Marco runs 22 miles in four hours. What is his unit rate?

Answer:

3 1/9

Step-by-step explanation:

divide 4 2/3 and 1 1/2 together to find width

Answer:

-3

Step-by-step explanation:

10+2X-4= 0

2X= -10 + 4

2X = -6

X = -3

Function that models the situation is  f(x) = 1/2(x-6)²+2.

A parabola is a plane curve which is mirror-symmetrical and is approximately U-shaped.

Given parabola is of concave upward type.

So, the parabola will be of form f(x)=p(x-q)²+r....(1)

As vertices of parabola are (6,2)

So, we can put q=6 and r =2 in (1)

So, (1) becomes f(x) = p(x-6)²+2.....(2)

The y-intercept of the parabola is 20

This means, (2) becomes 20 = p(0-6)²+2

i.e. p = 1/2

So, function will be f(x) = 1/2(x-6)²+2

Therefore, function that models the situation is  f(x) = 1/2(x-6)²+2.

To get more about parabola visit:

https://brainly.com/question/4148030

Answer:

Integers and decimals

Step-by-step explanation:

Soorry im too lazy to read all this

Answer:

Arnie is mixing red and yellow paints to make two different shades of orange. To make 1 cup of dark orange​ paint, he needs 7 ounces of red paint and 1 ounce of yellow paint. To make 2 cups of light orange​ paint, he needs 13 ounces of yellow paint and 3 ounces of red paint. Answer parts a and b.

a. Arnie buys a​ 32-oz can of red paint. Does he have enough red paint to make 3 cups of dark orange paint and 3 cups of light orange​ paint? Explain.

▼  

Yes.

No.

The 3 cups of dark orange paint require  

nothing ​ounce(s) of red​ paint, and the 3 cups of light orange paint require  

nothing ​ounce(s) of red paint. Arnie needs  

nothing ​ounce(s) of red paint in​ total, so the​ 32-oz can is  

▼  

enough.

not enough.

Step-by-step explanation:

Answer:

630

Step-by-step explanation:

Answer:

630

Step-by-step explanation:

1 minute = 60 words multiply everything by 10.5

10.5 minutes = 10.5(60) = 630 words

Answer:

C. As the children's weight increased, their height decreased

Step-by-step explanation:

This is your answer becuse you can see here that the height is increasing as the weight is increasing

Thanks!

Mark me brainliest!

Answer:

2.837%

Step-by-step explanation:

1/2 ×567.375/100

therefore= 2.837%

Answer:

Vol = 769.7 cubic ft

Step-by-step explanation:

"radius" is the distance from the center of a circle to the circle. So let's assume your pool is a circular pool with radius = 7ft and height = 5ft. It's a cylinder.

Volume of a cylinder:

Vol =

Base area•height

= pi•r^2 • h

= pi(7)^2•5

= pi•49•5

= pi • 245

= 245pi

Now, 245pi cubic ft is a perfectly good answer. But your teacher/text/class, may be asking for a decimal approximation.

If you use calculator pi (that's a lot of decimals) you get

Vol ~= 769.69 (to the hundredths place)

Vol ~= 769.7(to the tenths place)

If you were told to use 3.14 for pi

then you get

Vol ~= 769.3 cubic ft

But if you were told to convert units to gallons or liters there are more calculations (message, i can edit in these)

Answer:

Step-by-step explanation:

answer: owen can afford to keep and drive the car for 4 days.

The total owing on the car rental is R(d) = ($77.25/day)d + ($0.12/mile)m ≤ $330.  Substitute 1 for d (that is, the rental is for 1 day) and 175 for m:

R(d) = ($77.25/day)(d days) + ($0.12/mile)(175 miles) ≤ $330

    =   $77.25d                   + $21     ≤ $330

This simplifies to   $77.25d + $21 ≤ $330, or

                                $77.25d ≤ $309

Solving this by dividing both sides of the above equation by $77.25, we get                          

d = ($309)/($77.25) = 4

Answer:

1

Step-by-step explanation:

x is the number

x+2 is divided by 3

x+2 ÷ 3 =1

Multiple 3 on both sides

x=1

We know that:

This means that:

Step-by step calculations:

Subtract 3x both sides.

Subtract 4 both sides.

Divide 6 both sides.

*Note that:-

Using this equation we will solve for x and then find each angle...

[tex]\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}[/tex]

[tex]9x + 4 = 3x + 16 \\ 9x + 4 - 3x = 16 \\ 9x - 3x = 16 - 4 \\ 6x = 12 \\ x = 2[/tex]

[tex]\large{|\underline{\mathsf{\red{1}\blue{ ^{s} }\orange{^{t} }\pink{ \: }\blue{a}\purple{n}\green{g}\red{l}\blue{e}\orange{ \: }\green{↯}\red{}\purple{}\pink{}}}}[/tex]

[tex] \pmb{9x + 4} \\ \pmb{9 \times 2 + 4} \\ \pmb{18 + 4} \\ \boxed{ \tt \: ∠1 = 22 \degree }[/tex]

[tex]\large{|\underline{\mathsf{\red{2}\blue{ ^{n} }\orange{^{d} }\pink{ \: }\blue{a}\purple{n}\green{g}\red{l}\blue{e}\orange{ \: }\green{↯}\red{}\purple{}\pink{}}}}[/tex]

[tex] \pmb{3x + 16} \\ \pmb{3 \times 2 + 16} \\ \pmb{6 + 16} \\ \boxed{ \tt \: ∠2 = 22 \degree }[/tex]

Answer:

st-2f u

Step-by-step explanation:

so the essay 2+1=2

Answer :

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

[tex]{\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}[/tex]

[tex]\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}[/tex]

[tex]\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}[/tex]

Therefore,

[tex]{\qquad \dashrightarrow{ \bf{Volume \: of \: the \: wall = length \times breadth \times height}}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: the \: wall = 1000 \times 24 \times 400 \: {cm}^{3} }}}[/tex]

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

[tex]{\qquad \dashrightarrow{ \bf{Volume \: of \: each \: brick = length \times breadth \times height}}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: each \: brick = 24 \times 12 \times 8 \: {cm}^{3} }}}[/tex]

So,

[tex]{\qquad \dashrightarrow{ \bf{Volume \: of \: bricks \: required = \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \bf \: 4166.6} }}[/tex]

Therefore,

Answer:

Step-by-step explanation:

Area of the figure = area of semicircle + area of rectangle

Rectangle:

length = 11.25 in

width = 7.5 in

Area of rectangle = length * width

                            = 11.25 * 7.5

                            = 84.375 in²

Semicircle:

diameter =  width of the rectangle

d = 7.5 in

r = diameter 2 = 7.5/2 = 3.75 in

[tex]Area \ of \ circle = \dfrac{1}{2}\pi r^{2}\\\\[/tex]

                         [tex]=\dfrac{1}{2}*3.14*3.75*3.75\\\\= 22.08 \ in^{2}[/tex]

Area of the figure = 84.375 + 22.08

                                = 106.455

                                = 106.46 in²

Answer:

X=[tex]\frac{-16-Z}{Y}[/tex]

Step-by-step explanation:

XY+Z=-16

Subtract both sides by Z

XY=-16-Z

Divide both sides by Y

X=[tex]\frac{-16-Z}{Y}[/tex]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

[tex](\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})[/tex]

[tex]\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12[/tex]

Answer:

Step-by-step explanation:

2x-8+3x+2=4x+10+3x-6

5x-6=7x+4

minus 7x from both sides, add 6 to both dies

-2x=10

divide by -2

x=-5

? Pick one graph

Step-by-step explanation:

There's no graph visible

f(x) is the same as y

Hope this helps!

Answer:

The constant of proportionality is 5 minutes per bracelet

Step-by-step explanation:

If x and y are proportion, then y = k x, where

Let us solve our question

∵ Olivia is making bead bracelets for her friends

∵ She can make 3 bracelets in 15 minutes

We need to find the constant of proportionality in terms of minutes per bracelet, which means y represents the minutes and x represents the bracelet

∴ y = the time in minutes

∴ x = the number of bracelets

∵ y proportion with x

∴ k = [tex]\frac{y}{x}[/tex]

∵ y = 15 and x = 3

∴ k = [tex]\frac{15}{3}[/tex]

∴ k = 5

∴ The constant of proportionality is 5 minutes per bracelet

Answer:14

Step-by-step explanation:440 X .35 = 114. You have tto Turn 35% into a decimal. Move over 2 times now you get .35

Answer:

20705.875

Step-by-step explanation:

Area of a pentagon is 1/2 * P * A  p being the perimeter of the pentagon and a being the apothem.  1/2 * 548.5 * 75.5 equals 20705.875.  I'm almost positive this is correct.  So sorry if it's not.  Have a good day/night!

Answer: 9 over 10

Step-by-step explanation:

Answer:

b=119, and c=119

Step-by-step explanation:

this is because b+61 equal 180 degrees and b and c are congruent angles

Answer:

B

Step-by-step explanation:

The slope is -1, which equals m= -1.

The answer is B.

First of all, to find the area of a triangle you multiply the base * height and divide the result by two (2).

Let's use a triangle which sides are all 2 inches. To find the area, you do 2*2/2  which equals 2.

Now, double each side and each side of the triangle is now 4.

We do 4*4/2 which now equals 8.

The percentage increase from 2 --> 8 is 600%.

The percentage of the old area to the new area is 800%

ANSWER: 600%

Answer:

4

Step-by-step explanation:

Given,

[tex]6+log\frac{3}{2} (\frac{1}{3\sqrt{2} } \sqrt{4-\frac{1}{3\sqrt{2} }\sqrt{4-\frac{1}{3\sqrt{2} } ...} }[/tex]

Let,

[tex]x= \sqrt{4-\frac{1}{3\sqrt{2} }\sqrt{4-\frac{1}{3\sqrt{2} }\\[/tex]

By this we get

[tex]x=\sqrt{4-\frac{1}{3\sqrt{2} }(x) } }[/tex]

On squaring both sides,

[tex]x^{2} =4-\frac{1}{3\sqrt{2} }(x) } }\\\\x^{2} -4+\frac{x}{3\sqrt{2} } =0\\\\3\sqrt{2} x^{2} -12\sqrt{2} +x=0\\\\x=\frac{-1+\sqrt{1-(-12\sqrt{2})*(3\sqrt{2})*4 } }{2*3\sqrt{2} } \\\\x=\frac{-1+\sqrt{289} }{6\sqrt{2} } \\\\x=\frac{-1+17}{6\sqrt{2} } \\\\x=\frac{8}{3\sqrt{2} }[/tex]

Now,

[tex]6+log\frac{3}{2} [\frac{1}{3\sqrt{2} } *\frac{8}{3\sqrt{2} } ]+log\frac{3}{2} *[\frac{8}{9*2} ]\\\\6+log\frac{3}{2}(\frac{4}{9} )\\\\6-log\frac{3}{2}(\frac{9}{4} )\\\\6-log\frac{3}{2} (\frac{3}{2})^2 \\\\6-2=4[/tex]

[tex]\sqrt{4 - \dfrac1{3\sqrt2} \sqrt{4 - \dfrac1{3\sqrt2} \sqrt{4 - \dfrac1{3\sqrt2} \sqrt{\cdots}}}}[/tex]

Starting from the identity

[tex](x - y)^2 = x^2 - 2xy + y^2[/tex]

take the positive square root on both sides.

[tex]x - y = \sqrt{x^2 - 2xy + y^2}[/tex]

Note that we must have [tex]x\ge y[/tex]. Rewrite the radicand and substitute [tex]x-y[/tex].

[tex]x - y = \sqrt{x^2 - xy - y (x - y)} \\\\ ~~~~ = \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y (x - y)}} \\\\ ~~~~ = \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y (x - y)}}} \\\\ ~~~~ \vdots \\\\ ~~~~ = \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y \sqrt{\cdots}}}}[/tex]

Let [tex]y=\frac1{3\sqrt2}[/tex]. Solve for [tex]x[/tex].

[tex]x^2 - \dfrac x{3\sqrt2} = 4 \\\\ x^2 - \dfrac x{3\sqrt2} + \dfrac1{72} = \dfrac{289}{72} \\\\ \left(x - \dfrac1{6\sqrt2}\right)^2 = \dfrac{289}{72} \\\\ x - \dfrac1{6\sqrt2} = \pm \dfrac{17}{6\sqrt2} \\\\ x = \dfrac{18}{6\sqrt2} \text{ or } x = -\dfrac{16}{6\sqrt2} \\\\ x = \dfrac3{\sqrt2} \text{ or } x = -\dfrac8{3\sqrt2}[/tex]

Take the positive solution to ensure [tex]x>y[/tex]. Then the infinitely nested root expression in the logarithm converges to

[tex]x - y = \dfrac3{\sqrt2} - \dfrac1{3\sqrt2} = \dfrac{4\sqrt2}3[/tex]

and the overall expression has a value of

[tex]6 + \log_{\frac32} \left(\dfrac1{3\sqrt2} \times \dfrac{4\sqrt2}3\right) = 6 + \log_{\frac32} \left(\dfrac49\right) \\\\ ~~~~ = 6 + \log_{\frac32} \left(\dfrac23\right)^2 \\\\ ~~~~ = 6 - 2 \log_{\frac32} \left(\dfrac32\right) \\\\ ~~~~ = 6 - 2 = \boxed{4}[/tex]