On another planet, the isotopes of titanium have the given natural abundances.
Isotope Abundance
Mass (u)
46Ti
70.600%
45.95263
48Ti
12.900%
47.94795
50Ti
16.500%
49.94479
What is the average atomic mass of titanium on that planet?

Answers

Answer 1
im pretty sure you do the number times the percentage converted to a decimal and then add the sums so (46*0.706)+(48*0.129)+(50*0.165)
32.476+6.192+8.25
=46.918 amu

*i dont trust my calc so pleasee check if the answer is right and also remember to convert a percent to decimal move the decimal back 2 places so like for 12.9% the decimal is gonna be 0.129

hope this helpss ask if you have questions

Related Questions

When running an experiment, it is essential to record data and observations within your lab notebook. The data and observations are then discussed and analyzed, results and discussion. However, as you write a conclusion, some data are more important to include than others. Which of the following data would you include if you had to write a conclusion in for outcome of this week's LLE experiment?
a. MP range of product
b. mass of product
c. mass of flask and cork support
d. instrument used to evaporate the solvent
e. volume of crude reaction mixture used
f. % recovery
g. volume of acid and base used
h. theoretical MP
i. mass of flask, cork support, and product

Answers

Answer:

% recovery

MP range of product

mass of product

Explanation:

Liquid–liquid extraction (LLE) is a process of transferring one (or more) solute(s) which are present in a feed solution to another immiscible liquid (solvent). The other solvent that becomes enriched in the target solute(s) is called extract. The original feed solution that is depleted in solute(s) is subsequently referred to as the raffinate.

This method is used to purify compounds and  separate mixtures of compounds. This is very important when we want to isolate a product from a reaction mixture.

The percent recovery is the amount of solute that is transferred to the extract. This is the most important data to be recorded in an LLE experiment.

The melting point range necessarily helps us to identify the product and the mass of solid tells us the quantity of the solid obtained after extraction.

What is one of the major conclusions made from the study of line spectra of various elements?
A)
the movement of electrons outside the nucleus
B)
absorption and emission of energy is quantized
C)
the presence of energy beyond the visible spectrum
D)
the presence of electrons outside the nucleus of an atom

Answers

Answer:

B

Explanation:

A Period 2 element has the following successive ionization energies. Identify the element...

1st: 1087 kJ/mol

2nd: 2353 kJ/mol

3rd: 4621 kJ/mol

4th: 6223 kJ/mol

5th: 37832 kJ/mol

6th: 47279 kJ/mol

7th: 55261 kJ/mol

8th: 69875 kJ/mol

Answers

Answer:

9th:08473 kJ/mol

Explanation:

HAHAHAHAHAHAHAHAHAHA

what is the name of these 4 compound in isomers​

Answers

Answer:

C9H19 C5H12 C6H17 C7H20

How many pounds of ice are required to absorb 4900 kJ of heat as the ice melts? The heat of fusion of water is 0.334 kJ/g.


help pls

Answers

Answer:

Q = ΔH fusion * mass (g)

when we have:

ΔH fusion (the heat (or enthalpy) of fusion = 0.334 kJ/g

and mass of ice = 22.4 g  

so by substitution, we can get the energy (Q) required to melt this mass of ice:

∴ Q = 0.334KJ/g * 22.4 g  

      = 7.48 KJ

∴ the energy required to melt 22.4 g of ice is = 7.48 KJ

Explanation:

Which of the following may add salt to ocean waters?

volcanic eruptions

melting glaciers

rain

biological precipitation

Answers

Answer:

rain

Explanation:

The volcanic eruptions may add salt to ocean waters. option A is correct.

What is a volcanic eruption?

Volcanic eruption produces or releases direct minerals into the water or in the ocean and salt domes are also responsible to increase the salt concentration in the water.

Two of the most commonly found ions in the water of oceans are chloride ions and sodium ions. 85% of the concentration found remaining are the magnesium and sulfate salts.

This process also happens with the mountains but in oceans it invertases the concentration of salt.  

Therefore, volcanic eruptions may add salt to ocean waters. option A is correct.

Learn more about volcanic eruptions, here :

https://brainly.com/question/1622004

#SPJ2

I HAVE 25 MINUTES TO FINISH True or false the deeper you go into Earth the temperature goes up ?

Answers

Answer:

true

Explanation:

you are getting closer to the core hope this helps!

What is the solar radius of a main sequence star?

Answers

Answer:I'm going to give some fictitious values just so that we can get some perspective on the matter.

Let's say that the surface temperature of our sun is 10, the surface temp of the bigger star- the red giant formed from leaving the main sequence, has a temp of 0.2. of that- 2.

We can also say that the radius of our sun is 10, and the radius of the red giant is 1000. (100 times more)

Using the equation:

L

=

σ

A

T

4

σ

= The Stefan-Boltzmann constant =

5.67

×

10

8

But we can ignore the constant, as we are only interested in a ratio of these values.

L

S

u

n

=

4

π

(

10

)

2

×

10

4

=

1.26

×

10

7

L

S

t

a

r

=

4

π

(

1000

)

2

×

2

4

2.01

×

10

8

2.01

×

10

8

1.26

×

10

8

16

So the newly formed, red giant star is almost 16 times more luminous than the sun. This is owing to the increased surface area of the star due to the massively increased radius.

A small sidenote:

There is an equation that might be useful for comparing the radii, temperature and luminosity of main sequence stars. As red giants are not on the main sequence it could not be used here, but if you stumble across a question where they ask you to find the radius, luminosity or temperature given the other two, you can relate it to the sun's characteristics:

r

s

t

a

r

r

s

u

n

=

L

s

t

a

r

L

s

u

n

×

(

T

s

u

n

T

s

t

a

r

)

2

(I know, it's not a beauty to look at- but it works)

Where

X

s

u

n

is the radius, temperature, and luminosity of the sun. These are not often given in numerical values, but this equation serves well when asked to find e.g the radius of a star, in solar radii given that a star is twice as luminous and has 5 times the temperature of that of the sun.

Hence:

T

s

t

a

r

=

5

T

s

u

n

L

s

t

a

r

=

2

L

s

u

n

r

s

t

a

r

r

s

u

n

=

2

L

s

u

n

L

s

u

n

×

(

T

s

u

n

5

T

s

u

n

)

2

(cancel the common terms)

r

s

t

a

r

r

s

u

n

=

2

×

(

1

5

)

2

r

s

t

a

r

0.057

r

s

u

n

(divide both sides by 0.0057)

17.5

r

s

t

a

r

r

s

u

n

So the star's radius is almost 17.5 times that of the sun.

Hopefully, you find this info useful!

Explanation:

How does ice float on water?

Why does solid ice float on liquid water?

Answers

Answer:

Explanation:

Solid ice floats over water because ice is less dense than liquid water, or weighs less, by about 10%, than liquid water

Salt of a weak acid with strong base When
dissolved in water gives?​

Answers

Answer:

it gives base, it is process of neutralization,when acid reacts with base it gives salt and water

Fill in the blank with the correct answer to complete the sentence.
Word bank
size
velocity
distance
time
Momentum increases with an increase in mass and​

Answers

Explanation:

momentum increases with an increase in mass and velocity

Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is: CO(g)C(s) 1/2 O2(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

Answers

The question is missing some parts. Here is the complete question.

Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is:

[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]

we could also write this reaction three other ways listed below. The equilibrium constant for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex]       K₁ =

2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex]    K₂ =

3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex]    K₃ =

Answer: 1) [tex]K_{1}=\frac{1}{K}[/tex]

              2) [tex]K_{2}=\frac{1}{K^{1/2}}[/tex]

             3) [tex]K_{3}=K^{1/2}[/tex]

Explanation: A chemical reaction can be reversible, i.e., can proceed in both directions: to the right of the arrow (forward) or towards the left of the arrow (backward).

When the rates of forward and backward reactions are the same, the reaction is in equilibrium. In that state, we can determine the equilibrium constant, [tex]K_{c}[/tex].

For the first way to represent equilibrium of CO formed, the [tex]K_{c}[/tex] is calculated

[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]

[tex]K=\frac{[O_{2}]}{[CO]^{2}}[/tex]

in which the symbol [ ] is concentration of the compound.

In equilibrium constant, solids are not included.

Equilibrium constants for the other reactions:

1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex]  

[tex]K_{1}=\frac{[CO]^{2}}{[O_{2}]}[/tex]

Comparing K₁ and K, the first one is the inverse of K, so writing in terms of K

[tex]K_{1}=\frac{1}{K}[/tex]

2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex]

[tex]K_{2}=\frac{[CO]}{[O_{2}]^{1/2}}[/tex]

In terms of K, K₂ is

[tex]K_{2}=\frac{1}{K^{1/2}}[/tex]

3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex]

[tex]K_{3}=\frac{[O_{2}]^{1/2}}{[CO]}[/tex]

This constant in terms of K will be

[tex]K_{3}=K^{1/2}[/tex]

In conclusion, K₁, K₂ and K₃ in terms of K is [tex]\frac{1}{K}[/tex],[tex]\frac{1}{K^{1/2}}[/tex] and [tex]K^{1/2}[/tex], respectively.

What is the density of an object with mass 80 kg and volume 05 cubic meters

Answers

Answer:

mesure it

Explanation:

Examining the equations or equilibrium constants related to a base, salt, or an acid is an indirect way to determine strength of an electrolyte. The strength of an electrolyte can be examined directly by placing a solution into a circuit so that the voltage or amount of current can be measured. Although conductivity refers to the flow of charged species, we usually examine conductivity with respect to resistance. As the name implies, a solution that does not conduct electricity very well also has a very high resistance. If solutions containing various acids, bases, and salts were prepared and connected to a circuit that powers a light bulb, the strength of the electrolyte could be estimated by examining the intensity of the light bulb. Complete the following sentences regarding the experimental determination of the electrolyte strength for various molecules dissolved in solution.
a. strong electrolyte
b. weak electrolyte
c. non-electrolyte
1. A 20 mL solution containing 2 mmol of Ca3(PO4)2(s) was integrated into to a circuit that powers a light but, When the power supply was turned on, the light bulb produced a glow. Ca3(PO4)2(s) is__.
2. A 20 mL, solution containing 2 mmol of C12H22O11(aq) was integrated into a circuit that powers a light bulb. When the power supply was turned on the light bulb remained off. C12H22O11(aq) is___.
3. A 20 mL, solution containing 2 mmol of HF(g) was integrated into to a circuit that power a light bulb. When the power supply was turned on the light bulb faintly flickered. HF(g) is an____.
4. A 20 mL solution containing 2 mmol of LiOH(g) was integrated into to a circuit that power a light bulb. When the power supply was turned on the light bulb produced a bright glow LiOH(s) is a____.

Answers

Answer:

1 - Weak electrolyte

2- Non electrolyte

3- Weak electrolyte

4- Strong electrolyte

Explanation:

A strong electrolyte refers to an electrolyte that decomposes completely in solution. This means that there are more charge carriers in solution when a strong electrolyte is dissolved in water. A strong electrolyte produces a strong glow. LiOH is a strong electrolyte.

A weak electrolyte is not completely dissociated in water. Only a small amount dissociates in water. HF is a weak electrolyte. A weak electrolyte does not produce a bright light.

A non-electrolyte does not dissociate in solution at all hence it does not power a bulb E.g  C12H22O11.

The lobes are important for speech and language. O A. parietal O B. temporal o o Ο Ο C. frontal O D. occipital​

Answers

Answer:

Explanation:

D or b

Sorry if wrong

Answer:

temporal

Explanation:

The law that states when different compounds are formed by a combination of the same elements, different masses of one element combine with the same fixed to other elment

Answers

Answer:

The law of multiple proportions states that whenever the same two elements form more than one compound, the different masses of one element that combine with the same mass of the other element are in the ratio of small whole numbers.

I agree with the answer top

1. A solution is always a mixture (true or false)

im not sure what the answer is so if anyone could help me that would be great


(ps im in 5th grade)

Answers

Answer:

yes solution is always a mixture but not all mixtures are solution

Explanation:

A solution.is a homogeneous mixture of substance that have uniform composition throughout

And a mixture hVe twoo or more substances that are not chemically.combine

A student dissolves 12.1 g of potassium chloride (KCl) in 250. g of water in a well-insulated open cup. He then observes the temperature of the water fall from 21.0 °C to 17.1 °C over the course of 6.9 minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction:

KCl(s) → K (aq) + Cl (aq)

a. Is this reaction exothermic, endothermic, or neither?
b. Calculate the reaction enthalpy ΔH.rxn per mole of KCI.

Answers

Answer:

a. Endothermic

b. 26.37kJ/mol

Explanation:

a. As we can see, the temperature of the water is decreasing when the reaction is occurring, that means the reaction is absorbing heat and is endothermic

b. To find the enthalpy we must find the change in heat when 12.1g of KCl are dissolved. Using the equation:

Q = -m*ΔT*C

Where Q is change in heat

m the mass of solution (250g + 12.1g = 262.1g)

ΔT is change in heat (17.1°C - 21.0°C = -3.9°C)

And C is specific heat of the solution (4.184J/g°C assuming is the same than the specific heat of water).

Replacing:

Q = -262.1g*-3.9°C*4.184J/g°C

Q = 4277J = 4.28kJ

As reaction enthalpy is the change in heat per mole of reaction, we must find the moles of 12.1g of KCl:

Moles KCl -Molar mass: 74.55g/mol-:

12.1g KCl * (1 mol / 74.55g) = 0.1623 moles KCl

The reaction enthalpy us:

4.28kJ / 0.1623mol = }

26.37kJ/mol

When do Florida plants prepare themselves for the cold winter temperatures? (1 point)

a
Beginning of the spring

b
During the fall

c
End of the spring

d
End of the summer


PLEASE HELP ASAP!!! >.

Answers

Answer:

A. Beginning of the spring

Explanation:

Pa like, Pa follow, Pa rate

B. During the fall because that is when landscaping happens

Please help quickly as possible thank you :) ​

Answers

When an object/liquid/food etc contains hot energy, the heat particles are moving around causing the heat. 8ounces of soup would cool off faster, because there is less liquid for the heat particles to be in, there for less heat particles, therefore cooling off faster. Pls give Brainliest, and good luck!

Ce clasă ești sa văd daca te pot ajuta

why metals are good conductor of electricity​

Answers

Explanation:

silver is the best conductor

Answer:

Metals are an excellent conductor of electricity and heat because the atoms in the metals form a matrix through which outer electrons can move freely. Instead of orbiting their respective atoms, they form a sea of electrons that surround the positive nuclei of the interacting metal ions

A 50.0 mL solution of 0.129 M KOH is titrated with 0.258 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl.
A) 0.00ml
B)7.00ml
C)12.5ml
D)18.0ml
E)24.0ml
F)25.0ml
G)26.0ml
H)29.0ml

please show work with steps .

Answers

Answer:

A- pH = 13.12

B- pH = 12.91

C- pH = 12.71

D- pH = 12.43

E- pH = 11.55

F- pH = 7

G- pH = 2.46

H- pH = 1.88

Explanation:

This is a titration of a strong base with a strong acid. The neutralization reaction is: KOH (aq) + HCl (aq) →  H₂O(l) + KCl(aq)

Our pH at the equivalence point is 7, because we have made a neutral salt.

To determine the volume at that point we state the formula for titration:

mmoles of base = mmoles of acid

Volume of base  . M of base = Volume of acid . M of acid

50mL . 0.129M = 0.258 M . Volume of acid

Volume of acid = (50mL . 0.129M) / 0.258 M →  25 mL (Point F)

When we add 25 mL of HCl, our pH will be 7.

A- At 0 mL of acid, we only have base.

KOH → K⁺ + OH⁻

[OH⁻] = 0.129 M

To make more easy the operations we will use, mmol.

mol . 1000 = mmoles → mmoles / mL = M

- log 0.129 = 0.889

14 - 0.889 = 13.12

B-  In this case we are adding, (7 mL . 0.258M) = 1.81 mmoles of H⁺

Initially we have  0.129 M . 50 mL = 6.45 mmoles of OH⁻

1.81 mmoles of H⁺ will neutralize, the 6.45 mmoles of OH⁻ so:

6.45 mmol - 1.81 = 4.64 mmoles of OH⁻

This mmoles of OH⁻ are not at 50 mL anymore, because our volume has changed. (Now, we have 50 mL of base + 7 mL of acid) = 57 mL of total volume.

[OH⁻] = 4.64 mmoles / 57 mL = 0.0815 M

- log 0.0815 M = 1.09 → pOH

pH = 14 - pOH → 14 - 1.09 = 12.91

C- In this case we add (12.5 mL . 0.258M) = 3.22 mmoles of H⁺

Our initial mmoles of OH⁻ would not change through all the titration.

Then 6.45 mmoles of OH⁻ are neutralized by 3.22 mmoles of H⁺.

6.45 mmoles of OH⁻ - 3.22 mmoles of H⁺ = 3.23 mmoles of OH⁻

Total volume is: 50 mL of base + 12.5 mL = 62.5 mL

[OH⁻] = 3.23 mmol / 62.5 mL = 0.0517 M

- log  0.0517 = 1.29 → pOH

14 - 1.11 = 12.71

D- We add (18 mL . 0.258M) = 4.64 mmoles of H⁺

6.45 mmoles of OH⁻ are neutralized by 4.64 mmoles of H⁺.

6.45 mmoles of OH⁻ - 4.64 mmoles of H⁺ = 1.81 mmoles of OH⁻

Total volume is: 50 mL of base + 18 mL = 68 mL

[OH⁻] = 1.81 mmol / 68 mL = 0.0265 M

- log  0.0265 = 1.57 → pOH

14 - 1.57 = 12.43

E- We add (24 mL . 0.258M) = 6.19 mmoles of H⁺

6.45 mmoles of OH⁻ are neutralized by 6.19 mmoles of H⁺.

6.45 mmoles of OH⁻ - 6.19 mmoles of H⁺ = 0.26 mmoles of OH⁻

Total volume is: 50 mL of base + 24 mL = 74 mL

[OH⁻] = 0.26 mmol / 74 mL = 3.51×10⁻³ M

- log  3.51×10⁻³  = 2.45 → pOH

14 - 2.45 = 11.55

F- This the equivalence point.

mmoles of OH⁻ = mmoles of H⁺

We add (25 mL . 0.258M) = 6.45 mmoles of H⁺

All the OH⁻ are neutralized.

OH⁻  +  H⁺  ⇄   H₂O              Kw

[OH⁻] = √1×10⁻¹⁴   →  1×10⁻⁷  →  pOH = 7

pH → 14 - 7 = 7

G- In this case we have an excess of H⁻

We add (26 mL . 0.258M ) = 6.71 mmoles of H⁺

We neutralized all the OH⁻ but some H⁺ remain after the equilibrium

6.71 mmoles of H⁺ - 6.45 mmoles of OH⁻ = 0.26 mmoles of H⁺

[H⁺] = 0.26 mmol / Total volume

Total volume is: 50 mL + 26 mL → 76 mL

[H⁺] = 0.26 mmol / 76 mL → 3.42×10⁻³ M

- log 3.42×10⁻³ = 2.46 → pH

H- Now we add (29 mL . 0.258M) = 7.48 mmoles of H⁺

We neutralized all the OH⁻ but some H⁺ remain after the equilibrium

7.48 mmoles of H⁺ - 6.45 mmoles of OH⁻ = 1.03 mmoles of protons

Total volume is 50 mL + 29 mL = 79 mL

[H⁺] = 1.03 mmol / 79 mL → 0.0130 M

- log 0.0130 = 1.88 → pH

After equivalence point, pH will be totally acid, because we always have an excess of protons. Before the equivalence point, pH is basic, because we still have OH⁻ and these hydroxides, will be neutralized through the titration, as we add acid.

The pH value is given by 14 less the logarithm of the hydronium ion

concentration or the hydrogen ion concentration in the solution.

Responses (approximate values):

The pH values are;

A) 13.11

B) 12.91

C) 12.71

D) 12.42

E) 11.54

F) 7

G) 2.469

H) 1.884

Which is used to find the pH of the solution?

A) Concentration of the KOH = 0.129 M

Amount of HCl added = 0.00 ml

The pH = -log[H⁺] = 14 - pOH

pOH = -log[OH⁻]

Which gives;

pH = 14 - (-log[OH⁻] )

pH = 14 - (-log(0.129)) ≈ 13.11

B) Volume of acid added = 7.00 mL = 0.007 L

Concentration of the acid = 0.258 M HCl

Number of moles of acid, H⁺ = 0.007 × 0.258 moles = 0.001806 moles

Number of moles of KOH remaining, OH⁻= 0.05 × 0.129 - 0.001806 = 0.004644

Number of moles of OH⁻ = 0.004644 moles

[tex]Concentration, \ [OH^-] = \dfrac{0.004644 \, moles}{0.05 7 \, L} \approx \mathbf{ 0.0815 \, M}[/tex]

pH of solution = 14 - (-log(0.0815)) ≈ 12.91

C) 12.5 mL HCl contains, 0.0125 × 0.258 moles = 0.003225 moles

OH⁻ remaining = 0.05 × 0.129 - 0.003225 = 0.003225 moles

[tex]Concentration \ of \ [OH^-]= \dfrac{0.003225\, moles}{(0.05 + 0.0125) \, L} = \mathbf{0.0516 \, M}[/tex]

pH of solution = 14 - (-log(0.0516)) ≈ 12.71

D) 18.0 mL HCl contains, 0.018 × 0.258 moles = 0.004644 moles

OH⁻ remaining = 0.05 × 0.129 - 0.004644 = 0.001806 moles

[tex]Concentration \ of \ [OH^-] = \dfrac{0.001806\, moles}{(0.05 + 0.018) \, L} \approx \mathbf{0.0266\, M}[/tex]

pH of solution = 14 - (-log(0.0266)) ≈ 12.42

E) 24.0 mL HCl contains, 0.024 × 0.258 moles = 0.006192 moles

OH⁻ ion remaining = 0.05 × 0.129 - 0.006192 = 0.000258 moles

[tex]Concentration \ of \ [OH^-] = \dfrac{0.000258\, moles}{(0.05 + 0.024) \, L} \approx \mathbf{0.0035\, M}[/tex]

pH of solution = 14 - (-log(0.0035)) ≈ 11.54

F) 25.0 mL HCl contains, 0.025 × 0.258 moles = 0.00645 moles

[OH⁻] remaining = 0.05 × 0.129 - 0.00645 = 0 moles

[tex]Concentration \ of \ [OH^-] = \dfrac{0\, moles}{(0.05 + 0.024) \, L} \approx 0\, M[/tex]

Therefore;

Number of moles of KOH = 0, or the solution is neutralized

[OH⁻] = [H⁺]

Which gives;

pH = pOH = 7

G) 26.0 mL HCl contains, 0.026 × 0.258 moles = 0.006708 moles

[OH⁻] remaining = 0.05 × 0.129 - 0.006708 = -0.000258 moles

Therefore

Number of moles of H⁺ = 0.000258

[tex]\mathbf{Concentration} \ of \ \mathbf{[H^+] }= \dfrac{0.000258\, moles}{(0.05 + 0.026) \, L} \approx 0.003395\, M[/tex]

pH of solution = (-log(0.003395)) ≈ 2.469

H) 29.0 mL HCl contains, 0.029 × 0.258 moles = 0.007482 moles

H⁺ remaining = 0.007482 - 0.05 × 0.129 = 0.001032 moles

Therefore

Number of moles of H⁺ = 0.001032

[tex]Concentration \ of \ [H^+] = \mathbf{ \dfrac{0.001032\, moles}{(0.05 + 0.029) \, L}} \approx 0.01306\, M[/tex]

pH of solution = (-log(0.01306)) ≈ 1.884

Learn more about the pH of a solution here:

https://brainly.com/question/1195974

Animals get energy from the food that they eat. However, when the molecules from the food enter your cells, how do the molecules turn in to energy?

Question 3 options:

The glucose molecules from the food are broken down by the mitochondria in the cell to produce ATP which the cells use as energy.


The ATP is broken down into glucose which the cells use for energy.


Upon hitting the stomach, the food molecules are changed to energy molecules which fuel the body.


The cells absorb ATP from food and use it for energy.

Answers

Answer:

The ATP is broken down into glucose which the cells use for energy.

Which of the following is the best example of water changing from a liquid to a gas?

A. clouds on a summer day


B. morning dew on orange trees


C. fog rising from a pond on a cold day


D. ice melting back to water when it is left out at room temperature

Answers

Answer:

c

Explanation:

hope this helps! ^-^

Answer:

C

Explanation:

It's the answer

Help pls! I need help im just writing to use the character limit!

Answers

Answer:

se que la imaje es un poco confusa con la materia pero

desiaria ayudarte pero CREO que con mi TÉCNICA  es la A

Write True if the statement is correct and False if it is incorrect.
1. Mosquitos are flies.
2. All large invertebrates live in the
sea or at least in water.
3. An arthropod is a form of arachnid.
4. The giant squid is the world's largest
invertebrate.
5. Earthworms have skeleton
6. The octopus is the most advance of
the mollusks.
7. Insects are vertebrates animals.
8. Starfish have shells.
9. Snails have spiral protective shell.
10. Ants and termites both live in colonies
with a complex social structure.​

Answers

T
F
F
T
F
T
T
F
T
T...............................

A per the statement the true and false have been stated.

The mosquitos are flies is True. All large invertebrates live in the sea or at least in water is False. An arthropod is a form of arachnid. False. The giant squid is the world's largest  invertebrate is true. Earthworms have skeleton is false. An octopus is the most advance of  the mollusks is True. Insects are vertebrates animals is false . Most starfish have shells is true.   All Snails have a spiral protective shell is true. The Ants and the termites both live in their colonies  with a complex social structure true.

Learn more about the statement is correct and False if it is incorrect.

brainly.com/question/25942470.

1) De los siguientes cambios indicar cuál es químico y cual es físico:


• Aplastar una lata:


• Congelar agua:


• Quemar pasto:


• Hervir agua:


• Se descompone fruta:


• Se oxida hierro:


• Derretir chocolate:


• Mezclar agua y sal:


• Pulverizar un ladrillo:


• Quemar pólvora ​

Answers

fisco quimicoquimicoquimicoquimicoquimicofisico fisico fisico quimico

What is the formula for Decaoxygen pentasulfide

Answers

Answer:

Compound Formula. 1, Carbon dioxide, CO2. 2, Carbon monoxide, CO. 3, Diphosphorus pentoxide, P2O5. 4, Dinitrogen monoxide, N2O.

Explanation:

dont even know by thoAnswer:

Explanation:

Two identical spoons are electroplated with Ag or Cd through the use of the electrolytic cells. A current of 5.00A was supplied to each cell for 600. seconds, and the masses of the spoons before and after the electroplating were recorded. Write down the mathematical equations can best be used to account for the much larger increase in mass of the spoon electroplated with Ag compared with the spoon electroplated with Cd.

Answers

Answer:

Explanation:

One farad of charge is capable of depositing one gram equivalent of a metal

One gram equivalent of Ag = 108 grams

One gram equivalent of Cd = 112 / 2  grams

= 56 grams . [ for cadmium equivalent mass = atomic mass / s ]

electric charge flowing = current x time = 5 x 600 = 3000 coulomb

one farad = 96500 coulomb

96500 coulomb  deposits 108 gram of Ag

3000 coulomb deposits 108 x 3000 / 96500 gram

= 3.35 grams of Ag

Similarly ,

96500 coulomb  deposits 56 gram of Cd

3000 coulomb deposits 56 x 3000 / 96500 gram

= 1.74  grams of Cd

So there will be much larger increase in the spoon of Ag due to larger deposit of Ag by charge .

What is a mixture of two insoluble mixtures called​

Answers

Answer:

Emulsion

Explanation:

Emulsion is a special type of mixture formed by combining two liquids that do not normally mix. An example of emulsion is;

Oil and Water

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