N a carton of a dozen eggs of which four are cracked, how many ways could you select 3 cracked and 2 good if you randomly select 5 eggs

Answers

Answer 1

The number of ways we can select 3 cracked and 2 good is 1200 ways.

Given there are 5 eggs in which 3 eggs are cracked and 2 eggs which are good.

We have to find the number of ways we can select 3 cracked and 2 good eggs from 5 eggs.

Number of ways can be found through permutations.

The factorial of n  equals the product of n with the smaller factorial..

Permutations is the technique of calculating  various ways in which objects from a set may be selected, generally without replacement, to form subsets.

n[tex]P_{r}[/tex]=n!/(n-r)!

So the number of ways will be 5[tex]P_{3}[/tex]*5[tex]P_{2}[/tex]

([tex]5P_{3}[/tex] for cracked eggs and [tex]5C_{2}[/tex] for good eggs)

=5!/(5-3)!*51/(5-2)!

=5*4*3*2!/2!*5*4*3!/3!

=5*4*3*5*4

=1200

Hence there are 1200 ways through which 3 cracked and 2 good eggs can be selected from 5 eggs.

Learn more about permutations at https://brainly.com/question/1216161

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Answers

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Answers

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