please help me !! find the missing side and round to the nearest tenth !!

Please Help Me !! Find The Missing Side And Round To The Nearest Tenth !!

Answers

Answer 1
The answer is 22.8
Cos 64 = adj./hypotenuse
Cos64=10/x
X(cos64)=10
X= 10/cos64
= 22.8
Answer 2
please look at the photo above, and please give thanks.

hence: x = 22.8
Please Help Me !! Find The Missing Side And Round To The Nearest Tenth !!

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You know when you drop a plate and it shatters?, and if you say sorry to the plate it wont be one whole plate again... now replace that plate with someones heart. A "sorry" doesnt make a shattered heart a whole heart again.

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At 12:45 Jimmy left his home in Pinetrees and cycled to visit his grandmother in Oakville. On his
way he stopped for 10 minutes in Rowan for a coffee and then he popped in to see his friend in
Yewton. He arrived in Oakville at 16:25. Jimmy cycled at a steady speed of 24 km/h and his
average speed for the whole journey, including the stops, was 18 km/h.
For how long did Jimmy stop in Yewton?
А
40 minutes
B
45 minutes
C
55 minutes
D
60 minutes

Answers


t=45min
d=4km

45min/60min = 0.75 hours

v=d/t
v=4km/0.75hours
v=5.33km/hour. So the answer is B. 45 minutes.

Jimmy stopped in Yewton for 45 minutes if Jimmy cycled at a steady speed of 24 km/h and his average speed for the whole journey, including the stops, was 18 km/h.

What is the distance?

Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.

It is given that:

At 12:45 Jimmy left his home in Pinetrees and cycled to visit his grandmother in Oakville.

Let x be the total time Jimmy stops in Yewton:

Total time for the journey = 220 minutes (12:45 to 16:25)

As we know:

distance = speed×time

24(220 - 10 - x) = 18(220)

220 - 10 - x = 165

x = 210 - 165

x = 45 minutes

Thus, Jimmy stop in Yewton for 45 minutes if Jimmy cycled at a steady speed of 24 km/h and his average speed for the whole journey, including the stops, was 18 km/h.

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Step-by-step explanation:

Round 1231.50432 to the nearest tenth

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

(×+6)^2 + (y -7 ) ^2=81

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Step-by-step explanation:

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Answer:

2/3

Step-by-step explanation:

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Answer:

B

Step-by-step explanation:

Answer:

B

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Answers

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Exact Form:

4

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Decimal Form:

16.49242250

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Multiplicacion de 3 Dube.com Dube
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Step-by-step explanation:

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Answers

Answer:

A circle of radius = 12 or diameter = 24 or circumference = 75.4 cm has an area of: 4.524 × 10-8 square kilometers (km²)

The area of the circular region will be 113 square centimeters.

What is an area?

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

The formula to calculate the area of the circle is given by:-

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Given that the diameter of the circular region is 12 centimeters. The radius will be half of the diameter.

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The area of the region will be calculated as below:-

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Therefore, the area of the circular region will be 113 square centimeters.

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Step-by-step explanation:

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Answer: See explanation (btw, the answer is always in bold letters)

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Write your answer using integers, proper fractions, and improper fractions in simplest form.

Answers

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Answer:

A.    

   

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Step-by-step explanation:

Answer:

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Answer:

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have a nice day bye ^_^

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Step-by-step explanation:

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Answer:

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Answer:

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any genious help please ​

Answers

Rewrite the limand as

(1 - sin(x)) / cot²(x) = (1 - sin(x)) / (cos²(x) / sin²(x))

… = ((1 - sin(x)) sin²(x)) / cos²(x)

Recall the Pythagorean identity,

sin²(x) + cos²(x) = 1

Then

(1 - sin(x)) / cot²(x) = ((1 - sin(x)) sin²(x)) / (1 - sin²(x))

Factorize the denominator; it's a difference of squares, so

1 - sin²(x) = (1 - sin(x)) (1 + sin(x))

Cancel the common factor of 1 - sin(x) in the numerator and denominator:

(1 - sin(x)) / cot²(x) = sin²(x) / (1 + sin(x))

Now the limand is continuous at x = π/2, so

[tex]\displaystyle\lim_{x\to\frac\pi2}\frac{1-\sin(x)}{\cot^2(x)}=\lim_{x\to\frac\pi2}\frac{\sin^2(x)}{1+\sin(x)}=\frac{\sin^2\left(\frac\pi2\right)}{1+\sin\left(\frac\pi2\right)}=\boxed{\frac12}[/tex]

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