Please answer this. List the three most abundant minerals in this bottle of mineral water.​

The new volume of the balloon : V₂ = 4.89 L

Given

V₁ = 4.96 L

T₁ = 6 + 273 = 279 K

T₂ = 2 + 273 = 275 K

Required

The new volume

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

Input the value :

V₂=V₁.T₂/T₁

V₂ = 4.96 x 275 / 279

V₂ = 4.89 L

Answer:

No, it is not appropriate to mix water and DMSO

Explanation:

We have to realize that DMSO is a highly polar solvent and water is a highly polar solvent. The question explicitly says that our target is to produce a solvent of intermediate polarity.

We can only do this by mixing a polar and a nonpolar solvent. We have been given the example of the mixture of acetone/hexane which is quite a perfect mixture.

Thus, it is inappropriate to mix DMSO and water.

The water-DMSO mixture has a high polarity and is not appropriate for intermediate polarity solution.

The interactions between solute-solvent result in the solubility and the polarity of the solution. The polar and non-polar solvents result in intermediate polarity of the solution.

The water and DMSO both are highly polar in nature. The addition of polar DMSO to polar water results in the dipole-dipole interaction between the molecules.

The interactions result in the solubility of the solute with solvent.  However, the polarity of the solution will be high as both the molecules gave synergistic mixture polarity to the solution.

Thus, to obtain the solution of intermediate polarity, water-DMSO mixture is not appropriate.

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Answer:

I believe its Alpha, might not be right though

Explanation:

The atomic number of helium is 2

Answer:

See explanation below

Explanation:

To get a better understanding watch the picture attached.

In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.

In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.

Hope this helps.

The average speed = 43.33 miles per hours(mph)

Given

distance = 65 miles

time = 1.5 hours

Required

The average speed

Solution

The average speed : distance traveled divided by time taken or total distance divided by total elapsed time

Can be formulated :

avg speed = distance : time

avg speed = d : t

Input the value :

avg speed = 65 miles : 1,5 hours

avg speed = 43.33 miles per hours(mph)

Answer:

Li3PO4 - correct

FePO4 - correct

Cu3PO4 - correct

Mg3(PO4)2 - correct

Explanation:

In order to answer this question we must be conversant with the idea of valency as well as the idea of writing formula of ionic substances.

Lithium has a valency of 1 while PO4^3- has a valency of 3 so the correct formula of lithium phosphate must be Li3PO4 after the exchange of valencies.

Iron III has a valency of 3 while the phosphate ion also has a valency of 3 so the subscripts cancel out and iron III phosphate is FePO4.

Copper I ion has a valency of 1 and the phosphate ion has a valency of 3. When they exchange valencies, the formula of the compound is Cu3PO4.

Magnesium has a valency of 2 while the phosphate ion has a valency of 3. The exchange of valency gives us the formula Mg3(PO4)2.

Answer:

237.5 grams CaCl2

Explanation:

Use the periodic table to calculate the mass of CaCl2

40.078+(35.45*2)=110.97800

Convert: 2.14 mol CaCl2 * 110.98g CaCl2/1 mol CaCl2 = 237.4972 g

120.1 g CH₃COOH

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

1.204 × 10²⁴ molecules CH₃COOH

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of CH₃COOH - 12.01 + 3(1.01) + 12.01 + 16.00 + 16.00 + 1.01 = 60.06 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

120.08 g CH₃COOH ≈ 120.1 g CH₃COOH

Answer:

D. 4

Explanation:

Answer:

[tex]atoms= 1.204x10^{24}atoms[/tex]

Explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:

[tex]atoms=2.00mol*\frac{6.022x10^{23}atoms}{1mol} \\\\atoms= 1.204x10^{24}atoms[/tex]

Best regards!

Answer:

Xb = 0.59

Explanation:

Let's analyze the given data.

We have a total vapor pressure of 263 Torr for the mix of the two gases. And the individual vapour pressures for each gas is given, and it's 425 Torr for pentane and 151 Torr for hexane.

We are asked to determine the mole fraction of hexane. For practical purposes, we will label pentane as "a" while hexane would be "b". So, let's write the equations that we need to calculate this.

We know that the total pressure of a solution would be:

P = Pa + Pb    (1)

And we also know that these individual pressures are:

Pa = Xa * Pa°    (2)

Pb = Xb * Pb°    (3)

Where Pa° and Pb° are the vapour pressures of each gases.

The mole fractions (Xa and Xb), can be expressed, one in function of the other:

Xa + Xb = 1 -----> Xa = 1 - Xb     (4)

Now that we know this, we can replace (4) in (2), and then, (2) and (3) can be replaced in (1):

Pa = (1 - Xb)Pa°

P = (1 - Xb)Pa° + XbPb°      (5)

Replacing the given data, we have:

263 = (1 - Xb)*425 + 151Xb

Now solving for Xb, which is the mole fraction of hexane:

263 = 425 - 425Xb + 151Xb

263 - 425 = (-425 + 151)Xb

-162 = -274Xb

Xb = -162 / -274

Hope this helps

Answer:

wheres the map? I can't see it even tho im using my eye glasses

Answer:

50

Explanation:

5000/100 = 50

Answer:

It uses this term to represent the economic use of land and nature, with minimal degradation and maximum environmental preservation.

Explanation:

Capitalism is an economic system that promotes the maximum economic exploitation of terrestrial resources. It is common for this exploitation to be strongly associated with environmental degradation, destruction of natural habitats, deforestation and death of fauna and flora. With this, we can consider that capitalism is one of the main formulators of environmental degradation, however many professionals have considered the term "capitalism mated with conservation," where terrestrial resources are exploited consciously and with the objective of reducing degradation to the maximum. environmental impact and maximize conservation.

Answer:

1450 W

Explanation:

5800n x 20m        =1450w

      80s

Answer:

27.08 x 10²³ atoms of Al .

Explanation:

121.4 grams of Aluminum = 121.4 / 26.98  moles of Aluminum

= 4.4996 moles

1 mole of Aluminum contains 6.02 x 10²³ atoms of Al

4.4996 moles of Aluminum contains 6.02 x 10²³ x 4.4996 atoms of Al

= 27.08 x 10²³ atoms .

Answer:

i think that b is the awnser sorry if im wrong

Explanation:

Answer:

i think that b is the awnser sorry if im wrong

Explanation:

Answer:

Zn + 2HCl -----> ZnCl2 + H2

Explanation:

Zinc chloride and hydrogen gas is formed

When zinc was combined with hydrochloric acid, hydrogen gas was evolved.

We know that a general property of metals is that they react with metals to evolve hydrogen gas. All metals that are above hydrogen in the activity series will undergo this reaction.

Hence, when hydrochloric acid and zinc were combined, the following reaction occured; Zn(s) + 2HCl(aq) -----> ZnCl2(aq) + H2(g). The colorless odorless gas evolved after this combination is hydrogen gas.

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This is a two-step question. First, convert the mass of NO2 into the number of moles of NO2. Secondly, quantify the number of moles of NO2 in terms of the number of moles of NO2. The steps and answer are as follows

[tex]122 \text{ g NO}_\text{2 } \div 46.0055 \text{ g NO}_2/\text{moles of NO}_2 = 2.652 \text{ moles of NO}_2 \\ 2.652 \text{ g NO}_{2 } \times 6.022 \times 10^{23} \text{ molecules of NO}_{2 }/\text{moles of NO}_2 = {1.60 \times 10^{24} \text{ molecules of NO}_2}[/tex]

The answer has been provided to three significant figures to correspond with the number of sig figs given in the mass.

Answer:

[tex]\frac{3}{2}He[/tex]

[tex]\frac{6}{2} He[/tex]

[tex]\frac{7}{4}Be[/tex]

[tex]\frac{3}{1} H[/tex]

[tex]\frac{6}{4}Be[/tex]

[tex]\frac{7}{3} Li[/tex]

Explanation:

In the first nucleus we are told that there are two protons and one neutron. Let us remember that the mass number = number of protons + number of neutrons.

This implies that, for the first specie the mass number is 3, for the second specie the mass number is 6 and the third specie has a mass number of 7 and so on. The mass number is indicated as a superscript.

The atomic number is the number of protons in the nucleus of the atom and helps us to identify the atom. It is always written as a subscript as shown.

Answer:

9 moles of H₂ are produced

Explanation:

Note: The question is incomplete. the complete question and the given image is found below:

The diagram represents a high-temperature reaction between CH4 and H2O. Based on this reaction, how many moles of H2 can be obtained starting with 3 mol CH4?

From the attachment, the equation of the reaction can be written as:

2CH₄ + 2H₂O ----> 2CO + 6H₂

From the equation the reaction shown above, 2 moles of methane, CH₄ reacts with 2 moles of gaseous water or steam, H₂O (since the reaction occurs at a high temperature) to produce six moles of hydrogen gas, H₂.

Therefore, starting with 3 moles of CH₄ and assuming the number of H₂O are equal to or greater than three moles (since the mole ratio of CH₄ to H₂O is 1 : 1 according to the equation of the reaction), number of moles of H₂ that will be produced = 3 * 6/2 moles of H₂

number of moles of H₂ produced = 9 moles

Therefore, 9 moles of H₂ are produced

Considering the reaction stoichiometry, 9 moles of H₂ can be obtained starting with 3 moles of CH₄.

The balanced reaction is:

CH₄ + H₂O → CO + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 1 mole of CH₄ produce 3 mole of H₂, 3 moles of CH₄ will produce how many moles of H₂?

[tex]amount of moles of CH_{4} =\frac{3 moles of CH_{4}x3 moles of H_{2} }{1 mole of CH_{4}} [/tex]

amount of moles of H₂= 9 moles

Finally, 9 moles of H₂ can be obtained starting with 3 moles of CH₄.

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Explanation:

a. LiCl is an ionic molecule whereas water is a polar molecule with net dipole moment in it. There LiCl in water would have an ion-dipole force of interaction.

b. Both NF3 and CH3CN have dipole moment in them, since both are polar molecule. Hence, there would be dipole-dipole interaction.

c. Here both CCl4 and benzene are non polar molecules therefore, they have London dispersion force of interaction.

d. In methylamine and water both have hydrogen bonding in them. The nitrogen of CH3NH2 forms hydrogen bond with water.

The type of interactions in the following solutions are:

In a solution, the dissolution of solute molecules is driven by the interactions between the solute and solvent molecules.

The solute solvent interaction is based on the nature of the molecules. The interactions in the following solutions are:

The water is polar solvent and LiCl is an ionic molecule. The interaction between the molecules will be Ion-dipole force.

The acetronitrile and [tex]\rm NF_3[/tex] both are polar molecules. The force present in the interactions is Dipole-dipole force.

The benzene and [tex]\rm CCl_4[/tex] both are nonpolar molecules. The type of interaction present in the solution is London Dispersion force.

The water is a polar solvent, and Methylamine is an organic compound. The interaction in the solution is hydrogen bonding.

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Answer:

421.32774 grams

Explanation:

Answer:

Lithium oxide, Li₂O.  

Explanation:

Hello!  

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

[tex]M_2O+H_2\rightarrow 2M+H_2O[/tex]  

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

[tex]5.00gM_2O*\frac{1molM_2O}{(2*X+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{XgM}{1molM}=2.32gM[/tex]  

Thus, we perform the operations in order to obtain:

[tex]\frac{10X}{(2X+16)}=2.32[/tex]  

So we solve for x as shown below:

[tex]10X=2.32(2X+16)\\\\10X=4.64X+37.12\\\\X=\frac{37.12}{10-4.64}\\\\X= 6.93g/mol[/tex]  

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.  

Best regards!

Answer:

A. Nucleus

B. Electron

C. Protons

D. Neutrons

Explanation:

- A proton carries a positive charge (+) and an electron carries a negative charge (-), so the atoms of elements are neutral, all the positive charges canceling out all the negative charges. Atoms differ from one another in the number of protons, neutrons and electrons they contain.

- Electron:

a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

Answer:

See explanation

Explanation:

We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;

Step 1

2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)

Step 2

2NO(g) + O2(g) -------> 2NO2(g)

So, the overall reaction equation is;

2SO2(g) + O2(g) ------> 2SO3(g)

Answer:

[a]. - 445.45J,

[b]. - 367.92 J

Explanation:

The following parameters are given in the question above. These information are used in solving this problem.

The mass of Xenon = 65.0 g of xenon, pressure = 2.00 atm, temperature = 298 K.

The number of moles of xenon = mass/ molar mass = 65g/ 131.293= 0.495.

The cp= 3/2 R, cp =3/2R + R = 5/2 R.

j = cp/cv = 3/2.

[a]. The final temperature,T2 = (2)^-2/3 × (298)^5/3 = T2^5/3.

Final temperature,T2 = 225.84K.

Expansion work = nCv [ T₂ - T₁] = 0.495 × 3/2 × 8.314 × [ 225.84 - 298] = - 445.45J.

(b). The final temperature can be Determine as;

3/2( T2 - 298k) = - 1 (T2 /1 - 298/2).

3/2(T2 - 298) = - T2 + 149K.

3T2 - 894 = - 2T2 +298K.

T2 = 238.4 K.

Workdone= nCv (T2 - T1) = 0.495 × 3/2 × 8.314 (238.4 - 298) = - 367.92 J.