Need some help with trinomial​

Answer:

D. Volume

Explanation:

Here the substance is soil and planter will hold the specific volume of soil.

Answer:

b no.is the correct answer.

Answer:

Area of a Rectangle: l x w

2 x 3 = 6

Area of a Triangle:

[tex] \frac{b \times h}{2} [/tex]

The slanted height of the triangle is 2 and the base of the triangle is also 2 so

[tex] \frac{2 \times 2}{2} \\ \\ \frac{4}{2} = 2[/tex]

So to get the area of the figure you add the area of the rectangle plus the area of the triangle.

6+2=8

The area of the figure is 8 units square

Answer:

$40

Step-by-step explanation:

Old Sale Price = $100

It was given 60% discount

 60% of 100 = 0.6 x 100 = 60

we remove the discount from  the original price( 100 -60 ) =  40.

So the new sale price for the pants are now $40

Answer:

x-y=3

Step-by-step explanation:

Answer:

[tex]x - y = 3[/tex]

is

[tex]y - 3 = (x - 6)[/tex]

in standard form

The volume of this right prism that has a triangular base is equal to 108 cubic meters.

Mathematically, the volume of a right prism is given by this formula:

V = L x W x H

Where:

Given the following data:

Length of base = 6 meters.

Width of base = 4 meters. cm.

Height of prism = 4.5 meters.

Substituting the given parameters into the formula, we have;

V = 6 x 4 x 5

V = 108 cubic meters.

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Answer: 54 m³

Step-by-step explanation: proof with more answers

Here's how we know that  [tex]\sqrt37[/tex] is a little more than 6:

6 squared is 36.

7 squared is 49.

Since 37 is between 36 and 49, we know that  [tex]\sqrt{37}[/tex] must be between 6 and 7. In other words, [tex]\sqrt{37}[/tex] is a little more than 6.We can also see this visually by looking at a number line. If we plot the numbers from 6 to 7 on a number line, we can see that  [tex]\sqrt{37}[/tex] is somewhere between 6 and 7.

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Answer:

N = -1

explanation:

x = N

solving steps:

[tex]\sf f(x)=x^2+2x-15[/tex]

To find symmetry of a quadratic function.

                                                                   vertex formula    :   [tex]\sf x=\dfrac{-b}{2a}[/tex]

[tex]a=1,\:b=2[/tex]

[tex]\sf x=\dfrac{-2}{2\cdot \:1}[/tex]

[tex]\sf x = -1[/tex]

Then,

N = -1

Answer:

B

Step-by-step explanation:

(8,12)=(x1, y1)

(1,3)=(X2, y2)

distance=√(x2-x1)^2+(y2-y1)^2

=√(1-8)^2+(3-12)^2

=√(49+81)

√130

=11.40

Step-by-step explanation:

Answer:

11.42

Step-by-step explanation:

Answer:

The answer should be C. 250 in^3

Answer:

C. 250 in^3

Step-by-step explanation:

Answer for first question: x-intercept(s): (92,0)(92,0) y-intercept(s): (0,−95) for second question : x-intercept(s): (23,0)(23,0) y-intercept(s): (0,−12)

Step-by-step explanation:

Answer:

2x/x+2

Step-by-step explanation:

Factor out 2x in the numerator

Then you get: 2x(x+4)

Factor the denominator

Two numbers that multiply to 8 and add to 6(2 and 4)

So you get: (x+2)(x+4)

Now you have: (2x(x+4))/(x+2)(x+4)

Simplify by cancelling the x+4

2x/x+2

Hey there!

Answer: [tex] \Rightarrow \boxed {\sf{\frac{2x}{(x+2)}}}[/tex]

Solving steps:-

[tex] \rightarrow\sf{\frac{ {2x}^{2} + 8x}{ {x}^{2} + 6x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ {x}^{2} + 4x +2x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ x (x + 4) +2(x + 4)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x\sout{(x + 4)}}{ \sout{(x + 4)} (x + 2)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x}{ (x + 2)} }[/tex]

~Done~

Answer:

it's 2.9 that's how. I get the qnswer

Answer:O a=5,b= -4,0 = 9?

Step-by-step explanation:i am not sure if this is right

[tex]\dfrac{3a^2-6a+3}{a^2-1}\\\\=\dfrac{3(a^2 -2a+1)}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)^2}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)}{a+1}\\\\=\dfrac{3a-3}{a+1} ~~~\text{for}~ a\neq 1[/tex]

Answer:

black screen

Step-by-step explanation:

this is a black screen

Answer: 3.75 is at it's lowest terms. if you mean fractions its 15/4 or 3 & 3/4

Step-by-step explanation:

Answer:

[tex]\begin{aligned}{&\cos \theta=\frac{10}{26} \\\bf{&\tan \theta=\frac{24}{10}}\end{aligned}[/tex]

Step-by-step explanation:

Since the angle is in the first quadrant, the values of all trigonometric functions are positive. Also. the formulas for the trigonometric functions we need to find from the problem are shown below:
[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\\tan \theta &=\frac{y}{x}\end{aligned}[/tex]

Based on the formulas listed, the value of y and r are y = 24 and r = 26 respectively. This means that in order to determine the value of the other functions, we need In compute for the value of x using the Pythagorean Theorem:

[tex]\begin{aligned}r^{2} &=x^{2}+y^{2} \\r^{2}-y^{2} &=x^{2}+y^{2}-y^{2} \quad\left[\text { \text{Subtracting \ both \ sides \ of \ the \ equation\ by} } y^{2}\right] \\r^{2}-y^{2} &=x^{2} \\\sqrt{r^{2}-y^{2}} &=\sqrt{x^{2}} \\\sqrt{r^{2}-y^{2}} &=x \\\sqrt{26^{2}-24^{2}} &=x \\10 &=x\end{aligned}[/tex]Then, substituting this to the formula to determine the answers yields:

[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\&=\frac{10}{26} \\\tan \theta &=\frac{y}{x} \\&=\frac{24}{10}\end{aligned}[/tex]

Therefore, the answers are:

[tex]\begin{aligned}&\cos \theta=\frac{10}{26} \\&\tan \theta=\frac{24}{10}\end{aligned}[/tex]

Answer:

See below

Step-by-step explanation:

We are here given that ,

[tex]\longrightarrow \sin\theta =\dfrac{24}{26}[/tex]

And we would like to find out other trigonometric ratios ( since it is not mentioned about which two I will find out all 6 ) . As we know that ,

[tex]\longrightarrow \sin\theta =\dfrac{perpendicular}{hypotenuse} =\dfrac{p}{h}[/tex]

So that ,

[tex]\longrightarrow \dfrac{p}{h} =\dfrac{24}{26}[/tex]

Let us assume the given ratio to be 24x : 26x .

So we can say that ,

Now let's find out the value of base , so that we can find out the other ratios .

By Pythagoras Theorem ,

[tex]\longrightarrow (perpendicular) ^2+(base)^2=(hypotenuse) ^2[/tex]

Substitute the respective values ,

[tex]\longrightarrow (26x)^2=(24x)^2+b^2\\[/tex]

[tex]\longrightarrow 676x^2 = 576x^2+b^2\\ [/tex]

[tex]\longrightarrow b^2=100x^2\\[/tex]

[tex]\longrightarrow b =\sqrt{100x^2}\\[/tex]

[tex]\longrightarrow \boldsymbol{ b = 10x } [/tex]

Now we may find the other ratios as ,

[tex]\longrightarrow \cos\theta = \dfrac{base}{hypotenuse}=\dfrac{10x}{26x}=\boxed{\boldsymbol{\dfrac{5}{13}}}\\[/tex]

[tex]\longrightarrow \tan\theta =\dfrac{perpendicular}{base}=\dfrac{24x}{10x}=\boxed{\boldsymbol{\dfrac{12}{5}}}\\[/tex]

[tex]\longrightarrow \cosec\theta =\dfrac{hypotenuse}{perpendicular}=\dfrac{26x}{24x}=\boxed{\boldsymbol{\dfrac{13}{12}}}\\ [/tex]

[tex]\longrightarrow \sec\theta =\dfrac{hypotenuse}{base}=\dfrac{26x}{10x}=\boxed{\boldsymbol{\dfrac{13}{5}}} \\[/tex]

[tex]\longrightarrow \cot\theta =\dfrac{base}{perpendicular}=\dfrac{10x}{24x}=\boxed{\boldsymbol{\dfrac{5}{12}}} [/tex]

And we are done !

Answer:

x = 2

x = -1.5

Step-by-step explanation:

The graph is of function f(x) = x²

Therefore, to find where the function intersects with y = 0.5x + 3,

equal the functions and solve for x:

⇒ x² = 0.5x + 3

⇒ x² - 0.5x - 3 = 0

Multiply both sides by 2:

⇒ 2x² - x - 6 = 0

Factor:

⇒ 2x² - 4x + 3x - 6 = 0

⇒ 2x(x - 2) + 3(x - 2) = 0

⇒ (x - 2)(2x + 3) = 0

Therefore:

(x - 2) = 0  ⇒  x = 2

(2x + 3) = 0  ⇒  x = -1.5

Step-by-step explanation:

1-(a)

2-(c)

3-(d)

4-(b)

I hope it helped you

If u didn't understand anything pls ask in comment

Answer:

$168.75

Step-by-step explanation:

In the morning you'll have a time of about 4 hours.

In the afternoon you'll have 8.5 hours.

You take these and add them together 4 + 8.5 = 12.5

Then you take your sum and multiply it by the wage you make per hour 13.50 x 12.5 = $168.75

Answer:

20% off

Step-by-step explanation:

Divide:

72.8/364

Answer:

.20

Convert:

.20=20%

The shopkeeper giving 80% discount on the Christmas tree during the sale.

A discount is an amount that is subtracted from the regular price of an item.

[tex]discount \ percent = \frac{original \ price - final \ price }{original \ price } \times 100[/tex]

According to the given question.

The marked price of the Christmas tree i.e. original price = $364.

The price of the Christmas tree on sale i.e. final price  = $72.80

So,

The discount given on the Christmas tree

= Original price - final price

= $364 - $72.80

= 291.2

Therefore,

Discount percent  = [tex]\frac{291.2}{364} (100)= 80 \ percent[/tex]

Hence, the shopkeeper giving 80% discount on the Christmas tree during the sale.

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4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.

5) B

Area of a triangle = ½ bh.

where b = base &

h = height.

Area of outer shape = (½ x 16 x 12) in^2.

= 96 in^2.

Area of unshaded inner shape = (½ x 3 x 4) in^2.

= 6 in^2.

Area of shaded region = (96 – 6) in^2.

= 90 in^2.

The value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

The difference formula in trignometry for the sine funciton is given as,

[tex]\sin(A-B)=\sin(A)\cos(B) -\cos(A)\sin(B)[/tex]

The trignometric equation given in the problem is,

[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)[/tex]

Compare this equation with the above eqution, we get,

[tex]A=80^o\\B=20^o[/tex]

Thus, this equation can be written as,

[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(80-20)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(60)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\dfrac{\sqrt{3}}{2}[/tex]

Hence, the value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

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Answer:

6

Step-by-step explanation:

because 5 is greater than 4

Use the slope formula and pick any two points  to find the slope.

m= Y2- Y1/x2-x1

I picked the points (1,8) (3,14).

14-8/3-1= 6/2= 3

Hope this helps .

How far both planes travelled is an illustration of distance

Both planes are 510 km apart at 2 pm

The rates of the two planes are given as:

Plane A = 300km/h

Plane B = 45km/h

Calculate the difference (r) in their rates

r = 300km/h - 45km/h

This gives

r = 255km/h

At 2 pm, both planes have travelled for 2 hours.

So, the distance between them is:

d = 255 * 2

d = 510km

Hence, both planes are 510 km apart at 2 pm

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