of the 80 students who signed up for after school clubs , 16 students signed up for the art club and the the other one signed up for different clubs find the ratio of the number of students who signed up for art club and student who sighned up for other clubs express your answer in simplest form

Answer:

3.6 kg

Step-by-step explanation:

A meat packer has 180 kilograms of ground meat. He will divide it equally into 50 packages. How much will each package weigh??

Since he is dividing equally, we have:

50 packages = 180 kg

1 package = x kg

Cross Multiply

x kg × 50 packages= 180kg × 1 packages

x kg = 180 kg × 1/50 packages

x kg = 3.6 kg

Hence, 1 package would weigh 3.6 kg(kilograms)

Answer:

7. A

8. D

9. C

10. D

13. D

Step-by-step explanation:

Hope that helps :)

[tex]the \: surface \: area \: of \: both \: cone = 2(\pi{rl} + \pi{ {r}^{2} } ) \\ total \: surface \: area \: of \: both \: cone = 2(\pi{( \frac{1.4}{2} )(2.7)} + \pi{ {( \frac{1.4}{2} )}^{2} } ) \\ total \: surface \: area \: of \: both \: cone = \boxed{4.76\pi} \\ \\ the \: surface \: area \: of \: the \: cylinder = 2\pi{rl} +2 \pi{ {r}^{2} } \\ the \: surface \: area \: of \: the \: cylinder = 2\pi{( \frac{1.4}{2} )(7.5)} +2 \pi{ {( \frac{1.4}{2} )}^{2} } \\ the \: surface \: area \: of \: the \: cylinder = \boxed{11.48\pi} \\ \\ therefore \: the \: surface \: area \: of \: the \: composite \: object \: = \boxed{4.76\pi + 11.48\pi} \\ the \: surface \: area \: of \: the \: composite \: object \: = \boxed{16.24\pi}[/tex]

Answer: 120 sq in.

Step-by-step explanation:

Answer:

sry I can't understand how to do this question

Answer:

I think it is 5 + 2x

Step-by-step explanation:

Answer:

Answer:

Transitive property of segment congruence

Step-by-step explanation:

The reflexive, symmetric, and transitive properties are the criterion for an equivalence relation. In terms of congruence,

In terms of general equivalence relations,

That's the transitive property.

The fact that congruence is transitive means exactly what you have written: if A is congruent to B and B is congruent to C, then you can "bridge" from A to C.

Answer:

x=-9

Step-by-step explanation:

9=-3(x+6)

9=-3x-18

27=-3x

-9=x

Answer:

25 miles

Step-by-step explanation:

50/2=25

Answer:

25 miles

Step-by-step explanation:

it would be half of 50 so it would be 25 because it goes up by 25 each time

Answer:

The altitude is changing at a speed of 200 √3 km/hr

Step-by-step explanation:

Here, we want to know how far the altitude of the plane is changing

we are told that the airplane makes an angle of 60 degrees with the ground

So therefore , the rate of change of its altitude will be ;

sin 60 = x/ 400

x = 400 sin 60

x = 400 * √3/2

x = 200 √3 km/hr

The altitude is increasing at a rate of 346.61 km/hr.

The diagram below denotes the given scenario.

Then from the diagram we have,

[tex]sin60^{\circ}=\frac{y}{z}\\\frac{\sqrt{3}}{2} =\frac{y}{z}\\ y=\sqrt{3}\\z=2[/tex]

Then,

[tex]sin\theta =\frac{y}{z}\\cos\theta \frac{d\theta}{dt}\\=\frac{z\frac{dy}{dt}-y\frac{dz}{dt}}{z^2} \\\frac{dy}{dt}=\frac{z^2cos\theta\frac{d\theta}{dt+y\frac{dz}{dt}}}{z}\\\frac{dy}{dt} =\frac{2^2(cos60^{\circ})+\sqrt{3}(400)}{2}\\ \frac{dy}{dt}=346.41 km/hr[/tex]

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Answer: 1.55%

Step-by-step explanation:

p = Principal = $40000

r = Interest rate = 1.55% = 0.0155

n = Number of periods = 365

APY = [1 + (r/n)^n - 1]

= [1 + (0.0155/365)^365 - 1]

= [1 + 0.000042)^365 - 1]

= [1.000042]^365 - 1

= 1.015448 - 1

= 1.55%

Happy Holidays! :)

[tex]\large\boxed{h(x) = 4x + 48}[/tex]

[tex]f(x) = \frac{1}{4}x - 12[/tex]

Find the inverse. Begin by swapping the x and y (f(x)) variables:

[tex]x= \frac{1}{4}y - 12[/tex]

Begin isolating for y. Add 12 to both sides:

[tex]x + 12 = \frac{1}{4}y[/tex]

Multiply both sides by 4:

[tex]4(x + 12) = \frac{1}{4}y * 4[/tex]

[tex]4x + 48 = y[/tex]

Therefore:

[tex]h(x) = 4x + 48[/tex]

Answer:

B.)  Flip a coin for each person on the list. If the coin comes up heads, they will be put in the group that exercises before lunch. If the coin comes up tails, they will be put in the group that exercises after lunch.

D.)  The names are put into a bowl and mixed around. The first 50 names drawn will be put in the group that exercises before lunch, and the others will exercise after lunch.

Step-by-step explanation:

These are all the random ones I picked.

The two methods that can be adopted are Option 1 and 3

Random Sampling is the sampling method where samples are chosen randomly.

each unit has an equal chance of being selected in a sample.

It is given that

One hundred people are recruited for an experimental study to determine whether

exercising 30 minutes before lunch or 30 minutes after lunch will help improve heart health more.

They will be split into two groups that do not necessarily need to be the same size

the methods that can be used to randomly assign people in the experimental study into two groups.

1. Flip a coin for each person on the list. If the coin comes up heads, they will be put in the group that exercises before lunch. If the coin comes up tails, they will be put in the group that exercises after lunch

2.The names are put into a bowl and mixed around. The first 50 names drawn will be put in the group that exercises before lunch, and the others will exercise after lunch.

Therefore Option 1 and 3 are the two methods that can be adopted.

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Answer:

Three piles

Let No. of shells =S

pile1=0.5 S

pile2=0.5S-10

pile 3=10

The required expression is [tex]y=x-10[/tex]

Computation:

Let us that,

The number of shells in pile 1 be[tex]'x'[/tex]

The number of shells in pile 2 be [tex]'y'[/tex]

The number of shells in pile 3 be [tex]'z'[/tex]

Now,

The number of shells in pile 2 is 10 fewer than the number of shells in pile 1.

So, the expression is, [tex]y = x - 10[/tex]

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Answer:

WAIT WHERE IS THE QUESTION

Step-by-step explanation:

Answer:

11 dollars

Step-by-step explanation:

82-16=66

You subtract the money she has left over and then divide that number by the amount of books that were bought

66 Divided by 6 = 11

Answer:

The cubic function is f(x) = (27/32)·x  - 3/32·x³ - -9/32·x² - 9/32

Step-by-step explanation:

The given function is f(x) = a·x³ + b·x² + c·x + d

By differentiation, we have;

3·a·x² + 2·b·x + c = 0

3·a·(-3)² + 2·b·(-3) + c = 0

3·a·9 - 6·b + c = 0

27·a - 6·b + c = 0

3·a·(1)² + 2·b·(1) + c = 0

3·a + 2·b + c = 0

a·(-3)³ + b·(-3)² + c·(-3) + d = -3

-27·a + 9·b - 3·c + d = -3...(1)

a + b + c + d = 0...(2)

Subtracting equation (1) from equation (2) gives;

28·a - 8·b + 4·c = 3

Therefore, we have;

27·a - 6·b + c = 0

3·a + 2·b + c = 0

28·a - 8·b + 4·c = 0

Solving the system of equations using an Wolfram Alpha gives;

a = -3/32, b = -9/32, c = 27/32 from which we have;

a + b + c + d = 0 3 × (-3/32) + 2 × (-9/32) + (27/32) + d = 0

d = 0 - (0 3 × (-3/32) + 2 × (-9/32) + (27/32)) = -9/32

The cubic function is therefore f(x) = (-3/32)·x³ + (-9/32)·x² + (27/32)·x + (-9/32).

Answer:

165*6+53+792= 990+845 = 1,835

Step-by-step explanation:

All you have to do is reflect the triangle over the line x = -1.

The answer is in the graph below.

Answer:

p + n ≠ 18

Step-by-step explanation:

Answer:

she would be 16 years old

Step-by-step explanation:

hope this helps!! :D

From the given information we found out that age of Mia is 16 years.

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

Given, Mia discovered that if she takes half her age and adds 3,

Assuming Mia's age to be x years.

∴ (1/2)x + 3...(i)

It produces the same result as taking one-fourth of her age and adding 7,

∴ (1/4)x + 7...(ii)

So, (1/2)x + 3 = (1/4)x + 7.

(1/2)x - (1/4)x = 7 - 3.

(1/4)x = 4.

x = 4×4/1.

x = 16.

So, Age of Mia is 16 years.

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Answer:

Ummmmm ehhhhhh

I need points for a hw

Let [tex]p[/tex] and [tex]q[/tex] be two numbers, such that

[tex]10000 < 210p < 11000, \quad 10000 < 210q < 11000[/tex]

If [tex]p[/tex] and [tex]q[/tex] have no common factors, the greatest common factor between [tex]210p[/tex] and [tex]210 q[/tex] is obviously 210.

If we divide the inequalities above by 210, we see that

[tex]\dfrac{10000}{210} < p < \dfrac{11000}{210}, \quad \dfrac{10000}{210}< q< \dfrac{11000}{210}[/tex]

And rounding to the nearest integer, we deduce that [tex]p[/tex] and [tex]q[/tex] must be between 48 and 52.

We may pick [tex]p=49[/tex] and [tex]q=50[/tex], because they have no common factors. So, our numbers would be

[tex]210\cdot 49=10290,\quad 210\cdot 50=10500[/tex]

The correct format of the question is

At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equation below, where t represents the number of years since the end of 2006 and P represents the number of people. [tex]P = 400 ( 1.2 )^ t[/tex] Based on this model, approximately what was the increase in the population of Riverside at the end of 2009 compared to the end of 2006?

(A) 291

(B) 691

(C) 1040

(D) 1440

Answer:

The increase in the population at the end of 2009 is 291 people

Step-by-step explanation:

We are given the equation as [tex]P = 400 ( 1.2 )^ t[/tex]

where

P = No of People

t= No of Years

it is given that in the year 2006 the population is 400

this will only happen when we take t= 0

so for

Year    value of t

2006-    t = 0

2007-    t  = 1

2008-    t = 2

2009     t = 3

No of people in 2009 will be

[tex]P = 400(1.2)^3[/tex]

     = 400*1.728

   P  = 691.2

Since the equation represents no of people so it can't be in decimals, Therefore the population will be 691

Increase = P(2009) - P(2006)

               = 691 - 400

                = 291

The increase in the population at the end of 2009 is 291 people.

Answer:

(-8,-5)

Step-by-step explanation:

Well, if we divide the square root of M by the hypotenuse due to the activation of the square root of A, then we can achieve the absolute equilibrium between both statements as we bring the oven to about 220 degrees Farenheit, the brownies will look great.

Answer:

Rational

Step-by-step explanation:

All rational numbers can be written as fractions.