NH₄NO₃ → N₂O + 2H₂O When 45.70 g of NH₄NO₃ decomposes, what mass of each product is formed?

Answers

Answer 1

Answer: 25.13 g of [tex]N_2O[/tex]  and 20.56 g of [tex]H_2O[/tex] will be produced from 45.70 g of [tex]NH_4NO_3[/tex]

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} NH_4NO_3=\frac{45.70g}{80.04g/mol}=0.571moles[/tex]

The balanced chemical equation is:

[tex]NH_4NO_3\rightarrow N_2O+2H_2O[/tex]  

According to stoichiometry :

1 mole of [tex]NH_4NO_3[/tex] produce = 1 mole of [tex]N_2O[/tex]

Thus 0.571 moles of [tex]NH_4NO_3[/tex] will require=[tex]\frac{1}{1}\times 0.571=0.571moles[/tex]  of [tex]N_2O[/tex]  

Mass of [tex]N_2O=moles\times {\text {Molar mass}}=0.571moles\times 44.01g/mol=25.13g[/tex]

1 mole of [tex]NH_4NO_3[/tex] produce = 2 moles of [tex]H_2O[/tex]

Thus 0.571 moles of [tex]NH_4NO_3[/tex] will require=[tex]\frac{2}{1}\times 0.571=1.142moles[/tex]  of [tex]H_2O[/tex]  

Mass of [tex]H_2O=moles\times {\text {Molar mass}}=1.142moles\times 18g/mol=20.56g[/tex]

Thus 25.13 g of [tex]N_2O[/tex]  and 20.56 g of [tex]H_2O[/tex] will be produced from 45.70 g of [tex]NH_4NO_3[/tex]


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Question 10 options:
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Answers

Answer:

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Answer

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Explanation:

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Answer:

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Answer:

false

Explanation:

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Explanation:

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Answer:

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Explanation:

Answer:

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Answer:

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Answer:

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Explanation:

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Answers

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Answers

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Answers

Answer:

See explanation

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Answers

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Sandban
Grade 8 Science Winter Interim
Question
Q Zoom
Signed in as NOTRE
Q Review Finish Test
Question
>
Normal
ABC
Question 3
Twoiron balls are dropped from a height of 100 meters One Dal Frame A) is not moving when it is dropped and the second ball is moving horizontally at a constant velocity of 10 m/s when it is dropped (Frame B). The balls follow the
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Answers

Ahhhhhhhhhhhh Ask some one else

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Answer:

lol im sorry man

Explanation:

Answer:

My old acc got banned

Explanation:

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Answers

Given:
Fs=8.7N
K=190N/m
Unkown:
X=?
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Fs=Kx
8.7N=(190N/m)x
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The spring will stretch "4.6×10⁻2 m".

Given values are:

Force, Fs = 8.7 NSpring constant, k = 190 N/m

As we know the relation,

→ [tex]Fs = K\times x[/tex]

or,

→   [tex]x = \frac{Fs}{k}[/tex]

By putting the values, we get

        [tex]= \frac{8.7}{190}[/tex]

        [tex]= 4.6\times 10^{-2} \ m[/tex]

Thus the response above is right.

Learn more about spring constant here:

https://brainly.com/question/15404289

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Answers

Answer: carrier, is a person or other organism that has inherited a recessive allele for a genetic trait or mutation but usually does not display that trait or show symptoms of the disease. Carriers are, however, able to pass the allele onto their offspring, who may then express the genetic trait.

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