The centripetal force : F = 293.3125 N
Further explanationGiven
mass = 65 kg
v = 9.5 m/s
r = 20 m
Required
the centripetal force
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle
[tex]\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}[/tex]
F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
Input the value :
F = 65 x 9.5² / 20
F = 293.3125 N
An object that is slowing down is accelerating.
True
False
How much heat energy is given out when 500g of steam at 100 degrees celcius condenses to water at 100 degrees celcius
Explanation:
How much thermal energy is released when 500g of steam at 100° C condenses into water and cools to 50°C
Givens: m=0.5 kg
t = 50
c = 2.010
Qtotal = Q1 + Q2
Qtotal = QmcΔt + mLv
Qtotal = (0.5kg)(2.010)(50) + (0.5)(2.3*10^6)
Qtotal = 1.15 * 10^6
The book says that the answer is 1.3*10^6?
What did I do wrong here?
When there are too many neutrons compared to the number of protons, the atomic nucleus is
A. Stable
B. Unstable
C. Explosive
D . Noble gases
Answer:
99.9% sure it B. Unstable but if that’s wrong try A.stable
Explanation:
Too many protons (or too few neutrons) in the nucleus result in an imbalance between forces, which leads to nuclear instability.
if a nucleus is unstable due to too many neutrons, it will undergo Beta decay - this means they become stable by emitting a beta particle.
Formula for angular acceleration
Answer:
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]
Explanation:
The angular acceleration is given by the relation as follows :
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]
Where
[tex]\omega_i\ and\ \omega_f[/tex] are the initial and final angular velocities
t is time
The SI unit of angular acceleration is rad/s². Hence, this is the required solution.
27. Julie and Ashwin were doing an experiment in the classroom. They
each had to move a 15 kg box. Julie was able to move her box, but
Ashwin was only able to move his after removing half the items in the
box. Which is true regarding the force he applies after removing the
items from the box?
a
He has to apply more force to lift the box
because the mass is greater.
b
He has to apply less force to lift the box
because the mass has decreased.
С
He has to apply a different type of force after
changing the mass.
d
He has to apply the same amount of force to
the box to overcome gravity.
Answer:
b. He has to apply less force to lift the box because the mass has decreased.
Explanation: i just took a ck12 test and it was right lol
mary travelled 70mph due north
this is an example of
Acceleration
distance
speed
velocity
The air pressure inside a car tire is
3.00 atm, and it creates 41,500 N
of force pushing out on the tire.
What is the surface area of the
inside of the tire?
(Unit = m^2)
Answer:
[tex]A=0.136\ m^2[/tex]
Explanation:
The air pressure inside a car tire is 3 atm = 303975 Pa
The force of 41,500 N of force pushing out on the tire.
We need to find the surface area of the inside of the tire. The pressure acting on an object is given by :
[tex]P=\dfrac{F}{A}\\\\A=\dfrac{F}{P}\\\\A=\dfrac{41500}{303975}\\\\A=0.136\ m^2[/tex]
So, the surface area of the inside of the tire is [tex]0.136\ m^2[/tex].
Robert hook used an early microscope to observed a cork sample. How did this help contribute to cell theory?
Answer:
Robert Hooke used an early microscope to observe a cork sample. How did this help contribute to cell theory? It helped to show that cells contain water. ... It helped to show that some cells are visible to the naked eye.
Explanation:
If your teacher checks if it was copied just put it in your on words
What is the gravitational force between two 1 kg objects that are 1 m apart?
Answer:
[tex]F=6.67\times 10^{-11}\ N[/tex]
Explanation:
Given that,
The masses of two objects, m₁ = m₂ = 1 kg
The distance between masses, d = 1 m
We need to find the gravitational force between two masses. The force is given by the relation as follows :
[tex]F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1\times 1}{(1)^2}\\F=6.67\times 10^{-11}\ N[/tex]
So, the force between two masses of 1 kg is [tex]6.67\times 10^{-11}\ N[/tex].
need some help!!!!!!! please
An element has a charge of -3, has 8 protons, 11 neutrons, and electrons
Word Bank:
12 5 11 8 13
pls help
Horse's Motion
Pamond
25
20
Account
Velocity
(meters per second)
15
10
Dashboard
5
0
Courses
0 5 10 15 20 25
Time (seconds)
Groups
Based on the information in the graph, which statement is
true?
Calendar
The horse maintained a constant acceleration during this portion of the race.
Inbox
The horse maintained a constant velocity during this portion of the race.
The horse increased its acceleration during this portion of the race.
History
The horse decreased its velocity during this portion of the race.
Studio
Answer:
The answer will be the number 15 because it is subtracted to the number itself
7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is
8.85 kg-m/s. What is the mass of the ball?
Answer:
Approximately [tex]1\; \rm kg[/tex]. (Assumption: [tex]g = 9.8\; \rm m \cdot s^{-2}[/tex].)
Explanation:
Let the mass of this ball be [tex]x\; \rm kg[/tex].
Initial gravitational potential energy of this ball: [tex]m \cdot g \cdot h \approx (39.2\, x) \; \rm J[/tex].
Just before the ball hits the ground, all [tex](39.2\, x)\; \rm J[/tex] of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:
[tex]\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}[/tex].
Therefore, right before hitting the ground, the velocity of the ball would be:
[tex]\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}[/tex].
The momentum [tex]p[/tex] of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] would be [tex]p = m \cdot v[/tex]. Rewrite this equation to find an expression for mass [tex]m\![/tex] given velocity [tex]v\![/tex] and momentum [tex]p\![/tex]:
[tex]\displaystyle m = \frac{p}{v}[/tex].
Right before collision, the momentum of this ball is [tex]p = 8.85\; \rm kg \cdot m \cdot s^{-1}[/tex] while its velocity is [tex]v \approx 8.85\; \rm m \cdot s^{-1}[/tex]. Therefore, the mass of this ball would be:
[tex]\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}[/tex].
The planet Jupiter has much more mass than Earth. What would happen to an astronaut who landed on Jupiter
A. The astronaut would weigh somewhat less on Jupiter than on Earth
B. The astronaut would have the same weight on Jupiter as on Earth
C. The astronaut would be weightless on Jupiter
D. The astronaut would weigh mire on Jupiter than on Earth
Answer:
A. The astronaut would way somewhat less
The planet Jupiter has much more mass than Earth, is an astronaut who landed on Jupiter would weigh more on Jupiter than on Earth. Thus, the correct option is D.
What is Jupiter?
Jupiter is a planet of the Solar system of the Milkyway galaxy. It is made up of mostly hydrogen and helium gas. The temperature on this planet is extremely hot and an astronaut landing on this planet will experience free-floating in mid-Jupiter with no way of escaping.
Jupiter has more mass than that of the Earth thus, it exerts greater gravitational force than the Earth, and the weight is equal to the product of the mass and the gravitational acceleration. So, the mass of an astronaut will remain constant when he or she move from earth to jupiter however the weight of the astronaut will increase on jupiter.
Therefore, the correct option is D.
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its in the pic plz help
Answer:
Hand soap: basic
chocolate milk: neutral
apple juice: acidic
shampoo: acidic
mouthwash: acidic
tap water: basic
Explanation:
Check your PH scale
1-6 = acidic
7 = neutral
8-14 = basic
2. What is the y-component of a 95.3 N force that is exerted at 57.1
degree to the horizontal, *
Answer: 80N
Explanation:
The y-component would be the magnitude of the force multiplied by the sine of the angle.
[tex]95.3*\sin(57.1)=80N[/tex]
The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
What is Force?Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.
It can be expressed as:
F = m a
Where, F= Force
m= mass of the object
a= acceleration
In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,
so, For x component [tex]F_x[/tex] = Fcosθ
For y component [tex]F_y[/tex] = F sinθ
Given, F= 95.3 N ; θ= 57.1 °
[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]
Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
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A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.
The velocity of hitting the ground is 4.86 m/s and the velocity after hitting the ground is 4.53 m/s.
What is Velocity?Velocity can be defined as the direction of movement of the body or object. Velocity is a vector quantity. It is the rate of change of displacement.
Given data,
Initial velocity when dropped(u)=0 m/s
Distance traveled(s)=1.21 m/s
Distance traveled after leave the ground(s1) = 1.05 ms
According to third law of motion,
v² = u² + 2gs
Initial velocity u=0
v² = 2gs or v = [tex]\sqrt{2gs}[/tex]
by putting the value of s
v (hitting) = √(2 × 9.8 × 1.21) = [tex]\sqrt{23.71}[/tex] = 4.86m/s
After leaving ground at 1.21 m final velocity will be zero
So, velocity just after left the ground will be
2 = √(2 × 9.8 × 1.05) = [tex]\sqrt{20.58}[/tex] = 4.53m/s
So, velocity of hitting the ground is 4.86 m/s and after hitting is 4.53 m/s.
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3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?| I
Answer:
2.18 m/s.
Explanation:
no one can answer
why electrons are negetive?
Answer:
they're negative bc a proton is positive. a proton attracts an electron by the fact that opposite charges attract each other, while two electrons repel each other. Thus it shows that polarity of the charge on an electron and a proton is opposite.
Explanation:
Question 1
3 pts
When eating out in a restaurant, you
should
Answer:
Wear a mask and keep a solid 6 feet of social distance
Explanation:
Answer:
Be polite, wear a mask, social distance, don't eat sloppy, have a good time lol
Explanation:
If a 5.5 kg object experiences 15 N of force for .15 seconds what is the speed change
The speed change : Δv = 0.41 m/s
Further explanationGiven
mass = 5.5 kg
Force = 15 N
time = 0.15 s
Required
the speed change
Solution
Newton 2nd's law
Impulse and momentum
F = m.a
F = m . Δv/t
F.t = m.Δv
Input the value :
15 N x 0.15 s = 5.5 kg x Δv
Δv = 0.41 m/s
Which green shape is the least reactive?
(Subjective is actually science)
Answer:
the green smiley face
Explanation:
its is farthest from the right
and as stated on the chart, the farther left, the more reactive
less stable=more reactive
more stable= less reactive
To test the strength of a retainment wall designed to protect a nuclear reactor,
a rocket-propelled F-4 Phantom jet aircraft was crashed head-on into a
concrete barrier at high speed in Sandia, New Mexico, on April 19, 1988. The
F-4 phantom had a mass of 19,100 kg, while the retainment wall's mass was
469,000 kg. The wall sat on a cushion of air that allowed it to move during
impact. If the wall and F-4 moved together at 8.41 m/s during the collision,
what was the speed of the F-4 Phantom upon impact?
Answer:
The speed of the F-4 Phantom upon impact is approximately 214.92 m/s
Explanation:
The given parameter of the motion of the F-4 Phantom jet aircraft are;
The mass of the F-4 phantom rocket, m₁ = 19,100 kg
The mass of the retaining wall, m₂ = 469,000 kg
The velocity of the combined mass of the wall and the F-4 after collision, v₃ = 8.41 m/s
The retainment wall was initially at rest, therefore, v₂ = 0 m/s
Let 'v₁', represent the speed of the F-4 Phantom upon impact
By the principle of conservation of linear momentum, we have;
m₁·v₁ + m₁·v₂ = m₁·v₃ + m₂·v₃ = (m₁ + m₂)·v₃
Plugging in the values, we have;
19,100 × v₁ + 469,000 × 0 = (19,100 + 469,000) × 8.41
∴ v₁ = (19,100 + 469,000) × 8.41/(19,100) = 214.917329843
v₁ ≈ 214.92
The speed of the F-4 Phantom upon impact, v₁ ≈ 214.92 m/s.
A book of mass 1.5 ,kg exerted a downward force on the table
What is the direction of this second force?
Answer:
up ward force it is balanced by dow ward force
Student agrees to do only 300 joules of work, how far will the student push the box using a constant 84 N force
Answer:
Explanation:
Work = Force*Distance
300 = 84*d
d = 3.57 meters
Which of the following represents a chemical change?
A. Melting
of ice to water.
B. Combustion of a firecracker
C. Salt dissolves in water
D. The iron stretched into wires-ductile and iron pounded into sheets-malleable.
Explain why the following statement is either true or false: The idea that all matter consists of the elements was first introduced a few hundred years ago
It is a true statement that the idea that all matter consists of elements was first introduced a few hundred years ago.
What is the matter?Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
Individuals have believed that earth, air, water, and fire are the only four elements that make up matter for roughly two thousand years.
For more than two thousand years, Aristotle's theory that all matter is composed of just four elements was accepted, but only around 500 years ago did scientists begin to find all of the elements that are currently recognized.
Beginning around five hundred years ago, scientists started learning about all of the elements that are currently recognized.
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What is the centripetal acceleration of an object moving 25 m/s around a 6 m curve?
O 104.2
O 84.2
O 64.2.
O 44.2
Answer:
Centripetal acceleration = 104.2 (Approx)
Explanation:
Find:
Centripetal acceleration
Given:
Velocity = 25 m/s
Radius r =6 m
Computation:
Centripetal acceleration = v² / r
Centripetal acceleration = 25² / 6
Centripetal acceleration = 104.467
Centripetal acceleration = 104.2 (Approx)
If a girl does 1,350 Joules of work to pedal her bike using a force of 75 N, how far did she ride her bike?
Answer:
D = 18m
Explanation:
We use this formula:
Work = Force * Distance
Now, we replace it:
W = F*D
1,350J = 75N * D
D = 1,350/75
D = 18m
Hope it was helpful ;)
Which distance increases?
Answer:
wY
Explanation:
it increases my mercury righy basically also on the atmosphere pressure