need help with this problem
2x+y=1
y =−x + 1

Answer:

I believe the answer is C

Answer:2

Step-by-step explanation:

Answer:

its true i cant pay attention in class cuz its boring but im

not failing it thank god

Answer:

sameeee but im currently not failing, lets hope it stays like that ;-;

Step-by-step explanation:

im smart

Answer:

m = 4 + (2n)/(3)

Step-by-step explanation:

Move all terms that contain m to the right side and solve it.

Answer:

it’s just 2x^2

it’s not factorable

Answer:

Yes

Step-by-step explanation:

Because you're multiplying by 1 so it stays the same value

Answer:

There is sufficient evidence to support the claim.

Step-by-step explanation:

Given

[tex]\alpha = 0.10[/tex]

Make A

[tex]\bar x_1 = 41[/tex]

[tex]\sigma_1= 4.6[/tex]

[tex]n = 35[/tex]

Make B

[tex]\bar x_2 = 45[/tex]

[tex]\sigma_2 = 4.3[/tex]

[tex]n = 35[/tex]

First, we state the null and alternate hypothesis

[tex]H_0 : \mu_1 = \mu_2[/tex]

[tex]H_1 : \mu_1 \ne \mu_2[/tex]

Next, calculate test statistic:

[tex]z = \frac{(\bar x_1 - \bar x_2)-(\mu_1 - \mu_2)}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}}[/tex]

[tex]z = \frac{(41- 45)-0}{\sqrt{\frac{4.6^2}{35}+\frac{4.3^2}{35}}}[/tex]

[tex]z = \frac{-4}{\sqrt{0.6046+0.5283}}[/tex]

[tex]z = \frac{-4}{\sqrt{1.1329}}[/tex]

[tex]z = \frac{-4}{1.0643}[/tex]

[tex]z = -3.7583[/tex]

The critical value at [tex]\alpha = 0.10[/tex] is: [tex]\±1.282[/tex]

[tex]-3.7583 < -1.282[/tex]

So, we reject [tex]H_0[/tex]

This implies that; there is sufficient evidence to support the claim.

Answer:

i think y=2 and x=-7

Step-by-step explanation:

Answer:

5

step by step explanation:

if she gets $10 off of her purchase that means she would have a little extra money to another shirt

Answer:

they all go straight across

Step-by-step explanation:

Answer:

Go across from each

Step-by-step explanation:

Answer:

B)

Step-by-step explanation:

A function is when every input has one output.

Easiest way is to do the "vertical line test" and "horizonal line test."

Basically you draw a vertical line and a horizontal line.

If either line passes through more than one point, then it is not a function.

The only one that passes them is B, the line.

Answer:

B

Step-by-step explanation:

A function is when every input has one output.

Easiest way is to do the "vertical line test" and "horizonal line test."

Basically you draw a vertical line and a horizontal line.

If either line passes through more than one point, then it is not a function.

The only one that passes them is B, the line.

Answer:

57.14$

Step-by-step explanation:

70/100 ( Remember 30% off so only paid 70% of original price) = 40/x ( 40$ is the price paid, x is the unknown original price)

70 = 40

100 X

40×100 = 4,000

4,000÷ 70X = 57.14

Answer:

(0.223 - 0.058) ± 2.576 * sqrt[((0.223)(0.777))/1018 - ((0.058)(0.942))/1013]

Step-by-step explanation:

Given that :

P1 = 22.3% = 0.223

q1 = 1 - P1 = 1 - 0.223 = 0.777

Sample size, n1 = 1018

P2 = 5.8% = 0.058

q2 = 1 - P2 = 1 - 0.058 = 0.942

Sample size, n2 = 1013

Confidence level, Zcritical at 99% = 2.576

Using the relation :

(P1 - P2) ± Zcritical * Sqrt[(P1q1/n1 + P2q2/n2)

(0.223 - 0.058) ± 2.58 * sqrt[((0.223)(0.777))/1018 - ((0.058)(0.942))/1013]

Answer:

Step-by-step explanation:

[tex]r_1(t) = < t^2 , 8t-15,t^2> \\ \\ r_2(t) = < 11t-30, \ t^2 , \ 13t-40> \\ \\ at \ r_1 = r_2 \\ \\ t^2 = 11t - 30 , \ \ \ \ \ \ \ \ \ \ \ \ 8t - 15 = t^2 , \ \ \ \ \ \ \ \ \ t^2 = 13t -40 \\ \\ t^2 - 11t + 30\ \ \ \ \ \ \ \ \ \ \ \ t^2 -8t + 15 , \ \ \ \ \ \ \ \ \ \ \ \ t^2 -13t + 40 \\ \\ t^2 -8t-3t + 30=0 \ \ \ \ \ \ t^2 - 2t -4t + 15=0 \ \ \ \ \ \ t^2 - 1t - 13t + 40 =0[/tex]

[tex](t-6)(t-5) \ \ \ \ \ \ \ \ \ \ \ (t-5)(t-3) \ \ \ \ \ \ \ \ \ \ \ (t-5)(t-8)[/tex]

[tex]\mathbf{The \ common \ value \ of \ t \ = \ 5}[/tex]

Answer:

cos P = 71.09

Step-by-step explanation:

cos = [tex]\frac{adajcent}{hypotenuse}[/tex]

cos P = [tex]\frac{24}{74}[/tex]

cos P = 0.324

cos-1 of 0.324 is 71.09

cos P = 71.09

Answer:

5.50 + 2.25 ≥ c

Step-by-step explanation

Movie = 5.50

Popcorn = 2.25

C = The total cost

5.50 + 2.25 = C

Hope this helps you If you need any more help let me know in the comments

Answer:

cos 225° = [tex]-\frac{\sqrt{2} }{2}[/tex]

sin 225° = [tex]-\frac{\sqrt{2} }{2}[/tex]

tan 225° = 1

Step-by-step explanation:

I cannot sketch a diagram, but a 225° angle is a 3rd quadrant angle and the reference angle is 45°   (225 - 180 = 45)

cos and sin are negative in the 3rd quadrant and the tan is positive

cos 225° = - cos 45° = [tex]-\frac{\sqrt{2} }{2}[/tex]

sin 225° = -sin 45° = [tex]-\frac{\sqrt{2} }{2}[/tex]

tan 225° = tan 45° = 1

9514 1404 393

Answer:

  $14.14

Step-by-step explanation:

The amount of interest earned is ...

  I = P((1 +r/365)^n -1) . . . . interest on principal P at annual rate r compounded daily for n days

  I = 3021(1 +0.055/365)^31 -1) ≈ 14.14

$14.14 in interest is earned in 31 days.

Answer:

Step-by-step explanation:

1)(-3x+10)(50-x)=180

-4x+60=180

-4x=120

x=-30

2)6x+2+2x=90

8x=88

x=11

larger angle: 68°

3) a=3x°

4)(7x-5)=-2x+22

9x=27

x=3

DBE=16°

5)(x-39)=2x-59)

x=20

Answer:

110

Step-by-step explanation:

because you have to add the number

Answer:

True

Step-by-step explanation:

from the scale 0-1, 2/8 is closer to 0 because you round 2 down to 0, which gives you 0.

Answer: x=2

Isolate the variable by dividing each side by the factors that don't contain variables.

Answer:

11/6 - 5/6 = 6/6

Step-by-step explanation:

Answer:

Normality assumptions are met.

The 90% confidence interval for the proportion of adult drivers that run at least one red light in the last month is (0.4892, 0.5356). The interpretation is that we are 90% sure that the true proportion of all adult drivers than ran at least one red light in the last month is between these bounds.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Out of 1251 adult drivers, 641 of them have run at least one red light in the last month.

This means that [tex]n = 1251, \pi = \frac{641}{1251} = 0.5124[/tex]

Normality assumptions:

We need that: [tex]n\pi[/tex] and [tex]n(1-\pi)[/tex] are 10 or greater. So

[tex]n\pi = 1251*0.5124 = 641[/tex]

[tex]n(1-\pi) = 1251*0.4876 = 610[/tex]

So the normality assumptions are met.

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5124 - 1.645\sqrt{\frac{0.5124*0.4876}{1251}} = 0.4892[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5124 + 1.645\sqrt{\frac{0.5124*0.4876}{1251}} = 0.5356[/tex]

The 90% confidence interval for the proportion of adult drivers that run at least one red light in the last month is (0.4892, 0.5356). The interpretation is that we are 90% sure that the true proportion of all adult drivers than ran at least one red light in the last month is between these bounds.