Out of 30 tudent urveyed, 17 have a dog. Baed on thee reult, predict how many of the 300 tudent in the chool have a dog?

The maximum volume is 63.75 cubic cm. The rectangular is kind of shape that has lenght and width.

To find the dimensions of the rectangular solid that will result in a maximum volume, we can use the formula for the surface area of a rectangular solid, which is:

Surface Area = 2lw + 2lh + 2wh

where l is the length, w is the width (which is the same as the base of the square), and h is the height.

We can set up an equation using this formula, with the given surface area:

181.5 = 2lw + 2lh + 2wh

To find the maximum volume, we can take the derivative of the volume equation and set it equal to 0, then solve for the value of the variable.

The volume of the rectangular solid is V = lwh

The derivative of V with respect to l is : dV/dl = wh

The derivative of V with respect to w is : dV/dw = lh

The derivative of V with respect to h is : dV/dh = lw

Therefore, the maximum volume occurs when dV/dl = 0, dV/dw = 0 and dV/dh = 0

Since the base of the rectangular solid is a square, we know that l = w

If we substitute this value into the equation for the surface area, we get:

181.5 = 2l^2 + 2lh

Solving for h in terms of l, we get:

h = (181.5 - 2l^2) / (2l)

We can now differentiate this equation with respect to l, and set it equal to 0, then solve for l:

[tex]\frac{dV}{dl} = (2lh + l^2h - 2l^3) / l = 0\\2l(181.5 - 2l^2) + l^3 = 0\\2l(181.5 - 2l^2) = -l^3\\2(181.5 - 2l^2) = -l^2\\363 - 4l^2 = -l^2\\l^2 = 181.5 / 2\\l = \sqrt{\frac{181.5}{2} } \\I = \sqrt{90.75} \\I = 3.5[/tex]

So the dimensions that will result in a maximum volume are:

length (l) = 3.5 cm

width (w) = 3.5 cm

height (h) = (181.5 - 23.53.5) / (2*3.5) = 5 cm

The maximum volume is V = lwh = 3.53.55 = 63.75 cubic cm

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Answer:

1096.63316

Step-by-step explanation:

Check the picture below.

Answer:

Step-by-step explanation:

So we know what a gradient is = y=mx+c So you have to make a triangle with the 2 numbers touching a line and make a triangle the conects to both of them. and then you will get the answer

The total number of functions from a set with 4 elements to a set with 3 elements is 333 × 3 = 64.

There are a total of 4³ = 64 functions from a set with 4 elements to a set with 3 elements.

A function from a set A to a set B is a rule or a correspondence that assigns to each element of A exactly one element of B. Set A is called the domain of the function and set B is called the co-domain.

Since there are 4 elements in the domain and 3 elements in the co-domain, each element in the domain can be mapped to any of the 3 elements in the co-domain.

So for the first element in the domain, there are 3 options to map it to in the co-domain. Similarly, for the second element, there are 3 options, and so on.

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Answer:

A)57   film a music video

Step-by-step explanation:

Let x represent measure of angle 1.

We have been given that measure of angle 3 is six more than twice the measure of angle 1. So measure of angle 3 would be .

We are also told that measure of angle 2 is 27 less than measure of angle 3, so measure of angle 2 would be .

We have been given that angle 1, angle 2 and angle 3 form a straight line, so the sum of angles 1, 2 and 3 would be 180 degrees.

Upon substituting the expressions for measure of angles, we will get:

Now, we will combine like terms.

The measure of angle 2 would be .

Therefore, the measure of angle 2 is 57 degrees.  

A positive average rate of change over any interval [a,b] such that b > a + (1/8a^3 - a^2)/(1/8a^3 - a^2).

Average rate is a term used to describe the mean value of a set of data points or the mean rate of change of a function. It is calculated by adding all the values in a set and then dividing the sum by the total number of values.

The average rate of change of a function over an interval [a,b] is given by the formula (f(b) - f(a))/(b - a). Therefore, for h to have a positive average rate of change over an interval, we must have f(b) - f(a) > 0.
Substituting h(x) into this formula, we get (1/8b^3 - b^2 - 1/8a^3 + a^2) / (b - a) > 0.
Solving for b, we get b > a + (1/8a^3 - a^2)/(1/8a^3 - a^2).
Therefore, h has a positive average rate of change over any interval [a,b] such that b > a + (1/8a^3 - a^2)/(1/8a^3 - a^2).

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The numbers in the ascending order is given by A , where

-73 < -21 < -6 1/2 < -4.7 < 0 < 8 8/9 < 11 < 13 < 38

When numbers are arranged in ascending order, they are done so from least to largest. We must first compare the numbers before we may arrange them in any order. Compare first, then order. Numbers arranged in ascending order: Determine how many digits each number has.

Given data ,

Let the set of numbers be represented as set P

The value of set P is P = { -4.7 , 11 , 13 , -21 , 8 8/9 , 0 , -6 1/2 , 38 , -73 }

On simplifying the equation , we get

The larger the negative number , the lesser is its value

And , larger the positive number , the greater is its value

So ,

The ascending order of the numbers are

-73 < -21 < -6 1/2 < -4.7 < 0 < 8 8/9 < 11 < 13 < 38

Hence ,

The ascending order is -73 < -21 < -6 1/2 < -4.7 < 0 < 8 8/9 < 11 < 13 < 38

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Yes, a domain can be all numbers. This type of domain is called a numerical domain.

A numerical domain is a set of numbers that is used to define a function. It is usually represented by the formula D= {x: x is a real number}. This formula can be used to calculate the domain of a given function by determining which values of x, or the independent variable, produce a valid output. Numerical domains are becoming increasingly popular as they are easier to remember than domains composed of letters and hyphens. They can also be used to represent a business’s contact information, such as a phone number or street address. When registering a numerical domain, it is important to ensure that it is not already taken, as numerical domains are becoming increasingly sought after. For example, if a function is defined as f(x) = x2 + 3, then the domain would be all real numbers, since any real number would produce a valid output.

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Therefore , we may now say that the requisite unequal declaration is 4.50x+1.75y 50 if the expression problem is resolved.

In mathematics, an expression is made up of a claim, two or more integers or variables, and one or more arithmetic operations. This mathematical operation can multiply, divide, add, or remove numbers. The following is how an expression is put together: Expression: A variable or a number, a math operator, and a math operator.

Here,

$4.50 is the price per assignment.

The assignment cost "x" is equivalent to 4.50x as a result.

$1.75 for each task.

Therefore, the cost of assignment "Y" is 1.75Y.

Because of this, 4.50x+1.75y should be $50 maybe less.

As a result, the inequality declaration required is 4.50x+1.75y ≤50.

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a) The reason for which r > 3 is because a side length in a figure cannot assume a negative value.

b) The double inequality for r is given as follows: 3 < r < 8.

The perimeter of a rectangle of base b and height h is given by the equation presented as follows:

P = 2(b + h).

The dimensions for this problem are given as follows:

The perimeter of the rectangle is smaller than 26 cm, hence the inequality is defined as follows:

P < 26.

2(b + h) < 26

b + h < 13 (simplifying by 3 both sides of the inequality).

r + r - 3 < 13

2r < 16

r < 8.

Hence the double inequality is defined as follows:

3 < r < 8.

As a side length cannot be negative nor zero, hence it is also needed that r - 3 > 3 -> r > 3.

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Answer:

Step-by-step explanation:

[tex]\mathrm{\cfrac{3^5\times\:10^5\times\:25}{5^7\times\:6^5}}[/tex]

Factor:

6^5= 2^5*3^5

10^5= 2^5*5^5

25 = 5^2

[tex]\mathrm{\cfrac{3^5\times\:2^5\times\:5^5\times\:5^2}{5^7\times\:2^5\times\:3^5}}[/tex]

3^5*2^5*5^5*5^2 = 3^5*2^5*5^7

[tex]\mathrm{\cfrac{5^7\times\:3^5\times\:2^5}{5^7\times\:2^5\times\:3^5}}[/tex]

Now, cancel common factor:-

[tex]\mathrm{3^5\times\:2^5\times\:5^7}[/tex]

[tex]\mathrm{1}[/tex]

-Hope this helps!

Quadrant Class 9 is a level of mathematics taught in secondary school in the United Kingdom. It is the equivalent of Algebra 1 and Geometry combined in the United States.

This class teaches students how to graph equations, solve equations, and use the properties of shapes to solve problems. Quadrant Class 9 also covers the basics of calculus, such as derivatives, integrals, and limits.

The main focus of Quadrant Class 9 is on graphing equations. Students learn how to plot points on a graph, connect the points to make a line or curve, and solve equations by finding the intersection of two lines. They also learn how to graph the solutions of inequalities and identify the domain and range of a function.

In addition to graphing, students learn how to solve equations using basic algebraic principles, such as the order of operations and the distributive property. They also learn how to solve systems of equations, manipulate polynomials, and find the roots of a quadratic equation.

Quadrant Class 9 also covers the basics of geometry, such as the Pythagorean Theorem, the properties of triangles, and the area and perimeter of shapes. Students learn how to use these skills to solve problems involving angles, area, and volume.

Overall, Quadrant Class 9 is a challenging and rewarding mathematics class that prepares students for higher-level math classes in the future.

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Applying the relation between the force and the distance between the two objects , the force between the objects when the distance between the objects is 7 meters is 0.21 N.

Force is a physical quantity that describes the interaction between two objects. It is the push or pull exerted on an object that changes or tends to change its motion. Force is measured in units of Newtons (N) and it can be a vector quantity, meaning that it has both magnitude and direction.

The unit of measurement for force is the Newton (N). It is important in physics because it is one of the fundamental quantities used to describe the motion and interactions of objects. Forces are responsible for changes in an object's motion, such as acceleration or deceleration, and they play a key role in many physical phenomena, including gravity, friction, and tension.

As given in the question , the force is 0.65 Newtons when the distance between the objects is 4 meters.

Let the force when the distance is 7 meters be F2.

So using the relation between the force and the distance , i.e Force is inversely proportional to the square of distance between the objects.

[tex]\frac{F2}{0.65} =\frac{4^{2} }{7^{2} }[/tex]

Therefore, F2 = 0.21 Newtons

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The unit rate of the pound of rice is given by the equation A = $ 2

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the unit rate of the pound of rice be represented as A

Now , the equation will be

The cost of 2 pounds of rice = $ 4

So , the cost of 1 pound of rice = cost of 2 pounds of rice / 2

Substituting the values in the equation , we get

The cost of 1 pound of rice A = 4 / 2

The cost of 1 pound of rice A = $ 2

Therefore , the value of A is $ 2

Hence , the equation is A = $ 2

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The range of y=2x^(2)+12x-13 is all real number Option C

Generally, A quadratic function is a type of polynomial function that has the form

f(x) = ax^2 + bx + c,

where

a, b, and c are constants and x is the variable.

The graph of a quadratic function is a parabola that opens either upward or downward, depending on the value of a. The vertex of the parabola is the point (h, k), where h = -b/2a and k = f(h). The roots of the quadratic function, or the x-coordinates of the points where the parabola crosses the x-axis, can be found using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a.

The range of a quadratic function in the form of y = ax^(2) + bx + c is all real numbers for a ≠ 0, and for a = 0,

the range is {c}. In this case, a = 2, so the range of y = 2x^(2) + 12x - 13 is all real numbers.

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The range of the given quadratic equation is y ≤ 5.

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function, the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

For solving a quadratic function you should find the discriminant: Δ=b²-4ac . And after that, you should apply the discriminant in the formula:[tex]x=\frac{-b\pm\sqrt{\Delta} }{2a}[/tex] .

The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.  While the domain is related to the values ​​of x, the range is related to the possible values ​​of y that the function can have.

For a quadratic function,  the range is defined from the y-coordinate of the vertex  ( [tex]y_v=\frac{-\Delta}{4a}[/tex]).

If a<0, the range is y≤ yv

If a>0, the range is y≥ yv

The question gives the following quadratic equation: -2x²+12x-13, then:

a=-2

b=12

c=-13

Δ= b²-4ac=12²-4*(-2)*(-13)=144-104=40

Therefore,

[tex]y_v=\frac{-\Delta}{4a}=\frac{-40}{4*(-2)}=\frac{-40}{-8}=5[/tex]

Thus, yv=5 and the range is ≤ 5.

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For each type of book, Elliott has 19 fiction books and 7 nonfiction books.

To solve for the number of fiction books (x), we can use the first equation of the system: x + y = 26. We know that the number of nonfiction books (y) can be represented by x - 12 (from the second equation of the system: x - y = 12).

So we can substitute x - 12 for y in the first equation:

Combining like terms:

Adding 12 to both sides:

Dividing both sides by 2:

Therefore, Elliot has 19 fiction books.

To solve for the number of nonfiction books (y), we can use the first equation of the system: x + y = 26 and input the value of x:

Therefore, Elliot has 7 nonfiction books.

This question is incomplete and should be written as:

Elliot has a total of 26 books. He has 12 more fiction books than nonfiction books. Let x represent the number of fiction books and y represent the number of nonfiction books.

This system of equations models the number of books.

Elliot added the two equations and the result was 2x = 38. How many fiction and nonfiction books does Elliot have?

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From the centre formula the distance is between two points in a plane.

A mathematical calculation known as the distance formula is used to calculate the separation between two points on a plane. The Pythagorean theorem, which asserts that the square of the length of the hypotenuse in a right triangle equals the sum of the squares of the lengths of the legs, is the source of the distance formula which is the side opposite the right angle.

The distance formula is frequently shown as: d = √((x2 - x1)² + (y2 - y1)²). The first point's coordinates are x1 and y1, the second point's coordinates are x2 and y2, and d is the distance between the two points. It's crucial to keep in mind that this method only works when the two points are in a 2D plane.

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Answer:

0.0625 pounds are in an ounce

Step-by-step explanation:

Hope This Helps!

Answer:

Below

Step-by-step explanation:

There are 16 oz to a pound

if you have    'z' ounces    then you have   z/16  pounds

z oz   /  16 oz/lb =   z/16  lb

Writing 5/x + 1 + 2/3x as a single fraction will result to (17 + 3x)/3x

The expression is written with parameters having unlike terns. The terms consist of the constant term and the variable parameters.

The constant terms are 1

terms with variables are 5/x and 2/3x

adding like terms gives

= 5/x + 2/3x

the LCM of x and 3x is 3x and this will be the common denominator

= (15 + 2) / 3x

= 17/3x

adding both together

= 17/3x + 1

the LCM of 1 and 3x is 3x and this will be the common denominator

= (17 + 3x) / 3x

The single fraction is (17 + 3x) / 3x

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Bases are chemical compounds that can accept hydrogen ions (H+) when added to water. Bases have a pH higher than 7 on the pH scale. Common bases include baking soda (sodium bicarbonate), lye (sodium hydroxide), ammonia (NH3), and calcium hydroxide (CaOH2).

Bases are an important concept to understand in Grade 7 Chemistry. They are chemical compounds that have a pH higher than 7 on the pH scale and are capable of accepting hydrogen ions (H+) when added to water. Knowing the basics of bases can help students in a variety of ways, from understanding the properties of solutions to being able to identify and use different bases in lab experiments.

To begin with, understanding the properties of bases is essential in order to properly identify and use them in experiments. Bases can be divided into two categories: alkalis and acids. Alkalis are bases that are soluble in water, while acids are bases that are insoluble in water. Each type of base has its own unique properties and uses. For example, baking soda (sodium bicarbonate) is a common alkali that can be used for baking, cleaning, and even as an antacid. Meanwhile, lye (sodium hydroxide) is an acid that is used in many industrial processes, such as soap and textiles manufacturing.

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To calculate the sale price, we need to find out how much the TV is discounted by, which we can do by multiplying the original price by the percentage discount (expressed as a decimal).

35% of the original price can be expressed as 0.35.

so,

Discount = 540 omr * 0.35 = 189 omr

To find the sale price, we can subtract the discount from the original price:

Sale price = Original price - Discount

Sale price = 540 omr - 189 omr

So the sale price is 351 omr.

Answer:

A) 0

Step-by-step explanation:

h/4+(12-y)/3

-12/4+(12-3)/3

-3+(9)/3

-3+9/3

-3+3

0

The minimum number of jumps required to reach the flag's height is 3.

Let n be the height of the flag. We can use a recursive approach to determine the minimum number of jumps it takes to reach the flag's height.

For n = 0, it takes 0 jumps to reach the flag's height.

For n = 1, it takes 1 jump to reach the flag's height.

For n > 1, we can calculate the minimum number of jumps using the following equation:

minJumps(n) = 1 + min(minJumps(n-1), minJumps(n-j))

Where minJumps(x) is the minimum number of jumps required to reach the flag's height from ground level x.

For example, if the flag's height is 5 and Bob can jump a height of 2, the minimum number of jumps required to reach the flag's height is 3.

minJumps(5) = 1 + min(minJumps(4), minJumps(3))

= 1 + min(1 + min(minJumps(3), minJumps(2)), 1 + minJumps(2))

= 1 + min(1 + 1, 1 + 1)

= 3

Therefore, the minimum number of jumps required to reach the flag's height is 3.

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The age of a fossil can be determined using Carbon 14 dating. Carbon 14 dating is a method of determining the age of an object that is based on the decay of the isotope carbon-14. Carbon-14 has a half-life of approximately 5,730 years, which means that half of the initial amount of carbon-14 in a sample will decay in 5,730 years.

What is carbon dating in simple words?

Simply said, carbon dating is the process of using the presence of carbon 14 to estimate the age of ancient material (such as an archaeological or paleontological specimen).

If 32% of the initial amount of Carbon 14 in a sample remains, we can use the formula:

Age = t = (t1/2) * ln(2) / ln(A0/A)

Where t1/2 is the half-life of carbon-14 (5730 years), A0 is the initial amount of carbon-14 (100%), and A is the remaining amount of carbon-14 (32%).

Age = (5730) * ln(2) / ln(100/32)

Age = (5730) * 0.693 / (-1.51)

Age = 8129 years

So, approximately 8129 years have elapsed since the fossil was formed.

Note that this is an estimate and this method of dating can only be used for fossils that are less than about 60,000 years old. Also, this method assumes that the initial amount of carbon-14 in the sample is known, which can be affected by the environment and other factors that can affect the accuracy of the dating.

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Answer:

28.2 percent

Step-by-step explanation:

multiply 1/5 by 141

Step-by-step explanation:

we need Pythagoras for right-angled triangles

c² = a² + b²

with c being the Hypotenuse (the side opposite of the 90° angle), a and b being the legs.

we also need to remember that the sum of all angles in a quadrilateral (4-sided shape) is 360°.

so, as 3 angles in the main quadrilateral are 90°, so is also the 4th angle. and that makes the quadrilateral a regular rectangle.

we know the length of the rectangle (15 ft).

the width is also the second leg of the attached right-angled triangle.

so, we know

13² = 5² + (leg2)²

169 = 25 + (leg2)²

144 = (leg2)²

leg2 = sqrt(144) = 12 ft

the total area is

the area of the rectangle

+

the area of the triangle

the area of the rectangle is

length × width = 15 × 12 = 180 ft²

the area of the right-angled triangle is

leg1 × leg2 / 2 = 5 × 12 / 2 = 5×6 = 30 ft²

the total area is

180 + 30 = 210 ft²

FYI - a different way is to directly calculate the area of the trapezoid :

(base1 + base2)×height/2

height = the width of the rectangle or leg2 of the right-angled triangle.

so, we have

(15 + (15 + 5))×12/2 = (15 + 20)×6 = 35×6 = 210 ft²