Please help and thank u

Answer:

1

Step-by-step explanation:

An equilateral triangle is a triangle with all three sides of equal length, so there's only one option, a triangle with all three sides 7 centimeters.

Answer:

x = 4

Step-by-step explanation:

Given that DE is parallel to AC then DE divides the sides proportionally, so

[tex]\frac{BD}{DA}[/tex] = [tex]\frac{BE}{EC}[/tex] , substitute values

[tex]\frac{x+2}{x}[/tex] = [tex]\frac{3}{2}[/tex] ( cross- multiply )

3x = 2(x + 2) ← distribute

3x = 2x + 4 ( subtract 2x from both sides )

x = 4

Answer:

5

Step-by-step explanation:

AC=AB+BC

so 16=x+1+x+7

which simplifies to 16=2x+8

subtract eight from both sides to get 8=2x

then divide by 2 to get that x=4

AB=x+1, which substitutes into 4+1=5

Answer:

The length of the equal sides of the isosceles triangle with a perimeter of 34 cm perimeter is 12 cm

The length of the equal sides of the isosceles triangle with a perimeter of 82 cm perimeter is 36 cm

The base length of both triangles is 10 cm

Step-by-step explanation:

The given parameters are;

The base length of the triangles are equal

The base length of one of the triangle = The base length of the other triangle

The equal sides of one of the triangles = 3 × The length of the equal sides of the other

The perimeter of the triangles are; 34 cm and 82 cm

Let 'b' represent the base length of each triangle, let 'a' represent the length of an equal side of the smaller triangle with a perimeter of 34 cm and let 'c' represent the length of an equal side of the larger triangle with a perimeter of 82 cm

For the smaller triangle, we have;

b + 2·a = 34..(1)

For the other triangle;

b + 2·c = 82...(2)

Given that the side length of the larger triangle are larger than those of the smaller triangle, and that the side length of the larger triangle is 3 times the side length of the smaller triangle, we get;

c = 3·a

By the substitution method, from equation (2) we get;

b + 2·c = b + 2 × 3·a = b + 6·a = 82

∴ b + 6·a = 82...(3)

Subtracting equation (1) from equation (3) gives;

b + 6·a - (b + 2·a) = 82 - 34 = 48

b - b + 6·a - 2·a = 48

4·a = 48

a = 48/4 = 12

The length of the equal sides of the 34 cm perimeter (smaller) isosceles triangle, a = 12 cm

From c = 3·a, and a = 12, we get;

c = 3 × 12 = 36

The length of the equal sides of the 82 cm perimeter (larger) isosceles triangle, c = 36 cm

From equation (1), we get;

b + 2·a = 34

∴ b + 2 × 12 = 34

b = 34 - 2 × 12 = 10

The base length of both triangles, b = 10 cm

Answer:

{2, 4, 6, 8,10}

Step-by-step explanation:

GIven U={1,2,3,.............,10} A={2,4,6,8,10} and B= {1,3,5,7,9);

Required

A-B = AnB'

B' = {2, 4, 6, 8,10}

AnB' are elements common to both A and B'.Hence;

AnB' = A- B = {2, 4, 6, 8,10}

Given:

The inequalities are:

[tex]2x-3<7[/tex]

[tex]2x+1>-3x-4[/tex]

To find:

The range of values of [tex]x[/tex] for the given inequalities.

Solution:

We have,

[tex]2x-3<7[/tex]

Adding 3 on both sides, we get

[tex]2x-3+3<7+3[/tex]

[tex]2x<10[/tex]

Divide both sides by 2.

[tex]\dfrac{2x}{2}<\dfrac{10}{2}[/tex]

[tex]x<5[/tex]                      ...(i)

The second inequality is:

[tex]2x+1>-3x-4[/tex]

Subtracting 1 from both sides, we get

[tex]2x+1-1>-3x-4-1[/tex]

[tex]2x>-3x-5[/tex]

Adding [tex]3x[/tex] on both sides, we get

[tex]2x+3x>-3x-5+3x[/tex]

[tex]5x>-5[/tex]

Divide both sides by 5.

[tex]\dfrac{5x}{5}>\dfrac{-5}{5}[/tex]

[tex]x>-1[/tex]            ...(ii)

Using (i) and (ii), we get

[tex]-1<x<5[/tex]

Therefore, the required range is [tex]-1<x<5[/tex].

Step-by-step explanation:

is it a question ? please check.

Answer:

Step-by-step explanation:

D.

supplementary.

BC.

D.

The answer for the following question is 12i.

Answer:

t + u = 10 + 2i

Step-by-step explanation:

t + u

= 4 + 6 + 2i ← collect like terms

= 10 + 2i

Answer:

x = 135

Step-by-step explanation:

The angles are vertical angles and vertical angles are equal

125 = x-10

Add 10 to each side

125+10 = x

135 =x

Answer:

0.9999

Step-by-step explanation:

One way to calculate the probability that at least one of them need repairs is that we can calculate the opposite (none need repairs) and subtract that from 1 (100%).

The probability that a car does not need repairs is 0.2. To find the probability that six cars all fulfill this 0.2 probability, we can get [tex]0.2^{6} =0.000064[/tex] . This is the probability that none require repairs. The opposite of this is that at least one needs repairs, so 1-0.000064 - 0.999936. Rounded to 4 decimal places, the probability is 0.9999

Answer:

Given

To find f(x + 2) substitute x with x + 2 in the given function:

f(x+2)= 4(x + 2)² + 2(x + 2) - 4

         = 4(x² + 4x + 4) + 2x + 4 - 4

         = 4x² + 16x + 16 + 2x

         = 4x² + 18x + 16

f(x+2)

Answer:

complete the square 2 x + 38 = 0

Step-by-step explanation:

Answer:

this is the answers

Answer:

∠AEC ≅ ∠BED by vertical angles theorem

Answer:

Answer:

∠AEC ≅ ∠BED by vertical angles theorem

Step-by-step explanation:

Answer:

16days

Step-by-step explanation:

1 man =4days

4men=4men/1man×4days

=4×4days

=16days

Answer:

1

Step-by-step explanation:

averaging

Answer:

0.0067 = 0.67% probability of selecting at least 3 defective fuses.

Step-by-step explanation:

For each fuse, there are only two possible outcomes. Either it is defective, or it is not. The probability of a fuse being defective is independent of any other fuse, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

A company manufactures fuses. The percentage of non-defective fuses is 95.4%.

This means that 100 - 95.4 = 4.6% = 0.046 are defective, which means that [tex]p = 0.046[/tex]

A sample of 9 fuse was selected.

This means that [tex]n = 9[/tex]

Calculate the probability of selecting at least 3 defective fuses.

This is:

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{9,0}.(0.046)^{0}.(0.954)^{9} = 0.6545[/tex]

[tex]P(X = 1) = C_{9,1}.(0.046)^{1}.(0.954)^{8} = 0.2840[/tex]

[tex]P(X = 2) = C_{9,2}.(0.046)^{2}.(0.954)^{7} = 0.0548[/tex]

Then

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.6545 + 0.2840 + 0.0548 = 0.9933[/tex]

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0.9933 = 0.0067[/tex]

0.0067 = 0.67% probability of selecting at least 3 defective fuses.

Answer:

3. first make Y the subject, then x^2 will become negative which will make the the parabola open up

Answer:

m = 3 , n = 4

Step-by-step explanation:

Using Section Formula.

[tex]If \ the \ line \ segment \ AB \ where \ A = (x _1, y_1) \ and \ B = (x_2, y_2) \ divided \ by \ P =(x , y) \ in \ the \ ratio \ a : b,\\\\Then \ the \ points \ of \ P \ \\\\x = \frac{ax_2 + bx_1}{a+b} \ and \ y = \frac{ay_2 + by_1}{a+b}[/tex]

   [tex]Here (x_1 , y_ 1 ) = ( -7 , 1 ) \ and \ (x_ 2 , y _ 2 ) = (m , 6)\\\\ratio\ a:b = 3 : 2\\\\Therefore, P (x, y) \\\\x = \frac{3m + (2\times -7)}{5} \ \ \ \ \ \ \ \ \ \ \ [ \ x = -1 \ ] \\\\-1 = \frac{3m - 14}{5}\\\\- 5 = 3m - 14\\\\-5 + 14 = 3m\\\\9 = 3m \\\\m = 3[/tex]

  [tex]y =\frac{3\times 6 + 2 \times 1}{5}\\\\n = \frac{18 + 2}{5} = \frac{20}{5} = 4[/tex]

Answer:

It's well be 2 cause that is the only one thag makes sense

3+2=5

Milk =3/5×640 = 384

Curd 2/5×640 = 256

Answer:

z = -74

Step-by-step explanation:

12 = (2+z) / -6

Multiply each side by -6

-6 * 12 = (2+z)/ -6 * -6

-72 = 2+z

Subtract 2 from each side

-72-2 = 2+z-2

-74 =z

Answer:

[tex]3[/tex] times

Step-by-step explanation:

[tex]5x=15[/tex]

Divide both sides by 5

[tex]x=3[/tex]

Hope this helps

Answer:

9 Times

Step-by-step explanation:

You need to find how many times farther away Amy sets up her target. She used to set it up 5 feet away. Start by finding how many feet away she sets up her target now.

There are 3 feet in a yard, so multiply 15 yards by 3.

15×3=45

Now, Amy sets up her target 45 feet away. She used to set it up 5 feet away. You can use a multiplication fact to find how many times farther away she sets up her target now.

5×9=45

Amy sets up her target 9 times farther away now.

Answer:

45 Tokens

Step-by-step explanation:

3:5:7

Anya = 3

Daniel = 5

Victoria = 7

Daniel + Victoria = 36

5 + 7 = 36

12 = 36

1 = 3

(1 ratio is 3 tokens)

(3 + 5 + 7) × 3 = 45

Answer:

The true statements are;

1) The center of the ellipse is at (-2, -5)

3) The covertices are at (-2, -4) and (-2, -6)

4) The distance between the center and each focus is 2·√6 units

Step-by-step explanation:

The given graph of the ellipse gives;

1) The location of the center of the ellipse = (-2, -5)

2) The location of the vertices of the ellipse = (-7, -5) and (3, -5)

The distance between the center (-2, -5) and each vertex, d, is given as follows;

d = -2 - (-7) = 5 and d = 3 - (-2) = 5

Therefore, the distance between the center (-2, -5) and each vertex is 5 units

3) The location of the covertices, given in the diagram are (-2, -4), and (-2, -6)

4) The coordinates of the focus of an ellipse = h - c, k

c = √(a² + b²)

Where, for the given ellipse, h = -2, k = -5, c = √(5² - 1²) = √(24) = 2·√6

∴ The location of the focus of the ellipse = (-2 - 2·√6, -5)

The distance between the center and each focus, d = -2 - (-2 - 2·√6) = 2·√6

5) The x-coordinate of the directrices of the ellipse = ± a/e

Where; a = 5

b² = a²·(1 - e²)

∴ e² = 1 - b²/a² = 1 - 1/25 = 24/25

e = 2·√6/5

The directrices = -2 ± 5/(2·√6/5) ≈ -2 ± 5.1

The distance between the center and the directrices ≈ 5.1 units

Therefore, the directrices are vertical lines approximately 5.1 units from the center

Answer:

your answer would be B. -5 +3i✓3

Answer:

The standard equation is 7x + y = 9

Step-by-step explanation:

Equations given are:  

7x + 3 = 5 and y - 1 = 6

Set both given equations equal to zero, then combine them into one standard form equation

Set the equations to zero by moving the constant from R.H.S to L.H.S

7x + 3 - 5 = 0

7x - 2 = 0 ---- eq 1

y - 1 = 6

y - 1 - 6 = 0

y - 7 = 0 ----- eq 2

We have to combine eq 1 and eq 2

7x - 2 + y - 7 = 0

7x + y - 9 = 0

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Thus the standard equation is:

7x + y - 9 = 0

7x + y = 9

Thus the standard equation is 7x + y = 9