one fifth of the sum of four and m

Answer:

37.854

Step-by-step explanation:

59.73-21.876=37.854

Answer:

4th Option isn't a function

Step-by-step explanation:

it is because a domain can't have two images in the co domain set

Hope it helps

Please mark as brainliest

Answer:

"D" (the fourth one....(7,1),(6,2)....

a "function" is a very specific relationship in math...

for a relationship to be "a function" every possible INPUT (x-values) has to map (correspond) to a UNIQUE output value (Y-value)

a line is a function (all x's have unique y values.

A circle is NOT ..... at the center (x-value) there are two y values (one above and one below)

in your problem answer "D" the "x-value" "5" has two different "y-values"

3 and 4

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex] = > 12 \times 2[/tex]

[tex] = 24[/tex]

Answer:

66 in^2

Step-by-step explanation:

Imagine that the figure is a whole square, where the space between is filled in.

Find the area of the imaginary square (l x w):

9 in. x 9 in. = 81 in^2

Lets make that whole square the original figure it used to be (take away the space we “filled in”)

Lets find the area of the space we filled in:

5 in x 3 in= 15 in^2

Subtract the imaginary square’s area by the area of the space that was originally blank:

81 in^2 - 15 in^2 = 66 in^2

66 in^2 IS YOUR FINAL ANSWER, that is the real area of the composite figure you have.

Hope this helps!

Answer:

(8,5):

8 is x-axis

5 is y-axis

Answer:

2/11 x + 70/11

Step-by-step explanation:

Given the coordinate (-2, 6), (9,8), the equation in standard form is of the form y = mx+b

m is the slope = 8-6/9-(-2)

m = 2/11

Get the y-intercept

Substitute m = 2/11 and (-2, 6) into the expression y = mx+b

6 = 2/11(-2)+b

6 = -4/11 + b

b = 6 + 4/11

b = (66+4)/11

b = 70/11

Get the required equation

y = 2/11 x + 70/11

Hence the required equation is 2/11 x + 70/11

Answer:

x is equal to 12 which represents the situation

Answer:

Draw 8 boxes with 8 cupcakes in each one of them.

Step-by-step explanation:

34+30=64, and 64/8 also equals 64.

Answer:

250

Step-by-step explanation:

Given

[tex]n =3[/tex] --- digit code

[tex]First = Even[/tex]

[tex]Last=Odd[/tex]

Required

The different combination of codes

The set of even number is:

[tex]Even = \{0,2,4,6,8\}[/tex]

The set of odd is:

[tex]Odd = \{1,3,5,7,9\}[/tex]

This means that:

The first can be any of the 5 even digits

The last can be any of the 5 odd digits

Since there is no restriction in selection;

The [tex]second[/tex] can be [tex]any[/tex] of [tex]the[/tex] 10 digits

So, the possible combination (k) is:

[tex]k =5 * 10 * 5[/tex]

[tex]k =250[/tex]

Answer:

[tex]x=-2[/tex] ⇒ [tex]y=2[/tex]

[tex]x=-1[/tex] ⇒ [tex]y=-4[/tex]

[tex]x=0[/tex] ⇒ [tex]y=-6[/tex]

[tex]x=1[/tex] ⇒ [tex]y=-4[/tex]

Step-by-step explanation:

Formula: [tex]y=2x^{2} -6[/tex]

To find the value of [tex]y[/tex] add the value of [tex]x[/tex] given:

Now solve for each:-

For:

[tex]x=-2[/tex]

[tex]y=2(-2)^{2} -6[/tex]

[tex]y=2[/tex]

For:

[tex]x=-1[/tex]

[tex]y=2(-1)^{2} -6[/tex]

[tex]y=-4[/tex]

For:

[tex]x=0[/tex]

[tex]y=2(0)^{2} -6[/tex]

[tex]y=-6[/tex]

For:

[tex]x=1[/tex]

[tex]y=2(1)^{2}-6[/tex]

[tex]y=-4[/tex]

hope this helps.....

Answer:

See in details.

Step-by-step explanation:

Categorical data don't have any logical order and it can't be translated into a numerical value.

Numerical data are numbers and they represent some order and value.

Answer:

Step 3

Step-by-step explanation:

Answer:

$625.6

Step-by-step explanation:

Information about a holiday:

7 night holiday

$340 per person

8% discount if you book before 31 March

Number of people Naseem booked the holiday for = 2

Date of booking of the holiday = February 15

Total cost of the holiday per person = cost per person - discount before March 31

= $340 - 8% of $340

= 340 - 8/100 * 340

= 340 - 0.08 * 340

= 340 - 27.2

= $312.8

Total cost of the holiday for 2 persons = 2 × Total cost of the holiday per person

= 2 * $312.8

= $625.6

Answer:

yes.

Step-by-step explanation:

it is correct

Answer: Yes, this is correct.

The criteria that is excluded from national benchmark test is Qualitative literacy. That is option C.

National Benchmark Test is an academic assessment test usually written by students that are about entering the university.

The National Benchmark Tests comprise three multiple choice tests, written as:

Qualitative literacy is the ability to understand and interpret qualitative evidence. It is not included in the national benchmark test criteria.

Learn more here:

https://brainly.com/question/22566767

Answer:

9. a) 180 - (55+90) = a

b) a=35 degrees

10. a) 2w + 3w + 40 = 180

b) w=28

c) 2w=56      3w=84

Step-by-step explanation:

Answer:

the person above is 100% right trust me :)

Step-by-step explanation:

Answer:

<B = <K

<C = < L

AC= JL

BC= KL

Step-by-step explanation:

The triangles are equel, meaning the letters will be in the same place on a triangle, hope this helps

Answer:

11,304.0 cm³

Step-by-step explanation:

the volume = π.r².h

= 3.14 × 20² × 9

= 11,304

Answer:

- 10p2

Step-by-step explanation:

p(8p - 18 p)

p x -10p

ans = -10p2

Answer:  -10p²

This is the same as saying -10p^2

============================================

Explanation:

Both terms 8p² and -18p² are like terms.

We combine them in much the same way as 8-18 = -10, just with a p² attached to everything.

So 8p² - 18p²  = (8-18)p² = -10p²

The coefficient -10 is negative because we're subtracting small minus big. If it was the other way around, then we'd get a positive value.

Answer:

60 degress

Step-by-step explanation:

Edgen 2021

60° is the angle at which the hexagon rotate so that it maps onto itself.

A polygon is a plane figure made up of line segments connected to form a closed polygonal chain.

When a figure has a rotational symmetry, it maps onto itself under rotation about a point at the centre.

When an hexagon rotate onto itself,the vertices must cover to vertices and from sides to sides.

There are six angles in a hexagon and the sum of the angles is 360°. Therefore, each angle has a measure of 360°/6 is equal to 60°.

Rotating subsequently by 60 degree will rotate a hexagon onto itself. A hexagon has 6 rotations, that is, a hexagon has a rotational symmetry of 6 and at angle 60°, the hexagon will rotate onto itself.

Hence,  60° is the angle at which the hexagon rotate so that it maps

onto itself.

To learn more on Polygons click:

https://brainly.com/question/24464711

#SPJ7

Answer:

I've attached the Answer

Step-by-step explanation:

here it is

Answer:

[tex](\sqrt{6}+\sqrt{3})(\sqrt{6}-\sqrt{3})=3[/tex]

[tex](\sqrt{5}-\sqrt{2})(\sqrt{2}+\sqrt{5})=3[/tex]

Step-by-step explanation:

We want to simplify the expression:

[tex](\sqrt{6}+\sqrt{3})(\sqrt{6}-\sqrt{3})[/tex]

Notice that this is the difference of two squares pattern. Namely:

[tex]a^2-b^2=(a+b)(a-b)[/tex]

If we let a = √6 and b  =√3, we acquire:

[tex](a+b)(a-b)[/tex]

Expand accordingly:

[tex]=a^2-b^2[/tex]

Back-substitute:

[tex]=(\sqrt{6})^2-(\sqrt{3})^2[/tex]

Simplify:

[tex]=6-3=3[/tex]

For the second expression, we have a similar pattern:

[tex](\sqrt{5}-\sqrt{2})(\sqrt{2}+\sqrt{5})[/tex]

We can first rewrite the expression (commutative property):

[tex]=(\sqrt{5}-\sqrt{2})(\sqrt{5}+\sqrt{2})[/tex]

And if we let a = √5 and b = √2:

[tex]=(a-b)(a+b)[/tex]

Expand accordingly:

[tex]=a^2-b^2[/tex]

Back-substitute and simplify:

[tex]=(\sqrt{5})^2-(\sqrt{2})^2=5-2=3[/tex]

Answer:

20

Step-by-step explanation:

Take note of the important information/key words:

60 total ornaments

3 grandchildren

Divide them evenly

Set up an equation:

60 ornaments ÷ 3 grandchildren = ornaments per grandchild

60 ÷ 3 = 20 ornaments per grandchild.

In other words, each grandchild will receive 20 ornaments.

Answer:

$2,226.20

Step-by-step explanation:

[tex]a_{5}[/tex] = 500e^5(0.03)

Answer:

c. 165.6 cm²

Step-by-step explanation:

We are given two sides of a triangle and an included angle. To find the area, we would apply the following formula:

Area = ½*b*c*Sin(A)

b = 25 cm

c = 25 cm

A = 32°

Area = ½*25*25*Sin(32)

Area = 165.59977

Area ≈ 165.6 cm² (nearest tenth)

Answer:

y ≤ x - 2

Step-by-step explanation:

Using the coordinate points on the graph (0, -2) and (2,0)

The general equation of the line will be y = mx+b

Slope m = 0-(-2)/2-0

m = 2/2

m = 1

From the coordinate (0, -2), this shows that the y intercept is -3

Get the equation

y = 1x + (-2)

y = x - 2

Since the line is a thick line and shaded towards the negative y-axis, the required inequality expression will be y ≤ x - 2

Answer:

x = 2

Step-by-step explanation:

AE is equal to the sum of AB and BE because of segment addition postulate, we can substitute to get AE = 11 + x + 1 = x + 12

DE is equal to the sum of DC and CE because of segment addition postulate, we can substitute to get DE = 1 + x + 4 = x + 5

To solve the problem, we can use power of a point, more specifically exterior secants products scenario. In this case, we can get the equation:

AE * BE = DE * CE

Now, we can substitute and solve:

(x + 12)(x + 1) = (x + 5)(x + 4)

x^2 + 13x + 12 = x^2 + 9x + 20

13x + 12 = 9x + 20

4x + 12 = 20

4x = 8

x = 2

Answer: -1410

Step-by-step explanation:

Let's start by subbing in -4 for x

[tex]-4x^4 - 3x^3 - 29x^2 - 114\\-4(-4)^4-3(-4)^3-29(-4)^2-114[/tex]

Now we can solve

[tex]-4(256)-3(-64)-29(16)-114\\-1024--192-464-114\\-832-464-114\\-1296-114\\-1410[/tex]

Answer:

[tex]-1440[/tex]

Step-by-step explanation:

------------------------------

Given:

[tex]-4x^4-3x^3-29x^2-114=[/tex]

[tex]x=-4[/tex]

--------------->>>>

Let's substitute [tex]-4[/tex] for [tex]x[/tex] and solve

[tex]-4(-4)^4-3(-4)^3-29(-4)^2-144=[/tex]

Multiply the exponents

[tex]-4(256)-3(-64)-29(16)-144=[/tex]

Multiply the parenthesis

[tex]-1024+192-464-144=[/tex]

[tex]-832-464-144=[/tex]

[tex]-1296-144=[/tex]

[tex]=-1440[/tex]

------------------------------

Hope this helps.

Answer: the factored form of 3x+24y is 3(x+8y) 3(x+8y)

1) 7/12= 0.58, 4/7= 0.57

they are about 1/2

2) 7/12 + 4/7 = 97/84= 1.15 approximately 1

which is 1m from the option