Answers
Check the picture below.
so if the triangles are congruent, then CPCTC.
Related Questions
describe all the x -values at a distance of 13 or less from the number 8 . enter your answer in interval notation.
Answers
The set of all x-values that are at a distance of 13 or less from the number 8 in the interval notation is given by [ -5, 21 ].
The distance between x and 8 is |x - 8|.
Find all the values of x such that |x - 8| ≤ 13.
This inequality can be rewritten as follow,
|x - 8| ≤ 13
⇒ -13 ≤ x - 8 ≤ 13
Now,
Adding 8 to all sides of the inequality we get,
⇒ -13 + 8 ≤ x - 8 + 8 ≤ 13 + 8
⇒ -5 ≤ x ≤ 21
Therefore, all the x-values which are at a distance of 13 or less from the number 8 represented in the interval notation as [ -5, 21 ].
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A cylindrical aluminum can is being constructed to have a height h of 7 inches. If the can is to have a volume of 56 cubic inches, approximate its radius r. (Hint: V = 2²h)
The radius of the can is about _ inches.
(Type an integer or decimal rounded to two decimal places as needed)
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When rounded to two decimal places, the radius of the can is approximately 1.6 inches.
What exactly is a cylinder?Surface fοrmed by a straight line mοving parallel tο a fixed straight line and intersecting a fixed planar clοsed curve. a sοlid οr surface defined by a cylinder and twο parallel planes that cut all οf its elements. See Vοlume Fοrmulas Table, particularly fοr the right circular cylinder.
The volume of a cylinder can be calculated using the following formula:
V = πr²h
where
V denotes volume,
r denotes radius, and
h denotes height.
The cylindrical aluminium can has a height of 7 inches and a volume of 56 cubic inches. We can calculate the radius using the volume of a cylinder formula:
V = πr²h
56 = πr²(7)
56 = (22/7)r²(7)
56 = 22r²
56/22 = r²
2.54 = r²
r = [tex]\sqrt{2.54}[/tex]
r ≈ 1.6
As a result, when rounded to two decimal places, the radius of the can is approximately 1.6 inches.
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solve the quadratic equation 9×^2-15×-6=0
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Answer:
To solve the quadratic equation 9×^2-15×-6=0, we can use the quadratic formula, which is given by:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.
In this case, a = 9, b = -15, and c = -6, so we can substitute these values into the quadratic formula:
x = (-(-15) ± sqrt((-15)^2 - 4(9)(-6))) / 2(9)
Simplifying this expression gives:
x = (15 ± sqrt(225 + 216)) / 18
x = (15 ± sqrt(441)) / 18
x = (15 ± 21) / 18
So the two solutions to the quadratic equation are:
x = (15 + 21) / 18 = 2
x = (15 - 21) / 18 = -1/3
Therefore, the solutions to the quadratic equation 9×^2-15×-6=0 are x = 2 and x = -1/3.
Simplify without calculator: (-5) (7)+4×5 (Show all calculations)
Answers
Step-by-step explanation:
this is the answerrr
without calculator
given a function that is continuous on [a,b] and differentiable on (a,b), find a c in (a,b) that satisfies the mean value theorem.
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According to the Mean Value Theorem, if f(x) is a function that is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one c in (a, b) such that:
f(b) - f(a) = f'(c) x (b - a)
To find a c that satisfies the theorem, we need to solve for c:
c = (f(b) - f(a)) / (b - a) / f'(c)
However, this equation cannot be solved directly because c appears on both sides. Instead, we can use an iterative numerical method to approximate c.
One such method is the bisection method, which involves repeatedly dividing the interval (a, b) in half and checking which subinterval contains a root. Here's how it works:
1. Set c = (a + b) / 2, the midpoint of the interval.
2. Evaluate f'(c) using the derivative of f.
3. Calculate f(b) - f(a) and f'(c) x (b - a).
4. If f'(c) x (b - a) = f(b) - f(a), then c is the solution.
5. If f'(c) x (b - a) > f(b) - f(a), then the solution is in the left subinterval (a, c), so set b = c and go to step 1.
6. If f'(c) x (b - a) < f(b) - f(a), then the solution is in the right subinterval (c, b), so set a = c and go to step 1.
Repeat steps 1-6 until the solution is found to a desired degree of accuracy.
Note that this method assumes that f'(x) is continuous on [a, b], which is not always the case. In such cases, other numerical methods may be required.
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evaluate the following limits?
a=?
b=?
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The value of the limits are:
lim x → ∞√(9+3x²)/(2+7x) = 1lim x→-∞ √(9+3x^2)/(2+7x) = -∞.What is the value of the limits?The highest degree terms in the numerator and denominator are both 3x^2.
So, as x approaches infinity, the expression behaves like √(3x^2)/√(3x^2) = 1.
Therefore, the limit evaluates to:
lim x → ∞√(9+3x²)/(2+7x) = lim x → ∞(√(3x²)/√(3x²))
lim x → ∞√(9+3x²)/(2+7x) = 1.
(b) The highest degree term in the numerator is 3x^2, while the highest degree term in the denominator is 7x.
Therefore, as x approaches negative infinity, the expression behaves like:
√(3x^2)/√(7x) = √(3/7)(x^2/x) = √(3/7)x.
Since the coefficient of x is positive, the expression approaches negative infinity as x approaches negative infinity.
Therefore, the limit evaluates to:
lim x→-∞ √(9+3x^2)/(2+7x) = lim x→-∞ √(3/7)x
lim x→-∞ √(9+3x^2)/(2+7x) = -∞.
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Complete question:
Evaluate the following limits. If needed, enter 'INF' for ∞ and '-INF for -∞.
(a)
lim x → ∞√9+3x²/2+7x
(b)
lim x→-∞ √9+3x2/2+7x
Modulus of Rigidity or Shear Modulus (G) The modulus of rigidity or shear modulus is a measure of the rigidity of the material when in "shear' - when it is twisting. It is a ratio of the shear stress and the shear strain of the material: Shear Stress F/ A1 (6.1) Shear Strain Ax/h This formula only works when the material is stressed in its elastic region. דן Polar Moment of Inertia (J) This is an equation that shows the ability of a circular cross-section beam or specimen to resis torsion (twisting). A higher polar moment of inertia shows that the beam or specimen can resist i higher torsion or twisting force. The diameter of the beam determines polar moment of inertia A larger diameter gives a larger polar moment of inertia. #D* J = 32 (6.2) The general equation for the torque in a circular cross-section beam or specimen is: TG (6.3) Where is in radian. Torque The twisting force (torque) at the end of a specimen is the moment of force on the torque arm: T = F x Torque Arm Length (m) (6.4) Shear Stress
Answers
Modulus of rigidity (shear modulus) measures a material's rigidity in shear stress/strain. Polar moment of inertia measures the ability of a circular beam to resist torsion measured with J = 32 / (pi x D^4) , and torque is the twisting force on a specimen measured as T = G x J x θ.
The modulus of rigidity or shear modulus, represented by G, is a measure of a material's rigidity when subjected to shear stress. Shear stress is the force applied perpendicular to the cross-sectional area of a material, while shear strain is the resulting deformation or twisting of the material.
The equation G = shear stress / shear strain is only valid in the elastic region of a material, where it can return to its original shape after the force is removed.
The polar moment of inertia, J, is a measure of a circular cross-section beam or specimen's resistance to torsion or twisting. A larger diameter of the beam results in a larger polar moment of inertia.
The equation J = 32 / (pi x D^4) is used to calculate the polar moment of inertia, where D is the diameter of the beam.
The torque in a circular cross-section beam or specimen is given by the equation T = G x J x θ, where G is the shear modulus, J is the polar moment of inertia, and theta is the angle of twist in radians.
The torque arm length and the applied force F are used to calculate the twisting force or torque in the specimen.
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WILL MARK AS BRAINLIEST!!!!!!!!!!!!!!!!!!
The point on the parabola y=x^2 that is closest to the point (1,0) is (_______,_______). The distance between the two points is ________.
you can use Newtons's Method or Bisection to help but you don't have to.
Answers
Answer:Approximately
(0.58975,0.34781)
Step-by-step explanation:
If (x,y) is a point on the parabola, then the distance between (x,y) and (1,0) is:
√(x−1)2+(y−0)2=√x4+x2−2x+1
To minimize this, we want to minimize
f(x)=x4+x2−2x+1
The minimum will occur at a zero of:
f'(x)=4x3+2x−2=2(2x3+x−1)
graph{2x^3+x-1 [-10, 10, -5, 5]}
Using Cardano's method, find
x=3√14+√8736+3√14−√8736≅0.58975
y=x2≅0.34781
You read online that a 15 ft by 20 ft brick patio would cost about $2,275 to have professionally installed. Estimate the cost of having a 13 by 18 ft brick patio installed.
$
Round your answer to the nearest dollar.
Answers
Answer: $1,775
Step-by-step explanation:
We can use a proportion to estimate the cost of having a 13 ft by 18 ft brick patio installed, based on the cost of a 15 ft by 20 ft patio:
(cost of 13 ft by 18 ft patio) / (cost of 15 ft by 20 ft patio) = (area of 13 ft by 18 ft patio) / (area of 15 ft by 20 ft patio)
The area of the 13 ft by 18 ft patio is 13 x 18 = 234 sq ft, and the area of the 15 ft by 20 ft patio is 15 x 20 = 300 sq ft.
So,
(cost of 13 ft by 18 ft patio) / ($2,275) = 234 / 300
Solving for the cost of the 13 ft by 18 ft patio, we get:
cost of 13 ft by 18 ft patio = ($2,275) x (234 / 300) = $1,775.25
Rounding to the nearest dollar, the estimated cost of having a 13 ft by 18 ft brick patio installed is $1,775.
write a quadratic equation in the form x2+bx+c=0 that has the following roots: -8±4i
Answers
A quadratic equation in the form [tex]x^2[/tex]+bx+c=0 that has the roots -8±4i is [tex]x^2[/tex] + 16x + 48 = 0
If the roots of a quadratic equation are -8+4i and -8-4i, then the factors of the quadratic equation are (x-(-8+4i))(x-(-8-4i))=0.
Simplifying this expression, we get:
(x+8-4i)(x+8+4i) = 0
Expanding this expression, we get:
[tex]x^2[/tex] + (8-4i+8+4i)x + (8-4i)(8+4i) = 0
Simplifying this expression, we get:
[tex]x^2[/tex] + 16x + ([tex]8^2[/tex] - [tex](4i)^2[/tex]) = 0
[tex]x^2[/tex] + 16x + 48 = 0
Therefore, the quadratic equation in the form [tex]x^2[/tex]+bx+c=0 that has the roots -8±4i is:
[tex]x^2[/tex] + 16x + 48 = 0
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evaluate the function h(x)=-2x^4+x^2-13;x=y+1
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The function[tex]h(x) = -2x^4 + x^2 - 13; x = y+1,[/tex] can be simplified as [tex]h(y+1) = -2y^4 - 8y^3 - 10y^2 - 8y - 14.[/tex]
What exactly are function and example?A function is a type of rule that produces one output for a single input. Source of the image: Alex Federspiel. This is illustrated by the equation y=x2. Any input for x results in a single output for y. Considering that x is the input value, we would state that y is a function of x.
To evaluate the function[tex]h(x) = -2x^4 + x^2 - 13[/tex] when x = y + 1, we can substitute y + 1 for x:
[tex]h(y+1) = -2(y+1)^4 + (y+1)^2 - 13[/tex]
Simplifying this expression involves some algebraic manipulation. We can start by expanding the fourth power using the binomial theorem:
[tex](y+1)^4 = y^4 + 4y^3 + 6y^2 + 4y + 1[/tex]
Substituting this expression into h(y+1), we get:
[tex]h(y+1) = -2(y^4 + 4y^3 + 6y^2 + 4y + 1) + (y^2 + 2y + 1) - 13[/tex]
Simplifying further, we get:
[tex]h(y+1) = -2y^4 - 8y^3 - 10y^2 - 8y - 14[/tex]
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Translate the phrase into an algebraic expression.
The product of 9 and x
Answers
The algebraic expression for the product of 9 and x is 9x. This can be expressed in steps as follows:
Step 1: Identify the values that are being multiplied together. In this case it is 9 and x.
Step 2: Write the two values side by side and place a multiplication sign between them.
Step 3: The algebraic expression for the product of 9 and x is then written as 9x.
A block of mass 2kg is attached to the spring of spring constant 50Nm −1. The block is pulled to a distance of 5 cm from its equilibrium position at x=0 on a horizontal frictionless surface from rest at t = 0. The displacement of the block at any time t is thenA. x= 0.05sin5tmB. x= 0.05cos5tmC. x= 0.5sin5tmD. x= 5sin5tm
Answers
The displacement of the block at any time t is then x= 0.05cos5tm. (option b).
Now, when the block is released, it starts oscillating back and forth about its equilibrium position due to the force exerted by the spring. This motion is described by the equation of motion for a simple harmonic oscillator:
x = Acos(ωt + φ)
The angular frequency ω of the oscillation is given by:
ω = √(k/m)
where k is the spring constant and m is the mass of the block.
Substituting the given values of k and m, we get:
ω = √(50/2) = 5 rad/s
The phase angle φ depends on the initial conditions of the system, i.e., the initial displacement and velocity of the block. Since the block is initially at rest, its initial velocity is zero and the phase angle is zero as well.
Therefore, the equation of motion for the displacement of the block is:
x = 0.05cos(5t)
Hence, option B, x = 0.05cos(5t), is the correct answer.
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find the value of x in the following figure
Answers
Answer:
20
Step-by-step explanation:
Use the drop-down menus and enter values to complete the statements below.
Answers
An equation is a statement that two expressions are equal. The expressions on both sides of the equation can be made up of variables, constants, and mathematical operations.
What is the expression of an equation?For example, the equation:
[tex]2x + 5 = 11[/tex]
Has two expressions on either side of the equals sign. The expression on the left side is 2x + 5, which consists of the variable x, the constant 2, and the constant 5, combined using the mathematical operation of addition.
The expression on the right side is 11, which is a constant. The equation states that the two expressions are equal, which means that the value of x can be determined to be 3 by solving the equation.
Part A:
The value for x that is a solution to [tex]2x - 5 = 3 is x = 4.[/tex]
The value for x that is a solution to [tex]2x - 5 > 3[/tex] is [tex]x > 4[/tex] .
Part B:
The solution to [tex]-2x - 5 = 3[/tex] is [tex]x = -4[/tex] .
The solution to [tex]-2x - 5 > 3[/tex] is [tex]x < -4[/tex] .
A value for x that is a solution to [tex]-2x - 5 = 3[/tex] is [tex]x = -4[/tex] .
A value for x that is a solution to [tex]-2x - 5 > 3[/tex] is [tex]x = -5[/tex] .
Therefore, The value for x that is a solution to [tex]2x - 5 > 3[/tex] is [tex]x > 4[/tex] . and A value for x that is a solution to [tex]-2x - 5 > 3[/tex] is [tex]x = -5[/tex] .
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Find the exact value of the expression: tan270 degrees
Answers
Answer:
What is the Value of Tan 270 Degrees? The value of tan 270 degrees is undefined. Tan 270 degrees can also be expressed using the equivalent of the given angle (270 degrees) in radians (4.71238 . . .) ⇒ 270 degrees = 270° × (π/180°) rad = 3π/2 or 4.7123 . . .
please marke a a brainalist pls
The state lottery board is examining the machine that randomly picks the lottery numbers. On each trial, the machine outputs a ball with one of the digits 0 through 9 on it. (The ball is then replaced in the machine.) The lottery board tested the machine for 50 trials and got the following results.
(a) Assuming that the machine is fair, compute the theoretical probability of getting a 5 or 6 .
(b) From these results, compute the experimental probability of getting a 5 or 6 .
(c) Assuming that the machine is fair, choose the statement below that is true:
o With a large number of trials, there might be a difference between the experimental and theoretical probabilities, but the difference should be small.
o With a large number of trials, there must be no difference between the experimental and theoretical probabilities.
o With a large number of trials, there must be a large difference between the experimental and theoretical probabilities.
Answers
(a) The theoretical probability of getting a 5 or 6 is 1/5
(b) The experimental probability of getting a 5 or 6 is 1/5
(c) The true statement is the first statement.
What is a probability?A subfield of statistics known as probability studies random events and their likelihood of happening. It is calculated by dividing the number of favorable outcomes by the total number of possible outcomes and is used to make predictions and estimate the likelihood of future events.
(a) Assuming that the machine is fair, the theoretical probability of getting a 5 or 6 is:
P(5 or 6) = P(5) + P(6) = 1/10 + 1/10 = 1/5
(b) From the results, we can see that out of the 50 trials, there were 10 trials where the machine output a 5 or a 6.
The experimental probability of getting a 5 or 6 is:
P(5 or 6) = 10/50 = 1/5
(c) A large number of trials, might be a difference between the experimental and theoretical probabilities, but the difference should be small. This is because the theoretical probability is based on the assumption of a fair machine, while the experimental probability is based on actual results.
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without calculation, find one eigenvalue and two linearly independent eigenvectors of a d [2 4 5 5 5 5 5 5 5 5 5 3 5]. justify your answer.
Answers
To find the eigenvalues and eigenvectors of a matrix, we need to solve the equation Ax = λx, where A is the matrix, λ is the eigenvalue, and x is the eigenvector. In this case, we have a 3x3 matrix, so we expect to find three eigenvalues and three eigenvectors.
Without performing the calculations, it is difficult to determine the exact eigenvalues and eigenvectors of matrix D. However, based on the structure of the matrix, we can make some observations. We notice that the matrix has a repeating pattern of the number 5, which suggests that 5 is a dominant eigenvalue. Additionally, the matrix is symmetric, so we know that the eigenvectors will be orthogonal.
One possible approach to finding the eigenvectors is to use the Gram-Schmidt process, which is a method for orthogonalizing a set of vectors. We can start with a vector that is parallel to one of the columns of the matrix, and then subtract the projection of that vector onto the next column to obtain a vector that is orthogonal to the first. We can continue this process for each column to obtain a set of orthogonal vectors, which will be our eigenvectors.
Based on these observations, we can hypothesize that 5 is an eigenvalue of D and that we can find two linearly independent eigenvectors by using the Gram-Schmidt process on the columns of the matrix. However, we would need to perform the calculations to confirm this hypothesis and determine the exact values of the eigenvectors.
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consider a beam with the cross section shown, made of a material with an allowable stress of 119 mpa.
Answers
The largest couple M that can be applied to the cross-section of beam is 108.23 kN.m.
To determine the largest couple M that can be applied to the cross-section shown, we need to calculate the maximum shear stress in the cross-section and ensure that it is less than the allowable stress of the material.
The cross-section can be divided into two rectangles, and the centroid of the combined shape can be found to be at a distance of 2.5 mm from the top edge and 7.5 mm from the left edge. Using the formula for maximum shear stress, τ = VQ/It, we can find the maximum shear stress as:
V = M*d/A, where d is the distance from the neutral axis to the outermost fiber, and A is the area of the cross-section.
d = 5 mm + 2.5 mm = 7.5 mm
A = (10 mm * 5 mm) + (5 mm * 5 mm) = 75 mm^2
Therefore, V = (M*7.5)/75 = M/10
The second moment of area (I) of the combined shape can be found by summing the second moments of area of the two rectangles about their centroids:
I = (1/12 * 10 mm * (5 mm)^3) + 10 mm * (2.5 mm - 7.5 mm)^2 + (1/12 * 5 mm * (5 mm)^3) + 5 mm * (7.5 mm - 2.5 mm)^2
I = 8541.67 mm^4
The elastic modulus of the material is assumed to be constant and is equal to 200 GPa.
Using these values, we can find the maximum shear stress as:
τ = (M7.5)/(108541.67) * (10/5) = M/916.28 MPa
The maximum allowable stress is given as 118 MPa, so we set τ = 118 MPa and solve for M:
M/916.28 = 118 MPa
M = 108227.68 N.mm = 108.23 kN.m (rounded to two decimal places)
Therefore, the largest couple M that can be applied is 108.23 kN.m.
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_____The given question is incomplete, the complete question is given below:
Consider a beam with the cross section shown, made of a material with an allowable stress of 118 MPa. 10 mm 10 mm 801111n- 5mm 5 mm References eBook & Resources Section Break Difficulty: Easy 2· value: 10.00 points Determine the largest couple M that can be applied to the cross section shown. (Round the final answer to two decimal places.) The largest couple M that can be applied is kN m.
using the definition of compactness (i.e. you should not use the heine-borel theorem), show that the finite union of compact sets is compact.
Answers
To show that the finite union of compact sets is compact, we need to show that any open cover of the union has a finite subcover.
Let A and B be two compact sets. Suppose that U is an open cover of A ∪ B. also U is also an open cover of A and an open cover ofB. Since A is compact, there exists a finite subcover of U that coversA. Let this subcover be{ U1, U2,., Un}. also, since B is compact, there exists a finite subcover of U that coversB. Let this subcover be{ V1, V2,., Vm}.
Also the union of these two finite subcovers is a finite subcover of U that covers A ∪B. Specifically, the subcover is{ U1, U2,., Un, V1, V2,., Vm}. thus, any open cover of the finite union of compact sets A ∪ B has a finite subcover, and therefore A ∪ B is compact. By induction, we can extend this result to any finite union of compact sets.
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If z=x+y ;where x varies p Square and y varies 1/p, find the equation connecting z and p . If z=5 when p=2 ,and z=6 when p=4 find z when p=6
Answers
The equation connecting z and p is:
z = x + (1/p)
To find z when p = 6, we can use the values of x and y when p = 2 and p = 4 to calculate the corresponding value of z when p = 6.
When p = 2, x = 4 and y = 1, so z = 5
When p = 4, x = 16 and y = 0.25, so z = 16.25
Therefore, when p = 6, x = 36 and y = 0.167, so z = 36.167
1//3 x 3.14 x 16^2 x 10
Answers
Answer:
[tex]2679\frac{7}{15}[/tex]
Step-by-step explanation:
[tex]\frac{1}{3}\times 3.14\times 16^2 \times 10[/tex]
First thing we need to do is to evaluate 16^2.
[tex]16^2 = 16\times 16 =256[/tex]
Now, because multiplication is an associative and communitative property, the order that we multiply won't matter. I will rearrange terms to multiply in a more easier way, left to right.
[tex]\frac{1}{3}\times 10\times 256\times 3.14[/tex]
Lets multiply the fraction first. Multiply across, divide 10 by 3. 3R1 gives us:
[tex]3\frac{1}{3} \times 256 \times 3.14[/tex]
Now lets multiply 256. Same method as before.
[tex]853\frac{1}{3}\times 3.14[/tex]
Now, finally, the decimal. Lets convert it to a fraction.
[tex]3.14=\frac{314}{100}[/tex]
Now, replace the decimal in the expression.
[tex]853\frac{1}{3}\times \frac{314}{100}[/tex]
Same method as before. Through rigorous simplifying, we get:
[tex]2679\frac{7}{15}[/tex]
find the smallest value of n that you can for which s n has an element of order greater than or equal to 100
Answers
The value of n that yields the smallest S_n element having an order of at least 100 is 101.
To find the minimum value of n for which the set S_n contains an element with an order equal to or greater than 100, the formula S_n = n!/r!(n-r)! can be used. This formula calculates the number of permutations in a set with n elements, where r elements are chosen at a time. By substituting r=100 into the formula, it is determined that n must be at least 101 to contain an element with an order of 100 or greater. Therefore, the smallest value of n for which S_n contains an element with an order of 100 or greater is 101.
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Complete question:
Find the smallest value of n that you can for which S_n has an element of order greater than or equal to 100
7. Jada walks up to a tank of water that can hold up to 10 gallons. When it is active, a
drain empties water from the tank at a constant rate. When Jada first sees the tank, it
contains 7 gallons of water. Three minutes later, the tank contains 5 gallons of water.
a. At what rate is the amount of water in the tank changing? Use a signed number, and
include the unit of measurement in your answer.
b. How many more minutes will it take for the tank to drain completely? Explain or
show your reasoning.
c. How many minutes before Jada arrived was the water tank completely full? Explain
or show your reasoning.
Answers
In the word problem,
a)Gallons per minute change is -2/3 gallons per minute
b) 7.5 minutes to drain the other 5 gallons
c)The tank was full 4 1/2 minutes before Jada arrived.
What is word problem?
Word problems are often described verbally as instances where a problem exists and one or more questions are posed, the solutions to which can be found by applying mathematical operations to the numerical information provided in the problem statement. Determining whether two provided statements are equal with respect to a collection of rewritings is known as a word problem in computational mathematics.
a) Gallons per minute change is -2/3 gallons per minute since it decreases by 2 gallons in 3 minutes.
b) we have 5 gallons and lose 2/3 gallons per minute
=> (2/3 gal/minute)(x minutes) = 5 gallons
=> x = 5(3/2) = 15/2 = 7.5 minutes to drain the other 5 gallons
c) There was 10 gallons when the tank is full . That is 3 gallons more than the 7 gals there when Jada arrived.
=> (2/3)(x) = 3
=> x = 3(3/2) = 9/2 = 4 1/2 minutes
The tank was full 4 1/2 minutes before Jada arrived.
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Explain the Pythagorean identity in terms of the unit circle.
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The three Pythagorean trigonometric identities, which I’m sure one can find in any Algebra-Trigonometry textbook, are as follows:
sin² θ + cos² θ = 1
tan² θ + 1 = sec² θ
1 + cot² θ = csc² θ
where angle θ is any angle in standard position in the xy-plane.
Consistent with the definition of an identity, the above identities are true for all values of the variable, in this case angle θ, for which the functions involved are defined.
The Pythagorean Identities are so named because they are ultimately derived from a utilization of the Pythagorean Theorem, i.e., c² = a² + b², where c is the length of the hypotenuse of a right triangle and a and b are the lengths of the other two sides.
This derivation can be easily seen when considering the special case of the unit circle (r = 1). For any angle θ in standard position in the xy-plane and whose terminal side intersects the unit circle at the point (x, y), that is a distance r = 1 from the origin, we can construct a right triangle with hypotenuse c = r, with height a = y and with base b = x so that:
c² = a² + b² becomes:
r² = y² + x² = 1²
y² + x² = 1
We also know from our study of the unit circle that x = r(cos θ) = (1)(cos θ) = cos θ and y = r(sin θ) = (1)(sin θ) = sin θ; therefore, substituting, we get:
(sin θ)² + (cos θ)² = 1
1.) sin² θ + cos² θ = 1 which is the first Pythagorean Identity.
Now, if we divide through equation 1.) by cos² θ, we get the second Pythagorean Identity as follows:
(sin² θ + cos² θ)/cos² θ = 1/cos² θ
(sin² θ/cos² θ) + (cos² θ/cos² θ) = 1/cos² θ
(sin θ/cos θ)² + 1 = (1/cos θ)²
(tan θ)² + 1 = (sec θ)²
2.) tan² θ + 1 = sec² θ
Now, if we divide through equation 1.) by sin² θ, we get the third Pythagorean Identity as follows:
(sin² θ + cos² θ)/sin² θ = 1/sin² θ
(sin² θ/sin² θ) + (cos² θ/sin² θ) = 1/sin² θ
1 + (cos θ/sin θ)² = (1/sin θ)²
1 + (cot θ)² = (csc θ)²
3.) 1 + cot² θ = csc² θ
Find the value of cos H rounded to the nearest hundredth, if necessary.
Answers
Given:-
A right angled triangle right angled at I is given to us.The measure of the longest side (hypotenuse) is 41 and the other two sides are 40 and 9 .To find:-
The value of cosH .Answer:-
In the given right angled triangle, cosine is the ratio of base and hypotenuse. In this triangle with respect to angle H , IH is base, IJ is perpendicular and JH is hypotenuse. And their measures are ,
HJ = 41 IH = 40IJ = 9 .And as mentioned earlier, we can find cosH as ,
[tex]\implies\cos\theta =\dfrac{b}{h} \\[/tex]
[tex]\implies \cos H =\dfrac{IH}{HJ} \\[/tex]
On substituting the respective values, we have;
[tex]\implies\cos H = \dfrac{40}{41}\\[/tex]
[tex]\implies \cos H = 0.975 [/tex]
Value rounded to nearest hundred will be ,
[tex]\implies \cos H =\boxed{0.98}[/tex]
Hence the value of cos H 0.98 .
Answer:
cos H = 0.98 (rounded to the nearest hundredth)
Step-by-step explanation:
Answer:
[tex]\cos R=\dfrac{3}{5}[/tex]
Step-by-step explanation:
To find the cosine of an angle in a right triangle, we can use the cosine trigonometric ratio.
The cosine trigonometric ratio is the ratio of the side adjacent to the angle to the hypotenuse.
[tex]\boxed{\cos \theta=\sf \dfrac{A}{H}}[/tex]
From inspection of the given right triangle HIJ, the side adjacent to angle H is IH, and the hypotenuse is HJ. Therefore:
θ = HA = IH = 40H = HJ = 41Substitute these values into the formula:
[tex]\implies \cos H=\dfrac{40}{41}[/tex]
As 41 is a prime number, the fraction cannot be reduced any further.
The value of cos H rounded to the nearest hundredth is:
[tex]\implies \cos H=0.975609756...[/tex]
[tex]\implies \cos H=0.98[/tex]
Solve the equation. (Enter your answers as a comma-separated list. Use n as an arbitrary integer. Enter your response in radians.) tan2(x) + tan(x) − 20 = 0
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The solution of equation of trigonometric functions, tan²(x) + tan(x) − 20 = 0, is equals to the x = 1.33 radians , 1.37 radians (x = arc tan(4) = 1.33 , x = arc tan(-5)= 1.37).
We know that trigonometric functions are periodic functions, solutions of trigonometric equations are then infinite and periodic. In these equations, it is essential to know the reduction formulas of each quadrant, which allows each angle in the first quadrant to be related to its corresponding angle in the other three quadrants. We have an equation which contains triagmometric function,
tan²(x) + tan(x) − 20 = 0 --(1) and we have to solve it. First we change the variable as y = tan(x). Rewrite the equation (1), y² + y - 20 = 0 --(2) which is an quadratic equation. The quadratic formula helps to solve the equation (2).
=> y = ( -1 ± √1 - 4(-20))/2
=> y = ( -1 ± √81)/2
=> y = ( -1 ± 9)/2
=> y = ( -1 + 9)/2 or (-1 -9)/2
=> y = 4, -5
Now x = tan⁻¹(y), and so, x = tan⁻¹(4) = 1.33 radians, or tan⁻¹(-5) = 1.37 radians. Hence, required value is ( 1.33, 1.37).
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T/F. To construct a confidence interval for sigma (or sigma squared), the population from which the sample was drawn must be normally distributed.
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To construct a confidence interval for sigma the population from which the sample was drawn must be normally distributed. -
It is not necessary to make the normalcy assumption in order to build a confidence interval for sigma. To employ the central limit theorem, however, the sample size must be adequate which ideally enables the use of the normal distribution to approximate the sampling distribution of the sample variance. Alternative techniques, like t-distribution, can be employed if total sample size is limited.
It's also important to remember that, regardless of sample size, the distribution of sample variance will be normal if population is known and recognizable to have a normally distributed population. As long as the sample size is appropriate, the sample variance may still be utilized to create a confidence range for sigma even if the population is not normally distributed.
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p(b)=1/4 p(a and b)=3/25 p(a/b(=
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Event a has a 12/25 chance of happening provided that event b has already happened.
what is probability ?It is stated as a number between 0 and 1, where 0 denotes that the event is hypothetical and 1 denotes that it is unavoidable. Furthermore, probability can be stated as a percentage, with a range of 0% to 100%. By dividing the number of favourable outcomes by the entire number of possible possibilities, the probability of an event is determined. Many disciplines, such as statistics, economics, and physics, among others, utilise probability theory.
given
We may apply the conditional probability formula to determine p(a/b):
p(a and b) / p = p(a and b) (b)
Given that p(b) = 1/4 and p(a and b) = 3/25, we may enter these numbers in the formula as follows:
p(a/b) = (3/25) / (1/4)
p(a/b) = (3/25) * (4/1)
p(a/b) = 12/25
Event a has a 12/25 chance of happening provided that event b has already happened.
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Estimate the product. Then find each product 2 1/6 x 4 1/2
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Answer: The estimated product is about 10.
Step-by-step explanation:
To estimate the product, we can round 2 1/6 to 2 and 4 1/2 to 5. Then, we multiply 2 x 5 to get an estimated product of 10.
To find the exact product, we can use the following steps to multiply the two mixed numbers:
Convert each mixed number to an improper fraction:
2 1/6 = 13/6
4 1/2 = 9/2
Multiply the two fractions:
(13/6) x (9/2) = (13 x 9) / (6 x 2) = 117/12
Simplify the fraction, if possible:
117/12 = 9 3/4
Therefore, the exact product of 2 1/6 x 4 1/2 is 9 3/4.