please help.......................

Answer:

52.7 miles

Step-by-step explanation:

Please refer to attached photo. (Apologies for the terrible drawing).

We can deduce from A to B the distance is 20 miles, therefore no calculations is required.

However, from B to C, we will have to find the horizontal and vertical distances.

Horizontal Distance B > C =  = hBC = [tex]BCcos(52)[/tex] = [tex]38cos(52) miles[/tex]

Vertical Distance B > C = vBC = [tex]BCsin(52)[/tex] = [tex]38sin(52)miles[/tex]

Here you can see the whole diagram is a right angle triangle. Which means, we can use Pythagoras' Theorem to find AC.

By Pythagoras Theorem,

[tex]c^{2} =a^{2}+b^{2}[/tex]

[tex]AC^{2} = (AB + hBC)^{2} + vBC^{2} \\AC^{2} = (20+38cos(52))^{2} +(38sin(52))^{2} \\AC = \sqrt{(20+38cos(52))^{2} +(38sin(52))^{2} } \\AC = 52.7 miles[/tex](nearest tenth)

8/9 = 0.888888....

7/18 = 0.388888888889

10/16 = 0.625

Ascending order - means going up, smallest to largest. (Imagine climbing a ladder, where you start of low, then, go higher up the ladder.)

Thus, answer is 7/18, 10/16, 8/9

Hope this helps!

Answer:

of course 0

Step-by-step explanation:

because it doesn't have any value in its first equation

Excel uses VAR function for determining the residual variance.

The variation of any error is known as residual variance, also known as unexplained variance or error variance.

Depending on the type of analysis you're doing, the precise definition will vary. For instance, random fluctuations in regression analysis produce volatility around the "actual" regression line.There are two components to a regression line's total variance: variation that can be explained and variance that cannot. Simply put, the residual variance after deducting the variation resulting from the regression from the total variance of the dependent variable is the residual variance.

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On the number line the position of point F is at point 4.

According to the statement

We have a given that the on a number line , point D is at -3, and point E is at 6. The point F lies on the ratio of to is 2 : 3.

and we have to find the F point on the number line.

Firstly,

Number line is a line on which numbers are marked at intervals, used to illustrate simple numerical operations.

So, According to given information,

Point D is at -3, and point E is at 6.

Ratio of point E to F = 6*2/3

Then

Ratio of point E to F = 6*2/3

After solving it

The point F = 2*2

The point F = 4.

So, On the number line the position of point F is at point 4.

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Answer:

Step-by-step explanation:

      the answer is on the graph

Answer:

h(x) = 6x² - 10x - 4

Step-by-step explanation:

h(x) = f(x) g(x)

       = (2x - 4)(3x + 1)

each term in the second factor is multiplied by each term in the first factor, that is

2x(3x + 1) - 4(3x + 1) ← distribute parenthesis

= 6x² + 2x - 12x - 4 ← collect like terms

= 6x² - 10x - 4

that is h(x) = 6x² - 10x - 4

Answer:

100.5 inches

Step-by-step explanation:

If each course has 3/8 inch of concrete below it  (including the bottom one)

  8 in * 12   + 3/8 in * 12 = 100 1/2 inches

Equation of the line which is passing through the points [tex](-1,7)[/tex] and perpendicular to the line [tex]$y=-\frac{1}{8}x-1$[/tex]

is [tex]y=8x+15[/tex]

How to find the equation which passing through one point [tex](-1,7)[/tex]and perpendicular to the equation [tex]$y=-\frac{1}{8}x-1$[/tex] ?

We know that the equation of line in form of slope and point is

[tex]y-y_{1} =m(x-x_{1} )[/tex]

So first equation of line which is passing through point [tex](-1,7)[/tex] is

[tex]y-7=m_{1} (x-(-1))\\y-7=m_{1}(x+1)[/tex].....(a)

Line [tex]$y=-\frac{1}{8}x-1$[/tex] perpendicular to the line (a)

And we know when two lines are perpendicular then

[tex]m_{1} m_{2} =-1[/tex]

So [tex]m_{1} =-1/m_{2}[/tex]

and we know [tex]m_{2} =-1/8[/tex]

So

[tex]m_{1} =-1/\frac{-1}{8} \\=-1*8/-1\\=8[/tex]

The equation of the line is

[tex]y-7=8(x+1)\\y-7=8x+8\\y=8x+8+7\\y=8x+15[/tex]

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The height of the cylinder is 4 x units.

The area of the cylinder’s base is One-fourthπx2 square units .

What is the volume of cylinder?

We know the volume of a cylinder is given by the formula  π r2 h, where r is the radius of the cylinder and h is the height.

Formula for volume of the cylinder

V = r² π h

Volume of the cylinder= πx³

Diameter=x

Radius (r)=diameter/2

       r  =  x/2

     V = r² π h

   πx³=(x/2)² πh

πx³= (x²/4)πh

Divide both sides by π

x³ =(x²/4)h

Make h the subject of the formula

  h = x³ ÷ x²/4

     =x³ ×4 / x²

     =4x³ / x²

     =4 * x * x * x / x * x

  h=4x

Area of the base:

B = r² π

r=x/2

B=(x/2)² * π

 =(x²/4)π

=πx²/4

=1/4(πx²)

Therefore, The area of the cylinder’s base is One-fourthπx2 square units.

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The complete question is -

A cylinder with a base diameter of x units has a volume of πx3 cubic units. A cylinder with a base diameter of x units has a volume of pi x cubed cubic units. Which statements about the cylinder are true? Select two options. The radius of the cylinder is 2x units. The area of the cylinder’s base is One-fourthπx2 square units. The area of the cylinder’s base is One-halfπx2 square units. The height of the cylinder is 2x units. The height of the cylinder is 4x units.

Answer:

7x = 14

x + 4y = 2

Step-by-step explanation:

3x − 2y = 6

x + 4y = 2

6x - 4y = 12

x + 4y = 2

-----------------------

7x = 14 Replace the first equation with this one.

Answer:

8(3j - 2).

Step-by-step explanation:

24j-16

GCF = 8

so the answer is

8(3j - 2).

The equations which gave the same solution as; 2.3p – 10.1 = 6.5p – 4 – 0.01p are;

It follows from the answer choices that the equation; 2.3p – 10.1 = 6.49p – 4 is equivalent to the given equation as the algebraic sum of p variables is evaluated on the right hand side.

The second equation; 230p – 1010 = 650p – 400 – p also is equivalent to the given equation, when multiplied through by 100.

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The extreme value of y = (x - h)² - c is the vertex of the equation.

The extreme values of a function are either the maximum or minimum values of the function.

The equation of a parabola in vertex form with vertex (h', k) is given by

y = a(x - h')² + k and its extreme values are

Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

So, the cooordinates of the vertex of y = (x - h)² - c is (h, -c).

Now, since a = 1 > 0, (h, -c) is a minimum point.

So, the extreme value of y = (x - h)² - c is the vertex of the equation.

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Answer:

The lowest value is at (1, -8). H and C are equal to 1 and 8 in the equation y = (x - 1)2 - 8. Therefore, the minimum's x-coordinate corresponds to the equation's h-value, and its y-value is the opposite of the c-value.

Step-by-step explanation:

i re wrote it

The lateral and total surface areas of the given cone are 753.98 cm² and 1206.31 cm² respectively.

A cone has a height 'h', radius 'r', and slant height 'l'.

The slant height of the cone is obtained by the Pythagorean theorem. I.e.,

l² = h² + r²

Then,

Its lateral surface area(LSA) = πr([tex]\sqrt{h^2+r^2}[/tex]) square units and

Its total surface area(TSA) = πr(r + l) square units

It is given that,

A cone has a height h = 16 cm and radius r = 12 cm

Then, the slant height is calculated by

l² = h² + r²

l  = [tex]\sqrt{h^2+r^2}[/tex]

On substituting,

l = [tex]\sqrt{16^2+12^2}[/tex]

 = [tex]\sqrt{400}[/tex]

 = 20 cm

So,

LSA = πr([tex]\sqrt{h^2+r^2}[/tex])

       = π × 12 × ([tex]\sqrt{16^2+12^2}[/tex])

       = π × 12 × 20

       = 753.98 cm²

and

TSA = πr(r + l)

       = π × 12 × (12 + 20)

       = π × 12 × 32

       = 1206.37 cm²

Therefore, the lateral and total surface areas of the cone with a height of 16 cm and a radius of 12 cm are 753.98 cm² and 1206.37 cm².

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Answer: The lateral area is 240π square centimeters. The total surface area is 384π square centimeters.

Step-by-step explanation:

The cross-section of a right rectangular pyramid will be shaped similar to the base, that is, a rectangle. Hence, 4th option is the right choice.

If the peak of the rectangular pyramid is directly above the center of the base, it creates a perpendicular to the base, indicating the height of the pyramid. This type of rectangular pyramid is known as the right rectangular pyramid.

A rectangle is a quadrilateral, that is a closed figure with 4 line segments, with all four interior angles at 90°.

When we slice a right rectangular pyramid vertically down at the red line by a plane, not passing through the vertex, of the pyramid will be a dilated image of its base.

A dilated image is an enlarged or diminished image of the preimage, similar with all angles.

Thus, the cross-section of a right rectangular pyramid will be shaped similar to the base, that is, a rectangle. Hence, 4th option is the right choice.

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For complete question, refer to the attachment.

Answer:trapozoid

Step-by-step explanation:

The ordered pairs of Nicole and Ian's sequence pattern are:(5,1),(17,3),(53,5),(161,10),(485,20).

Given that Nicole uses the  rule multiply by 3 then add 2 starting with it and Ian uses the rule add 1/2 then multiply by 2 starting from 0,

We ar rquired to find the ordered pairs of Nicole's and Ian's rules.

We are told that Nicole's pattern is multiply by 3 then add 2 starting with 1.

Thus Nicole's pattern is :5,17,53,161,485.

Ian's pattern is add 1/2 then multiply by 2 and starting with 0.Thus the  numbers are :1,3,5,10,20.

If we combine the numbers of both the person'rule then we will get the ordered pairs which can be written as under:

The ordered pairs are (5,1),(17,3),(53,5),(161,10),(485,20).

Hence the ordered pairs are (5,1),(17,3),(53,5),(161,10),(485,20).

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(a) The city with a larger median room temperature is city B.

(b) The city having the highest noon temperature is city B.

(c) The city having the noon temperatures with a higher interquartile range is city A.

(d) The city having more noon temperatures that 81°F is city B.

In the given question, the noon temperatures for two cities, A and B, recorded over a month are shown via the box-and-whisker plots.

We are asked to use it and answer the questions:

(a) The median of data is represented by the line in the box of the box-and-whisker plot. Thus,

The median noon temperature for city A is 73°F.

The median noon temperature for city B is 76°F.

Thus, the city with a larger median room temperature is city B.

(b) The highest temperature is seen as the end point of the whiskers. Thus,

The highest temperature for city A is 85°F.

The highest temperature for city B is 92°F.

Thus, the city having the highest noon temperature is city B.

(c) The interquartile range is the difference between the end line of the box and its start line. Thus,

The interquartile range for city A is (81 - 64)°F or 17°F.

The interquartile range for city B is (81 - 68)°F or 13°F.

Thus, the city having the noon temperatures with a higher interquartile range is city A.

(d) From the given box-and-whisker plots, we can see that after 81°F, city B has a long whisker, showing more outliers.

Thus, the city having more noon temperatures that 81°F is city B.

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Answer:

Quadrant II

Step-by-step explanation:

This is because the top right is I, the top left

is II, the bottom left is III, and the bottom right is IV.

Answer: The figure changed size.

Step-by-step explanation:  Dilations change the sizes of shapes.  They can either make them bigger or make them smaller.

Answer:B & E

Step-by-step explanation:

We can first rearrange the function to isolate y. Then, we can find the slope as the function is in the form y=mx+b.

[tex]3x-4y=7\\-4y=-3x+7\\y=\frac{3}{4}x-\frac{7}{4}[/tex]

Since parallel lines have the same slope, we can put the slope of 3/4 into the point slope form to get the answer.

For reference, the point-slope form is [tex]y-y_1=m(x-x_1)[/tex]

[tex]y+2=\frac{3}{4}(x+4)\\y+2=\frac{3}{4}x+3\\y=\frac{3}{4}x+1[/tex]

The first line is found in option E, so option E is one of the correct options.

We can also move the x to the other side, as two of the 5 options have both variables on the left (B and C).

[tex]-\frac{3}{4}x+y=1[/tex]

If we multiply the whole equation by -4, we can get rid of the fraction.

[tex]-4(-\frac{3}{4}x+y)=-4(1)\\3x-4y=-4[/tex]

Hence, option B is also correct.

Answer:

B.

Step-by-step explanation:

Vertex with (2,4) means that the equation will have:

y=a(x-2)^2 + 4

Open downwards means that the a will be negative:

so: y = -a (x-2)^2 + 4

Stretched by a factor of 3 means that the a=3

So if we combine all of these, we will get the equation:

y = -3 (x-2)^2 + 4

Step-by-step explanation:

Use the slope-intercept form to find the slope and y-intercept.

Slope:

−

1

3

y-intercept:

(0 , 3)

Any line can be graphed using two points. Select two

x

values, and plug them into the equation to find the corresponding

y

values

Graph the line using the slope and the y-intercept, or the points.

Slope:

−

1

3

y-intercept:

(0 , 3)

1) Correct.

2) The y-intercept is when x=0, so it is (0,5).

By applying the transformation rules for horizontal and vertical translation, we find that the resulting function is g(x) = cos (x - 7) + 4.

Transformation rules are rules that makes changes on charateristics and behavior of a function to create a new one. Rigid transformations like horizontal and vertical translations are examples of transformation rules. In this question we must apply the following transformation rules to the parent cosine function f(x) = cos x:

Now we proceed to derive the resulting function by applying the rules defined above:

Horizontal translation

f'(x) = cos (x - 7)      (3)

Vertical translation

g(x) = cos (x - 7) + 4     (4)

By applying the transformation rules for horizontal and vertical translation, we find that the resulting function is g(x) = cos (x - 7) + 4.

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The relation between the variables in the equation x^4/y=7 is (b) x^4 varies directly as y

The complete question is added as an attachment

From the attached figure, we have the following equation

x^4/y = 7

Multiply both sides of the equation by y

x^4 = 7y

The above represents a direct variation from x^4 to y.

Where 7 represents the variation constant

Hence, the relation between the variables in the equation x^4/y=7 is (b) x^4 varies directly as y

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Answer:

y = 3x + 5

Step-by-step explanation:

x = number of years

• bush grows 3cm per year

• the initial height is 5cm

3cm per year times x number of years: y = 3x

Add the initial height of 5cm: y = 3x + 5

The expressions for the length and the width of the rectangular garden are 3x + 2 feet, and x + 5 feet respectively where x is the length of the square patch for tomatoes.

A square is a quadrilateral with all four sides equal, and all four angles at 90°, whereas a rectangle is a quadrilateral with opposite pair of sides equal, and all four angles at 90°.

In the question, we are informed that Melissa is planning a rectangular vegetable garden with a square patch for tomatoes.

The side of the square is given to be x feet.

We are asked to write expressions for the length and width of the rectangular garden.

For the length of the rectangle:-

We are informed that she wants the length of the garden to exceed three times the length of the tomato patch by 2 feet.

Thus, the length of the garden can be shown as the expression 3x + 2 feet.

For the width of the rectangle:-

We are informed that she also wants the garden's width to exceed the width of the tomato patch by 5 feet.

Thus, the width of the garden can be shown as the expression x + 5 feet.

Thus, the expressions for the length and the width of the rectangular garden are 3x + 2 feet, and x + 5 feet respectively where x is the length of the square patch for tomatoes.

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The provided question is incomplete. The complete question is:

"Melissa is planning a rectangular vegetable garden with a square patch for tomatoes. She wants the length of the garden to exceed three times the length of the tomato patch by 2 feet. She also wants the garden's width to exceed the width of the tomato patch by 5 feet.

Let x represent the length, in feet, of the square tomato patch.

Write expressions to represent the length and width of Melissa's vegetable garden in terms of x.

Enter the correct answer in the box."

1) [tex]\overline{JK} \perp \overline{MN}[/tex]

2) [tex]\angle JKM[/tex] is a right angle (perpendicular lines form right angles)

3) [tex]\triangle JKM[/tex] is a right triangle (definition of a right triangle)

4) [tex]\angle 1[/tex] and [tex]\angle 2[/tex] are complementary (the acute angles of a right triangle are complementary)