In(x-1) + In(x) = In(6)

In((x-1)x) = In(6)

In(x^2-x) = In(6)

x^2-x=6

x^2-x-6=0

x^2+2x-3x-6=0

x(x+2)-3(x+2)=0

(x-3)(x+2)=0

x=3 because x=-2 need to be cancel out

$641.29 is what percent of $986,60?

I need this ASAP

Answers

Answer:

65%

Step-by-step explanation:

You start by dividing 641.29 by 986.60 (641.29/986.60). This gets you .65, which as a percentage is 65%

65% use a website for calculating percentages

HELP! Should be easy for people who have taken the class.

Answers

Answer:

See below

Step-by-step explanation:

Definitions are:

1. Straight line2. Transitive 3. Subtraction 4. ∠1 ≅ ∠3

Find the value of x?

Answers

Answer:

x=25

All triangles must equal 180

95+35=130

P = 0.5e - 5 to determine P

Answers

Answer:

Let's solve your equation step-by-step.

p=(0.5)(2.718282)−5

Step 1: Simplify both sides of the equation.

p=(0.5)(2.718282)−5

p=1.359141+−5

p=(1.359141+−5)(Combine Like Terms)

p=−3.640859

p=−3.640859

Answer:

p=−3.640859

Step-by-step explanation:

From a group of six people, two individuals are to be selected at random. How many selections are possible?

Answers

Answer:

15

Step-by-step explanation:

15 is the answer....

Which number is divisible by both 3 and 9?
OA) 21,369
OB) 27.621
OC) 27,629
OD) 36,663

Answers

It’s c you should see if others got it too tho.

Answer: A) 21,369

Step-by-step explanation: since 21,369 can be divided by 3 and = a whole number then it's divisible and also it's divided without a remainder / it's compatible so, 21,369/3= 7,123 which makes (A) your correct answer

Solve the following compound inequality: 4x + 8 15

Answers

Answer:

4x - 8 = 15

4x = 15 + 8

4x = 23 (divide both sides by 4 to get x)

4x/4 = 23/4

x = 5.75

Step-by-step explanation:

x = 5.75!!!!!

This trapezoid represents the base of a right prism that has a surface area of 1280 square feet. The sum of the lengths of the legs of the trapezoid is 52 feet. What is the height of the prism? Enter your answer in the box.



PLEASE HELP I WILL GIV BRAINLY. 50 POINTS.​

Answers

Answer:

6

Step-by-step explanation:

i took the test

The height of the prism is 49.2 feet

How to determine the height?

The given parameters are:

Area = 1280 square feetThe sum of the length legs = 52 feet

The area of the trapezoid is:

Area = 0.5 * (Sum of opposite sides) * Height

So, we have:

1280 = 0.5 * 52 * Height

This gives

1280 = 26 * Height

Divide both sides by 26

Height = 49.2

Hence, the height of the prism is 49.2 feet

Read more about trapezoids at:

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A baker makes apple tarts and apple pies each day. Each tart, t, requires 1 apple, and each pie, p, requires 8 apples. The baker receives a shipment of 184 apples every day. If the baker makes no more than 40 tarts per day, which system of inequalities can be used to find the possible number of pies and tarts the baker can make?

Answers

Answer: t<40

8p+<184

Step-by-step explanation:

The inequalities representing the given condition will be [tex]t\leq40[/tex] and [tex]8p+t\leq184[/tex].

Given information:

A baker makes apple tarts and apple pies each day.

The baker receives a shipment of 184 apples every day.

A tart requires 1 apple and a pie requires 8 apples.

Let t be the number of tarts made each day and p be the number of pies made each day.

The baker makes no more than 40 tarts per day. So, the condition can be written as,

[tex]t\leq40[/tex]

And the condition for each day apple delivery can be written as,

[tex]8p+t\leq184[/tex]

Therefore, the inequalities representing the given condition will be [tex]t\leq40[/tex] and [tex]8p+t\leq184[/tex].

For more details, refer to the link:

https://brainly.com/question/19491153

Find the value of xx, yy, and zz in the parallelogram below.

Answers

Answer:

Step-by-step explanation:

Opposite sides of a parallelogram are congruent, so:

[tex]8x+3=19 \longrightarrow x=2[/tex]

[tex]27=-y-5 \longrightarrow y=-32[/tex]

I took a picture bc I don’t feel like typing the question

Answers

I really can’t see the picture I’m so sorry but I can’t help

Hope this helps!!

The radii of two similar cones are 27:125. What is the ratio of their areas?

Answers

Answer:

729 : 15,625

Step-by-step explanation:

the ratio of their areas is 27² : 125² = 729 : 15,625

Solve the equation. Check your solution using substitution.

{45.28 = 19.83 + z}


Group of answer choices

z=25.45

z=65.11

z=897.9

z=2.28

Answers

Answer:

z=25.45

because {45.28=19.83+25.45}

{45.28=45.28}

50 POINTS PLUS BRANLEST ANSWER!!!!!!!!!!

Complete the table by writing the two missing forms of the number. Make sure your fractions are reduced to lowest terms.

Answers

Answer: Look at picture

Answer:

a.) 0,51

b.) 51%

c.) 1/100

d.) 1%

e.) 3/20

f.) 0,15

Step-by-step explanation:

[tex]a.) \: \frac{51}{100} = 51 \div 100 = 0.51[/tex]

[tex]b.) \: \frac{51}{100} = 51\%[/tex]

[tex]c.) \: 0.01 = \frac{1}{100} [/tex]

[tex]d. )\: 0.01 = \frac{1}{100} = 1\%[/tex]

[tex]e.) \: 15\% = \frac{15}{100} = \frac{3}{20} [/tex]

[tex]f.) \: 15\% = \frac{15}{100} = 0.15[/tex]

Detail :

===============================

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Ethan is packing bags with treats for a party. He wants every bag to have exactly the same treats in it. Ethan had 96 granola bars and 64 lollipops. If he wants to make the most number of bags possible, how many bags can he make?

Answers

Answer:

32 Bags.

Step-by-step explanation:

Please solve with explanation (10 points)

Answers

Answer:

Question (a)

[tex]x^2-a^2-bx-ab=0[/tex]

Write in standard form [tex]ax^2+bx+c=0[/tex]:

[tex]\implies x^2-bx-(a^2+ab)=0[/tex]

Therefore,

[tex]a=1[/tex][tex]b=-b[/tex][tex]c=-(a^2+ab)[/tex]

Using quadratic formula:

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\implies x=\dfrac{b\pm\sqrt{(-b)^2+4(1)(a^2+ab)} }{2(1)}[/tex]

[tex]\implies x=\dfrac{b\pm\sqrt{b^2+4a^2+4ab} }{2}[/tex]

[tex]\implies x=\dfrac{b\pm\sqrt{(b+2a)^2} }{2}[/tex]

[tex]\implies x=\dfrac{b \pm (b+2a)} {2}[/tex]

[tex]\implies x=\dfrac{2b+2a} {2}=b+a[/tex]

[tex]\implies x=\dfrac{-2a} {2}=-a[/tex]

Question (b)

[tex]6x^2-15ax=2bx-5ab[/tex]

Write in standard form  [tex]ax^2+bx+c=0[/tex]:

[tex]\implies 6x^2-15ax-2bx+5ab=0[/tex]

[tex]\implies 6x^2-(15a+2b)x+5ab=0[/tex]

Therefore,

[tex]a=6[/tex][tex]b=-(15a+2b)[/tex][tex]c=5ab[/tex]

Using quadratic formula:

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{(-15a-2b)^2-4(6)(5ab)} }{2(6)}[/tex]

[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{225a^2+60ab+4b^2-120ab} }{12}[/tex]

[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{225a^2-60ab+4b^2} }{12}[/tex]

[tex]\implies x=\dfrac{(15a+2b)\pm\sqrt{(15a-2b)^2} }{12}[/tex]

[tex]\implies x=\dfrac{(15a+2b) \pm (15a-2b) }{12}[/tex]

[tex]\implies x=\dfrac{30a }{12}=\dfrac52a[/tex]

[tex]\implies x=\dfrac{4b}{12}=\dfrac13b[/tex]

Question (c)

[tex]\dfrac{x^2}{x-1}=\dfrac{a^2}{2a-4}[/tex]

Cross multiply:

[tex]x^2(2a-4)=a^2(x-1)[/tex]

Write in standard form  [tex]ax^2+bx+c=0[/tex]:

[tex](2a-4)x^2-a^2x+a^2=0[/tex]

Therefore,

[tex]a=(2a-4)[/tex][tex]b=-a^2[/tex][tex]c=a^2[/tex]

Using quadratic formula:

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\implies x=\dfrac{a^2\pm\sqrt{(-a^2)^2-4(2a-4)(a^2)} }{2(2a-4)}[/tex]

[tex]\implies x=\dfrac{a^2\pm\sqrt{a^4-8a^3+16a^2} }{4a-8}[/tex]

[tex]\implies x=\dfrac{a^2\pm\sqrt{a^2(a-4)^2} }{4a-8}[/tex]

[tex]\implies x=\dfrac{a^2\pm a(a-4)}{4a-8}[/tex]

[tex]\implies x=\dfrac{a^2\pm (a^2-4a)}{4a-8}[/tex]

[tex]\implies x=\dfrac{2a^2-4a}{4a-8}=\dfrac{2a(a-2)}{4(a-2)}=\dfrac12a \ \ \ (a\neq 2)[/tex]

[tex]\implies x=\dfrac{4a}{4a-8}=\dfrac{a}{a-2} \ \ \ \ (a\neq 2)[/tex]

thanks again everyone ​

Answers

Answer:

4x^3

Step-by-step explanation:

GCF is the Greatest Common Factor

12x^6 + 4x^4 + 28x^3

= 4x^3(3x^3 + x + 7)

GCF is 4x^3

Trevor folded a corner of a rectangular piece of paper to form a pentagon, as shown below. What is the area of the shaded pentagon? A. 84.5 square inches B. 75.5 square inches c. 39.5 square inches D. 35 square inches.
PLEASE HELP I WILL GIVE BRAINLIEST.

Answers

Answer:

B. 75.5 square inches

Step-by-step explanation:

Area (pentagon) = Area (rectangle) - Area (triangle)

= length x width - 1/2 x breadth x height

= 10 x 8 - 1/2 x 3 x 3

= 80 - 4.5

= 75.5 square inches

Solution :-

B. 75.5 square inches

Answer:

B) 75.5 in²

Step-by-step explanation:

Area of rectangle = width × length

⇒ area of rectangle = 8 × 10 = 80 in²

Area of triangle = 1/2 × base × height

⇒ area of triangle = 1/2 × 3 × 3 = 4.5 in²

Area of pentagon = area of rectangle - area of triangle

                              = 80 - 4.5

                             = 75.5 in²


Which scale of measurement most reasonably applies to Confidence in Education?

Answers

Answer:

I guess how many times out of x they will do something.

for example how many times out of 10 will bob ask out his crush vs Joe

Step-by-step explanation:

There isn't really an easy way to measure this.

The scale of measurement most reasonably applies to Confidence in Education would be the Ordinal scale.

What is the scale of measurement?

The scale of measurement deals with how the variables are defined and categorized.

There are 4 types of scales of measurement;

1. Nominal scale

2. Ordinal scale

3. Interval scale

4. Ratio scale

We know that the Ordinale scale is used for variables in ranked order but the difference between them could not be determined.

Hence, The scale of measurement most reasonably applies to Confidence in Education would be the Ordinal scale.

Learn more about scales;

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Please help! Will award BRAINLIEST if you complete it correctly!
Jen was making cake pops for the bake sale. After 3 hours, she had completed half of the work. She called Maryna for help and together they finished everything in half an hour. How long would it take Maryna to finish the job alone if she replaced Jen after Jen baked for 3 hours?

Answers

Answer:

3 hours

Step-by-step explanation:

as jen took 3 hours maryana will take equal amount of time as jen

Well, we already know that it took Jen, 3 hours, by herself to complete half the work. Then, together they both completed it in half an hour. Now, you must summarize your given data.

3 hours = Half of the work for Jen

30 Minutes = Jen and Maryna Together To Finish

If the two girls were working at the same pace, it would take them an hour and a half. However, it only took them 30 minutes to complete that. Now, we realize that Maryna works 3x faster than Jen does.

The question is asking, how long would it take her to FINISH the job.

So that means, we must divide 3 by Jen's time.

3 / 3 = 1

So, that means that it would only take Maryna 1 hour to complete the rest of the job.

What is the equation in slope intercept form of a line that is perpendicular to y = 1/4x - 1 and passing through the point (4, 1)?

1. y = 4x + 17
2. y = 4x - 1
3. y = 4x + 17
4. y = 1/4x + 17

Answers

It would be 4. You can do 2 of the following. Do process of elimination or solve it. If you were to do process of elimination, then you would find out that 4 would be the only possible answer since 1/4x is the only slope that there is.

How many lateral faces does a triangular pyramid have?

one

two

three

four​

Answers

Answer:

three

Step-by-step explanation:

The lateral faces are any faces besides the base.

In summary, we will count how many sides there are in a triangular pyramid, and subtract one for the base.

-> A triangular pyramid has four sides / faces

-> A triangular pyramid has three lateral faces

Answer: 3

Step-by-step explanation: i did the quiz

Blue priced $25.00. How much would they cost if they were 60% off?

Answers

Answer:

10

Step-by-step explanation:

25 times .60 then take that answer and subtract it from 25 or half of 25 which it 12.5 then take off another 10%

What are the coordinates of your new IMAGE A’B’C’?

A’=____
B’=____
C’=____

Answers

Answer:

Sensor Calibration

Convert between coordinate systems of every sensor, image, vehicle and global coordinate axis system. So data from a sensor can be mapped globally.

Calibration of a camera helps to convert a pixel in an image to

Computer Vision

Step-by-step explanation:

please help me asap​

Answers

Answer:

The second option: Waxing crescent - first quarter; Waning gibbous - third quarter

Jennifer has a total of $50 to spend on a new outfit. She bought a sweater for $20. Which shows the part of her total Jennifer spent on the sweater?

A. 1/2
B. 0.4
C. 30%
D. 2/10

Answers

Answer: B 0.4

Step-by-step explanation:

50-20=30

0.4 is 40%

40% of 50 is 20

Let f(x)=[tex]\footnotesize \rm \lim_{n \to \infty } \left \lgroup \frac{ {n}^n(x + n) \bigg( x + \dfrac{n}{ 2} \bigg) \dots \bigg(x + \dfrac{n}{n} \bigg)}{n!( {x}^{2} + {n}^{2}) \bigg( {x}^{2} + \dfrac{ {n}^2 }{4} \bigg) \dots \bigg( {x}^{2} + \dfrac{ {n}^{2} }{ {n}^{2} } \bigg) } \right \rgroup^{ \dfrac{x}{n} } \\ [/tex] , for all x > 0. Then

[tex]\rm(A) \: f \bigg( \dfrac{1}{2} \bigg ) \geq f(1)[/tex]

[tex]\rm(B) \: f \bigg ( \dfrac{1}{3} \bigg) \leq f \bigg ( \dfrac{2}{3} \bigg)[/tex]

[tex]\rm(C) \: f'(2) \leq0[/tex]

[tex] \rm(D) \: \frac{f'(3)}{f(3)} \geq \frac{f'(2)}{f(2)} \\ [/tex]​

Answers

Use the old exp-log trick and properties of the logarithm to rewrite the limit as

[tex]\displaystyle \lim_{n\to\infty} \left(\frac{n^n \left(x+\frac n1\right) \left(x+\frac n2\right) \cdots \left(x+\frac nn\right)}{n! \left(x^2+\left(\frac n1\right)^2\right) \left(x^2+\left(\frac n2\right)^2\right) \cdots \left(x^2+\left(\frac nn\right)^2\right)}\right)^{\frac xn}[/tex]

[tex]\displaystyle = \exp\left[\lim_{n\to\infty} \frac xn \ln \left(\frac{n^n \left(x+\frac n1\right) \left(x+\frac n2\right) \cdots \left(x+\frac nn\right)}{n! \left(x^2+\left(\frac n1\right)^2\right) \left(x^2+\left(\frac n2\right)^2\right) \cdots \left(x^2+\left(\frac nn\right)^2\right)}\right)\right][/tex]

[tex]\displaystyle = \exp\left[x \lim_{n\to\infty}\frac1n\ln\left(\frac{n^n}{n!}\right) + \frac1n \sum_{k=1}^n \ln\left(x+\frac nk\right) - \frac1n \sum_{k=1}^n \ln\left(x^2+\left(\frac nk\right)^2\right)\right][/tex]

[tex]\displaystyle = \exp\left[x \lim_{n\to\infty}\frac1n\ln\left(\frac{n^n}{n!}\right) + \frac1n \sum_{k=1}^n \ln\left(x+\frac1{k/n}\right) - \frac1n \sum_{k=1}^n \ln\left(x^2+\frac1{\left(k/n\right)^2}\right)\right][/tex]

The first limit converges to 0, since n! asymptotically behaves like nⁿ, so ln(nⁿ/n!) → ln(1) = 0.

The two remaining sums converge to definite integrals:

[tex]\displaystyle \lim_{n\to\infty} \frac1n \sum_{k=1}^n \ln\left(x + \frac1{\frac kn}\right) = \int_0^1 \ln\left(x + \frac1y\right) \, dy = \frac{(x+1) \ln(x+1)}x[/tex]

[tex]\displaystyle \lim_{n\to\infty} \frac1n \sum_{k=1}^n \ln\left(x^2 + \left(\frac1{\frac kn}\right)^2\right) = \int_0^1 \ln\left(x^2 + \frac1{y^2}\right) \, dy = \frac{2\tan^{-1}(\sqrt x)}{\sqrt x} + \ln(1+x)[/tex]

It follows that

[tex]f(x) = \exp\left[x\left(0 + \dfrac{(x+1)\ln(x+1)}x - \dfrac{2\tan^{-1}(\sqrt x)}{\sqrt x} - \ln(x+1)\right)\right][/tex]

[tex]f(x) = \exp\left[\ln(x+1) - 2\sqrt x \tan^{-1}(\sqrt x)\right][/tex]

[tex]f(x) = (x+1) e^{-2\sqrt x \tan^{-1}(\sqrt x)}[/tex]

By computing f'(x) and f''(x), it's easy to show that f'(x) ≤ 0 and f''(x) ≥ 0 for all x > 0. So f(x) is decreasing and f'(x) is increasing, and

• (A) f(1/2) ≥ f(1) is true

• (B) f(1/3) ≤ f(2/3) is false

• (C) f'(2) ≤ 0 is true

• (D) f'(3)/f(3) ≥ f'(2)/f(2)   ⟺   f'(3)/f'(2) ≥ f(3)/f(2)   ⟺   (something larger than 1) ≥ (something smaller than 1) is true

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