Answer:
max{x²-4x²+5} = 5 at x = 0
Step-by-step explanation:
1. Find the critical numbers by finding the first derivative of f(x), set it to 0 and solve for x.
[tex]f'(x)=0[/tex]
We get:
[tex]f(x) = -3x^2+5\\f'(x) = -6x\\-6x = 0\\x = 0[/tex]
So the critical number is x = 0.
2. Evaluate the first derivative by plugging in the critical number and see if the derivative is positive or negative on both sides:
[tex]f'(x)[/tex] is positive when the x < 0 (for example: -6*(-1)=+)
[tex]f'(x)[/tex] is negative when the x > 0 (for example: -6*(1)=-)
Therefore, you have a local maximum.
Now just get the Y value by plugging in the critical number in the original function. [tex]f(0)=5[/tex]
local maximum is (0,5)
Solve the following system by graphing and identify the point of intersection -5x+2y=-4 2x-y=2
Answer: Point of intersection (0, -2)
Step-by-step explanation:
Answer:
S = (0, -2)
Step-by-step explanation:
Convert both standard form equations to slope-intercept form.
-5x+2y=-4 ⇒ y = 5/2(Decimal form: 2.5)x - 2
2x-y=2 ⇒ y = 2x - 2
Given:
⇒ L1 = y = 5/2x - 2
⇒ L2 = y = 2x - 2
The intersection is point:
⇒ S = (0, -2)
Steps:
To find intersection point we need to solve the following system of equations.
y = 5/2x - 2y = 2x-2STEP 1: Solve for x
5/2x - 2 = 2x - 2
5/2x - 2x = -2 + 2
1/2x = 0
x = 0
STEP 2: Solve for y by substituting x = 0 into first equation.
y = 5/2 * 0 - 2 = 0 - 2 = -2
An employee at a fireworks company is designing a rocket. The rocket will consist of a cardboard circular cylinder with a height that is seven times as large as the radius. On top of the cylinder will be a cone with a height of 5 in. and a radius equal to the radius of the base as shown in the figure. If the company wants to fill the cone and the cylinder with a total of 204 in.^3 of powder, then what should be the radius of the cylinder? Note that the volume of a right circular cylinder with radius r and height h is and the volume of a cone with a base of radius r and height h is .
The radius of the cylinder should be approximately 2.040 inches long.
How to calculate the radius of a rocket to contain a required quantity of powder
The volume required to store the powder is the sum of the volumes of the cylinder and the cone, whose expression is in this case:
204 in³ = (π/3) · r² · (4 in) + π · r² · h
204 in³ = (4/3 + h) · π · r²
204 in³ = (4/3 + 7 · r) · π · r²
204 = (4π/3) · r² + 7π · r³
7π · r³ + (4π/3) · r² - 204 = 0
The positive roots of the cubic equation are:
r ≈ 2.040 in
The radius of the cylinder should be approximately 2.040 inches long.
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30 POINTS!,!!!!!!!!!!!!
A packaging factory is open from Monday to Saturday. In a particular week, 15,000 packets were packed on Monday and the factory was also closed on Tuesday. If no less than 100,000 packets should be packed in that week, what is the minimum equal number of packets that must be packed per day for the remaining days?
Answer:
A minimum of 21250 packets per day.
Step-by-step explanation:
If Monday produced 15,000 packets, and Tuesday was closed they produced 15,000 packets in 2 days.
The factory is open 6 days a week.
They need 100,000 packets.
They have 15,000 packets.
6 subtract 2 is 4.
100,000 subtract 15,000 is 85,000.
They need 85,000 packets in 4 days.
That is a minimum of 21250 packets per day.
Find the missing side of the triangle.
pythagorean 4
A. 337‾‾‾‾√ km
B. 5‾√ km
C. 193‾‾‾‾√ km
D. 112‾√ km
Applying the Pythagorean theorem, the missing side of the triangle is: C. √193 km.
How to Apply the Pythagorean Theorem?To find the missing side (x) in the right triangle, based on the Pythagorean theorem, we would have the following equation:
x = √(12² + 7²)
x = √(144 + 49)
x = √193
The missing side of the triangle is: C. √193 km
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Answer:
C.) 193√ km
Step-by-step explanation:
I got it right on founders edtell
Explain the difference between using the trigonometric ratios (sin, cos, tan) to solve for a
missing angle in a right triangle versus using the reciprocal ratios (sec, csc, cot). You must
use complete sentences and any evidence needed (such as an example) to prove your
point of view. (10 points)
Answer:
ok
this called f to do
Step-by-step explanation:
1. take a _____
find the equation of the tangent line at the given point on the following curve.
x^2+y^2=8, (-2,-2)
Using derivatives, the equation of the tangent line is: y + 2= -(x + 2)
What is the equation to the tangent line of a function f(x) at point (x0, y0)?The equation is:
[tex]y - y_0 = m(x - x_0)[/tex]
In which m is the derivative at point [tex](x_0, y_0)[/tex].
The function is:
[tex]x^2 + y^2 = 8[/tex].
Applying implicit differentiation, the derivative is:
[tex]2x\frac{dx}{dx} + 2y\frac{dy}{dx} = 0[/tex]
[tex]2ym = -2x[/tex]
[tex]m = -\frac{x}{y}[/tex]
We have that x = y = -2, hence m = -1 and the equation is:
y + 2= -(x + 2)
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What are the coordinates of the point p if the coordinates of the other three vertices of the rectangle in the figure shown to the right are (3,7),(3,9) and (6,9)
Considering the given rectangle, the coordinates of p are (6,7).
What are the coordinates of p?For x, there are two vertices at x = 3 and one at x = 6, hence the x-coordinate of p is x = 6.
For y, there are two vertices at y = 9 and one at y = 7, hence the y-coordinate of p is y = 7.
Then, the coordinates of p are (6,7).
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What is the radian measure of central angle AOB in the circles? Write down the answer in the lowest terms
5pi/12 radians
The arc measure is 75, so theta must also be the same. if theta is 75, and 75 in radians is 5pi/12 radians, then the answer is that.
round 14.81 to the nearest tenth
Answer: 14.8
Step-by-step explanation: If the number in the hundredths place is less than 5, you must round down. On the contrary, if that number is 5 or greater, you must round up. This applies for rounding to any place not just the tenths place. For example, if you were to round it to the ones place, the answer would be 15.
Answer:
14.8
Step-by-step explanation:
The hundredth is smaller than 5, therefore you have to round down.
hope it helps
Chad used the table to show the ratios of the different types of sports game cards that he owns. For every 2 offense cards, he owns 4 defense cards. Which graph represents the proportional relationship between his defense and offense cards?
Chad’s Sports Cards
Card Type
Kicking Team
Offense
Special Teams
Defense
Quantity
1
2
3
4
The equation that shows the proportional relationship between his defense and offense cards is y = 2x
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let y represent the defense cards and x represent the offense cards.
For every 2 offense cards, he owns 4 defense cards. Hence:
4 = 2m
m = 2
y = 2x
The equation that shows the proportional relationship between his defense and offense cards is y = 2x
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Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?
(–∞, –3)
(–∞, 3)
(–3, ∞)
(3, ∞)
Using translation concepts, it is found that g(x) is positive on the following interval:
(3, ∞)
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
Function [tex]g(x) = \sqrt[3]{x - 3}[/tex] is a shift right of 3 units of [tex]f(x) = \sqrt[3]{x}[/tex], which is positive on the interval (0, ∞), hence g(x) is positive on the interval (3, ∞).
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Evaluate the limit, lim x -> 0 (x * cos theta - theta * cos x)/(x - theta)
The limit of
[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)=1$$[/tex].
What are limits?In Mathematics, a limit exists described as a value that a function approaches the output for the provided input values. Limits exist necessary in calculus and mathematical analysis and exist utilized to determine integrals, derivatives, and continuity.
Given:
[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)$$[/tex]
Substitute the value x = 0, then we get
[tex]$=\frac{0 \cdot \cos (\theta)-\theta \cos (0)}{0-\theta}$$[/tex]
Simplify the above equation, we get
[tex]$\frac{0 \cdot \cos (\theta)-\theta \cos (0)}{0-\theta}= 1$[/tex]
Therefore, the limit of
[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)=1$$[/tex]
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Identify the vertices of the feasible region for the given linear programming constraints.
System of Linear Programming:
z=−3x+5y
x+y≥−20
x−2y≥−2
x−y≤2
Fill in the vertices of the feasible region:
(−14, )
( ,−11)
(6, )
The vertices of the feasible region are as follows,
(-14, -11), (9, -11) and (6, 4)
What is a Feasible Region?
The area of the graph where all constraints are satisfied is the feasible solution zone or feasible region. It might also be thought of as the point where each constraint line's valid regions intersect. Any decision in this region would lead to a workable resolution for our objective function.
Vertices of the Feasible Region
As it can be seen in the graph, the vertices of the feasible region surrounded by the given constraints are:
(-14, -11), (9, -11) and (6, 4)
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La siguiente figura 1, ilustra el salto de una rana sobrepuesto en un plano cartesiano. La longitud del salto es de 9 ft y la altura máxima con respecto al suelo es 3 ft. Encuentra la ecuación estándar a fin de calcular la trayectoria de la rana.
3. La salinidad de los océanos se refiere a la cantidad de material disuelto que se encuentra en una muestra de agua marina. La salinidad S se puede calcular a partir de la cantidad C de cloro en agua de mar con la ecuación S = 0.03 + 1.805 C, donde S y C se miden por peso en partes por millar. Calcula la C si S es 0.35.
4. El arco de un puente es semielíptico, con eje mayor horizontal. La base del arco mide 50 ft de un lado al otro y la parte más alta del arco mide 15 ft arriba de la calzada horizontal. Encuentre la altura del arco a 12 ft del centro de la base.
Investiga la hipérbola con centro en el origen y fuera del origen. Eje focal en x y en y.
2. De las expresiones que se indican a continuación, Identifica si es una recta o ecuación lineal,
una ecuación cuadrática o de segundo grado, una ecuación de tercer grado, una
circunferencia, una hipérbola, justifica tu respuesta y elabora su respectiva gráfica.
3x – 2y + 4= 0
4x + y2 -7 = 0
x2 + y2 = 16
y = x3 - 3x +1
x2 + 4y2 = 4
3. A partir de tu investigación resuelve los siguientes ejercicios:
a) Traza la gráfica
9x2 – 4 y2 = 36
Encuentra los focos y ecuaciones de las asíntotas.
b) Traza la gráfica
4y2 – 2 x2 = 1
Encuentra los focos y ecuaciones de las asíntotas.
c) Dadas las siguientes ecuaciones, decir qué cónica representan:
9 x2 - 4 y2 - 54 x - 16 y + 29 = 0
4 x2 + 2 y2 - 7 x + y - 5 = 0
x2 - 6 x + 5 y - 11 = 0
Debido a restricciones de longitud invitamos cordialmente a leer la explicación de esta pregunta para aprender sobre las cuestiones de las ecuaciones cónicas.
¿Cómo analizar y aplicar las ecuaciones cónicas?
Según la geometría analítica, existen cinco tipos de secciones cónicas: recta, circunferencia, elipse, parábola e hipérbola. Aquí se presentan problemas que emplean este tipo de ecuaciones.
1) La trayectoria de la rana describe la forma de una parábola. Asumimos que el punto máximo de la trayectoria de la rana es de la forma (h, k) = (0, k), entonces tenemos que la ecuación de la parábola es:
y - k = C · x² (1)
Donde C es la constante del vértice.
Si sabemos que (h, k) = (0, 3) y (x, y) = (9, 0), entonces la ecuación de la parábola es:
C = (0 - 3) / 9²
C = - 1 / 27
La ecuación de la parábola es y - 3 = (- 1 / 27) · x².
2) Se determina el tipo de categoría de cada ecuación:
a) 3 · x - 2 · y + 4 = 0: Recta (a · x + b · y + c = 0)
b) 4 · x + y² - 7 = 0: Parábola ((y² - k) = 4 · p · (x - h))
c) x² + y² = 16: Circunferencia ((x - h)² + (y - k)² = r²)
d) y = x³ - 3 · x + 1: Ecuación cúbica
e) x² + 4 · y² = 4: Elipse (b² · (x - h)² + a² · (y - k)² = a² · b²)
3) Se debe hallar el valor C de la función lineal tal que S = 0.35 por medios algebraicos:
0.35 = 0.03 + 1.805 · C
0.32 = 1.805 · C
C = 0.32 / 1.805
C = 0.177
4) El arco semielíptico tiene una longitud de semieje mayor de 25 pies (paralelo al eje x) y una longitud de semieje menor de 15 pies (paralelo al eje y). Si consideramos que el centro de la elipse está en el origen, entonces tenemos que la ecuación es:
x² / 25² + y² / 15² = 1
y = 15 · √(1 - x² / 25²)
y = 15 · √(1 - 12² / 25²)
y = 13.159 pies
5) a) y b) Ahora graficamos la hipérbola y presentamos las ubicaciones de los focos y las asíntotas correspondientes. a) Las ecuaciones de las asíntotas son y = ± (3 / 2) · x, b) Las ecuaciones de las asíntotas son y = ± (√ 2 / 2) · x.
c) Se puede determinar la naturaleza de cada ecuación por métodos algebraicos:
9 · x² - 4 · y² - 54 · x - 16 · y + 29 = 0
[9 · x² - 2 · 9 · (3 · x) + 81] - [4 · y² - 2 · 8 · (2 · y) + 64] = 116
(3 · x - 9)² - (2 · y - 8)² = 116
9 · (x - 9)² - 4 · (y - 4)² = 116
(x - 9)² /12.889 - (y - 4)² / 29 = 1 - Hipérbola
4 · x² + 2 · y² - 7 · x + y - 5 = 0
[4 · x² - 2 · (7 / 4) · (2 · x) + 49 / 16] + [2 · y² + 2 · (√2 / 2) · (√2 · y) + 1 / 2] = 5
(2 · x - 7 / 4)² + (√2 · y + √2 / 2)² = 5
4 · (x - 7 / 8)² + 2 · (y + 1 / 2)² = 5
(x - 7 / 8)² / 1.25 + (y + 1 / 2)² / 2.5 = 1 - Elipse
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the formula for the circumference (c) of a circle is c= 2πr. calculate c if r=0.8695 mm, keeping the highest possible number of significant figures in your answer
The value of the circumference (C) of a circle, having a radius (r) = 0.8695 mm, using the formula C = 2πr, is calculated to be 5.4632296245926504416865368435231 mm.
A circle is a shape formed by all points in a plane that are at a particular distance from the center.
The linear distance around a circle is defined as its circumference. In other words, if a circle is opened to produce a straight line, the length of that line equals the circumference of the circle.
The formula for the circumference of a circle is given:
C = 2πr,
where C is the circumference of the circle, r is its radius, and π is a constant.
We are asked to find the circumference of the circle (C), given its radius (r) = 0.8695 mm.
Using the formula of the circumference C = 2πr, we can find the circumference as:
C = 2*π*(0.8695) mm,
or, C = 5.4632296245926504416865368435231 mm.
Thus, the value of the circumference (C) of a circle, having a radius (r) = 0.8695 mm, using the formula C = 2πr, is calculated to be 5.4632296245926504416865368435231 mm.
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To fight a fire breathing dragon, a knight needs a sword made of Dragon Alloy #13, which contains 7% gold, 3% silver, and 90% magic steel. The dwarves promised to forge such a sword for the knight. At the moment, they have an alloy that contains magic steel, 21% gold, and 9% silver. How much of that alloy and how much magic steel do the dwarves have to combine to get 2.7 kg of Dragon Alloy #13?
Let [tex]x[/tex] and [tex]y[/tex] be the amounts of available alloy (AA) and pure magic steel that are used, so we also have
[tex]x + y = 2.7[/tex]
DA13 is supposed to contain 7% gold, 3% silver, and 90% steel, so that 2.7 kg of it is made up of
[tex]0.07 \times 2.7 \,\mathrm{kg} = 0.189 \,\mathrm{kg} \text{ gold}[/tex]
[tex]0.03 \times 2.7 \,\mathrm{kg} = 0.081 \,\mathrm{kg} \text{ silver}[/tex]
[tex]0.90 \times 2.7 \,\mathrm{kg} = 2.43 \,\mathrm{kg} \text{ magic steel}[/tex]
For each kg of the available alloy (AA), there is a contribution of 0.21 kg of gold, 0.09 kg of silver, and therefore 0.70 kg of steel; [tex]x[/tex] kg of it will contain [tex]0.21x[/tex] kg of gold, [tex]0.09x[/tex] kg of silver, and [tex]0.70x[/tex] kg of steel. Each kg of magic steel of course contributes 1 kg of steel; [tex]y[/tex] kg of it will contribute [tex]y[/tex] kg of steel.
Then the dwarves need
• total gold: [tex]0.21x = 0.189[/tex]
• total silver: [tex]0.09x = 0.081[/tex]
• total steel: [tex]0.70x + y = 2.43[/tex]
Solve for [tex]x[/tex] and [tex]y[/tex]. The first two equations are consistent and give [tex]x = 0.90[/tex], and substituting this into the third we find [tex]y = 1.80[/tex]. So the dwarves must combine 0.90 kg of AA and 1.80 kg of magic steel.
Suppose a set of scores in College Mathematics are 5, 15, 25, 30, 3. Which of the following is true?
a.
the mean is equal to the median
b.
the mean is less than the median
c.
the mean is greater than the median
d.
the mode is 15
Answer: c. the mean is greater than the median
Explanation:
To find out the correct answer, we first must know the true meanings and the method of calculation of the terms, "mean", "mode" and "median".
Mean: The mean is a type of average. It is the sum of all the values in a set of data, such as numbers of measurements, divided by the numbers of values on the list.
Formula for finding mean-[tex]\bar{x} = \dfrac{\sum x}{n}[/tex] where, [tex]\bar{x}=[/tex] sample mean
[tex]\sum x =[/tex] sum of each value in sample
[tex]n =[/tex] number of values in the sample
Example: in {6, 3, 9, 6, 6, 5, 9, 3} the mean is 5.875 (6+3+9+6+6+5+9+3/8).
Mode: The mode is the number which appears most often in a set of numbers.
Example: in {6, 3, 9, 6, 6, 5, 9, 3} the Mode is 6.
Median: The median is the "middle" of a sorted list of numbers in ascending order (small to big). To find the Median, place the numbers in value order and find the middle.
Example: in {6, 3, 9, 6, 6, 5, 9, 3} the median is 6. (in 3,3,5,6,6,9,9, the middle number is 6 )
with an even amount of numbers things are slightly different.
In that case we find the middle pair of numbers, and then find the value that is half way between them. This is easily done by adding them together and dividing by two. (basically averaging the middle two numbers incase there is an even set of numbers)
Example: 3, 13, 7, 5, 21, 23, 23, 40, 23, 14, 12, 56, 23, 29
When we put those numbers in order we have:
3, 5, 7, 12, 13, 14, 21, 23, 23, 23, 23, 29, 40, 56
There are now fourteen numbers and so we don't have just one middle number, we have a pair of middle numbers.
3, 5, 7, 12, 13, 14, 21, 23, 23, 23, 23, 29, 40, 56
In this example the middle numbers are 21 and 23.
To find the value halfway between them, add them together and divide by 2: 21 + 23 = 44, then 44 ÷ 2 = 22
So the Median in this example is 22.
(Note that 22 was not in the list of numbers ... but that is OK because half the numbers in the list are less, and half the numbers are greater.)
Now that you understand the terms clearly, let's find out the mean, mode and median from your given set of numbers.
5, 15, 25, 30, 3
Mean: (5+15+25+30+3)/5 is, 15.6
Mode: None since none of the numbers repeated more than once.
Median: 3,5,15,25,30 , so the middle number is 15 .
Since there is no mode, option d. can never be the answer. And clearly, 15.6 is greater than 15 so the answer should be c. the mean is greater than the median.
∩_∩
(„• ֊ •„)♡
┏━∪∪━━━━┓
hope it helped
┗━━━━━━━┛
Complete the table by finding the missing equivalent form for each row. a = b = c =
Answer:
a=10%, b=25/100, c=1/2
Step-by-step explanation:
a: If the denominator is exactly 100, then the numerator represents a percentage.
b: when you change a fraction to have a greater denominator, an easy way to figure out how to change the numerator to match it and make the value of the rewritten fraction equal to the old version, is to divide the new value of the denominator by the old value (in this case being 100/4=25), and put the answer where the numerator goes.
c: When simplifying a fraction with a lesser numerator than denominator, find the greatest common factor (a factor is a whole number a number can be divided by without resulting in a negative or a decimal number) and divide both the numerator and denominator by it.
what is 73 division 84,649
73 division 84, 649 would give 8. 64 × 10^-4
How to determine the valueIn order to determine the value of the division, we have
= [tex]\frac{73}{84649}[/tex]
Using the calculator, put the values in
We would have
= 8. 64 × 10^-4
Thus, 73 division 84, 649 would give 8. 64 × 10^-4
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he cone below has a radius of 3 inches, a height of 4 inches, and a slant height of 5 inches.
What is the approximate lateral area of the cone? Use 3.14 for π and round to the nearest whole number.
38 in.2
47 in.2
75 in.2
94 in.2
The lateral area of the cone is calculated as: B. 47 in.².
How to Find the Lateral Area of a Cone?Lateral area = πrl
Given the following:
Slant height (l) = 5 inches
Radius (r) = 3 inches.
π = 3.14
Plug in the values
Lateral area = (3.14)(3)(5)
Lateral area ≈ 47 in.²
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Someone please help!
Answer:
obtuse
Step-by-step explanation:
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
In the above problem, it's given that one of the angles of the triangle exceeds 90° [ that is : 97° ]
[tex] \qquad \large \sf {Conclusion} : [/tex]
hence, it's an obtuse angled triangle
Equation that represents a line which is parallel to the line y=-2/3x+1
Answer:
- 2/3
Step-by-step explanation:
Answer:
Any equation that has the same slope as the line y = -2/3x + 1 but a different y-intercept will be parallel because the lines will never intersect. For example, y = -2/3x + 2 or y = -2/3x + 3.
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what would be your return on the investment if you bought when rates were 7% and sold when rates were 10%
The return on the investment is 3%
How to determine the return on investment?The given parameters are:
Buying rate = 7%
Selling rate = 10%
The return on the investment is
ROI = Selling - Buying
So, we have:
ROI = 10% - 7%
Evaluate
ROI = 3%
Hence, the return on the investment is 3%
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The temperature at 6am is -8f , at 9am the temperature is 6f . If the temperature rises at a constant rate , what will the temperature be at 3:00pm
Answer:
24 F
Step-by-step explanation:
Temp increases by 4F per hour.
-8F - 6F = 12F / 3hours
Find the solution(s) to the system of equations represented in the graph. (5 points)
Answer:
(0, -2) and (2, 0)
Step-by-step explanation:
The solution to a systems of equations is when the x and y values are equal for two equations. This can also been seen as when the two equations intersect. So by looking at the graph you see the line and the circle intersect at the point (2, 0) and (0, -2) which are going to be the two solutions to the systems of equations.
What is the range of possible sizes for side xxx?
Answer:
1.6 < x < 9.6
Step-by-step explanation:
given 2 sides of a triangle then the third side x is in the range
difference of 2 sides < x < sum of 2 sides , that is
5.6 - 4 < x < 5.6 + 4
1.6 < x < 9.6
HELP !!show the work tooo
the probability of getting heads on a two-face coin is simply 1/2.
now, what is the probability of getting 1/2 AND 1/2 AND 1/2 AND 1/2 AND 1/2? well, AND means "times", namely
[tex]\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\implies \cfrac{1}{32}[/tex]
well, and since it's a two-face coin, the probability for each face is equal, 1/2, so Heads has a chance of 1/2 each time, or we can also say that Tails has a chance of 1/2 each time, so if Tails has the same probability over 5 times as Head does.
Please help!!!! all qustions please
See below for the missing terms of the sequences
The first term of the sequenceThe given parameters are:
T4 = 30
T5 = 49
Calculate the third term as follows:
T3 = T5 - T4
T3 = 49 - 30
T3 = 19
Calculate the second term as follows:
T2 = T4 - T3
T2 = 30 - 19
T2 = 11
Calculate the first term as follows:
T1 = T3 - T2
T1 = 19 - 11
T1 = 8
Hence, the first term of the sequence is 8
The first term and the other terms of the sequenceThe given parameters are:
T2 = x
T3 = y
Calculate the first term as follows:
T1 = T3 - T2
T1 = y - x
Calculate the fourth term as follows:
T4 = T2 + T3
T4 = x + y
Calculate the fifth term as follows:
T5 = T3 + T4
T5 = y + x + y
T5 = x + 2y
Hence, the missing terms of the sequence are y - x, x + y and x + 2y
Read more about Fibonacci sequence at:
https://brainly.com/question/26507758
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Induced pluripotent stem cells are cells from adults that have been reprogrammed to imitate embryonic stem cells. Why might induced pluripotent stem cells be a valuable tool in science and medicine?
Induced pluripotent stem cells can be a valuable tool in science and medicine because: A. induced pluripotent stem cells can become any cell type in the body, but are from adults, avoiding the controversies associated with embryonic stem cells.
What is a cell?A cell can be defined as the fundamental functional, structural and smallest unit of life, which is typically found in all living organisms.
In Science, all living organisms are broadly grouped into two (2) main categories according to cell type and these include the following;
Unicellular organismsMulticellular organismsBasically, the reason why induced pluripotent stem cells can be a valuable tool in science and medicine is simply because they can become any cell type within the body of a living organism, but are usually derived from adults that are avoiding the controversies associated with embryonic stem cells.
Read more on induced pluripotent stem cells here: https://brainly.com/question/13235525
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Complete Question:
Induced pluripotent stem cells are cells from adults that have been reprogrammed to imitate embryonic stem cells. Why might induced pluripotent stem cells be a valuable tool in science and medicine?
A. Induced pluripotent stem cells can become any cell type in the body, but are from adults, avoiding the controversies associated with embryonic stem cells
B. Induced pluripotent stem cells are the only type of stem cell that's truly pluripotent.
C. Induced pluripotent stem cells may become any cell type in the body, but are fraught with ethical questions over their use.
D. Induced pluripotent stem cells are derived from adult cells and therefore may have DNA abnormalities, allowing scientists to understand the effects of sun exposure or toxins on DNA
Use the following triangle to find Sec theta.
Note: enter the exact, fully simplified and rationalized answer
Answer:
[tex]\frac{\sqrt{41}}{4}[/tex]
Step-by-step explanation:
sec(theta) is defined as: [tex]sec(\theta)=\frac{1}{cos(\theta)} = \frac{hypotenuse}{adjacent}[/tex]
In the diagram you provided the hypotenuse of the triangle is sqrt(41) and the opposite side is 5, using these two sides, we can solve for the adjacent side by using the Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]
So this gives us the equation where a=adjacent side:
[tex]a^2+5^2=\sqrt{41}^2[/tex]
[tex]a^2+25=41[/tex]
Subtract 25 from both sides
[tex]a^2=16[/tex]
Take the square root of both sides
[tex]a=4[/tex]
So now plug this into the definition of sec(theta) and you get: [tex]\frac{\sqrt{41}}{4}[/tex]. This is in most simplified form since 41, has no factors besides 41 and 1.