My code doesn't give me the right output: I have to use the Python input command, and the number could be a decimal fraction, such as 6.5, so I should use floating point numbers?
I need to have a loop that repeats six times, with a routine in the middle of the loop to get the user input as a floating point number and add the number to a sum.

Can someone check it for me?
score_list = [ input("Judge No {} :score ".format(num+1)) for num in range(6)]
int_accumilator :int = 0
for score in score_list:
if(score > 10 ):
print("i only like numbers within the 0-10 range !")
exit()
int_accumilator+= score

print("the average score is ...", int_accumilator/ len(score_list))

Answer:

Here is some pseudocode that outlines the steps for creating a program that calculates overall final marks and outputs the necessary grades for a desired overall mark:

DEFINE a function called "calculate_final_mark"

INPUT: grades (list), weights (list), desired_mark (float)

CREATE a variable called "overall_mark" and set it to 0

FOR each grade and weight in the grades and weights lists:

 MULTIPLY the grade by the weight

 ADD the result to the overall_mark

IF overall_mark equals the desired_mark:

 OUTPUT "You have already achieved the desired mark."

ELSE:

 CREATE a variable called "needed_mark" and set it equal to the desired_mark minus the overall_mark

 OUTPUT "You need a" needed_mark "on your next assessment to achieve a" desired_mark "overall mark."

END the function

Here is the equivalent code in Python:

def calculate_final_mark(grades, weights, desired_mark):

 overall_mark = 0

 for grade, weight in zip(grades, weights):

   overall_mark += grade * weight

 if overall_mark == desired_mark:

   print("You have already achieved the desired mark.")

 else:

   needed_mark = desired_mark - overall_mark

   print(f"You need a {needed_mark} on your next assessment to achieve a {desired_mark} overall mark.")

The correct answer is B) send an email to all employees and attach the insurance documents. This is the most efficient and effective way for Steve to disseminate the insurance documents to all employees. It allows employees to access the documents electronically, at their convenience, and ensures that everyone receives the same information. Option A) using a digital ink pen to scan handwritten notes is not a viable option for distributing the insurance documents to all employees. Option C) calling each employee and asking them to pick up the documents at Steve's desk is also not practical, as it would be time-consuming and may not be convenient for all employees. Option D) creating a presentation is not relevant to the task at hand.

Answer:

To design a simple network for Maendeleo Institute of Technology with 240 employees, we could use a combination of routers, switches, and hubs.

Our network would consist of five separate networks, one for each department at the institute. We would use class C IP addresses, with a subnet mask of /24, to create the following subnets:

Computer Science department: 192.168.10.0/24

Information Technology department: 192.168.11.0/24

Account department: 192.168.12.0/24

Human Resource department: 192.168.13.0/24

Marketing department: 192.168.14.0/24

Each department would be connected to the network via a switch, which would allow for communication within the department and with other departments as needed. A router would be used to connect the individual department networks to the wider internet, and would also serve as a firewall to protect the network from external threats.

We would also include a hub in the network to allow for communication between devices within a department, as well as to provide additional connectivity and scalability.

Overall, our network design would provide each department with its own separate network, with the ability to communicate with other departments as needed. It would also be scalable, allowing for the addition of new devices and departments as the institute grows. The use of class C IP addresses and a /24 subnet mask would ensure that IP addresses do not overlap, ensuring efficient and reliable communication within the network.

Answer:

def new_balance(principal, gap, payout, duration):

   def calculate_balance(interest_rate):

       balance = principal

       for i in range(gap):

           balance *= (1 + interest_rate/12)

       for i in range(duration):

           balance *= (1 + interest_rate/12)

           balance -= payout

       return balance

   return calculate_balance

Explanation:

Answer:

def new_balance(principal, gap, payout, duration):

   # convert monetary amounts to cents

   principal_cents = principal * 100

   payout_cents = payout * 100

   def balance(rate):

       # calculate the interest earned during the deferment period in cents

       interest_cents = principal_cents * (1 + rate) ** gap - principal_cents

       # calculate the balance after the first payout in cents

       balance_cents = interest_cents + principal_cents - payout_cents

       # loop through the remaining payouts, calculating the balance after each one in cents

       for i in range(duration - 1):

           balance_cents = balance_cents * (1 + rate) - payout_cents

       # convert the balance back to dollars and round it to the nearest cent

       balance_dollars = round(balance_cents / 100)

       return balance_dollars

   return balance

test_balance = new_balance(1000, 2, 100, 2)

result = test_balance(0.1)

print(float(result))

Answer:

class MarksException extends Exception {

   public MarksException(String message) {

       super(message);

   }

}

public class Main {

   public static void main(String[] args) {

       try {

           checkMarks(35, 80);

       } catch (MarksException e) {

           System.out.println(e.getMessage());

       }

   }

   public static void checkMarks(int internal, int external) throws MarksException {

       if (internal > 30) {

           throw new MarksException("Internal mark exceeded");

       }

       if (external > 70) {

           throw new MarksException("External mark exceeded");

       }

   }

}

Explanation:

Answer:

def num_of_paths(maze):

   # Initialize the table with zeros

   n = len(maze)

   m = len(maze[0])

   table = [[0 for j in range(m)] for i in range(n)]

   # Fill in the first row

   for j in range(m):

       if maze[0][j] == 0:

           break

       table[0][j] = 1

   # Fill in the first column

   for i in range(n):

       if maze[i][0] == 0:

           break

       table[i][0] = 1

   # Fill in the rest of the table using dynamic programming

   for i in range(1, n):

       for j in range(1, m):

           if maze[i][j] == 0:

               table[i][j] = 0

           else:

               table[i][j] = table[i - 1][j] + table[i][j - 1]

   # Return the value in the bottom right corner of the table

   return table[n - 1][m - 1]

maze1 = ((1, 1, 1, 1, 1, 1, 1, 1, 0, 1),

(1, 0, 0, 1, 1, 1, 0, 0, 1, 1),

(0, 1, 1, 1, 0, 0, 1, 1, 1, 0),

(1, 1, 0, 1, 1, 1, 1, 0, 1, 1),

(0, 1, 0, 1, 0, 0, 1, 0, 1, 0),

(1, 0, 1, 1, 1, 1, 0, 1, 1, 1),

(1, 1, 0, 1, 0, 1, 0, 0, 1, 1),

(0, 1, 1, 1, 1, 1, 1, 1, 1, 0),

(1, 0, 1, 0, 0, 1, 1, 0, 1, 1),

(1, 0, 1, 1, 1, 0, 1, 0, 1, 0),

(1, 1, 0, 1, 0, 1, 0, 1, 1, 1))

maze2 = ((1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1))

maze3 = ((1, 0, 1, 1),

(1, 0, 1, 1),

(1, 0, 1, 1),

(1, 0, 1, 1),

(1, 0, 1, 0),

(1, 0, 0, 1))

print(num_of_paths(maze1))

print(num_of_paths(maze2))

print(num_of_paths(maze3))

Since the business wants to evaluate how much they're spending on their customers, versus how much their customers go on to spend. The measurement that a business would use to evaluate how much a customer will spend during the time they are a customer is called Customer Lifetime Value (CLV).

CLV is a prediction of the net profit attributed to the entire future relationship with a customer. It is calculated by multiplying the average value of a sale by the number of repeat transactions and the average retention time.

Therefore, based on the above, CLV can be used to identify which customers are the most valuable to a business and to allocate resources accordingly.

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Answer:

Here is one possible solution to this problem in Python:

from itertools import permutations

def addition_puzzle(*args):

 # Get all permutations of the digits 0-9

 digits = list(range(10))

 all_permutations = list(permutations(digits))

 # Iterate through each permutation

 for perm in all_permutations:

   # Create a dictionary mapping each alphabet to a digit

   mapping = {alphabet: digit for alphabet, digit in zip(args[0], perm)}

   if all(mapping[alphabet] != 0 for alphabet in args[0]):

     # Check if the sum of the numbers is equal to the last argument

     num1 = int(''.join(str(mapping[alphabet]) for alphabet in args[1]))

     num2 = int(''.join(str(mapping[alphabet]) for alphabet in args[2]))

     if num1 + num2 == int(''.join(str(mapping[alphabet]) for alphabet in args[3])):

       return mapping

 # If no solution is found, return False

 return False

print(addition_puzzle('ANT', 'MAN', 'COOL'))

print(addition_puzzle('AB', 'CD', 'E'))

Explanation:

This solution first generates all possible permutations of the digits 0-9 using the permutations function from the itertools module. Then, it iterates through each permutation and creates a dictionary mapping each alphabet to a digit. It checks if the leftmost letter in any word is not zero and if the sum of the numbers is equal to the last argument. If both conditions are satisfied, it returns the mapping. If no solution is found after iterating through all permutations, it returns False.

Sure, here's an example of a Python function that converts a decimal number to binary and returns the result as a list:

def ConvertToBinary(decimal):

binary = []

while decimal > 0:

remainder = decimal % 2

binary.append(remainder)

decimal = decimal // 2

return binary[::-1]

The function takes in an input decimal which is a number between 0 and 16 (not including 16) and uses a while loop to repeatedly divide the decimal number by 2 and take the remainder. The remainders are then appended to a list binary. Since the remainders are appended to the list in reverse order, the result is reversed by slicing the list [-1::-1] to give the proper order.

You can also add a check to make sure that the input is within the required range:

def ConvertToBinary(decimal):

if decimal < 0 or decimal >= 16:

return None

binary = []

while decimal > 0:

remainder = decimal % 2

binary.append(remainder)

decimal = decimal // 2

return binary[::-1]

this way you can make sure that the input provided is within the allowed range.

Answer:

To add a password to a SmartArt graphic in Microsoft PowerPoint, follow these steps:

Open the PowerPoint presentation containing the SmartArt graphic that you want to add a password to.

Select the SmartArt graphic by clicking on it.

In the ribbon at the top of the window, click the "Format" tab.

In the "Format" tab, click the "Security" button.

In the "Security" dialog box that appears, click the "Password" tab.

In the "Password" tab, enter a password in the "Password" field.

Re-enter the password in the "Confirm password" field to confirm it.

Click the "OK" button to save the password.

Save the presentation. The SmartArt graphic will now be protected with the password that you set. You will need to enter the password to edit or modify the SmartArt graphic.

Answer:

a type of software that can be freely used and modified.

Answer:

def faster_pascal(row, col):

   # Create a list of lists to store the values

   table = [[0 for x in range(col + 1)] for x in range(row + 1)]

   # Initialize the first row

   table[1][1] = 1

   # Populate the table

   for i in range(2, row + 1):

       for j in range(1, min(i, col) + 1):

           # The first and last values in each row are 1

           if j == 1 or j == i:

               table[i][j] = 1

           # Other values are the sum of values just above and left of the current cell

           else:

               table[i][j] = table[i-1][j-1] + table[i-1][j]

   # Return the required result

   return table[row][col]

print(faster_pascal(3, 2))

print(faster_pascal(4, 3))

print(faster_pascal(100, 45))

print(faster_pascal(500, 3))

print(faster_pascal(1, 1))

Brainliest if this helps! :))

Answer: So you Wait a minute I do believe that mysql is a sql cracking suit but you would need to build a hashing suit or you could use passlib.hash.mysql41 so you are looking to crack some stuff ok look at the file I sent.

Explanation:

Using the knowledge in computational language in python it is possible write the function exclamations that takes a string and then returns the same string with every lowercase i replaced with an exclamation point.

my_string = input("Enter text: ")

my_list = list(my_string)

for item in my_list:

   if item == "i":

       print "!"

       my_list.remove("i")

   print item

(" ").join(my_list)

my_string = list(input('Enter string: '))

for i, char in enumerate(my_string):

   if char == 'i':

       my_string[i] == '!'

print(''.join(my_string))

my_string = input("Enter text: ")

my_list = list(my_string)

for item in my_list:

   if item == "i":

       print "!"

       my_list.remove("i")

   else:

       print item

(" ").join(my_list)

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Since Grayson uses a program that allows him to keep track of how much money he earns and spends each week. The type of data that will be used to give him the answer to the question is option A: "Boolean".

A Boolean variable can hold only two values: true or false.

He can use a conditional statement to check if the amount of money he has left over after subtracting his expenses from his earnings is greater than or equal to the cost of the ice cream. If it is, he can set the Boolean variable to "True", indicating that he has enough money for ice cream. If it is not, he can set the Boolean variable to "False", indicating that he does not have enough money.

Therefore, Grayson can compare the value of his remaining money to the cost of the ice cream, if the remaining money is greater than or equal to $4, he can set the Boolean variable to "True" which means he has enough money.

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See full question below

Grayson uses a program that allows him to keep track of how much money he earns and spends each week. Which type of data will be used to give him the answer to the following question?

"Do I have $4 to buy ice cream?"

Boolean

Images

Numbers

Text

Hello there!

def kilo_to_pounds(kilos):

____pounds = 2.204 * kilos

____return pounds

kilos = int(input())

print(kilo_to_pounds(kilos), 'lbs')

The program that takes a weight in kilograms as input, converts the weight to pounds, and then outputs the weight in pounds is in the explanation part.

The process of carrying out a specific computation through the design and construction of an executable computer programme is known as computer programming.

Here is the completed program in Python:

def kilo_to_pounds(kilos):

   pounds = kilos * 2.204

   return pounds

# Main program

kilo_input = float(input("Enter weight in kilograms: "))

pounds_output = kilo_to_pounds(kilo_input)

print("Weight in pounds: ", pounds_output)

Thus, the kilo_to_pounds function takes a weight in kilograms as input and converts it to pounds using the conversion factor of 2.204.

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Answer:

To design a simple network for Maendeleo Institute of Technology with 240 employees, we could use a combination of routers, switches, and hubs.

Our network would consist of five separate networks, one for each department at the institute. We would use class C IP addresses, with a subnet mask of /24, to create the following subnets:

Computer Science department: 192.168.10.0/24

Information Technology department: 192.168.11.0/24

Account department: 192.168.12.0/24

Human Resource department: 192.168.13.0/24

Marketing department: 192.168.14.0/24

Each department would be connected to the network via a switch, which would allow for communication within the department and with other departments as needed. A router would be used to connect the individual department networks to the wider internet, and would also serve as a firewall to protect the network from external threats.

We would also include a hub in the network to allow for communication between devices within a department, as well as to provide additional connectivity and scalability.

Overall, our network design would provide each department with its own separate network, with the ability to communicate with other departments as needed. It would also be scalable, allowing for the addition of new devices and departments as the institute grows. The use of class C IP addresses and a /24 subnet mask would ensure that IP addresses do not overlap, ensuring efficient and reliable communication within the network.

Answer:Mac OS if there is a apple logo

Answer: True

Explanation:
Accenture is one of several hundred companies that has signed on to the United Nations Global Compact (UNGC) Business Ambition pledge. The UNGC is a voluntary initiative that encourages businesses to align their operations and strategies with ten universally accepted principles in the areas of human rights, labor, environment, and anti-corruption. The Business Ambition pledge is a component of the UNGC that invites businesses to set ambitious, science-based targets to reduce greenhouse gas emissions in line with the goals of the Paris Agreement. Accenture is one of many companies that have committed to this pledge and to taking action to combat climate change and support sustainable development.

The statement that does not pair with the corresponding output is system.out.printin (a + b+ c). The correct option is statement A.

Output is any information processed by and sent by a computer or other electronic device. Anything visible on your computer monitor screen, such as the words you write on your keyboard, is an example of output.

Outputs can be text displayed on the computer's monitor, sound from the computer's speakers, or a physical output such as a printed sheet of paper from a printer connected to the computer.

Therefore, the correct option is A, system.out.printin (a + b+ c).

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Involving or based on a hypothesis: conjectural; involving or based on a postulated concept or theory. speculative arguments a fictitious circumstance.

The words or abbreviations "for instance," "for example," "i.e." or "e.g." are frequently used after a hypothetical example, albeit the latter two, as you are probably aware, will only come after a comma and won't initiate a new sentence like "for instance" or "for example." Use hypothetical examples with caution.

The human whose existence is implied by other data rather than directly attested. theoretical individual hypothetical (adj.) is a 1580s term that means "based on or defined by a hypothesis, conjectural," from the Latinized form of the Greek word hypothesis, which means "pertaining to a hypothesis."

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It is to be noted that testing a self-driving car prototype on various types of roadways, such as a racetrack, hill rack, and dirt road, can be considered fair practice. It would only be unfair practice if the lives and property of humans are put at risk during the testing.

Unfair practices are behaviors that are neither just or fair. It would be deemed unjust to treat someone differently because of their color or gender, for example. Cheating or violating regulations to get an edge over others is also included. To develop a fair and just society, it is critical to constantly treat people with fairness and respect.

In this scenario, it is evident that endangering human life and property is unethical behavior.

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Answer:

def calculate_final_mark(courses):

   final_mark = 0

   total_weight = 0

   for course in courses:

       final_mark += course['mark'] * course['weight']

       total_weight += course['weight']

   return final_mark / total_weight

def calculate_required_mark(courses, desired_mark):

   current_mark = calculate_final_mark(courses)

   total_weight = 0

   for course in courses:

       total_weight += course['weight']

   required_mark = (desired_mark - current_mark) / (1 - total_weight)

   return required_mark

# Example usage:

courses = [

   {'name': 'Math', 'mark': 80, 'weight': 0.4},

   {'name': 'Science', 'mark': 70, 'weight': 0.3},

   {'name': 'English', 'mark': 65, 'weight': 0.3},

]

final_mark = calculate_final_mark(courses)

print(f"Your final mark is {final_mark:.1f}")

desired_mark = 80

required_mark = calculate_required_mark(courses, desired_mark)

print(f"You need to score at least {required_mark:.1f} on your next assessment to achieve a final mark of {desired_mark}")

Answer:Among other things, the fact that anyone can connect to such a server from their home and work on something remotely

Explanation:

Answer:

Explanation:

Here's one way you could write a C program to identify the highest value in a given set of numbers using a one-dimensional array:

Copy code

#include <stdio.h>

int main() {

   int nums[10]; // Declare an array of 10 integers

   int i, max;

   printf("Enter 10 numbers: ");

   for (i = 0; i < 10; i++) {

       scanf("%d", &nums[i]); // Read in the numbers

   }

   max = nums[0]; // Initialize max to the first number in the array

   for (i = 1; i < 10; i++) {

       if (nums[i] > max) { // Compare each number to the current max

           max = nums[i];  // If a number is larger, update the max

       }

   }

   printf("The highest value is: %d", max);

   return 0;

}

Answer:

I know it

Explanation:

I will tell later

Bad habits include reading in a crowded room, starting your schoolwork late at night, and cramming right before the exam. Good habits include taking breaks, having resources close by, and getting lots of rest.

Being uncoordinated. Being disorganized will simply make studying much more difficult because there are so many things to do and think about. Don't merely jot down notes and post reminders in random locations.

If a student stays up all night studying for the test, they usually forget the material during it. The ability of the brain to retain information increases with regular study schedules and thoughtful revision, and the material is ingrained much more deeply.

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Social engineering is a tactic used by attackers to manipulate individuals into divulging sensitive information or performing actions that may be harmful to the organization.

Social engineering attacks exploit human psychology, emotions, and trust to trick people into revealing sensitive information or performing actions that they otherwise wouldn't. The attacks can take many forms, such as phishing emails, phone scams, pretexting, and baiting.

The prevalence of social engineering attacks has increased in recent years, as attackers have become more sophisticated and creative in their methods.

According to the Verizon Data Breach Investigations Report (DBIR) in 2020, social engineering is used in 84% of successful cyber attacks and the most common form of social engineering is phishing. It is also reported that around 30% of phishing messages are opened and 12% of recipients click on the malicious link.

When it comes to combating social engineering, both employees and management carry some level of responsibility. Employees are the first line of defense and play a vital role in protecting the organization's sensitive information. They should be educated and trained on how to identify and avoid social engineering attacks. Management, on the other hand, is

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