Mary is 21 years old. She buys 50/100/25 liability insurance, and collision and
comprehensive insurance, each with $500 deductibles. What is her total annual
premium? Round to the nearest dollar. Do not state the units. Be sure to show work.

Liability Insurance
Type Amount Premium
25/50 $240
50/100 $385
100/300 $450

Property damage 25 $210
50 $150
100 $140


Collision and comprehensive premiums

$250 $172 $112
$500 $102 $87
$750 $85 $52

Rating factor
Age

17-20 male Female

3.1 1.64

21-24. 2.53. 1.22


25-29 1.73 1.0

Answer: 314 square meters

Step-by-step explanation:

The formula for the area of a circle is given by A = πr^2, where r is the radius of the circle. Since the diameter of the circular patch is given as 20 meters, the radius would be half of that or 10 meters.

So, using the formula, we can calculate the area of the circular patch as follows:

A = πr^2

A = π(10)^2

A = 3.14(100)

A = 314 square meters

Therefore, the area of the circular patch is 314 square meters.

so as we speak, the subfunctions are discontinued, the 1st goes close to 2 and who knows what happens it goes somewheres, the 2nd one makes it to 2.

we know that since the 2nd one makes to 2, to x = 2 that is, well, f(2) = kx, well, let's make f(2) for the 2nd one be equal to the 1st one then, if both they equate each other, that's where they meet, at x = 2.

[tex]f(x)= \begin{cases} k^2-24x,&x > 2\\\\ kx,&x\leqslant 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ k^2-24x~~ = ~~kx\hspace{5em}\stackrel{\textit{now let's go to f(2)}}{k^2 - 24(2)~~ = ~~k(2)}\implies k^2-48=2k \\\\\\ k^2-2k-48=0\implies (k-8)(k+6)=0\implies \boxed{k= \begin{cases} 8\\ -6 \end{cases}}[/tex]

[tex]53 - 3^2 * 3 = 35[/tex]

Answer: 6234 × 32 = 199488.

Step by step:

To calculate 6234 × 32 without using a calculator, you can use the traditional multiplication method as follows:

   6234

x    32

-------

  12468   (2 x 6234)

+ 62340   (3 x 6234 with a zero added)

--------

 199488

Answer:

Step-by-step explanation:

5m(4m) = 20m^2

Answer:

father age 45 son age 0 this is answer

Answer:

19782m

Step-by-step explanation:

1  revolution = circumference

circumference = π * diameter

π = 3.1416

Then

circumference = 3.1416 * 63

= 197.92m

1 revolution = 197.82m

100 revolutions = 100*197.82m

= 19782m

Answer:

19.8 km

Step-by-step explanation:

To find:-

Answer:-

We are here given that,

We can first find the circumference of the wheel using the formula,

[tex]:\implies \sf C = 2\pi r \\[/tex]

Here radius will be 63/2 as radius is half of diameter. So on substituting the respective values, we have;

[tex]:\implies \sf C = 2\times \dfrac{22}{7}\times \dfrac{63}{2} \ m \\[/tex]

[tex]:\implies \sf C = 198\ m \\[/tex]

Now in one revolution , the cycle will cover a distance of 198m . So in 100 revolutions it will cover,

[tex]:\implies \sf Distance= 198(100)m\\[/tex]

[tex]:\implies \sf Distance = 19800 m \\[/tex]

[tex]:\implies \sf Distance = 19.8 \ km\\[/tex]

Hence the bicycle would cover 19.8 km in 100 revolutions.

In this case, we'll have to carry out several steps to find the solution.

Step 1:

Data:

camera:

list price (before tax) = $459.99

sales tax = 7.25%

Step 2:

percentage:

[tex]sales \ tax = 7.25\% = 7/100 = 0.07[/tex]

[tex]total \ cost = \$459.99 + \$459.99 \times (0.07) = \$459.99 + \$32.1993 = \$492.1893[/tex]

The answer is:

$492.19

The toll calculation for driving on a certain stretch of a toll road is $5 except during rush hours when the toll is $7, depending on the time the driver uses the toll road.

To compute the toll for driving on the toll road during non-rush hours, simply add $5 to the total. During rush hour, however, the toll is $7.

To compute the toll for driving during rush hour, you must first determine when the driver intends to utilize the toll road. If the period is between 7 AM and 10 AM or 4 PM and 7 PM, the toll is $7.

For instance, if a vehicle expects to use the toll road at 8 a.m., the toll is $7. If the vehicle intends to use the toll road at 2 p.m., the toll is $5.

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The result of the formula  [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex] for y = 3 is  [tex]-29/2[/tex]  .

When [tex]y = 3[/tex] is used, the value of the expression [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex]  has a value of  [tex]-29/2[/tex] .

To analyse an algebraic expression is to determine its value when a certain number is used in lieu of the variable. To evaluate the expression, we first replace the variable with the given number, then we use the order of operations to simplify the expression.

If  [tex]y = 3[/tex] , we can insert it into the expression & simplify as follows to evaluate   [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex] for  [tex]y = 3[/tex]  .

[tex]12 - 3(3)^2 + (√4) / (2(3) - 2)[/tex] (y = 3 replacement)

[tex]12 - 27 + 2 / 4\s-15 + 1/2\s-29/2[/tex]

Therefore, The result of the formula  [tex]12 - 3y2 + (v=4) / (2y - 2)[/tex] for y = 3 is  [tex]-29/2[/tex]  .

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Answer:

Step-by-step explanation:

The center of the circle is the midpoint of the diameter. To find the midpoint, we use the midpoint formula:

Midpoint = [(x1 + x2)/2, (y1 + y2)/2]

where (x1, y1) and (x2, y2) are the coordinates of the endpoints of the diameter.

Midpoint = [(3 + (-2))/2, (1 + 3)/2]

Midpoint = [1/2, 2]

So, the center of the circle is (1/2, 2).

The radius of the circle is half the length of the diameter. To find the length of the diameter, we use the distance formula:

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) and (x2, y2) are the coordinates of the endpoints of the diameter.

Distance = sqrt((-2 - 3)^2 + (3 - 1)^2)

Distance = sqrt(25 + 4)

Distance = sqrt(29)

So, the length of the diameter is sqrt(29).

The radius of the circle is half of sqrt(29), which is sqrt(29)/2.

Therefore, the equation of the circle is:

(x - 1/2)^2 + (y - 2)^2 = (sqrt(29)/2)^2

Simplifying this equation, we get:

(x - 1/2)^2 + (y - 2)^2 = 29/4

So, the equation of the circle with a diameter whose endpoints are (3, 1) and (-2, 3) is (x - 1/2)^2 + (y - 2)^2 = 29/4.

Answer: Permutations that preserve distances are also known as isometries or distance-preserving transformations.

Step-by-step explanation:

Permutations that preserve distances refer to a type of mathematical transformation that preserves the distances between pairs of points in a geometric space. In other words, if you have a set of points arranged in a particular way and you apply a permutation that preserves distances, the resulting arrangement of points will have the same distances between each pair of points as the original arrangement. This type of permutation is important in geometry and can be used to study properties of geometric objects such as polyhedra, graphs, and other structures. Permutations that preserve distances are also known as isometries or distance-preserving transformations.

1. The diagonals are equal. Rectangle

2. All sides are equal, and one angle is 60°. Rhombus

3. All sides are equal, and one angle is 90°. Square

4. It has all the properties of parallelogram, rectangle, and rhombus. Square

5. It is an equilateral parallelogram. Rhombus

A rectangle is a four-sided figure with two sets of parallel sides, with each side being a different length. The opposite sides of a rectangle are always equal in length, so the angles of a rectangle are all 90 degrees. A rectangle can also be referred to as a quadrilateral.

A rhombus is a four-sided figure with all sides the same length. The angles of a rhombus are not all 90 degrees, but the opposite sides of a rhombus are equal in length. A rhombus can also be referred to as a diamond.

A square is a four-sided figure with all sides being the same length and all angles being 90 degrees. A square can also be referred to as a regular quadrilateral.

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The complete question is:

Identify whether the following statements describe a rectangle, rhombus or square.

1. The diagonals are equal. ____________

2. All sides are equal, and one angle is 60°. ____________

3. All sides are equal, and one angle is 90°. ____________

4. It has all the properties of parallelogram, rectangle, and rhombus. ____________

5. It is an equilateral parallelogram. ____________

The Euler's method was used to approximate the solution of two initial value problems at various time intervals with different step sizes. For problem, the solution is decreasing and converges to 1.

We will use the following formula for Euler's method:

y_{n+1} = y_n + h*f(t_n, y_n)

y' = 5 – 3sqrt(y), y(0) = 2

Using h = 0.1, we get:

t=0, y=2

t=0.1, y=1.738

t=0.2, y=1.508

t=0.3, y=1.303

t=0.4, y=1.119

t=0.5, y=0.953

Using h = 0.05, we get:

t=0, y=2

t=0.05, y=1.837

t=0.1, y=1.695

t=0.15, y=1.568

t=0.2, y=1.452

t=0.25, y=1.346

t=0.3, y=1.248

t=0.35, y=1.158

t=0.4, y=1.076

t=0.45, y=0.999

t=0.5, y=0.929

Using h = 0.025, we get:

t=0, y=2

t=0.025, y=1.861

t=0.05, y=1.737

t=0.075, y=1.622

t=0.1, y=1.516

t=0.125, y=1.418

t=0.15, y=1.328

t=0.175, y=1.246

t=0.2, y=1.17

t=0.225, y=1.101

t=0.25, y=1.038

t=0.275, y=0.98

t=0.3, y=0.927

t=0.325, y=0.878

t=0.35, y=0.833

t=0.375, y=0.791

t=0.4, y=0.753

t=0.425, y=0.718

t=0.45, y=0.685

t=0.475, y=0.655

t=0.5, y=0.627

Using h = 0.01, we get:

t=0, y=2

t=0.01, y=1.88

t=0.02, y=1.764

t=0.03, y=1.652

t=0.04, y=1.544

t=0.05, y=1.44

t=0.06, y=1.34

t=0.07, y=1.244

t=0.08, y=1.151

t=0.09, y=1.062

t=0.1, y=0.976

t=0.11, y=0.893

t=0.12, y=0.813

t=0.13, y=0.736

t=0.14, y=0.662

t=0.15, y=0.591

t=0.16, y=0.523

t=0.17, y=0.458

t=0.18, y=0

So, we can say that the step size had to be decreased to achieve more accurate approximations

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_____The given question is incomplete, the complete question is given below:

In each of Problems 9 and 10, use Euler's method to find approximate values of the solution of the given initial value problem at t = 0.5, 1, 1.5, 2, 2.5, and 3: a. With h=0.1. b. With h = 0.05. c. With h= 0.025. d. With h=0.01.

9. y' = 5 – 3 sqrt y,      y(0) = 2

The number of fractions between 0 and 1 (inclusive) with a denominator of 15 can be found using the formula (n-1)/n, where n is the denominator.

So, to answer your question, we can use the formula and plug in 15 for the value of n:

(15-1)/15 = 14/15

Therefore, there are 14 fractions between 0 and 1 (inclusive) with a denominator of 15.

The value of the triple integral[tex]\int \int\int _{E } \frac{e^{-(x^2+y^2+z^2)}}{\sqrt{(x^2+y^2+z^2}}\sqrt{dV}[/tex] by using spherical coordinates [tex]2\pi(e^{-1}-e^{-9})[/tex].

Given that the triple integral is-

[tex]\int \int\int _{E } \frac{e^{-(x^2+y^2+z^2)}}{\sqrt{(x^2+y^2+z^2}}\sqrt{dV}[/tex]

E is the region bounded by the spheres which are,

[tex]x^2+y^2+z^2=1\\\\x^2+y^2+z^2=9[/tex]

In spherical coordinates we have,

x = r cosθ sin ∅

y = r sinθ sin∅

z = r cos∅

dV = r²sin∅ dr dθ d∅

E contains two spheres of radius 1 and 3 () respectively, the bounds will be like this,

1 ≤ r ≤ 3

0 ≤ θ ≤ 2π

0 ≤ ∅ ≤ π

Then

[tex]\int \int\int _{E } \frac{e^{-(x^2+y^2+z^2)}}{\sqrt{(x^2+y^2+z^2}}\sqrt{dV}[/tex]

[tex]\int\int\int _{E} \frac{e^{-r^2}}{r}r^2Sin\phi drd\phi d\theta\\\\2\pi \int_{0}^{\pi} \int_1^3 re^{-r^2} dr d\phi\\\\2\pi \int_1^3 re^{-r^2} dr\\\\2\pi(e^{-1}-e^{-9})[/tex]

The complete question is-

Use spherical coordinates to evaluate the triple integral ∭ee−(x2 y2 z2)x2 y2 z2−−−−−−−−−−√dv, where e is the region bounded by the spheres x2 y2 z2=1 and x2 y2 z2=9.

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The correct option on Hash 1 and Hash 2 is C. Hash 1 is designed to work with small input data, while Hash 2 is optimized for processing large input data.

The main difference between Hash 1 and Hash 2 is the amount of input data they can process. Hash 1 can process input data that is 2 characters long, while Hash 2 can handle input data that is up to 300,000 characters long. This means that Hash 2 is better suited for processing larger datasets than Hash 1.

In terms of which hash function is better suited for different types of data, it depends on the specific application and the characteristics of the data being processed. For example, if the data being hashed is small and of low complexity, Hash 1 may be a good choice due to its speed and simplicity.

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The options for this question include:

The area of this triangle is 30 m².

Area is a surface measure, that is, it is the amount of space that a geometric figure occupies on a flat surface.

To calculate the area of a triangle, we can use the formula:

Area = (base x height) / 2

In the case of the given triangle, we can choose the measure of 5m as the base and the measure of 12m as the height, since the height forms a right angle with the base and is perpendicular to it.

So, we have:

Area = (b*h)/2

Area = (5m * 12m) / 2

Area = 30m²

Answer:

Step-by-step explanation:

To find the greatest profit, we need to determine the fare that will maximize revenue, while also considering the decrease in ridership due to the fare increase.

Let's assume the initial fare is $2, and the number of passengers is 800 per day. So, the initial revenue is:

$2 x 800 = $1600 per day

Now, let's say we increase the fare by 4 cents to $2.04. According to the problem, for each 4 cents increase in fare, there will be 5 fewer passengers. So, the number of passengers will decrease to:

800 - (5 x 4) = 780 passengers per day

The new revenue at this fare will be:

$2.04 x 780 = $1591.20 per day

By increasing the fare, the revenue decreased. This means that we may have increased the fare too much. Let's try another fare.

If we increase the fare by 2 cents to $2.02, the number of passengers will decrease by:

800 - (5 x 2) = 790 passengers per day

The new revenue at this fare will be:

$2.02 x 790 = $1595.80 per day

This is more revenue than the initial fare of $2 per person. Let's continue this process:

If we increase the fare by another 2 cents to $2.04, the number of passengers will decrease by:

790 - (5 x 2) = 780 passengers per day

The new revenue at this fare will be:

$2.04 x 780 = $1591.20 per day

This is less revenue than the $2.02 fare, so we can stop here.

Therefore, the greatest profit can be earned by charging $2.02 per person per day, and the maximum revenue will be:

$2.02 x 790 = $1595.80 per day

This is a bit less than the initial daily revenue of $1600, but it is the most revenue we can get by increasing the fare without causing a significant reduction in ridership.

Answer:

  $2205

Step-by-step explanation:

You want the greatest profit that can be earned by a commuter railway that has 800 passengers per day at a fare of $2, and 5 fewer for each 4¢ increase in the fare.

The number of riders (q) as a function of price (p) can be described by ...

  q = 800 -5(p -2)/0.04

  q = 1050 -125p . . . . . . . simplified

The daily revenue is the product of price and the number of riders who pay that price.

  r = pq

  r = p(1050 -125p)

  r = 125p(8.40 -p)

This function describes a parabola that opens downward. It has zeros at p=0 and p=8.40. The vertex of the parabola is on the line of symmetry, halfway between the zeros:

  pmax = (0 +8.40)/2 = 4.20

The maximum revenue is ...

  r(4.20) = 125·4.20(8.40 -4.20) = 125(4.20²) = 2205

The maximum revenue that can be earned is $2205.

__

Additional comment

The ridership at that fare is 125(4.20) = 525.

Profit is the difference between revenue and cost. Here, we have no information about the cost function, so we cannot predict the maximum profit. The question seems to assume that profit is equal to revenue.

Answer:

True

Step-by-step explanation:

A parallelogram has four sides so it's a quadrilateral

Answer:

it's 3.9

Step-by-step explanation:

Assume Samir has total 100 songs and use combined mean formula

(a) Therefore after t = 1.75 seconds the diver will hit the water.

(b) The velocity the diver hit the water is 56 ft/s.

From the given condition we have d(t) = 16t²

and the height is 49ft

(a) Now when the diver hit the water the equation become

16t² = 49

t² = 49/16

t = ±7/4

t = ±1.75

since time can not be negative so t = 1.75

Therefore after t = 1.75 seconds the diver will hit the water.

(b)

Now differentiating d(t) with respect to t we get

d'(t) = 32t

now putting t=7/4 we get

the velocity d'(7/4) = 32*7/4

d'(7/4) = 56ft/s

Therefore the velocity the diver hit the water is 56 ft/s.

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The complete question is :

A cliff diver plunges from a height of 49ft above the water surface. The distance the diver falls in t seconds is given by the function d(t)=16t²ft

(a) After how many seconds will the diver hit the water?

(b) With what velocity (in ft/s ) does the diver hit the water?

On Thursday, 12 students brought their lunch at school.

Using a number out of 100, a percentage is a technique to indicate a fraction or piece of a total. The word "percent" means "per hundred."

If 4% of the students bring their lunch to school every day, we can find the number of students who brought their lunch on Thursday by multiplying the total number of students by the percentage that brought their lunch:

Number of students who brought their lunch = (4/100) x 300

Number of students who brought their lunch = 12

Therefore, On Thursday, 12 students brought their lunch at school.

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The angle congruent to angle FYE is angle EYD.

A line known as a bisector splits an angle or a line into two equally sized segments. A segment's midpoint is always contained in the segment's bisector. Based on the geometric shape that they bisect, there are two different sorts of bisectors. An angle is divided into equal angles by an angle bisector. The line segment is split into two equal halves by a line segment bisector. It travels through the line segment's centre.

Given that, YE bisects the angle FYD.

That is, the segment YE divides the angle FYD into two equal parts.

Thus, the angle congruent to angle FYE is angle EYD.

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Answer:

The cyclist has travelled a distance of 931.888 meters.

For the equations 2xy - y^2 = 1 and xy + x + y = x^2y^2 using implicit differentiation the value Dxy is given by Dxy = (1 - 2xy + 3y^2)/(x - y)^3 and Dxy = (2y^2 - 2xy - 3y - 1)/(x - 2xy + 1)^3  respectively.

Equation 2xy - y^2 = 1,

Differentiate both sides of the equation with respect to x,

Treating y as function of x and then differentiate again with respect to x.

Using implicit differentiation,

First, differentiate both sides with respect to x,

2y + 2xy' - 2yy' = 0

Next, solve for y',

⇒2xy' - 2yy' = -2y

⇒y' (2x - 2y) = -2y

⇒y' = -y/(x - y)

Now, differentiate again with respect to x,

y''(x - y) - y'(2x - 2y) = y/(x - y)^2

Substitute the expression we obtained for y' in terms of y and x,

y''(x - y) - (-y/(x - y))(2x - 2y) = y/(x - y)^2

Simplify and solve for y'',

y''(x - y) + (2xy - 3y^2)/(x - y)^2 = 1/(x - y)^2

The expression for Dxy is,

Dxy = (1 - 2xy + 3y^2)/(x - y)^3

For the equation xy + x + y = x^2y^2,

Differentiate both sides of the equation with respect to x,

Using implicit differentiation,

First, differentiate both sides with respect to x,

⇒y + xy' + 1 + y' = 2xyy'

Solve for y',

⇒xy' - 2xyy' + y' = -y - 1

⇒y' (x - 2xy + 1) = -y - 1

⇒y' = -(y + 1)/(x - 2xy + 1)

Now, differentiate again with respect to x,

y''(x - 2xy + 1) - y'(2y - 2x y' + 1) = (y + 1)/(x - 2xy + 1)^2

Substitute the expression we obtained for y' in terms of y and x,

y''(x - 2xy + 1) - (-y - 1)/(x - 2xy + 1)^2 (2y - 2x y' + 1) = (y + 1)/(x - 2xy + 1)^2

Simplify and solve for y''

y''(x - 2xy + 1) - (2y^2 - 2xy - 2y)/(x - 2xy + 1)^2 = (y + 1)/(x - 2xy + 1)^2

The expression for Dxy is,

Dxy = (2y^2 - 2xy - 3y - 1)/(x - 2xy + 1)^3

Therefore , the value of Dxy using implicit differentiation for two different functions is equal to

Dxy = (1 - 2xy + 3y^2)/(x - y)^3 and Dxy = (2y^2 - 2xy - 3y - 1)/(x - 2xy + 1)^3

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The objective function that must be minimized is:

z = 40x + 50y

subject to the constraints:

0x + 4y ≥ 4 (protein constraint)

3x + 2y ≥ 11 (carbohydrate constraint)

2x + 4y ≤ 16 (fat constraint)

We want to find the number of ounces of fruit (x) and nuts (y) that will meet the requirement with the least number of calories.

Solving the system of inequalities, we get:

x = 2 ounces

y = 2 ounces

Therefore, the dietician should use 2 ounces of fruit and 2 ounces of nuts. These amounts will have a total of 180 calories (402 + 502).

Answer:

Step-by-step explanation:

Let's assume we need x ounces of fruit and y ounces of nuts to meet the requirements with the least number of calories. Then, the problem can be expressed as an optimization problem:

Minimize: 40x + 50y (since we want to minimize the number of calories) Subject to:

0x + 4y ≥ 4 (we need at least 4 units of protein)3x + 2y ≥ 11 (we need at least 11 units of carbohydrates)2x + 4y ≤ 16 (we cannot have more than 16 units of fat)

To solve this problem, we can use the simplex method. First, we convert the problem to standard form by introducing slack variables:

Minimize: 40x + 50y Subject to:

0x + 4y + s1 = 43x + 2y + s2 = 112x + 4y + s3 = 16

Now we can create the initial simplex tableau:

xys1s2s3RHSs1041004s23201011s32400116z-40-500000

We want to find the minimum value of z, so we need to choose the variable with the most negative coefficient in the bottom row as the entering variable. In this case, that is y. We then choose the variable with the smallest non-negative ratio between the right-hand side and the coefficient of the entering variable in its row as the leaving variable. In this case, that is s3, since 16/4 = 4 is the smallest non-negative ratio.

We then perform the pivot operation to eliminate the coefficient of y in the other rows:

     x  y  s1s2s3RHSs1001-214y3/2101/2-1/24s2-1001-1/25z-100025-15200

We repeat this process until all the coefficients in the bottom row are non-negative. The final tableau is:

x

Answer:

Total cost for groceries = ($3.75, $1.09,

$4.50, $3.25, $2.58, $4.71, $5.19, $0.89, and $5.34. add them all). = $ 31.3

the amount she paid= $ 35

balance =$ 3.7

therefore she have enough money

Answer:

32 units square

Step-by-step explanation:

Area of trapezoid = 1/2 x h x (a +b) {a and b are parallel sides}

1st parallel side = 2 + 6 + 2

                          = 10 units

2nd parallel side = 6 units

height = 4 units

Area = 1/2 x 4 x (10+6)

         = 2x16

         = 32 units square

The appropriate inference from the data is (B) Since [tex]20%[/tex] of this group read below grade level, we cannot draw any generalizations about the population. Thus, option B is correct.

A representative sample is a subset of data, often drawn from a wider population, that can show qualities that are similar.

Because the data produced contains more manageable, smaller representations of the larger group, representative sampling aids in the analysis of bigger groups.

Although the sample may be representative of seventh-grade American students, it is not necessarily representative of all seventh-graders or all American children. Hence, without additional data or research, we cannot extrapolate the sample's results to the overall population.

Therefore, 20%20, percent of all American students in seventh grade were reading below grade level.

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