Answer:
B
Explanation:
The pancreas is responsible for regulating blood sugar, exercise gives it less work to do
Excercise is particularly beneficial for the pancreas because physical activity positively impacts blood sugar, giving the pancreas less work. Correct option is B.
When you engage in physical activity, several things happen that benefit the pancreas:
Increased Insulin Sensitivity: Exercise helps improve the body's sensitivity to insulin. This means that cells become more responsive to the insulin signal, allowing glucose to enter the cells more effectively. This can help prevent insulin resistance, a condition where cells don't respond properly to insulin and blood sugar levels rise.
Improved Blood Sugar Regulation: Exercise can lower blood sugar levels by facilitating the uptake of glucose into cells for energy. This can reduce the burden on the pancreas to produce excess insulin to manage high blood sugar levels.
Reduced Risk of Type 2 Diabetes: Regular physical activity is associated with a reduced risk of developing type 2 diabetes, a condition characterized by impaired blood sugar regulation. By helping maintain healthy blood sugar levels, exercise supports the pancreas in its role of insulin production.
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Which state of matter has molecules that move the most?
liquid
solid
gas
They are all the same.
Answer:
gas
Explanation:
in gaseous state molecules move the most because force of attraction between atoms are least in gaseous state
The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32. 50 N/m, is 0. 640 J. Find by how much is the spring is compressed.
The spring in the dart gun is compressed by 0.16 m
From the question given above, the following data were obtained:
Spring constant (K) = 50 N/m
Potential Energy (PE) = 0.640 J
Compression (e) =?The compression experience by the spring can be obtained as follow:
PE = ½ke²
0.64 = ½ × 50 × e²
0.64 = 25 × e²
Divide both side by 25
e² = 0.64 / 25
Take the square root of both side
e = √(0.64 / 25)
e = 0.16 m
Therefore, the spring is compressed by 0.16 m
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which statement about moist air moving over a mountain is correct?
Answer:
Explanation:
The orographic effect occurs when air masses are forced to flow over high topography. As air rises over mountains, it cools and water vapor condenses. As a result, it is common for rain to be concentrated on the windward side of mountains, and for rainfall to increase with elevation in the direction of storm tracks.
When astronomers carefully examine the planets found by Kepler and draw conclusions from the Kepler sample, what do they conclude about planets the size (radius) of Earth
Given what we know about the Kepler space program, we know that the astronomers discovered that Earth-sized planets are more common than we imagined.
Kepler was launched with the intention of getting a closer look at other planets outside of our solar system using enhanced photometrics.
The idea behind this launch was to discover more Earth-sized planets, preferably within the habitable zone of their central star.
What this mission showed astronomers, is that Earth-sized planets are more common than we could have imagined, Kepler proved this by finding over 2,662 planets to date.
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when light enters water, it bends. what does the amount of bending depend on?
Answer:
the change of speed!
Explanation:
if light speeds up or slow down more it bend more
A 1300-kg car is traveling with a speed of 16.0 m/s. What is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 38.9 m?
Answer:
F=ma,a=0.329m/second squared,m=1300kg,F=1300*0.329=4277N
gold is a metal angu
Answer:
God is a metal- gold is a transition metal and a group 11 element. It is one of the least reactive chemical elements and is solid under standard condition.
•Gold is the chemical element with 79 protons in each atomic nucleus. Every atom containing 79 protons is a gold atom.
Why is wrestling ring floor always softThis is physics
Answer:
So the people in the ring don't get hurt or break anything on impact once they hit the floor
discrete packets of kinetic energy in light are called
Answer:
Photons
Explanation:
I just know
Discrete packets of kinetic energy in light are called photons. Photons are fundamental particles of light and electromagnetic radiation. The correct answer is photons.
Photons are fundamental particles of light and electromagnetic radiation. They carry energy in discrete quantities, known as quanta or packets, and exhibit both wave-like and particle-like properties.
The energy of a photon is directly proportional to its frequency, and inversely proportional to its wavelength. When light interacts with matter, it can transfer its energy to the particles it interacts with, leading to various phenomena such as absorption, reflection, and emission.
Therefore, Discrete packets of kinetic energy in light are called photons.
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Best definition of an electromagnetic wave?
A) an electromagnetic wave is a longitudinal wave with electricity
B) an electromagnetic wave is a mechanical wave
C) an electromagnetic wave is a transversal wave that has electrical and magnetic properties
Answer:
Longitudinal and mechanical waves require a medium to support their transmission:
C) is the correct answer
What happens in a nucleus during beta decay
The numbers of protons increases
The number of neutrons increases
The number of protons decrease
The number of protons plus the number of neutrons decreases
The number of protons plus the number of neutrons decreases
Beta decay occurs when, in a nucleus with too many protons or too many neutrons, one of the protons or neutrons is transformed into the other. In beta minus decay, a neutron decays into a proton, an electron, and an antineutrino: n Æ p + e - +.
The strength of the electric field 0. 5 m from a 6 µC charge is _______ N/C. (Use k = 8. 99 × 109 N•meters squared per Coulomb squared and round answer to the nearest whole number. ) 215760 539400 697976 512356.
The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.
We want to calculate the strength of the electric field 0.5 m (r) from a 6 μC charge (Q).
What is the electric field?The electric field (E) is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.
We can calculate the electric field at some distance from a punctual charge using the following formula.
E = (k × Q) / r²
E = [(8.99 × 10⁹ N.m².C²) × (4 × 10⁻⁶ C)] / (0.5 m)² ≈ 143,840 N/C
where,
k is the Coulomb's law constant.The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.
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7. A bus covers a certain distance in 60 minutes if it runs at a speed of 60 km/hr.
What must be the speed of the bus in order to reduce the time of journey by 40
minutes?
Answer:
90 Km/h
Explanation:
60 mins is 1 hr
so in an hour bus covers 60 Km
so new speed:
d/t
(60km/40mins)*60mins/h
90Km/h
a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time
find distance and acceleration
FAST PLEASE !!
Answer:
-1.2×10^2 m
I hope this helps you
How much energy must be transferred out of the system as heat q to lower its temperature to 0∘c?.
Answer:
2.20 × 104 J
Explanation:
How much energy must be transferred out of the system as heat Q to lower its temperature to 0?C? ANSWER Q = 2.20 x 10^4. Cooling Power of P is 36.6 W.
The first hill of a roller coaster is 42.0 meters high. The bottom of the first hill is 4.2 meters off the ground.The roller coaster cart has a mass of 4500 kg.
Calculate its potential energy at the top of the first hill.
Calculate its potential energy at the bottom of the first hill.
Challenge- What is the velocity of the cart at the bottom of the first hill?
Answer:
1.89*10⁶J
Explanation:
because 4500kg * 42m*10m/s² is 1890000J
Calculate the weight of an object that displaces 3 m2 of water and exerts a pressure of 500 Pa (500 N/m ).
The weight of the object from the information provided in the question is 1500 N.
We know that pressure = Force/area. We have the following information from the question;
Pressure =500 Nm-2
Area = 3 m2
Hence;
Force = Pressure × area
Force = 500 Nm-2 × 3 m2
Force = 1500 N
Hence, the weight of the object is 1500 N
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5. An acrobat, starting from rest, swings freely on a trapeze of
length 3.7 m (Figure 6). If the initial angle of the trapeze is
48°, use the law of conservation of energy to determine
(a) the acrobat's speed at the bottom of the swing
(b) the maximum height, relative to the initial position, to
which the acrobat can rise
The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.
Em = K + U
Let's write the energy in two points.
Starting point. Highest part of the oscillation
Em₀ = U = m g h
Final point. Lower part of the movement
[tex]Em_f[/tex] = K = ½ m v²
Energy is conserved.
Emo = [tex]Em_f[/tex]
m g h = ½ m v²
v² = 2 gh
Let's use trigonometry to find the height, see attached.
h = L - L cos θ
h = L (1- cos θ)
They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.
h = 3.7 (1- cos 48)
h = 1.22 m
this is the maximum height of the movement.
Let's calculate the velocity.
[tex]v= \sqrt{2 \ 9.8 \ 1.22}[/tex]
v = 4.89 m / s
In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
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Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an
an unbalanced force of 42 Newtons has been applied?
A 75.60 kg
B 00.04 kg
C 23.33 kg
D 43.80 kg
Answer:
23.33 kgExplanation:
The mass of the object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]
We have the final answer as
23.33 kgHope this helps you
Answer:
[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F=ma[/tex]
The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.
Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².
F= 42 kg*m/s² a= 1.8 m/s²Substitute the values into the formula.
[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².
[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]
[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]
The units of meters per second squared cancel.
[tex]\frac {42 \ kg}{1.8 } =m[/tex]
[tex]23.3333333 \ kg=m[/tex]
Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.
[tex]23.33 \ kg \approx m[/tex]
The mass of the ball is approximately 23.33 kilograms.
Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?
The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N
The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.
According to Newton's second Law;
Force = (Tension) = mass × acceleration due to gravity
∴
We can say:
Tension = 4kg × 9.81 m/s²
Tension = 39.24 N
Tension = 40 N (to the nearest whole number)
Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N
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The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat’s average kinetic energy? (1 kJ = 1000 J)
Need answers with explanaitions please
A. 4.2 kJ
B. 8.3 kJ
C. 69.0 kJ
D. 139.0 kJ
Answer:
C.69 kJ
Explanation:
kinetic energy
[tex] = 1 \div 2mv {}^{2} [/tex]
A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The block accelerates to the right and is moving with speed v once it has moved a distance d. Which of the following equations can be used to solve for the force of friction exerted on the block by the surface?
The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d
The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.
Therefore,
using Newtons third law
F - f = ma
a = v/t
t = d/v
F - f = m × v / t
F- f = m × [tex]\frac{v}{\frac{d}{v} }[/tex]
F- f = m × v²/d
Therefore,
F- f = mv² / d
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I rode my bicycle to grandmother's house at 6 km/h in a flat road for 5 min before reach a hill. I went at 2 km/h up the hill for 3minutes. I met a friend and stopped to talk for 5 minutes. I went on at 2 km/h to my grandmother's house. Draw (plot) the v against t graph for this motion.
The graph can be plotted based on the given information which are given
in pairs (velocity and time), and which the coordinate pairs are formed.
Please find attached the required v against t graph created with MS ExcelReasons:
The given data are presented in a tabular form as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 - 5 &6 \\5 - 8&2\\8 -13&0&\\13- &2&\end{array}[/tex]
The velocity time graph can be plotted using the above table values on
MS Excel using the above table elaborated as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 &6 \\5&6\\5 &2\\8&2\\8&0\\13&0&\\13 &2&\end{array}[/tex]
The attached graph can then be created using the Insert → Chart menu
after selecting the data above inputted in the spreadsheet button on MS
Excel.
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If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)
Answer:
10s
Explanation:
PLEASE ANSWER THIS RIGHT ASAP
What is the correct definition of energy?
A: chemical changes
B: force × distance
C: both kinetic and potential energy
D: the ability to do work or cause change
Answer:
D: The ability to do work or cause change.
Explanation:
Energy can be defined as the ability to do work. We apply energy in basically everything we do in life, energy is needed to walk or move from one position to another, it is required to eat and do other basic things of life. The body system converts the food that is being consumed into energy, this energy can be switched from one form to another.
There are various forms of energy which include solar energy, wind energy, electrical energy, mechanical energy, kinetic energy, potential energy, etc. This form of energy can be converted from one form to another but cannot be destroyed.
Hope this helps :)
What does 1 N = ? please I need help?
[tex]1~N = 1~ \text{kg~ms}{^{-2}[/tex]
1 N = 1 kg × m/s²
One Newton is equal to 1 kilogram multiplied by meter by second squared.
_____
Hope it helps ⚜
A car starts from rest, then accelerates at 1.20 m/s2 for 7.00 s. It hits the brakes,
slowing to a stop at a rate of -4.25 m/s2.
What is the total distance travelled?
Answer:
the answer is 4.15 m/s2
Explanation:
4.15 m/s2
A 46.5-kg ball has a momentum of 57.2 kg m/s. What is the ball's speed?
Answer:
1.23 m/s
Explanation:
p=mv
57.2 = 46.5v
v= 57.2/46.5
v= 1.23
If you want to verify your answer, just insert the value of v in the equation.
The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at 3. The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at atmospheric pressure, would have to be admitted into the space to cause the column of the mercury
to drop to 59 cm?
The ideal gas equation and the pressure in barometer allows us to find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The variation of the volume is: ΔV = 7.67 cm³
Pressure is defined by the relationship between force and area.
P = F / A
The ideal gas equation establishes a relationship between pressure, volume, and temperature of an ideal gas.
PV = nR T
Where P is pressure, V is volume, and T is temperature.
Let's write this equation for two points assuming that the temperature has not changed.
P₀ V₀ = P₁ V₁
V₁ = [tex]\frac{P_o}{P_1} \ V_o[/tex] (1)
The subscript "o" is used for the start point and the subscript "1" for the end point.
The pressure in a barometer is:
P = ρ g y
They indicate the initial height of the barometer y₀=75 cm, the distance from empty space y'₀ = 9 cm and the final height of the barometer y₁ = 59 cm.
The volume of the cylinder is
V = π r² y
Let's calculate the initial volume.
V₀ = π 1 9
V₀ = 28.27 cm³
We substitute in equation 1.
V₁ = [tex]\frac{\rho \ g \ y_o}{\rho \ g \ y_1} \ V_o[/tex]
V₁ = [tex]\frac{y_o}{y_1} \ V_o[/tex]
Let's calculate.
V₁ = [tex]\frac{75}{59} \ 27.27[/tex]
V₁ = 35.94 cm³
The volume to be incremented is
ΔV = V₁ - V₀
ΔV = 35.94 - 28.27
ΔV = 7.67 cm³
Using the ideal gas equation and the pressure in barometer we can find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The change of the volume is: ΔV = 7.67 cm³
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A car weighs 14500 N. What is its mass?
Answer:
w = mg
14500 = m ×10 [g=10m/s2]
m =14500/10
m=1450kg