Mr. Takaya can eat three slices of pizza in five minutes. If he continues to eat at the same rate, how many slices
could he eat in half of an hour?

Answer:

1:2

Step-by-step explanation:

Answer:

-2x-6

Step-by-step explanation:

Distribute -2x -2(3) = -2x-6

Answer:

Let x = Kilometers  by bus  

then x + (x + 350) = 1100

2x = 750

x = 375 by bus

x - 350 + x = 1100

2x = 1450

x = 725 by train

i hope this helps a little bit

Answer:

19 girls snd 10 boys

Answer:

68

Step-by-step explanation:

Their are 77 total, 77-3= 74-4= 70-2= 68

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:

1/2 M₀ = M₀ exp(12k)

for some decay constant k. Solve for this k :

1/2 = exp(12k)

ln(1/2) = 12k

k = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass M₀, the mass M remaining after time t is given by

M = M₀ exp(kt )

So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives

M = 590 exp(36k) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

Answer:

5.1

Step-by-step explanation:

hope it helps thank you

Answer:

We are 95 percent confident that the mean word length for all papers submitted by students in humanities programs is between 20,995 words and 22,905 words

Step-by-step explanation:

The confidence interval is used to predict the mean for the entire humanities program, not just the sample.

Answer:

1. y = 32

2. x = 6

3. -33 = n

4. a = -15.6

Step-by-step explanation:

1.

y-23=55

 +23  +23          (23 cancels)

y = 32

2.

x - 14 = -8

 +14      +14           (-14 cancels)

   x = 6

3.

-15 = n + 18

    -18       -18          (18 cancels)

    -33 = n

4.

18.3 + a = 2.7

-18.3        -18.3        (18.3 cancels)

         a = -15.6

Answer:

The second box is 1.125 pounds

Step-by-step explanation:

This is found by multiplying 1.5 by .75

Answer:

0.82 = 82/100

simplified= 41/50

Step-by-step explanation:

Answer:

.8

Step-by-step explanation:

you can round, and since two is a number lower than five, the number stays the same so...

.8

Answer:

113.04 feet²

Step-by-step explanation:

Use the circle area formula, A = [tex]\pi[/tex]r²

Sine the diameter is 12 feet, the radius is 6 feet

Plug in 6 as r into the formula, and 3.14 as pi, then solve:

A = [tex]\pi[/tex]r²

A = (3.14)(6²)

A = (3.14)(36)

A = 113.04

So, the area of the circle is approximately 113.04 feet²

Answer:

113.04 feet²

Step-by-step explanation:

Hope this helps

Answer:

14r+11

Step-by-step explanation:

3+5r+9r+8

=11+14r

Answer:

s< -7/11

Step-by-step explanation:

Answer:

for 3. the answer is 9

for 4. the answer is 12

Step-by-step explanation:

hope this helped!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer with explanation:

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. = 14

Median or second quartile i.e. = 18

Third quartile or upper quartile i.e. =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. = 26

Median or second quartile i.e. = 30

Third quartile or upper quartile i.e. = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

   The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.

   And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e.

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

Hence, the number is : 1.5

Answer:

ive seen this before

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

5/1 is not equal to 6/2 or 7/3 or 8/4

Answer:

The answer would be B instead of D

Answer:

i don't know

Step-by-step explanation:

Answer:

A (3 Oranges For $1.02)

Step-by-step explanation:

3 Oranges for $1.02 is $0.34 for each Orange

4 Oranges For $1.52 is $0.38 for each Orange

6 Oranges for $2.46 is $0.41 for each Orange

5 Oranges for $1.75 is $0.35 for each Orange

Which Makes The First One The Cheapest Out Of All

Answer:

x>16/5 or c<-1/12

Answer: x≥  

x≥16/5 or x≤-3/4

Step-by-step explanation: I think this is the answer but i´m not completely sure of it.

Answer:

2x(2a + b)

Step-by-step explanation:

4ax+ 2bx

= 2x (2a + b)

Answer:

Step-by-step explanation:

[tex] \frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4} [/tex]

[tex] \frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2} [/tex]

[tex] \frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2} [/tex]

[tex] \frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2} [/tex]

Answer:

The possible coordinates of point A are (-8,-4) or (-8,6)

Step-by-step explanation:

The distance between two points is given by the formula

[tex]d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }[/tex]

For point A [tex](x_{1} , y_{1})[/tex]; [tex]x_{1}= -8[/tex] and [tex]y_{1}[/tex] is unknown

For point B [tex](x_{2} , y_{2})[/tex]; (4,1) i.e [tex]x_{2}=4[/tex] and [tex]y_{2}=1[/tex]

and d = 13

Putting the values into the equation,

[tex]13= \sqrt{[(4-(-8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{[(4+8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{12^{2} + (1-y_{1})^{2} }\\13^{2} = 12^{2} + (1-y_{1})^{2} \\169 = 144 +(1-y_{1})^{2}\\169-144 = (1-y_{1})^{2}\\25 = 1 -2y_{1} +y_{1}^{2} \\y_{1}^{2} -2y_{1}+1-25 =0\\y_{1}^{2} -2y_{1}-24 =0\\y_{1}^{2} -6y_{1} + 4y_{1} -24 =0 \\y_{1}(y_{1}-6) +4(y_{1} -6) = 0\\(y_{1}+4)(y_{1}-6) =0\\(y_{1}+4)=0 or (y_{1}-6) =0[/tex]

[tex]y_{1}+4= 0[/tex] or [tex]y_{1}-6 =0[/tex]

[tex]y_{1} =-4[/tex] or [tex]y_{1} = 6[/tex]

Hence, the possible coordinates of point A are (-8,-4) or (-8,6)

Step-by-step explanation:

3).20⁰

4).60⁰

180-70+70_180-140__20

Answer:

Step-by-step explanation:

21

Answer:

B

Step-by-step explanation: