Match the following equations with their direction field. Clicking on each picture will give you an enlarged view. While you can probably solve this problem by guessing, it is useful to try to predict characteristics of the direction field and then match them to the picture. Here are some handy characteristics to start with -- you will develop more as you practice.
A. Setyequal to zero and look at how the derivative behaves along thex-axis.
B. Do the same for they-axis by settingxequal to0
C. Consider the curve in the plane defined by settingy'=0-- this should correspond to the points in the picture where the slope is zero.
D. Settingy'equal to a constant other than zero gives the curve of points where the slope is that constant. These are called isoclines, and can be used to construct the direction field picture by hand.
1.y'= e^{-x} + 2y
2.y'= 2\sin(x) + 1 + y
3.\displaystyle y'= -\frac{(2x+y)}{(2y)}
4.y'= y + 2
sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro
A B
sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro
C D
My answers are correct I just need someone to show me the work on how to get there

An equation which you can use to represent the relationship shown in the table is y = 4.5x.

Mathematically, the point-slope form of a straight line can be calculated by using this mathematical expression:

y - y₁ = m(x - x₁) or y - y₁ = (y₂ - y₁)/(x₂ - x₁)(x - x₁)

Where:

Based on the information provided in the table (see attachment), we can logically deduce the following data points on the line:

Points on x-axis = (4, 5).

Points on y-axis = (18.0, 22.5).

At point (4, 18.0), a linear equation of this line in slope-intercept form can be calculated by using the point-slope form as follows:

y - 18.0 = (22.5 - 18.0)/(5 - 4)(x - 4)

y - 18.0 = 4.5(x - 4)

y = 4.5x - 18 + 18.0

y = 4.5x.

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Recruiters have completely stopped using newspaper ads as a tool for external recruitment because job seekers use the Internet almost exclusively even in smaller cities and towns. - False

Although the majority of job seekers today utilise the Internet as their main source of job searching, businesses and recruiters still use newspaper ads as a technique for external hiring In order to reach a larger pool of candidates, many businesses still utilise a combination of traditional print marketing, social media, and online job boards.

Newspaper ads still have certain benefits, though, such as reaching a different group of job seekers who might not be as active online. Additionally, newspapers are a more efficient approach to contacting potential candidates in smaller towns and cities where there may not be as much internet job search activity. Therefore, it is still a tool that some businesses and recruiters utilise in their hiring processes, particularly when attempting to connect with a larger and more varied pool of prospects.

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We have proven that the sum of the squares of the diagonals of a parallelogram is equal to the sum of squares of its sides.

Parallelograms are quadrilaterals with opposite sides parallel to each other. They have many interesting properties, one of which is the relationship between the sum of the squares of the diagonals and the sum of squares of their sides. In this explanation, we will prove this relationship mathematically.

Let us consider a parallelogram with diagonals AC and BD, and sides AB, BC, CD, and DA.

To begin, let us draw line segments from the midpoints of each side to the midpoint of the opposite side. This divides the parallelogram into four congruent triangles, as shown below:

We can now use the Pythagorean theorem to find the length of each line segment. Let us denote the midpoint of AB as M, the midpoint of BC as N, and the midpoint of CD as P. Then we have:

AM² = AB²/4 + BM²

BN² = BC²/4 + CN²

CP² = CD²/4 + DP²

DM² = DA²/4 + AM²

Note that the line segments AM, BN, CP, and DM are half the length of the diagonals AC and BD. We can now add all these equations together:

=> AM² + BN² + CP² + DM² = (AB² + BC² + CD² + DA²)/4 + (AC² + BD²)/4

Rearranging this equation gives us:

=> AC² + BD² = 2(AM² + BN² + CP² + DM²) - (AB² + BC² + CD² + DA²)

Now, recall that the four triangles we divided the parallelogram into are congruent. Therefore, AM = BN = CP = DM, and AB = CD, BC = DA. Substituting these equalities into the above equation, we get:

=> AC² + BD² = 4(AM² + BN²) - 4(AB² + BC²)

We can further simplify this expression using the fact that the diagonals of a parallelogram bisect each other. Therefore, AM = CP and BN = DM. Substituting these equalities gives us:

AC² + BD² = 4(AM² + BN²) - 4(AB² + BC²)

= 4(AM² + BN² - AB² - BC²)

= 4(AN² + BM²)

Recall that AN and BM are half the length of the sides of the parallelogram. Therefore, we can write:

=> AC² + BD² = 4(AN² + BM²) = 4(AB² + BC² + CD² + DA²)

This completes the proof. We have shown that the sum of the squares of the diagonals of a parallelogram is equal to the sum of squares of its sides.

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The magnitude spectrum of Fourier coefficients a[n] = 4 sin(nπ/3) is: |C[k]| = 0 so the phase spectrum is undefined. Fourier coefficients of x[n] = cos(2nπ/3) + sin(2nπ/5) for all other values of k, C[k] = 0, so the magnitude and phase spectra are zero. The Fourier coefficient for  cos(x) sin(y) = 1/2 (sin(x + y) – sin(x – y)) C[k] is zero when k is not equal to ±2/3 and ±2/5.

To compute the Fourier coefficients of a[n] = 4 sin(nπ/3), we use the formula:

C[k] = (1/N) * Σ[n=0 to N-1] a[n] e^(-j2πkn/N)

where N is the period of the signal (in this case, N = 6 since sin(nπ/3) has a period of 6), and k is the frequency index.

For k = 0, we have:

C[0] = (1/6) * Σ[n=0 to 5] 4 sin(nπ/3) = (4/6) * (sin(0) + sin(π/3) + sin(2π/3) + sin(π) + sin(4π/3) + sin(5π/3))

C[0] = (4/6) * (0 + √3/2 + √3/2 + 0 - √3/2 - √3/2) = 0

For k = ±1, we have:

C[1] = (1/6) * Σ[n=0 to 5] 4 sin(nπ/3) e^(-j2πn/6) = (4/6) * (sin(0) - sin(π/3) - sin(2π/3) + sin(π) + sin(4π/3) - sin(5π/3))

C[1] = (4/6) * (0 - √3/2 + √3/2 + 0 + √3/2 - (-√3/2)) = 0

C[-1] = (1/6) * Σ[n=0 to 5] 4 sin(nπ/3) e^(j2πn/6) = (4/6) * (sin(0) - sin(π/3) - sin(2π/3) + sin(π) + sin(4π/3) - sin(5π/3))

C[-1] = (4/6) * (0 - √3/2 + √3/2 + 0 + √3/2 - (-√3/2)) = 0

For all other values of k, we have C[k] = 0. Therefore, the Fourier series of a[n] is:

a[n] = 0

The magnitude spectrum is:

|C[k]| = 0

The phase spectrum is undefined.

To compute the Fourier coefficients of x[n] = cos(2nπ/3) + sin(2nπ/5), we use the formula:

C[k] = (1/N) * Σ[n=0 to N-1] x[n] e^(-j2πkn/N)

where N is the period of the signal (in this case, N = lcm(3, 5) = 15 since both cos(2nπ/3) and sin(2nπ/5) have periods of 3 and 5, respectively), and k is the frequency index.

For k = 0, we have:

C[0] = (1/15) * Σ[n=0 to 14] (cos(2nπ/3) + sin(2nπ/5)) = (1/15) * (5 + 0 - 5 + 0 + 5 + 0 - 5 + 0 + 5 + 0 - 5 + 0 + 5 + 0 - 5 + 0 + 5) = 5/3

To compute C[k] for k ≠ 0 and k ≠ 5, we can use the trigonometric identity:

cos(x) sin(y) = 1/2 (sin(x + y) – sin(x – y))

Let x = 2kπ/3 and y = 2nπ/5, then:

cos(2kπ/3) sin(2nπ/5) = 1/2 (sin(2kπ/3 + 2nπ/5) – sin(2kπ/3 – 2nπ/5))

= 1/2 (sin(10knπ/15 + 6kπ/15) – sin(10knπ/15 - 2kπ/15))

= 1/2 (sin((2k + 3n)π/3) – sin((2k - n)π/3))

The first term is zero when (2k + 3n) is an odd multiple of 3, and the second term is zero when (2k - n) is an odd multiple of 3. Therefore, C[k] = 0 when k + 3n is odd or k - n is odd.

For k = 3n, we have:

C[3n] = (1/15) * Σ[m=0 to 14] (cos(2mπ/3) sin(2nπ/5))

= (1/30) * Σ[m=0 to 14] (sin((2m + 3n)π/3) – sin((2m - n)π/3))

= (1/30) * (sin(5nπ/3) – sin(nπ/3) + sin(7nπ/3) – sin(5nπ/3) + sin(9nπ/3) – sin(7nπ/3) + sin(11nπ/3) – sin(9nπ/3) + sin(13nπ/3) – sin(11nπ/3) + sin(15nπ/3) – sin(13nπ/3) + sin(17nπ/3) – sin(15nπ/3) + sin(19nπ/3) – sin(17nπ/3))

= (1/30) * (sin(nπ/3) – sin(19nπ/3)) = 0

Therefore, the only non-zero coefficients are C[0] = 5/3 and C[5] = -5/3. The magnitude and phase spectra are:

|C[0]| = 5/3, arg(C[0]) = 0

|C[5]| = 5/3, arg(C[5]) = π

For all other values of k, C[k] = 0, so the magnitude and phase spectra are zero.

To compute the Fourier coefficients of cos(x) sin(y) = 1/2 (sin(x + y) – sin(x – y))

x[n] = 1/2 (sin(2nπ/3 + π/2) - sin(2nπ/3 - π/2)) * 1/2 (sin(2nπ/5) - sin(-2nπ/5))

Using the formula for the Fourier coefficients of a sinusoidal signal:

C[k] = (1/N) Σ[n=0 to N-1] x[n] e^(-j2πnk/N)

we can compute the Fourier coefficients for x[n]:

C[k] = (1/N) Σ[n=0 to N-1] x[n] e^(-j2πnk/N)

= (1/N) [Σ[n=0 to N-1] 1/2 sin(2nπ/3 + π/2) e^(-j2πnk/N) - Σ[n=0 to N-1] 1/2 sin(2nπ/3 - π/2) e^(-j2πnk/N)] [Σ[n=0 to N-1] 1/2 sin(2nπ/5) e^(-j2πnk/N) - Σ[n=0 to N-1] 1/2 sin(-2nπ/5) e^(-j2πnk/N)]

= 1/4 [C1(k-2/3) - C1(k+2/3)] [C1(k-2/5) - C1(k+2/5)]

where C1(k) is the Fourier coefficient of the signal cos(2nπ/3), which is given by:

C1(k) = (1/N) Σ[n=0 to N-1] cos(2nπ/3) e^(-j2πnk/N)

= (1/N) Σ[n=0 to N-1] 1/2 [e^(-j2πnk/3) + e^(j2πnk/3)]

= 1/2 [δ(k-1/3) + δ(k+1/3)]

Therefore, the Fourier coefficient C[k] is zero when k is not equal to ±2/3 and ±2/5.

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Answer:

The area of the triangle formed by the tangent to the graph of the function f(x) = (x-6)/(x-2) at the point x = 3 with the axes of the coordinate system is 28.125 square units.

Step-by-step explanation:

Differentiation is an algebraic process that finds the gradient (slope) of a curve.  At a point, the gradient of a curve is the same as the gradient of the tangent line to the curve at that point.

Given function:

[tex]f(x)=\dfrac{x-6}{x-2}[/tex]

Differentiate the given function using the quotient rule.

[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Quotient Rule for Differentiation}\\\\If $y=\dfrac{u}{v}$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{v \dfrac{\text{d}u}{\text{d}x}-u\dfrac{\text{d}v}{\text{d}x}}{v^2}$\\\end{minipage}}[/tex]

[tex]\implies f'(x)=\dfrac{(x-2)\cdot 1-(x-6)\cdot 1}{(x-2)^2}[/tex]

[tex]\implies f'(x)=\dfrac{4}{(x-2)^2}[/tex]

To find the gradient of the tangent lines at x = 3, substitute x = 3 into the differentiated function:

[tex]\implies f'(3)=\dfrac{4}{(3-2)^2}=4[/tex]

Substitute x = 3 into the function to find the y-value of the point on the curve when x = 3:

[tex]\implies f(3)=\dfrac{3-6}{3-2}=-3[/tex]

The slope-intercept form of a linear equation is y = mx + b, where m is the gradient and b is the y-intercept.

Substitute the point (3, -3) and the found gradient m = 4 into the slope-intercept formula and solve for b:

[tex]\begin{aligned}y&=mx+b\\\implies-3&=4(3)+b\\-3&=12+b\\b&=-15\end{aligned}[/tex]

Therefore, the equation of the tangent to the curve at point x = 3 is:

To calculate the point at which the tangent line intersects the x-axis, substitute y = 0 into the equation of the tangent:

[tex]\begin{aligned}\implies 0&=4x-15\\4x&=15\\x&=3.75\end{aligned}[/tex]

To calculate the point at which the tangent line intersects the y-axis, substitute x = 0 into the equation of the tangent:

[tex]\implies y=4(0)-15=-15[/tex]

Therefore, the tangent line intersects the x-axis at (3.75, 0) and the y-axis at (0, -15).  

This means the triangle formed by the tangent and the axes of the coordinate system has a height of 15 units and a base of 3.75 units.  

[tex]\begin{aligned}\textsf{Area of a triangle}&=\dfrac{1}{2}\sf \cdot base \cdot height\\\\\implies \sf Area&=\dfrac{1}{2} \cdot 3.75 \cdot 15\\\\&=\dfrac{225}{8}\\\\&=28.125\;\; \sf square\;units\end{aligned}[/tex]

Therefore, the area of the triangle is 28.125 square units.

The correct constraint that ensures no more than 2 projects will be selected is: (B). X1 + X2 + X3 + X4 ≤ 2

This restriction specifies that the corporation can choose no more than two projects since the total of the choice factors X1, X2, X3, and X4 is less than or equal to 2. The other restrictions do not specifically place a cap on the number of chosen projects.

Binary constraint C guarantees that X1 is more than or equal to X2, but it does not place a cap on the number of projects that can be chosen.

The three-way constraint D does not guarantee that the corporation chooses no more than two projects, but it does limit the sum of X1, X2, and X3 to be less than or equal to X4.

Therefore, the correct option is (B). X1 + X2 + X3 + X4 ≤ 2

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The numeric value of the inverse function of f(x) at x = 10 is given as follows:

f –1(10) = 3.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which:

From the table, the parameters are given as follows:

Hence the function is defined as follows:

y = 3x + 1.

To obtain the inverse function, we exchange the variables x and y and then isolate y, thus:

x = 3y + 1

3x = x - 1

y = (x - 1)/3

Hence the numeric value of the inverse function at x = 10 is given as follows:

y = (10 - 1)/3

y = 3.

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The required Levi has 28 ounces of pretzels in total.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
To solve this problem, you can use the expression:

total ounces of pretzels = number of bags × ounces of pretzels per bag

Substituting the given values, we get:

total ounces of pretzels = 6 bags × 14/3 ounces per bag

total ounces of pretzels = 28 ounces

Therefore, Levi has 28 ounces of pretzels in total.

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The measurement closest to the area of the paper surface of the Do-Not-Disturb sign once the circle has been cut out is 120.79 [tex]cm^2[/tex].

What is area of rectangle ?

In geometry, a rectangle is a four-sided flat shape with four right angles (90-degree angles) and opposite sides that are parallel and equal in length. The two pairs of opposite sides in a rectangle are congruent (i.e., have the same length), and the perimeter of a rectangle is the sum of the lengths of its four sides.

The area of a rectangle is a measure of the amount of space enclosed by the rectangle and is always expressed in square units. The formula for the area of a rectangle is A = length x width, where A is the area, length is the distance between the two longer sides of the rectangle (also called the length of the rectangle), and width is the distance between the two shorter sides (also called the width of the rectangle). The unit of measurement for the length and width of a rectangle must be the same for the area calculation to be correct.

The area of a rectangle is a useful measure when calculating the amount of material needed to cover a flat surface, such as the floor area of a room or the area of a piece of paper. It is also useful in solving geometry problems, such as finding the area of a composite shape made up of several rectangles or finding the dimensions of a rectangle given its area and one of its side lengths.

According to given information :

To find the area of the Do-Not-Disturb sign once the circle has been cut out, we need to subtract the area of the circle from the area of the rectangle.

The rectangle has dimensions of 17 cm by 8 cm, so its area is:

Area of rectangle = length x width = 17 cm x 8 cm = 136 [tex]cm^2[/tex]

The circle has a radius of 2.2 cm, so its area is:

Area of circle = π[tex]r^2[/tex] = π(2.2 cm)[tex]^2[/tex] ≈ 15.21 [tex]cm^2[/tex]

To find the area of the Do-Not-Disturb sign once the circle has been cut out, we need to subtract the area of the circle from the area of the rectangle:

Area of Do-Not-Disturb sign = Area of rectangle - Area of circle

= 136 [tex]cm^2[/tex] - 15.21 [tex]cm^2[/tex]

≈ 120.79 [tex]cm^2[/tex]

Therefore, the measurement closest to the area of the paper surface of the Do-Not-Disturb sign once the circle has been cut out is 120.79 [tex]cm^2[/tex].

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Answer:

D) 9x + 126 = 180

Step-by-step explanation:

We know

The (9x) angle combined with the 126 degrees angle must make 180 degrees. Looking at all the options, we see that D is the only reasonable answer.

Yes, This statement "f(n)/g(n) as n goes to infinity = 0" is true, in this little o notation means that f(n) grows much slower than g(n) as n becomes large.

"f(n)/g(n) as n goes to infinity = 0" means that as n approaches infinity, the ratio of f(n) to g(n) gets arbitrarily small. This is a formal way of saying that g(n) grows faster than f(n), or equivalently, that f(n) is "smaller" than g(n) in the long run. Specifically, the little-o notation represents a formal definition of this concept: f(n) is said to be "little-o" of g(n) (written as f(n) = o(g(n))) if and only if f(n)/g(n) approaches 0 as n approaches infinity. In other words, if for any positive constant ε, there exists a positive constant N such that for all n > N, |f(n)/g(n)| < ε.

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____The given question is incomplete, the complete question is given below:

I'm just trying to understand how in little o notation this is true:

f(n)/g(n) as n goes to infinity = 0?

The reading on a scale could be less after leaving the top floor and heading downward due to gravity.

All objects that have mass or energy are subject to the fundamental natural force of gravity. It is the force that draws two objects together and maintains the orbits of things like planets, galaxies etc. The force of gravity is proportionate to an object's mass and inversely linked to the square of the distance among both. As a result, the gravity around two objects will be more considerable and closer if they are together.

Several events, like maintaining people and other objects on the surface of the Earth, creating ocean tides, and causing objects to fall to the ground when dropped, are caused by gravity. Due to its importance in helping to comprehend the mobility and behavior of celestial objects, it is also a fundamental idea in the sciences of astrophysics. Because gravity has an influence on the body, the reading on a scale could be lower as you descend from the top floor.

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An expression that represents the amount of canned food collected so far by the three friends is 15x^2 + 4xy - 1.

An expression that represents the number of cans the friends still need to collect to meet their goal is 9x^2 - 10xy - 1.

From the information provided above, we can logically deduce the following number of canned food collection expressions for each friend:

Jessa; 9x^2

Theresa: 6x^2 - 4

Ben: 4xy + 3

Canned food collection goal: 24x^2 - 6xy - 2

Therefore, an expression that represents the total amount of canned food collected so far by the three friends can be calculated and written as follows;

Total amount collected = 9x^2 + 6x^2 - 4 + 4xy + 3

Total amount collected = 15x^2 + 4xy - 1

In order to meet the goal, they need to collect this amount:

Remaining canned foods = 24x^2 - 6xy - 2 - (15x^2 + 4xy - 1)

Remaining canned foods = 24x^2 - 6xy - 2 - 15x^2 - 4xy + 1

Remaining canned foods = 9x^2 - 10xy - 1.

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The height h for the base that is 5/4 units long is 3/5 cm.

A triangle is a two dimensional figure which consist of three vertices, three edges and three angles.

Sum of the interior angles of a triangle is 180 degrees.

Given is a triangle and the three side lengths.

We have the area of a triangle is,

Area of the triangle = [tex]\frac{1}{2}[/tex] × base × height

We have base = 5/4 cm

Area of the triangle can be found using the Heron's formula.

Heron's formula states that,

Area of a triangle = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]

where s is the semi perimeter = (a + b + c) / 2 and a, b and c are the side lengths.

Given 5/4 cm, 1 cm and 3/4 cm are the side lengths.

s = (5/4 + 1 + 3/4) / 2 = 3/2

Area = [tex]\sqrt{\frac{3}{2}(\frac{3}{2} -\frac{5}{4} )(\frac{3}{2}-1)(\frac{3}{2}-\frac{3}{4} ) }[/tex]

        = [tex]\sqrt{\frac{9}{64} }[/tex]

        = [tex]\frac{3}{8}[/tex] cm²

Substituting in the formula A = [tex]\frac{1}{2}[/tex] × base × height,

[tex]\frac{3}{8}[/tex] = [tex]\frac{1}{2}[/tex] × [tex]\frac{5}{4}[/tex] h

h = [tex]\frac{3}{5}[/tex] cm

Hence the height is 3/5 cm.

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This argument is best interpreted as inductive. The presence of empirical evidence in the form of research data suggests that the conclusion is based on empirical observations and generalization.

The argument uses evidence to make a generalization about the talkativeness of men and women, which is the characteristic of inductive reasoning. Additionally, the lack of logical or deductive inferential links between premises and conclusion supports the inductive interpretation of the argument.on:

Inductive reasoning is a type of reasoning in which a conclusion is drawn based on observations or evidence, rather than from logical deduction. Inductive reasoning involves making generalizations from specific observations or examples

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(a) The probability of drawing the first club is 13/52 (since there are 13 clubs in the deck out of 52 total cards).

After that, there are 12 clubs left out of 51 cards, so the probability of drawing a second club is 12/51.

Similarly, the probability of drawing a third club is 11/50, the probability of drawing a fourth club is 10/49, and the probability of drawing a fifth club is 9/48. Therefore, the probability of drawing a 5-card hand with all clubs is: (13/52) x (12/51) x (11/50) x (10/49) x (9/48) = 0.000495% (rounded to six decimal places)

(b) The number of ways to choose 3 aces out of 4 is (4 choose 3) = 4, and the number of ways to choose 2 kings out of 4 is also (4 choose 2) = 6. The remaining card can be any of the 44 non-aces and non-kings in the deck. Therefore, the number of 5-card hands that contain 3 aces and 2 kings is: 4 x 6 x 44 = 1056

The total number of 5-card hands is (52 choose 5) = 2598960. Therefore, the probability of drawing a 5-card hand with 3 aces and 2 kings is: 1056/2598960 = 0.04074% (rounded to five decimal places)

(c) There are four suits in a standard deck, so there are four ways to choose the suit that will have 4 cards in the hand. The number of ways to choose 4 cards from a single suit is (13 choose 4) = 715. The remaining card can be any of the 39 cards in the other three suits. Therefore, the number of 5-card hands that contain 4 cards of the same suit and 1 card of another suit is: 4 x 715 x 39 = 111540

The total number of 5-card hands is (52 choose 5) = 2598960. Therefore, the probability of drawing a 5-card hand with 4 cards of the same suit and 1 card of another suit is:

111540/2598960 = 4.29% (rounded to two decimal places)

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Driving without an app would have been a much different experience. Instead of having turn-by-turn directions, one would need to rely on maps and other forms of navigation, such as written directions from friends or family, or using landmarks and street signs.

Besides converting distances, there are a number of other math concepts that one might need to use when driving without an app. For example, one might need to use basic arithmetic to calculate the estimated time of arrival based on average speed and distance. One might also need to use spatial reasoning to understand the layout of a city and the relative location of different streets and landmarks. Additionally, one might need to use problem-solving skills to make decisions about which route to take and how to handle unexpected road closures or detours.

[tex]{\Large \begin{array}{llll} y=ab^x \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x=2\\ y=360 \end{cases}\implies 360=ab^2\implies 360=abb\implies \cfrac{360}{b}=ab \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x=3\\ y=216 \end{cases}\implies 216=ab^3\implies 216=abb^2\implies \stackrel{\textit{substituting from above}}{216=\left( \cfrac{360}{b} \right)b^2} \\\\\\ 216=360b\implies \cfrac{216}{360}=b\implies \boxed{\cfrac{3}{5}=b} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{since we know that}}{360=ab^2}\implies 360=a\left( \cfrac{3}{5} \right)^2\implies 360=\cfrac{9a}{25} \\\\\\ \cfrac{25}{9}\cdot 360=a\implies \boxed{1000=a}~\hfill {\Large \begin{array}{llll} y=1000\left( \frac{3}{5} \right)^x \end{array}}[/tex]

The ratio of bananas to strawberries is 11:3.

A ratio is a comparison between two amounts that is calculated by dividing one amount by the other. The quotient a/b is referred to as the ratio between a and b if a and b are two values of the same kind and with the same units, such that b is not equal to 0. Ratios are represented by the colon symbol (:). As a result, the ratio a/b has no units and is represented by the notation a: b.

Given:

Number of bananas = 11 ounces,

Number of strawberries = 3 ounces

The ratio of bananas to strawberries

= 11/3

= 11:3.

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Freeda's weekly take home pay based on the 48 hours a week Freeda works with an hourly rate of $13.75 and an over time rate of a time and a half, obtained by finding the difference between the sum of earnings and the sum of deduction is $813.75

A salary rate is the amount received regular for a specified period.

The number of hours worked a week = 48 hours

Number of hours considered overtime = Time over 40 hours

Amount earned for normal working hours = $13.75 per hour

Amount she earns as bonus per week = $125

The deductions per week are;

FICA

Federal income tax = $5.50

State income tax = $2.75

401K = $10.00

Insurance = $8.00

Weekly take home (net) pay = Total weekly earnings - Total weekly deductions

Number of overtime hours Freeda works each week = 48 - 40 = 8

Freeda works 8 hours overtime each week

Her weekly earnings = 40 × 13.75 + 8 × 1.5 × 13.75 + 125 = 840

Freeda's weekly earning = $840

Weekly deductions = 5.5 + 2.75 + 10.00 + 8 = 26.25

Weekly take home (net) pay = $840 - $26.25 = $813.75

Freeda's weekly take home pay is $813.75

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Answer:

find the given numbers on the number line

Answer:

130.8

Step-by-step explanation:

Use law of cosine

12^2=9^2+4^2-2*9*4cos

144=97-72cos

47=-72cos

(Use cosine inverse now)

Cos-1(47/-72)

Largest angle is 130.8 when rounded to the nearest then the

The solution is, in cleaning she spend the most time doing.

In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.

here, we have,

Alicia listens to a podcast for hour.

She reads for hour.

Then she cleans her room 2 1/5 for hour.

we know that,

1 hour = 60 mint.

so, we get,

1) 60 mint

2) 60 mint

3) 11/5 * 60 = 132 mint.

Hence, The solution is, in cleaning she spend the most time doing.

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Answer:

Tyler is Correct

Step-by-step explanation:

Total Hike = 2.25 (0.75 + 1.5)

2.25/0.75 = 3

Tyler is correct, since the total hike is 3 times as long as the distance travelled from the parking lot

The equation of the line through point (6,2) and perpendicular to 4x+5y+7=0 is 5x-4y+14=0.

To find the equation of a line perpendicular to another line, we first need to determine the slope of the original line. We can rewrite the original line as 5y = -4x - 7, which is in the slope-intercept form y = (-4/5)x - 7/5. The slope of this line is -4/5.

Since the line we want is perpendicular to this line, it must have a slope that is the negative reciprocal of -4/5. The negative reciprocal is 5/4. We can use the point-slope form of the equation of a line to find the equation of the new line. Plugging in the point (6,2) and the slope 5/4, we get:

y - 2 = (5/4)(x - 6)

Simplifying and rearranging, we get:

5x - 4y + 14 = 0

So, the equation of the line through the point (6,2) and perpendicular to 4x+5y+7=0 is 5x-4y+14=0.

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The constant of proportionality is 2. (True)

The equation n = 2m represents this relationship. (True)

Frederick needs 5 cups of water for 10 tablespoons of the mic. (False)

Point (2, 4) means 2 tablespoons of ms is needed for 4 cups of water. (False)

In mathematics, a line's slope, also known as its gradient, is a numerical representation of the line's steepness and direction

If a line passes through two points (x₁ ,y₁) and (x₂, y₂) ,

then the equation of a line is

y - y₁ = (y₂- y₁) / (x₂ - x₁) x (x - x₁)

To find the slope;

m =  (y₂- y₁) / (x₂ - x₁)

Given:

Frederick is making hot chocolate from a mix.

The graph models, the relationship between tablespoons of mixing cups of water.

Let m be the variable that represents the number of cups of water and n is the number of tablespoons in the mix.

From the graph;

The line passes through (0, 0) and (1, 2),

So, the equation of the line is,

n - 0 = (0 - 2)/(0 - 1) m

n = 2m

Therefore, the constant of proportionality is 2.

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The measure of angle B in given triangle is approximately 59°.

Triangles are fundamental three-sided polygons having three internal angles. Due to the connection between the three vertices, it is one of the basic geometric shapes.

When combined, any two triangle sides will always be longer than the third side. A triangle's surface area is determined by the product of its base and height. The angles are created by connecting the triangle's three sides end to end at a single point. The sum of the triangle's three angles is 180 degrees.

The inverse tangent function, often known as tan1, can be used in this situation. Using the following equation:

tan(B) = adjacent/opposite

where the lengths of the triangle's opposite and adjacent sides, which together make up the desired angle B, are given. In this case, we know that side b is next to angle B and that side an is perpendicular to it.

We thus have:

tan(B) = a/b = 500/300 = 5/3

To find the value of angle B, we can take the inverse tangent of both sides of the equation, using table of trigonometric functions. We get:

B = tan⁻¹(5/3) ≈ 59°

Hence the correct answer is 59°

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Answer:

1.8

Step-by-step explanation:

Enter the data provided into any of the regression calculators available free online and it will plot and provide the regression equation

The equation provided by one such calculator is
y = 1.8204x +  96.6608

where y = sales in $ and x = temperature in °F

From the above it can be seen that the slope of the line is 1.8204 which, rounded to 1.8 to one decimal place

Answer:

b) - 11

Step-by-step explanation:

The two triangles ΔJKL and ΔGHK are similar since
LK = 2LH
JK = 2JK

(ratios of sides are same)

and the included angle ∠K is common to both triangles

So the sides are in the ratio 2:1 for larger to smaller triangle. Each side of the larger triangle is twice the length of the corresponding side of the smaller triangle

This means the ratio of side JL of the larger triangle ΔJKL must be twice the length of side GH of the smaller triangle ΔGHK

i.e.
JL = 2 x GH

We are given these sides as expressions in x
∴ x + 27 = 2(2x + 30)

x + 27 = 4x + 60

Subtract 4x from both sides:
x - 4x + 27 = 4x - 4x + 60

-3x + 27 = 60

Subtract 27 from both sides-3x = 60 - 27 = 33

==> 1

- 3x = 33

Divide by -3 both sides

-3x/-3 = 33/-3 = -11

x = -11

Answer b)

Do not be confused by the fact that x is negative. Many students get confused because they associate x as a length. x is just a variable used in the equations

The actual lengths will be positive
GH = 8 and JL = 16

You can work it out yourself