Physical science-current can be increased by...

Explanation:

the state or quality of being efficient or able to accomplish something

Answer: The Boat will rise

Explanation: Because high amplitude means high in heights.

Answer:

v = -19.6 m / s,    y =y₀ + v₀ t - ½ g t²

Explanation:

This is an exercise in kinetics in one dimension, let's take the upward direction as positive

           v = v₀ - g t

in this case as the body is released its initial velocity is zero and the acceleration is -g the sign indicates that it is directed downwards

           v = 0 -g t

           v = - 9.8 2

            v = -19.6 m / s

the sign indicates that the speed is down.

Galileo's equation is

            y =y₀ + v₀ t - ½ g t²

where i is the initial height, v₀ the initial velocity and -g the acceleration of the body

Time needed = t = 20.83 s

Given

car speed = 85 km/h

truck speed = 73 km/h

Required

the time it takes for the car to reach the truck

Solution

When the car reaches the truck, the distance between them will be the same

x car - 250 m = x truck

General formula for distance (d) :

d = v.t

So the equation becomes :

85t-250 = 73t

12t=250

t = 20.83 s

The average velocity of the car is 37.27 km/h.

The given parameters;

The average velocity of the car is calculated as follows;

[tex]average \ velocity = \frac{Total \ displacement}{Total \ time}[/tex]

The total displacement of the car is calculated as follows;

[tex]d = \sqrt{x^2 + y^2} \\\\d = \sqrt{100^2 \ + \ 50^2} \\\\d = 111.803 \ km[/tex]

The average velocity of the car is calculated as follows;

[tex]v = \frac{111.803}{3} \\\\v = 37.27 \ km/h[/tex]

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Answer:

Explanation:

Power, by definition, is the amount of work per unit of time. We arent given work in this question, but we can find it because work is how much force per unit of distance.

[tex]P=\frac{W}{t_f-t_i} =\frac{F*d}{t_f-t_i}[/tex]

Plug in all the values, and its algebra at this point

[tex]500=\frac{F*96}{12}[/tex]

6000 = 96F

F = 62.5 Newtons

The force which is being applied to the object with the power of 500 Watt is 62.5 N.

Power can be defined as the rate of doing work. It is the work done in unit time. The SI unit of power is Watt (W) which is equal to joules per second (J/s). Sometimes, the power of motor vehicles and other machines is given in terms of Horsepower (hp), This unit is approximately equal to 745.7 watts of power.

The power of a system can be calculated as the product of force applied and distance travelled by the system per unit time taken.

Therefore, the force of the object with power 500W can be calculated as:

P = f × d/ t

where, P = Power of the object,

f = Force applied,

d = distance travelled,

t = time taken to cover the distance

f = (P × t)/ d

f = (500 × 12) / 96

f = 6000/ 96

f = 62.5 N

Therefore, the force which is being applied to the object is 62.5N (Newton).

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Answer:

Explanation:

Considering non - relativistic approach : ----

Speed of electron = 1 % of speed of light

= .01 x 3 x 10⁸ m /s

= 3 x 10⁶ m /s

Kinetic energy of electron = 1/2 m v²

= .5 x 9.1 x 10⁻³¹ x ( 3 x 10⁶ )²

= 40.95 x 10⁻¹⁹ J

Kinetic energy in electron comes from lose of electrical energy equal to

Ve where V is potential difference under which electron is accelerated and e is electronic charge .

V x e = kinetic energy of electron

V x 1.6 x 10⁻¹⁹ = 40.95 x 10⁻¹⁹

V = 25.6 Volt .

Answer:

Conductivity, [tex]\sigma=500\ (\Omega-m)^{-1}[/tex]

Explanation:

Given that,

The resistivity of a material, [tex]\rho=2\times 10^{-3}\ \Omega-m[/tex]

We need to find the conductivity of the material.

We know that the reciprocal of resistivity is called conductivity.

[tex]\sigma=\dfrac{1}{\rho}\\\\\sigma=\dfrac{1}{2\times 10^{-3}}\\\\\sigma=500\ (\Omega-m)^{-1}[/tex]

So, the conductivity of the material is [tex]500\ (\Omega-m)^{-1}[/tex].

Answer:

Force is too large for a person to exert.

Explanation:

m = Mass of child = 14 kg

u = Initial velocity of compartment = 64 mi/h = [tex]\dfrac{64\times 1609.34}{3600}=28.61\ \text{m/s}[/tex]

v = Final velocity of compartment = 0

t = Time taken by the compartment to stop = 0.05 s

Force is given by

[tex]F=ma\\\Rightarrow F=m\dfrac{v-u}{t}\\\Rightarrow F=14\times \dfrac{0-28.61}{0.05}\\\Rightarrow F=-8010.8\ \text{N}[/tex]

The person has to exert a force of [tex]-8010.8\ \text{N}[/tex] in the opposite direction to keep holding the child. This is a huge amount of force and cannot be done by a person's physical strength alone.

Answer: a positive test charge

Explanation:

An electric field is a vector measure. Its direction is determined as the direction that a positive test charge would experience a force when it is placed in the field.

A positive charge has a higher potential and a negative charge is lower potential.

Thus, an electric field is represented by the force on a positive test charge.

Hence, the correct option is "a positive test charge".

Answer:

D. a positive test charge.

Explanation:

Edge 2021

Answer:

a) 13.7 m

b) 8.3 m

Explanation:

a)

       [tex]d = d_{1} + d_{2} = 11.0 m + 2.7 m = 13.7 m (1)[/tex]

b)

       [tex]x_{o} = 0 (2)[/tex]

       [tex]x_{f} = x_{1} - x_{2} = 11.0 m - 2.7 m = 8.3 m (3)[/tex]

      ⇒ Δx = xf - x₀ = 8.3 m  - 0 m =  8.3 m

Answer:

power is the rate at which energy is transferred or converted

the unit of power is Watts

Cope up with changes is significant in everyone's life. One of the suitable way is to remind ourselves that we can withstand with the changes.

Reminding a thing that is important to anyone or ourselves until we do it a better way. Thinking past time and wasting time is just ridiculous. Because we must cope up with the current scenario and build up our mental strength.

Our lives are constantly impacted by changes. Change is a constant, uncontrolled aspect of life that has an impact on our work ethics and routines.

Anything that changes may have major or little repercussions. As a result, since the extent of change's first consequences is uncertain, we must refrain from discriminating against it.

Organizations can effectively use change as a tool. Without change, people would be hesitant to form fresh perspectives and ideas. They wouldn't be able to respond to daily obstacles and would become inert in their work and their roles.

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Answer:

Explanation:

The point of destination is 141 north and 102 km east . Vectorially it is represented by unit vector as follows .

D = 102 i + 141 j

magnitude of D = √ ( 102² + 141² )

= √ ( 10404 + 19881)

= √ 30285

= 174 km

To go back to original position , ship should move on the following vector

D = -102 i - 141 j

Tan Ф = 141 / 102 = 1.38

Ф = 54⁰ , direction will be south of west . From north  east , angle will be

180 + 54 = 234⁰

Answer:

there are germs in your hand and soap has chemicals that kill germs

Answer:

dino nuggies

Explanation:

cause whynot

Answer:

0.97 id the correct answer

Explanation:

A piece of aluminium with mass 1 kg and density 2700 kg/m3 is suspended from a string and then completely immersed in a container of water. Calculate the tension in the string (a) before and (b) after the metal is immersed.

I am unable to add the workings out, however please do message me and I will be able to provide you with them :)

Answer:

I don't know lol good luck i guess

Answer:

A) v₁ = 10.1 m/s t₁= 4.0 s

B) x₂= 17.2 m

C) v₂=7.1 m/s

D) x₂=7.5 m

Explanation:

A)

       [tex]\Delta K + \Delta U = (K_{f} - K_{o}) +( U_{f} - U_{o}) = 0 (1)[/tex]

       [tex]\frac{1}{2}*v_{1}^{2} = g*h (4)[/tex]

       [tex]h = x_{1} * sin \theta_{1} = 20.0 m * sin 15 = 5.2 m (5)[/tex]

       Replacing (5) in (4) and solving for v₁, we get:

      [tex]v_{1} = \sqrt{2*g*h} = \sqrt{2*9.8m/s2*5.2m} = 10.1 m/s (6)[/tex]

       [tex]v_{1}^{2} - v_{o}^{2} = 2*a* x_{1} (7)[/tex]

       [tex]a = \frac{v_{1}^{2}}{2*x_{1} } = \frac{(10.1m/s)^{2}}{2* 20.0m} = 2.6 m/s2 (8)[/tex]

       [tex]t_{1} =\frac{v_{1} }{a} =\frac{10.1m/s}{2.6m/s2} = 4.0 s (9)[/tex]

B)

       [tex]x_{2} = v_{1} * t_{2} + \frac{1}{2} *a_{2}*t_{2}^{2} (10)[/tex]

       [tex]x_{2} = 10.1m/s * 2.0s + \frac{1}{2} *(-1.5m/s2)*(2.0s)^{2} = 17.2 m (11)[/tex]

C)  

       [tex]v_{2} = v_{1} + a_{2} *t_{2} = 10.1m/s - 1.5m/s2*2.0s = 7.1 m/s (12)[/tex]

D)

       [tex]\frac{1}{2}*v_{2}^{2} = g*h_{2} (13)[/tex]

       [tex]h_{2} =\frac{v_{2} ^{2}}{2*g} = \frac{(7.1m/s) ^{2}}{2*9.8m/s2} = 2.57 m (14)[/tex]

       [tex]x_{3} = \frac{h_{2} }{sin 20} = \frac{2.57m}{0.342} = 7.5 m (15)[/tex]

Answer:

E. Some charges in the region are positive, and some are negative.

Explanation:

Electric potential is given as;

[tex]V = \frac{W}{Q}[/tex]

where;

W is the work done in moving a charge between two points which have a difference in potential

Q is quantity of charge in the given region

If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.

Therefore, the correct statement in the given options is "E"

E. Some charges in the region are positive, and some are negative.

Answer:

[tex]4.77\ \text{A}[/tex]

Explanation:

F = Magnetic force = 4.11 N

[tex]I_n[/tex] = Net current

[tex]I_2[/tex] = Current in one of the wires = 7.68 A

B = Magnetic field = 0.59 T

[tex]\theta[/tex] = Angle between current and magnetic field = [tex]65^{\circ}[/tex]

[tex]l[/tex] = Length of wires = 2.64 m

[tex]I[/tex] = Current in the other wire

Magnetic force is given by

[tex]F=I_nlB\sin\theta\\\Rightarrow I_n=\dfrac{F}{lB\sin\theta}\\\Rightarrow I_n=\dfrac{4.11}{2.64\times 0.59 \sin65^{\circ}}\\\Rightarrow I_n=2.91\ \text{A}[/tex]

Net current is given by

[tex]I_n=I_2-I\\\Rightarrow I=I_2-I_n\\\Rightarrow I=7.68-2.91\\\Rightarrow I=4.77\ \text{A}[/tex]

The current I is [tex]4.77\ \text{A}[/tex].

h max = 45.92 m

Given

1 kg ball

vo=initial velocity = 30 m/s

Required

Height

Solution

We can use the principle of energy conservation or parabolic motion

For parabolic motion

h max = vo²sin²θ/2g(θ= 90° for straight up)

For conservation energy :

KE₁=PE₂

1/2.m.vo² = m.g.h

We choose parabolic motion

h max = vo²sin²θ/2g

h max = 30²sin²90/2 x 9.8

h max = 45.92 m

Answer:

36.1 nC

Explanation:

The electrostatic force F = kqq'/r² since q = q', F = kq²/r² where q = charge on tape, r = distance between tapes = 1.00 cm = 1 × 10⁻² m and k = 9 × 10⁹ Nm²/C².

Given that F = weight of 12.0 mg piece of tape, F = mg where m = mass of tape = 12.0 mg = 12 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²

So, kq²/r² = mg

q²/r² = mg/k

q² = mgr²/k

taking square-root of both sides,

q = √(mg/k)r

So, substituting the values of the variables into the equation, we have

q = √(mg/k)r

q = √(12 × 10⁻³ kg × 9.8 m/s²/ 9 × 10⁹ Nm²/C²)1 × 10⁻² m

q = √(117.6 × 10⁻³ kgm/s²/9 × 10⁹ Nm²/C²)1 × 10⁻² m

q = √(13.07 × 10⁻¹² C²/m²)1 × 10⁻² m

q = 3.61 × 10⁻⁶ C/m × 1 × 10⁻² m

q =  3.61 × 10⁻⁸ C

q = 36.1 × 10⁻⁹ C

q = 36.1 nC

Answer:

a)       v₂ = 13.20 m / s

Explanation:

To solve this exercise we will use the kinematic relations

Let's start with the Lioness.  Let's find the time to reach top speed

           v = v₀ + a t

as part of rest, its initial velocity is zero

           t = v / a

           t₁ = 21.0 / 2.57

           t₁ = 8.17 s

the total time is the acceleration time plus the time (t₂ = 25 s) that the maximum speed can withstand

          t = t₁ + t₂

          t = 8.17 +25.0 = 33.17 s

Now let's find out what distance the lioness travels in these times

during acceleration

         x = v₀ t + ½ a t²

         x = ½ a t²

         x₁ = ½ 2.57 8.17²

         x₁ = 85.77 m

during constant speed part

        x₂ = v t₂

        x₂ = 21.0 25.0

        x₂ = 525 m

therefore the total distance traveled is

        x = x₁ + x₂

        x = 85.77 + 525

        x = 610.77 m

a) the average speed of the gazelle

this must be the distance that the lioness travels minus the initial distance that separates the two animals (xo = 173 m) between the time taken

        v₂ = [tex]\frac{x -x_o}{t}[/tex]

        v₂ = [tex]\frac{610.77 - 173}{33.17}[/tex]

        v₂ = 13.20 m / s

b) in the attachment we can see a graph of the displacement of the two animals

Answer:

1. Speed=0

2. 2.46 s

3.30.1 m

4. 22.0 m

5.1.004 s

Explanation:

We are given that

Initial speed of blue ball, u=24.1 m/s

Height of blue ball from ground y_0=0.5 m

Initial speed of red ball , u'=7.2 m/s

Height of red from ground=y'0=32 m

Gravity, g=[tex]9.81ms^{-2}[/tex]

1.When the ball reaches its maximum height then the speed of the blue ball is zero.

2.v=0

[tex]v=u+at[/tex]

Using the formula and substitute the values

[tex]0=24.1-9.81t[/tex]

Where g is negative because motion of ball is against gravity

[tex]24.1=9.81t[/tex]

[tex]t=\frac{24.1}{9.81}=2.46s[/tex]

3.[tex]y=y_0+ut+\frac{1}{2}at^2[/tex]

Using the formula

[tex]y=0.5+24.1(2.46)-\frac{1}{2}(9.81)(2.46)^2[/tex]

[tex]y=30.1 m[/tex]

4.Time of flight for red ball=3.77-2.9=0.87s

[tex]y'=32-7.2(0.87)-\frac{1}{2}(9.81)(0.87)^2[/tex]

[tex]y'=22.0m[/tex]

Hence, the height of red ball 3.77 s after the blue ball is 22.0 m.

5.According to question

[tex]0.5+24.1(t+2.9)-\frac{1}{2}(9.81)(2.9+t)^2=32-7.2t-\frac{1}{2}(9.81)t^2[/tex]

[tex]0.5+24.1t+69.89-4.905(t^2+5.8t+8.41)=32-7.2t-4.905t^2[/tex]

[tex]0.5+24.1t+69.89-4.905t^2-28.449t-41.25105=32-7.2t-4.905t^2[/tex]

[tex]0.5+69.89-41.25105-32=-24.1t+28.449t-7.2t[/tex]

[tex]-2.86105=-2.851t[/tex]

[tex]t=\frac{2.86105}{2.851}=1.004 s[/tex]

Hence,  1.004 s  after the blue ball is thrown  are the two balls in the air at the same height.

Answer:

a) ω₁ = 0.97 rad/sec

b) K₀ = 1.31 J

   Kf  = 1.99 J

Explanation:

a)

       [tex]L_{o} = L_{f} (1)[/tex]

       [tex]L = I*\omega (2)[/tex]

       [tex]\omega_{f} = \frac{I_{o} *\omega_{o} }{I_{f} } = \frac{6.42kgm2*0.64rad/sec}{4.22kgm2} = 0.97 rad/sec (5)[/tex]

b)

       [tex]K_{rot} = \frac{1}{2} * I * \omega^{2} (6)[/tex]

      [tex]K_{roto} = \frac{1}{2} *I_{o} * \omega_{o} ^{2} = \frac{1}{2}* 6.42kgm2*(0.64rad/sec)^{2} = 1.32 J (7)[/tex]