On Monday at 1 p.M., when the ocean's surface was at an elevation of 2.2 feet, Winston went to a surf shop that was 8.2 feet above the ocean's surface. At 7 p.M. When the ocean's surface was at an elevation of -2.4 feet, Winston ate dinner at a restaurant whose deck was 10 feet above the ocean's surface.What was the distance between the deck and the ocean's surface at 1 p.M.?
Answers
Answer:
5.4 feet
Step-by-step explanation:
Let the reference line [tex]A_0B_0[/tex] represents the sea level without any elevation.
At 1 P.M. the ocean surface was at an elevation of 2.2 feet along the line [tex]A_1B_1[/tex] in the figure and the surf shop was 8.2 feet above of this elevated ocean's surface along the line [tex]A_2B_2[/tex] in the figure.
Similarly, at 7 P.M. the ocean surface was at an elevation of -2.4 feet along the line [tex]A_3B_3[/tex] in the figure and the deck in the restaurant was 8.2 feet above of this elevated ocean's surface along the line [tex]A_4B_4[/tex] in the figure.
From the figure, the distance between the deck and the ocean's surface at 1 P.M.= The distance between the lines [tex]A_1B_1[/tex] and [tex]A_4B_4[/tex].
[tex]d= 10- (d_1+d_2)[/tex]
[tex]=10-(2.2+2.4)[/tex]
=5.4 feet
Hence, the distance between the deck and the ocean's surface at 1 P.M. is 5.4 feet.
The distance between the deck and the ocean surface at 1 P.M. is 5.4 feet.
This is a problem of relative and absolute distances. First, we determine the absolute elevation of the surf shop at 1 P.M.:
[tex]x_{1} = 8.2\,ft + 2.2\,ft[/tex]
[tex]x_{1} = 10.4\,ft[/tex]
Now we determine the absolute elevation of the deck at 7 P.M.:
[tex]x_{2} = 10\,ft - 2.4\,ft[/tex]
[tex]x_{2} = 7.6\,ft[/tex]
Lastly, we calculate the elevation of the deck relative to the ocean surface at 1 P.M.:
[tex]x' = 7.6\,ft - 2.2\,ft[/tex]
[tex]x' = 5.4\,ft[/tex]
The distance between the deck and the ocean surface at 1 P.M. is 5.4 feet.
To learn more on distances, we kindly invite to check this verified question: https://brainly.com/question/989117
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Step-by-step explanation:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
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Answer:
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Answers
Answer:
10,500.93 feet
Step-by-step explanation:
From the question, we are told that Tom walks 3.2km every morning.
1 mile = 1.609km
1 mile = 5280 feet
Step 1
1.609km = 1 mile
3.2km = x mile
Cross Multiply
x mile × 1.609km = 3.2km × 1 mile
x mile = 3.2km × 1 mile/1.609.
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Answer:
10,500.93 feet
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Answers
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Answers
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Open-Ended Which of these situations can be represented by the opposite of 53? Use pencil and
paper. Describe two more situations that can be represented by the opposite of 53.
A book was 53 pages shorter than you expected.
Andrew spent $53.
The temperature was 53°F.
Jennifer sold 53 apples.
Select each situation that can be represented by the opposite of 53.
O A. Andrew spent $53.
OB. Jennifer sold 53 apples.
OC. A book was 53 pages shorter than you expected.
D. The temperature was 53°F.
Answers
Answer:
A book was 53 pages shorter than you expected
Jennifer sold 53 apples.
Andrew spent $53.
Step-by-step explanation:
The question proposed that we should determine which situation can be said to be the opposite of 53. From the listed option, we will realize that the following:
A book was 53 pages shorter than you expected
Jennifer sold 53 apples.
Andrew spent $53.
The above options are the opposite of 53. This is because a book that was shorter than expected will need to be refilled.
Suppose Jennifer has x apples, and She sold 53 apples out of it. It means x = -53, which is the opposite of 53.
Andrew spent $53; let say Andrew had y+$53. After spending $53, he has y = - $53, which is the opposite of 53.
But the temperature, which was 53°F, will still be at that position on the thermometer provided it is not being affected by external conditions.
The stemplot shows the number of magazines sold by students in a band. One data value was inadvertently omitted from the stemplot. A stemplot titled magazines sold has values 8, 9, 12, 12, 13, 15, 16, 16, 16, 18, 21, 22, 23, 27, 28, 32, 34, 40. Which statement is true? If the missing data value was 55, the range of the data would change significantly. If the missing data value was 55, the interquartile range of the data would change significantly. If the missing data value was 22, the range of the data would change significantly. If the missing data value was 22, the interquartile range of the data would change significantly.
Answers
Answer:
If the missing data value was 55, the range of the data would change significantly
If the missing data value was 22, the interquartile range of the data would change significantly
Step-by-step explanation:
Given the data
8, 9, 12, 12, 13, 15, 16, 16, 16, 18, 21, 22, 23, 27, 28, 32, 34,40
The range of the data is the difference between the highest value and the lowest value of the data.
Highest value = 40
Lowest value = 8
Range = 40-8
Range = 32
If 55 was missing, we need yo find the range of the data if 55 was included.
Highest value will be 55
Lowest value = 8
Range in this case = 55-8
Range = 47
Difference in range = 47-32= 15
This means that if 55 was missing, it will significantly affect the value of the range.
- Interquartile range = Q3-Q1
Q3 is the median value of the other half of the data.
Q1 is the median value of the first half of the data.
If 55 wasn't included, the first part of the data:
8, 9, 12, 12), 13, (15, 16, 16, 16
Q1 = 13 (median value of the extracted data)
The second part of the data if 55 wasn't included:
18, 21, 22, 23), 27, (28, 32, 34, 40
Q3 = 27 (median value of the second part of the data)
IQR = Q3-Q1
IQR = 27-13
IQR = 14
If 55 was included, the data will be;
8, 9, 12, 12, 13, 15, 16, 16, 16, 18, 21, 22, 23, 27, 28, 32, 34, 40,55
Q1 = N+1/4 the value
N is the sample size = 19
Q1 = 19+1/4
Q1 = 20/4
Q1 = 5th value
The 5th value in the data is 13, hence Q1 is 13
Q3 = 3(N+1)/4th value
Q3 = 3(19+1)/4
Q3 = 60/4
Q3 is the 15th value in the dataset. Since the 15th value is 28, Q3 is 28
IQR = 28-13
IQR = 15 (if 55 was included)
Difference in IQR = 15-14 = 1
This means that if 55 was the missing data, the IQR will not change significantly.
Note that the range of the data will not change if the missing value is 22 because, the 22 is a value lower than the highest value of the dataset, hence the range will remain the same (40-8 = 32) irrespective of 22 missing or not.
For the Interquartile range
If 22 was in
Q3 = 3(N+1)/4th value
Q3 = 3(19+1)/4
Q3 = 60/4
Q3 is the 15th value in the dataset. Since the 15th value is 28, Q3 is 28
IQR = 28-13
IQR = 15 (if 55 was included)
Difference in IQR = 15-14 = 1
This means that if 55 was the missing data, the IQR will not change significantly.
Based on the calculation, the correct options are:
- If the missing data value was 55, the range of the data would change significantly
- If the missing data value was 22, the interquartile range of the data would change significantly
Answer:
a
Step-by-step explanation:
edge 2021
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Step-by-step explanation:
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Answers
Answer:
59%
Step-by-step explanation:
Answer:
96=80% of 120
Step-by-step explanation: