PLEASE HELP!!!!!!!!!!!!!!!

The measure of the other two angles are 88 degrees and 22 degrees.

Let's call the two unknown angles x and y. Since the sum of all angles in a triangle is 180 degrees, we have:

x + y + 70 = 180

We also know that the ratio of the two angles is 4:7. We can set up a proportion to express this relationship:

x/y = 4/7

We can cross-multiply to get:

7x = 4y

We can substitute this equation into the first equation to eliminate one of the variables.

7x + y + 70 = 180

Now we have:

7x + y = 110

We can use the second equation to eliminate x:

7(4y/7) + y = 110

4y + y = 110

5y = 110

y = 22

Now that we know one of the angles is 22 we can substitute it back in the first equation

x+22+70 = 180

x = 88

Therefore, the measures of the other two angles are 88 and 22 degrees

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Answer: C. Equilateral

Step-by-step explanation:

Answer: option C is correct. two angle measures of an equilateral triangle is 60°

Step-by-step explanation: All the sides of an equilateral triangle are of equal lengths—each interior angle of this triangle measures 60°.

A A flavor of ice cream is selected at random; A topping for the ice cream is selected at random. This is B. dependent events.

Events that are dependent upon prior events are called dependent events. The results of earlier events have an impact on these current ones. For example, two or more events that are interdependent are referred to as dependent events.

If one event is accidentally altered, another is probably going to be different.

If two events are interdependent, then the result of the first event will influence the result of the second even more.

The ice cream in this case represented dependent event.

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Options A and B are the correct answers.

The exponent or power to which a base must be raised to yield a given number is called a logarithm.

x is the logarithm of n to the base b if bx = n, in which case one writes

x = logb n.

“The logarithm of a positive real number a with respect to base b, and a positive real number not equal to 1^[nb 1], is the exponent by which b must be raised to yield a”.

b^y=a ⇔logba=y

To calculate the value of log₁₂81 we use the formula of

log ab=logb/loga=ln b/ln a

log₁₂81=log₁₀81/log₁₀12

           =log81/log12

Also, log e81=loge81/loge12

                    =ln81/ln12

So, choose log81/log12 and ln81/ln12

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Answer:

see photo, they change out answer order to look close.  :-)

Step-by-step explanation:

Plato/Edmentum

Answer:

No, it is not possible to have a triangle with sides of 2cm, 2cm, and 5cm. This is because a triangle's sides must adhere to the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. In this case, 2cm + 2cm (4cm) is not greater than 5cm, so it is not possible to form a triangle with these side lengths.

Step-by-step explanation:

Answer:

Yes u can

Step-by-step explanation:

U can create a triangle with that because 2+2 is 4 which is less than 5 meaning it would work as a triangle

Answer:

There are 100 centimeters in 1 meter, so Maria'e height in meters would be:

1 meter and 36 centimeters, tall.

Step-by-step explanation:

Hope it helps! =D

A prime number is a natural number greater than 1 that is not a product of two smaller natural numbers. A prime number can only be divided evenly by 1 and itself.

To find the multiples of a prime number, you can use the following steps:

For example, if the prime number is 5, the multiples of 5 are 5, 10, 15, 20, 25, and so on.

It's important to note that a prime number only has two divisors: 1 and itself. This means that a multiple of a prime number will never be a prime number.

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Answer:

Yes, they do because -3+4=1 and -1+12=11

Step-by-step explanation:

Hope it helps!

Answer: If you mean + then, 12

Step-by-step explanation:

-3 + 4 = 1     -1 + 1 = 0      0 + 12 = 12

The homogeneous equation and a particular solution of the given nonhomogeneous equation is [tex]& y=c_1 e^{-2 x}+c_2 e^{2 x}-\frac{1}{2}[/tex].

The given nonhomogeneous equation is y" - 4y = 2

We are given [tex]$y_1=e^{-2 x}$[/tex]

Let [tex]$y_2=u y_1$[/tex]

Non-homogeneous differential equations are simply differential equations that do not satisfy the conditions for homogeneous equations. In the past, we’ve learned that homogeneous equations are equations that have zero on the right-hand side of the equation.

The two most common methods when finding the particular solution of a non-homogeneous differential equation are:

[tex]$$\begin{aligned}& y_2=u e^{-2 x} \\& y_2^{\prime}=u^{\prime} e^{-2 x}-2 u e^{-2 x} \\& y_2^{\prime \prime}=u^{\prime \prime} e^{-2 x}-2 u^{\prime} e^{-2 x}-2 u^{\prime} e^{-2 x}+4 u e^{-2 x} \\& y_2^{\prime \prime}=u^{\prime \prime} e^{-2 x}-4 u^{\prime} e^{-2 x}+4 u e^{-2 x}\end{aligned}$$[/tex]

Substitute in [tex]$y^{\prime \prime}-4 y=0$[/tex], we get

[tex]$$\begin{aligned}& u^{\prime \prime} e^{-2 x}-4 u^{\prime} e^{-2 x}+4 u e^{-2 x}-4 u e^{-2 x}=0 \\& u^{\prime \prime} e^{-2 x}-4 u^{\prime} e^{-2 x}=0 \\& e^{-2 x}\left(u^{\prime \prime}-4 u^{\prime}\right)=0 \\& u^{\prime \prime}-4 u^{\prime}=0 \\& u^{\prime \prime}=4 u^{\prime}\end{aligned}$$[/tex]

Substitute [tex]$$u^{\prime}=v$ and $u^{\prime \prime}=v^{\prime}$[/tex], we get

[tex]$$\begin{aligned}& v^{\prime}=4 v \\& \frac{d v}{d x}=4 v \\& \frac{1}{v} d v=4 d x\end{aligned}$$[/tex]

Integrate both sides, we get

[tex]$u=\frac{1}{4} C_1 e^{4 x}+C_2$$[/tex]

put in [tex]$y_2=u y_1$[/tex]

[tex]$$y_2=\left(\frac{1}{4} C_1 e^{4 x}+C_2\right) e^{-2 x}$$[/tex]

Choose [tex]$$C_1=4$ and $C_2=0$[/tex], we get

[tex]$$y_2=e^{2 x}$$[/tex]

[tex]$$\begin{aligned}& y_c=c_1 y_1+c_2 y_2 \\& y_c=c_1 e^{-2 x}+c_2 e^{2 x}\end{aligned}$$[/tex]

Particular Solution

[tex]$$\begin{aligned}& y_y=A \\& y_y{ }^{\prime}=0 \\& y_y{ }^{\prime \prime}=0\end{aligned}$$[/tex]

Substitute in [tex]$y^{\prime \prime}-4 y=2$[/tex], we get

[tex]$$\begin{aligned}& 0-4 A=2 \\& -4 A=2 \\& A=-\frac{1}{2} \\& \therefore y_y=-\frac{1}{2}\end{aligned}$$[/tex]

General Solution

[tex]$$\begin{aligned}& y=y_6+y_y \\& y=c_1 e^{-2 x}+c_2 e^{2 x}-\frac{1}{2}\end{aligned}$$[/tex]

Therefore, the second equation is [tex]& y_{2} =c_1 e^{-2 x}+c_2 e^{2 x}-\frac{1}{2}[/tex].

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Can you please copy and paste it here?
-
I cannot read it clearly.

Answer:

1.5 or greater than 1.5

Step-by-step explanation:

First, we need to determine the total score of your opponent's dive:

40.8 points / 2.4 (degree of difficulty) = 17 (total score)

Now, we know that your total score needs to be greater than 17, and the scores awarded by the three judges are added together.

To calculate the scores from the third judge, we can use the following equation:

(Total score) - (score from judge 1) - (score from judge 2) = (score from judge 3)

Let's assume that you received scores of 8 and 7.5 from the first two judges.

We can plug in the values into the equation:

(Total score) - (8) - (7.5) = (score from judge 3)

We know that your total score needs to be greater than 17, so we have to find the score from the third judge, that when added to the scores 8 and 7.5, gives a total score greater than 17

17 - 8 - 7.5 = 1.5

The score from the third judge should be 1.5 or greater than 1.5 in order to give you more points than your opponent.

Gametes carry half the genetic information of an individual, one ploidy of each type, and are created through meiosis, in which a germ cell undergoes two fissions, resulting in the production of four gametes.

Mendel's Law I has another name, namely the Law of Segregation. In the Law of Segregation it states that "In the formation of gametes (sex cells) in the two genes which are partners, will be separated in two daughter cells". Mendel's Law I or the Law of Segregation applies to monohybrid crosses, aka crosses with one different trait.

Mendel's First Law also states that two alleles (gene variants) that regulate certain traits will separate in two different gametes (sex cells). Mendel's Law I includes several things, namely:

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The rate of change of the area of the right triangle at that instant is -1.5 sq km/h.

Make ABC a right triangle with a right angle to B.

BC = x on the side decreasing be

with AB = y being the rising side.

After that, AC = z = (x² + y2) (using Pythagoras theorem)

Given that dx/dt is equal to -5 km/h and dy/dt is equal to 14 km/h

When x = 3 and y = 9, respectively.

currently, the triangle's area equals xy/1/2.

A = 1/2 xy

dA/dt = 1/2 (y) (y).

dy/dt = dx/dt + x/2.

by inserting the values at x = 3 and y = 9,

(dA/dt) = 1/2 (9)(-5) + 3/2 (14) (14)

= -1.5

As a result, the right triangle's area is changing at a rate of -1.5 sq km/h at the moment when x=3 and y=9.

Your question is incomplete but most probably your full question was

One leg of a right triengle is decreasing at a tate of 5 kilometers per hour and the other leg of the triangle is increasing at a rete of 14 kilometers per hour. Ara certain anstant the decreasing leg is 3 kilometers and the increasing leg is 9 kilometers. What is the rate of change of the area of the right triangle at that instant (in square kilometers per hour)? 11 e 111 01.5 -1.5 Stuck?

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The correct statement regarding the scatter plot is given as follows:

C. There were three athletes who had the same time in both races.

The scatter plot is built inserting all the points of the table in a graph, which are in the following input-output format:

(Input, Output).

The input and output variables for this problem are given as follows:

The points are given as follows:

(15, 15), (16, 15), (17, 15), (19, 15), (16, 16), (17, 16), (18, 16), (19, 16), (18, 18), (17, 19)

For example, the point (16, 15) means that the person took 16 seconds for the first race and 15 seconds for the second race.

Hence statement C is correct, as the points (15,15), (16, 16) and (18,18) means that there were three athletes who had the same time in both races.

The scatter plot is given by the image presented at the end of the answer.

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The length of u is 56.60 inches. The nearest inches it is 57 inch

What is a triangle?

A triangle is a three-edged polygon with three vertices. It is a fundamental shape in geometry. Triangle ABC denotes a triangle with vertices A, B, and C. In Euclidean geometry, any three non-collinear points define a unique triangle and, by extension, a unique plane.

Given that ΔTUV is a triangle with m∠T=99° and m∠U=53°.

The length of t is 70 inches.

The opposite side of ∠T is t, the opposite side of ∠U is u, and the opposite side of ∠V is v.

Sine rule of ΔABC:

a/sin A = b/sin B = c/sin C

Apply sine law in  ΔTUV:

t/sin T = u/sin U = v/sin V

Putting ∠T=99°, ∠U=53°, and t = 70.

70/ sin 99° = u/sin 53°

u = (70sin 53°)/ sin 99°

u =  56.60 inches

The digit after the decimal point is greater than 5, thus add 1 with the 56 to get the nearest inch.

u = 57 inches

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Answer:

2

Step-by-step explanation:

The rule is multiplying by 2 every time

-2 times 2 is -4

0 times 2 is 0

2 times 2 is 4

Answer:

------------------------

Given system:

Rewrite equations to bring to slope-intercept form:

Plot each line and find the intersection, this is the solution.

The solution is (2, 4) as per attached graph.

The four parts of a polygon are: sides, vertices, diagonals, and interior angles.

Polygon is a closed figure in a plane made of of straight line or curved line that insert in pairs a polygon has at least three side of angle the height can be of any length and the angle can be of any measure polygon or classified according to the number of side they have such as triangle.

A polygon is a closed, two-dimensional shape with three or more straight sides. The four parts of a polygon are: sides, vertices, diagonals, and interior angles. The sides are the straight line segments that make up the shape. The vertices are the points where the sides meet. The diagonals are line segments joining any two non-adjacent vertices. The interior angles are the angles inside the polygon, which are determined by the number of sides the polygon has.

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Answer:

"A) 12n + 14m + 4" would be the standard form.

Step-by-step explanation:

the expression written correctly in standard form would be "A) 12n + 14m + 4"

10m + 3(n + 8) + 4(m - 5) + 9n you need to first clear the parenthesis by applying distributive property:

10m + 3(n + 8) + 4(m - 5) + 9n = 10m + 3n + 24 + 4m - 20 + 9n

After that you combine like terms

= 10m + 4m + 3n + 9n + 24 - 20 = 14m + 12n + 4

"A) 12n + 14m + 4" would be the standard form.

(3,1) is not the solution of the equation 3x + 6y = 12. So the option D is correct.

In the given question, we have to check which of the following is not the solution of 3x+6y=12.

To check which is not the solution of the given equation, we put the value of x and y from the given point. If for any point the condition is true then that point is the solution of the given equation. If that point doesn't satisfy the condition then that point is not the solution of the given equation.

The given equation is 3x+6y=12.

Firstly we check for the point (-4,4), where x = -4, y = 4

3(-4) + 6(4) = 12

-12 + 24 = 12

12 = 12(True)

Now we check for the point (0,2), where x = 0, y = 2

3(0) + 6(2) = 12

0 + 12 = 12

12 = 12(True)

Now we check for the point (8,-2), where x = 8, y = -2

3(8) + 6(-2) = 12

24 - 12 = 12

12 = 12(True)

Now we check for the point (3,1), where x = 3, y = 1

3(3) + 6(1) = 12

9 + 6 = 12

15 = 12(False)

Hence, (3,1) is not the solution of the equation 3x + 6y = 12. So the option D is correct.

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The expressions that have a sum or difference equal to 3/4 are:

The correct options are B, C, and E

Sum mean the addition of numbers or expression

Difference means the subtraction of numbers or expressions.

The sum or difference of the number are as given below:

a. 1/2 + 2/4 = 4/4

b. 11/12 - 1/6 = (11 - 2) / 12

11/12 - 1/6 = 9/12

9/12 = 3/4

c. 3/5 + 3/20 = (12 + 3)/20

3/5 + 3/20 = 15/20

15/20 = 3/4

d. 7/8 - 1/2 = (7 - 4)/8

(7 - 4)/8 = 3/8

e. 2/3 + 1/12 = (8 + 1)/12

(8 + 1)/12 = 9/12

9/12 = 3/4

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Answer:72

Step-by-step explanation:

8x9=72

2x36= 72

12x6=72

Answer:

the second option

Step-by-step explanation:

y=mx+c

therefore y=10x+20

20 is the y intercept, 10 is the gradient

Answer:

1.  7[tex]\frac{1}{2}[/tex] = [tex]\sqrt{7}[/tex]

2. 4[tex]\frac{7}{2}[/tex] = [tex]\sqrt{4} x^{7}[/tex]

3. 7[tex]\frac{1}{4}[/tex] = [tex]\sqrt[4]{7}[/tex]

4. 4[tex]\frac{1}{7}[/tex] = [tex]\sqrt[7]{4}[/tex]

Step-by-step explanation: