The term that describes the situation is called: stabilizing selection.
What is Stabilizing Selection?Unlike disruptive selection (diversifying selection) that tends to favor extreme traits when changes occur, stabilizing selection is defined as changes in population genetics in which extreme traits are not favored, rather, traits that are of intermediate variants are most favored and selected for.
Stabilizing selection can simply be described as the exact opposite of disruptive selection.
In the scenario given, traits of producing fewer starlings or more are extreme traits that are not favored and have reduced fitness. Intermediate variants of producing moderate number of starlings that have high fitness demonstrates the type of selection that is referred by the term called: stabilizing selection.
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does anyone want to play tarkov and run customs or something lol? add me on disc destructer11#0001
Answer:
Step-by-step explanation:
Mabye later
How much work is performed lifting in order to lift a 50.0 kg block 7.00 meters? Use g=9.81 m/s^2
The work done in lifting the block is 3430 J
Calculating workFrom the question, we are to determine the work done in lifting the block
Using the formula,
Work done = mgh
Where m is the mass
g is the acceleration due to gravity
and h is the height
From the question,
m = 50.0 kg
g = 9.81 m/s²
h = 7.00 m
Putting the parameters into the formula,
Work done = 50.0 ×9.8 × 7.00
Work done = 3430 J
Hence, the work done in lifting the block is 3430 J
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Solve for x in the diagram below
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Equation:}[/tex]
[tex]\text{3x = 120}^\circ[/tex]
[tex]\huge\textbf{Simplifying:}[/tex]
[tex]\text{3x = 120}^\circ[/tex]
[tex]\huge\textbf{Divide \boxed{\bf 3} to both sides:}[/tex]
[tex]\rm{\dfrac{3x}{3} = \dfrac{120}{3}}[/tex]
[tex]\huge\textbf{Simplify it:}[/tex]
[tex]\rm{x = \dfrac{120}{3}}[/tex]
[tex]\rm{x = 40}[/tex]
[tex]\huge\textbf{Therefore, your answer should be:}[/tex]
[tex]\huge\boxed{\mathsf{x =}\frak{40}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
12 x (3 + 2 to the second power) divied by 2 - 10
Answer:
32Step-by-step explanation:
Assuming that the question is:
12 * (3 + 2^2) : 2 - 10 = remember PEMDAS
12 * (3 + 4) : 2 - 10 =
12 * 7 : 2 - 10 =
84 : 2 - 10 =
42 - 10 =
32
Answer:
-10.5
Step-by-step explanation:
[tex]\frac{12*(3+2^2)}{2-10}[/tex]
2²= 4
3+4=7
12×7=84
2-10=-8
84÷-8= -10.5
Hope it helped, comment below if you need more assistance! :)
Find the slope of the line on the graph.write your answer as a fraction or a whole number, not a mixed number
Answer:
slope = [tex]-\frac{1}{2}[/tex] if it were in an
Step-by-step explanation:
the graph is a negative and will therefore have a negative slope. to find the slope, pick a point on the graph and find the [tex]\frac{rise}{run}[/tex].
for instance, start with the point (0,1). Then go down 1 and left 2 to get to the next point on the graph (2,0). 1 is the "rise" and 2 is the "run" hence -1/2 being the slope.
you could also use the slope formula: [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
point 1: (0,1) (x₁ ,y₁)
point 2: (2,0) (x₂ , y₂)
[tex]\frac{0-1}{2-0} =-\frac{1}{2}[/tex]
Prove or disprove the following. In any group of two or more people, there are always at least two people who have the same number of friends. Assume that if a person p is a friend of a person q then q is also a friend of p.
Yes we can prove that in the group of more than two people that there are at least two people that have the same number friends given the condition here.
How to go about this proofLet us create a variable P. P is an individual called Joe. Now Joes seems to know all at this party. This tells us that all at this party should at least know him.
We have the set {1,2,...n-1} , given that the minimum number of persons that one person knows is 1.
Let us assume we have Harry. Harry is a party crasher who came to the party. Hence it is possible that someone like Joe that knows all at the party may not even know him. Hence the maximum persons that a person would know is given to be n. The set would then be {0, 1,...,n-2}.
There are n elements in the 2 sets that we have above. Given that n people are at this function, and there are n possibilities for the number that one person can know of the participants, then we can say that at least two people can then know equal number of persons at the party.
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A conjecture and the paragraph proof used to prove the conjecture are shown. Given: angle 2 is congruent to angle 3. Prove: angle 1 and angle 3 are supplementary. A horizontal line. Two rays extend from upper region of the line diagonally down to the left and right and intersect the line forming interior angles labeled as 2 and 3 and an exterior angle labeled as 1. Drag an expression or statement to each box to complete the proof. Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. ∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Response area. Therefore, m∠1+ Response area = 180° by the definition of supplementary. It is given that ∠2≅ Response area, so m∠2=m∠3 by the Response area. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary by the definition of supplementary. angle congruence postulatelinear pair postulatem∠2m∠3∠3∠2
The fill up of the missing points are:
∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Linear Postulate theorem. Therefore, m∠1+m∠2 = 180° by the definition of supplementary. It is given that ∠2≅ ∠3, so m∠2=m∠3 by the Congruence Postulate theorem. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary.What is the angles about?Using the image attached, one can see that m<1 and m<2 creates a kind of linear pair hence one can say they are both supplementary using the law of LINEAR POSTULATE THEOREM.
Based on the fact that the supplementary angles add up to 180 degrees, therefore:
m<1 + m<2 = 180 - will be equation 1
Since the interior angles m<2 and m<3 are known to be equal based on the CONGRUENCE POSTULATE THEOREM. Therefore
m<2 = m<3 --- will be equation 2
Then place eqn. 2 into eqn. 2
m <1 + m <3 = 180
This connote that m<1 and m<3 are supplementary.
Hence, The fill up of the missing points are:
∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Linear Postulate theorem. Therefore, m∠1+m∠2 = 180° by the definition of supplementary. It is given that ∠2≅ ∠3, so m∠2=m∠3 by the Congruence Postulate theorem. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary.Learn more about the angle from
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Do you think any resulting prediction would be more or less reliable than your original one?
No, The resulting prediction would be more or less reliable than your original one.
Importance:
Prediction is a forecast or a prophecy. An example of a prediction is a psychic telling a couple they will have a child soon, before they know the woman is pregnant. A statement of what will happen in the future.
Predictions provide a reference point for the scientist. If predictions are confirmed, the scientist has supported the hypothesis. If the predictions are not supported, the hypothesis is falsified. Either way, the scientist has increased knowledge of the process being studied.
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To find proportion of the area under the normal curve between two Z scores that are both above the mean, it is necessary to examine the ______. Group of answer choices
It is necessary to imagine the sum of the areas between each z-score and the average.
Given as the ratio of the area under the normal curve between two z-scores, both above average.
The Z score accurately measures the number of standard deviations above or below the mean of the data points.
The formula for calculating the z-score is
z = (data points – mean) / (standard deviation).
It is also expressed as z = (x-μ) / σ.
A positive z-score indicates that the data points are above average.A negative z-score indicates that the data points are below average.A z-score close to 0 means that the data points are close to average. The normal curve is symmetric with respect to the mean and needs to be investigated.Therefore, to find the percentage of the area under the normal curve between two z-scores, both above the mean, you need to look at the sum of the areas between the z-score and the mean.
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HELP ASAP PLEASE
Select the correct answer. Figure 1 has been transformed to produce figure 2. Which notation describes this transformation?
Figure 1 was translated using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.
What is transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.
Translation is the movement of a point either up, down, left or right on the coordinate plane.
Figure 1 was translated 9 units left and 2 units up using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.
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El rio Lempa sirve de linea fronteriza entre Honduras y El Salvador, mide 300km
de largo. ¿Cuántos metros mide este rio?
Answer:
El río mide:
300000 metros.
Step-by-step explanation:
1 km = 1000 metros
300 km = 300 * 1000 = 300000 metros
...
How many 4-digit positive integers are there for which there are no repeated digits, or for which there may be repeated digits, but all digits are odd?
The number of ways of arranging 4-digit positive integers with no repeated digits is 4536 ways and number of ways of 4-digit positive integers with repeated digits, but all digits are odd is 625 ways.
In this question,
Positive integers are 0,1,2,3,4,5,6,7,8,9
Total number of integers = 10
This can be solved by permutation concepts.
Case 1: 4-digit positive integers with no repeated digits,
First digit, cannot be zero. So remaining 9 digits.
Second digit, can be any digit other than the first digit. So 9 digits.
Third digit, can be any digits other than first and second. So 8 digits.
Fourth digit, can be any digits other than first, second, third digit. So 7 digits.
Thus, Number of ways of 4-digit positive integers with no repeated digits ⇒ (9)(9)(8)(7)
⇒ 4536 ways.
Case 2: 4-digit positive integers, there may be repeated digits, but all digits are odd
Odd integers are 1,3,5,7,9
Number of digits = 5
In this case, we can repeat the digits. So all places can have 5 possibilities.
Thus number of ways of 4-digit positive integers with repeated digits, but all digits are odd = (5)(5)(5)(5)
⇒ 625 ways.
Hence we can conclude that the number of ways of arranging 4-digit positive integers with no repeated digits is 4536 ways and number of ways of 4-digit positive integers with repeated digits, but all digits are odd is 625 ways.
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why is there always more than one parallelogram with the same area and base
Answer:
If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.
There are infinitely many parallelograms with the same area and base due to the variability of the height.
We have,
There is always more than one parallelogram with the same area and base because the height of the parallelogram can vary while keeping the base and area constant.
The formula to calculate the area of a parallelogram is:
Area = base × height
If the base and area of a parallelogram are fixed, we can rearrange the formula to solve for the height:
height = Area/base
Since the height can be any value as long as it satisfies the above equation, there are infinitely many possible heights for a given base and area.
And for each height, there will be a unique parallelogram with that base and area.
Imagine a rectangle as a special case of a parallelogram where all angles are 90 degrees.
For a given base and area, you can have an infinite number of rectangles by varying the height.
Each rectangle will have different side lengths, but they will all have the same base and area.
Thus,
The variability of the height while keeping the base and area constant allows for the existence of multiple parallelograms with the same area and base.
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Given g of x equals cube root of the quantity x plus 6, on what interval is the function negative? (–∞, –6) (–∞, 6) (–6, ∞) (6, ∞)
The interval where the function is negative is (–∞, –6)
How to determine the negative interval?The function is given as:
[tex]f(x) = \sqrt[3]{x + 6}[/tex]
Set the radicand to less than 0
x + 6 < 0
Subtract 6 from both sides
x < -6
Rewrite as an interval notation.
(–∞, –6)
Hence, the interval where the function is negative is (–∞, –6)
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Find the inverse of the function.
y = 2x^2 -4
Answer:The inverse of the function y = 2x^2 –4 is;. y = √(x +4)/2To find the inverse of the function;We must first solve for x in the equation as follows;y = 2x² - 4y + 4 = 2x²x² = (y +4)/2x = √ (y +4)/2By swapping x and y; we then have;y = √(x +4)/2
Four pounds of apples cost $5 How much would 10 pounds o apples cost?
Answer:
Step-by-step explanation:
plus all of them 5times 10
ppppp-pp help please.
Answer:
There are two complex roots:
[tex]-3\pm i[/tex]============
Given equation:x² - 6x + 10 = 0The standard form is:
ax² + bx + c = 0Compared we can find values of the coefficients and the constant:
a = 1, b = - 6, c = 10Substitute these values into quadratic formula:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
and work out roots:
[tex]x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4*1*10} }{2*1}=x=\dfrac{6\pm\sqrt{36-40} }{2}=\dfrac{6\pm2\sqrt{-1} }{2}=3 \pm i[/tex]
What is the conditional probability that, when flipping a non-biased coin four times, there are at least two hs, given that the first flip is a h?
The conditional probability that, when flipping a non-biased coin four times, there are at least two heads, given that the first flip is a head, is 3/4.
Calculating the Conditional Probability:
Let us assume that getting a head in the first flip of coin is event B
Also, let us assume that getting a head in on of the remaining three flips is A
Then we have to find the probability of A given B, that is, P(A|B).
The formula for conditional probability is given as follows,
P(A|B) = P (A∩B) / P(B)
The probability of getting two heads, P(A∩B) = 3/8
The probability of getting head in the first flip, P(B) = 1/2
∴ P(A|B) = (3/8) / (1/2)
P(A|B) = 3/4
Thus, the conditional probability of getting at least two heads, given that the first flip is a head is 3/4.
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What is the probability that any given car will have a brake failure if it is make a?
The probability that any given car will have a brake failure if it is make a is 0.0065%
How to determine the probability?The complete question is added as an attachment
From the table in the question, we have:
P(Brake failure|car a) = 0.0065%
The above represents the required conditional probability
Hence, the probability that any given car will have a brake failure if it is make a is 0.0065%
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Answer: The probability that any given car will have a brake failure if it is making A, is 0.0065%.
Step-by-step explanation:
I got it right on Edmentum!
1. in the function equation ff (xx ) = 1500 (1.43)^x,is this growth or decay? what is the percent of growth/decay? what is the initial value? 2. the number of bacteria in a sample can be modeled by the equation yy = 75(.8)^x, where y is the number of bacteria and x is the number of days elapsed. what is the rate of decay? 3. monthly car sales for a certain type of car are $350,000 and sales are depreciating at a rate of 3% per month. a. write an equation to represent this situation. b. what will the monthly sales be after 8 months? 4. two auction websites start with 100 members each. at site a, the number of members doubles each month. at site b, 500 new members are added each month. between months 5 and 6, which website gains more members and by how much?
1. The given function is growth.
The percent of growth is 43%.
The initial value is 1500.
2. The rate of decay is 20% per day.
3. a. The exponential equation representing the sales after x months for the given situation is 3500000(0.97ˣ).
b. The monthly sales after 8 months will be $274,310.1758.
4. Between months 5 and 6, the website gains more members. The difference between the two sites for this period is 2700 members.
An exponential function is of the form f(x) = (a)(bˣ), where a is the initial value, and b is the exponential factor.
When b > 1, we have growth, and when b < 1, we have decay or depreciation.
1. Given function, f(x) = 1500(1.43ˣ).
The exponential factor in this function is 1.43, which is greater than 1, thus we have growth.
The percent of growth = (1.43 - 1)*100% = 43%.
The initial value = 1500.
2. Given an equation, y = 75(.8ˣ).
The exponential factor in this function is 0.8, and x signifies the days passed.
Thus, the rate of decay = (1 - 0.8)*100% per day = 20% per day.
3. Initial value = $350,000.
Rate of depreciation = 3% per month.
a. Thus, the equation for the sales after x months can be given as:
f(x) = 350000(1 - 0.03)ˣ = 350000(0.97ˣ).
b. To find the monthly sales after 8 months, we substitute x = 8.
Sales = 350000(0.97⁸) = $274,310.1758.
4. Initial members for both sites = 100.
For site a:-
Members double each month.
This makes an exponential equation, f(x) = 100.(2ˣ), where x is the number of months.
The growth between months 5 and 6 can be calculated as:
f(6) - f(5) = 100.(2⁶) - 100.(2⁵) = 6400 - 3200 = 3200.
For site b:-
500 new members are added each month.
This makes a linear equation, f(x) = 100 + 500x, where x is the number of months.
The growth between months 5 and 6 can be calculated as:
f(6) - f(5) = (100 + 500*6) - (100 + 500*5) = 3100 - 2600 = 500.
Thus, between months 5 and 6, the website a gains more members. The difference between the two sites for this period is 2700 members.
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20 POINTS
good morning, can you please help me
Answer:
Khan Academy.
Step-by-step explanation:
You can go on khan academy and search up "percentages and numbers." The videos should immediately pop up. there are also lessons if you don't want to risk getting your problem wrong. If you are still confused and do not understand please just comment and I will respond.
How many more times intense, to two decimal places, was the 2011 earthquake in Japan that measured 9.0 on the Richter scale than the 1905 earthquake in San Francisco that measured 8.1 on the Richter scale?
Using the properties of logarithms, it is found that the earthquake in Japan in 2011 was 12.92 times more severe.
How to find the ratios of the intensity of earthquakes?As given in the problem, the intensities of the earthquakes are given by logarithms of base 10. Then, supposing that the intensities are [tex]R_1, R_2 > 0, R_1 > R_2[/tex], the ratio of the intensities is given by:
[tex]10^{\frac{R_1}{R_2}}[/tex]
The intensities for this problem are [tex]R_1 = 9, R_2 = 8.1[/tex], hence the ratio is:
[tex]10^{\frac{9}{8.1}} = 12.92[/tex]
The earthquake in Japan in 2011 was 12.92 times more severe.
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5/8 + 1 1/4 = x/10
solve for x
Answer:
x = 75/4
Step-by-step explanation:
5/8 + 1 1/4 = x/10
5/8 + 5/4 = x/10
15/8 = x/10
8x = 15 × 10
8x/8 = 150/8
x = 150/8
x = 75/4
Based on the graphs of the equations y = x + 7 and y = x2 – 3x + 7, the solutions are located at points:
The correct option is A. (4, 11) and (0, 7).
The solution of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points: (4, 11) and (0, 7).
What is the system of linear equation?Estimate the y-intercept, slope, and express the equation in the form of the y-intercept (y = mx + b) to find the graphed equation. The slope is the difference between the y- and x-axis values.
A graph equation is an equation in graph theory where the unknown is a graph. Isomorphic ideas are one of the key issues in graph theory.
The equations are; y = x + 7 and y = x² - 3x + 7
At the solution, the u-values are equal, which gives;
y = y
x + 7 = x² - 3·x + 7
x² - 3·x + 7 - (x + 7) = 0
x² - 4·x = 0
x·(x - 4) = 0
x = 4, or x = 0
When x = 4, y = 4 + 7 = 11
When x = 0,
y = 0 + 7 = 7
Therefore, the solution for the equations y = x + 7 and y = x² - 3x + 7 are are located at points: (4, 11) and (0, 7).
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The complete question is-
Based on the graphs of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points:
A. (4, 11) and (0, 7)
B. (4, 11) and (–7, 0)
C. (–7, 0) and (1.5, 4.75)
D. (1.5, 4.75) and (0, 7)
Graph the function shown g(x)=-|x-4|
Using translation concepts, the graph of g(x) = -|x - 4| is shown at the end of the answer.
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
The graph of g(x) = -|x - 4| is the graph of f(x) = |x| with these following changes:
Reflection over the x-axis.Shift right of 4 units.At the end of the answer, the graph shows functions f(x) in red and g(x) in blue.
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P(A)=[tex]\frac{9}{20}[/tex],P(B)=[tex]\frac{3}{5}[/tex],P(A∩B)=[tex]\frac{27}{100}[/tex] ,P(A∪B)=?
The value of the probability P(A∪B) is 39/50
How to determine the probability?The given parameters are:
P(A)= 9/20
P(B) = 3/5
P(A∩B) = 27/100
To calculate the probability P(A∪B), we make use of the following equation
P(A∪B) = P(A) + P(B) - P(A∩B)
So, we have:
P(A∪B) = 9/20 + 3/5 - 27/100
Evaluate the expression
P(A∪B) = 78/100
Simplify
P(A∪B) = 39/50
Hence, the value of the probability P(A∪B) is 39/50
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Can someone help me please
Answer: B. [tex]12log(x)-4log(y)[/tex]
Step-by-step explanation:
Properties of logs:
[tex]log_{a} (\frac{B}{C} )=log_{A}B-log_{A} C[/tex]
[tex]logA^B = BlogA[/tex]
So, [tex]log\frac{x^{12} }{y^4} =logx^{12} -logy^4 =12log(x)-4log(y)[/tex]
It would be 12 log x - 4 log y (B)
Make a study of minimum amount of basic nutrients needed for a 12-year-old child to survive in the world
Basic nutrients a 12-year-old needs are:
ProteinCarbohydratesFatsCalciumIronFolate FiberVitamin AVitamin CWhat are nutrients?A nutrient is a material that an organism requires in order to survive, grow, and reproduce. Animals, plants, fungi, and protists are all required to consume dietary nutrients. Nutrients can be absorbed by cells for metabolic reasons or expelled by cells to form non-cellular structures such as hair, scales, feathers, or exoskeletons. Some nutrients, such as carbohydrates, lipids, proteins, and fermentation products (ethanol or vinegar), can be metabolically reduced to smaller molecules in the process of generating energy, resulting in the end products of water and carbon dioxide.The following are the nine nutrients that a youngster should consume on a daily basis:
ProteinCarbohydratesFatsCalciumIronFolate FiberVitamin AVitamin CTherefore, basic nutrients a 12-year-old needs are given.
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I am a 3 digit positive number. The sum of my digits is 18. My middle digit is the product of -2 and -4. My first digit is 3^2.
Hi! ⋇
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
The first digit of this number is 3², which is 9.
The Number is : 9xx
________
The second digit is: -2·(-4)=8.
The Number is : 98x.
________
The sum of all the digits is 18. This gives us an equation that we can solve in terms of x!
[tex]\multimap\sf{9+8+x=18}[/tex] (x is the digit we are looking for)
Now it takes a little arithmetic to find x :)
[tex]\multimap\sf{17+x=18}[/tex]. Just subtract 17 from both sides to find x!
[tex]\multimap\sf{x=1}[/tex]. And Now, can you see the number!
It's 981, of course :)
Hope this made sense to you!
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
[tex]\large\it{\overbrace{Calligrxphy}}[/tex]
i’ll give brainliest!!
(last choice is d^2sqrt7e)
Answer:
D (the last choice)
Step-by-step explanation:
Taking the fourth root of each element individually:
49^(1/4) = sqrt(7)
(d^8)^(1/4) = d^2
(e^2)^(1/4) = sqrt(e)
Multiplying them back together:
sqrt(7) * d^2 * sqrt(e) = d^2 * sqrt(7e)
Answer:
The last bubble (that of which is cut from the screen) is simplified.
Step-by-step explanation:
The provided equation is simplified by following these steps:
[tex](49d^{8}e^2)^\frac{1}{4}[/tex]
= [tex](49)^\frac{1}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}[/tex]
[tex](7)^\frac{2}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}[/tex]
=[tex]\sqrt{7} (d^2)(\sqrt{e})[/tex]