Explanation:
Q = energy applied
m = mass
C = specific heat
ΔT = delta T = change in temperature
anyone know the answer ?
Yes. Many people either know the answer, or can figure it out using the information in the picture.
A 7.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball. How fast does the ball need to be moving in order to send the man off at a speed of 3.00 m/s?
Answer:
35.14 m/s
Explanation:
The Law of Conservation of Momentum states that the momentum before and after a collision is the same.
m₁ v₁ + m₂ v₂ = m₁ v₁ + m₂ v₂Let's set the ball to have the subscript of 1 and the man to have the subscript of 2.
The initial and final mass of the ball is the same, so m₁ = 7.00 kg on both sides of the equation.
The initial velocity of the ball, v₁ on the left side of the equation, is the unknown variable we are trying to find.
The initial and final mass of the man is the same, so m₂ = 75.0 kg on both sides of the equation.
The man starts at rest, meaning that his initial velocity is v₂ = 0 m/s on the left side of the equation.
The final velocity of both the ball and the man is 3.00 m/s, so we can set v₁ and v₂ on the right side of the equation to equal 3.00 m/s.
Left side of the equation:
m₁ = 7.00 kg v₁ = ?m₂ = 75.0 kgv₂ = 0 m/sRight side of the equation:
m₁ = 7.00 kg v₁ = 3.00 m/sm₂ = 75.0 kgv₂ = 3.00 m/sSubstitute these values into the Law of Conversation of Momentum formula.
(7.00) v₁ + (75.0)(0) = (7.00)(3.00) + (75.0)(3.00)Multiply and simplify.
7.00 v₁ = 21 + 225 7 v₁ = 246Divide both sides of the equation by 7.
v₁ = 35.14 m/sThe ball needs to be moving at a speed of 35.14 m/s in order to send the man off at a speed of 3.00 m/s.
What is the best example of a compound machine A ax. B ramp. C car D screw
Answer: I believe the answer is C
Explanation:
Cars are composed of hundreds of simple machines
CaN i GeT sUm HeLpPpP
Answer:
perhaps remote learning, which is a form of remote observation. Hope that it helps.
While an object is moving at a constant 20 m/s, a 5 N forcepushes the object to the left. At the same time, a 5 N force ispushing the object to the right. What will the object'svelocity be after 10 seconds?
Answer: 20m/s.
Explanation:
Remember the second Newton's law:
F = a*m
This is:
The net force acting on an object is equal to the mass of the object times the acceleration of the object.
In this case, we have a force of 5N pushing the object to the right.
We also have a force of 5N pushing the object to the left.
These forces act on opposite directions.
Then the net force will be equal to the difference of these forces, this is:
F = 5N - 5N = 0N
Then the net force is 0N, then we have:
0N = m*a
0N/m = 0m/s^2 = a
This means that the acceleration of the object is 0, then the velocity of the object does not change.
This means that if the object was moving at a constant velocity of 20m/s, the velocity of the object will still be equal to 20m/s. (because the net force acting on the object is zero)
Two spherical shells have a common center. A -1.50 × 10-6 C charge is spread uniformly over the inner shell, which has a radius of 0.050 m. A +4.50 × 10-6 C charge is spread uniformly over the outer shell, which has a radius of 0.15 m.Find the magnitude and direction of the electric field at a distance (measured from the common center) of______________.
a: 0.20m
b: 0.10m
c: 0.025m
Answer:
a) At 0.20 m, the magnitude of the field is 675.0 kV
The direction of the field is acting outwards from the center of the charged spheres
b) At 0.10 m, the magnitude of the field is 135 kV
The direction is acting outwards from the center of the charged spheres
c) At 0.025 m
The magnitude of the field, V = -270.0 kV
The direction of the field is inwards, towards the center of the charged spheres
Explanation:
The charged spherical shell parameters are;
The charge on the inner sphere, q₁ = -1.50 × 10⁻⁶ C
The radius of the inner shell, R₁ = 0.050 m
The charge on the outer sphere, q₂ = +4.50 × 10⁻⁶ C
The radius of the outer shell, R₂ = 0.15 m
Let 'r', represent the distance at which the electric field is measured, the following relationships can be obtained;
When r < R₁ < R₂,
[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]
When R₁ < r < R₂,
[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]
When R₁ < R₂ < r,
[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]
a) When r = 0.20 m, we have;
R₁ < R₂ < r, therefore
[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]
By plugging in the values, we get;
[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} + 4.50\times 10^{-6} }{0.20^2} \right ) = 675.0 \ kV[/tex]
Therefore, the magnitude of the field, V = 675.0 kV
The direction of the field is outwards
b) When r = 0.10 m, we have;
When R₁ < r < R₂, therefore;
[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]
By plugging in the values, we get;
[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.10} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = 135 \ kV[/tex]
Therefore, the magnitude of the field, V = 135 kV
The direction of the field is outwards from the center
c) When r = 0.025 m, we have;
When r < R₁ < R₂, therefore;
[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]
By plugging in the values, we get;
[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.05} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = -270 \ kV[/tex]
Therefore, the magnitude of the field, V = -270.0 kV
The direction of the field is inwards, towards the center of the charged spheres.
The momentum of a 3000 kg truck is 6.36 x 104 kg·m/s. At what speed is the truck traveling? m/s
472
19,080
2.1
21.2
19.6
24.5
Answer:
21.2m/s
Explanation
Given data
P=6.36 x 10⁴kg·m/s.
M=3000kg
From the momentum expression
P=mv
v=p/m
Substitute
v=63600/3000
v=21.2m/s
Hence the Velocity is 21.2m/s
The speed of the truck is 21.2 m /s
Momentum is the product of the mass of the object and the velocity of the object. Therefore,
p = mv
where
m = mass
v = velocity
m = 3000 kg
p = 6.36 x 104 kg·m/s.
lets find the velocity
6.36 x 10⁴ = 3000 × v
v = 6.36 x 10⁴ / 3000
v = 21.2 m / s
The speed of the truck is 21.2 m /s
read more; https://brainly.com/question/18558072?referrer=searchResults
How would the force between two charged particles change if one of the charges were to triple in strength (3x stronger)?
A. 9x stronger
B. 1/3 as strong
C. 1/9 as strong
D. 3x stronger
Answer:
The correct option is (d). "3x stronger".
Explanation:
The force between two charged particle is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
If one charge is tripled, [tex]q_1'=3q[/tex]
New force will be :
[tex]F'=\dfrac{kq_1'q_2}{r^2}\\\\=3\times F[/tex]
It means if one of the charges were to triple in strength, then the force will become 3 times of the initial force.
can someone help me please
Explain how smoking damages the respiratory system and name two conditions that can develop when a person smokes. ribe the location and importance of cilia and mucus in the respiratory system.
Answer:
Smoking damages the respiratory system by irritating the trachea and larynx due to the toxic chemicals and by causing swelling and narrowing of the airways and excess mucus in the lung passages. Two conditions that can develop when a person smokes is breathlessness and reduced lung function.
Explanation:
Smoking causes damages to the respiratory system by narrowing the airways and filling an excess of mucus in the lungs. It is a bad habit that may cause emphysema and chronic bronchitis.
Cigarettes contain more than 500 chemical substances in addition to nicotine, an addictive substance found in tobacco.
Cilia are hair-like projections localized in the airways that act to eliminate mucus and foreign (potentially harmful) matter.
The toxic compounds contained in cigarettes can paralyze the cilia in the airways and destroy them.
Smoking may produce:
The irritation and inflammation of the components of the respiratory system (e.g., trachea, larynx, lungs, etc)BreathlessnessExcess of mucous secretion in the lungs.Irreversible damage in the small air sacs of the lungs.In consequence, smoking is associated with chronic obstructive pulmonary diseases, including chronic bronchitis or emphysema.
In conclusion, smoking causes damages to the respiratory system by narrowing the airways and filling an excess of mucus in the lungs. It is a bad habit that may cause emphysema and chronic bronchitis.
Learn more in:
https://brainly.com/question/1193094?referrer=searchResults
Suppose the moon rotated on its axis just as quickly as Earth. Would we still always see the same side of the moon from Earth?
Answer:
No, The Moon, on the other hand, rotates once around its every 28 days, and once around the Earth in that same 28 days. The result of this combination is that the same side of the Moon is always facing the Earth.
What equation/formula would you use to find the amount of time an object traveled? Use the triangle
a.Time = d/t
b.Time = d/s
c.time = d x t
Answer:
d/s
Explanation:
speed = distance / time
speed × time = distance
time = distance / speed = d/s
What reasoning correctly pairs a body system with its relationship to the digestive system?
Group of answer choices
excretory system; transports nutrients from the small intestine to other tissues
respiratory system; obtains oxygen so the energy in nutrients can be extracted
circulatory system; regulates and controls digestive functioning
nervous system; removes wastes from the blood SCIENCE
Answer:
I Believe the Correct Answer is respiratory system; obtains oxygen so the energy in nutrients can be extracted.
Explanation:
Respiratory System is made for oxygen and involves the Lungs Diaphragm etc.
Please give me Brainliest!
Is this acceleration away, acceleration back , constant speed back, constant speed away, constant speed (or velocity), or constant negative acceleration (decreasing speed or velocity ) at a constant rate?
Answer:
ya daddy is my zaddy
Explanation:
3V battery is used with a 15 ohm resistance.What is the current?
Answer:
0.2 A
Explanation:
V= IR
3 = I × 15
I = 3/15
= 1/5 = 0.2 A
The flow of current in a battery will be "0.2 A". To understand the calculation, check below.
Current, Resistance and VoltageAccording to the question,
Voltage, V = 3 V
Resistance, R = 15 ohm
We know the relation,
→ Voltage (V) = Current (I) × Resistance (R)
or,
→ Current, I = [tex]\frac{V}{R}[/tex]
By substituting the values,
= [tex]\frac{3}{15}[/tex]
= 0.2 A
Thus the above answer is correct.
Find out more information about current here:
https://brainly.com/question/1176850
Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.
Answer:
the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position x= l/3
Explanation:
The forces in this system are given by Coulomb's law
F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]
As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .
Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge
Let's find the location of charge 3 so that it is in balance
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we seek every force
F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]
F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]
the distances are
x₁₃ = x-0 = x
x₂₃ = l -x
we substitute
k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}
we solve
(l-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
l² - 2lx + x² = \frac{4q}{q} x²
3x² + 2l x - l² = 0
we solve the quadratic equation
x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)
x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6
x₁ = -l
x₂ = l / 3
as charge 3 must be between the two charges the correct answer is
x = l / 3
with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.
now let's analyze the force on the other charges
charge 1 so that it is in balance
∑F = F₁₃ - F₁₂ = 0
F₁₃ = F₁₂
[tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]
l² q₃ = q₂ (l/3)²
q₃ = q₂ / 9
q₃ = 4q / 9
q₃ = [tex]\frac{4}{9} q[/tex]
in summary the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q
in the position x= l/3
Which of the following terms corresponds to #2 on the image?
Answer:
Trough
Explanation:
cuz physics you see
if an object can make 10 revolutions in a minute, what's is period
Answer:
Period = 6 seconds.
Explanation:
Given the following data;
Number of oscillation, n = 10
Time = 1 minute to seconds = 60 seconds
To find the period;
A period is the number of revolutions in a minute.
[tex] Period = \frac {time}{number \; of \; oscillations}[/tex]
Substituting into the equation, we have;
[tex] Period = \frac {60}{10}[/tex]
Period = 6 seconds.
A student is preparing to take a bath when she realizes the hot water tap in the bathroom is not working the student go to the kitchen and prepares 10 of 100°C water to mix with 10 L of 10°C water
Answer:
The final temperature of the bath water will be 55°C
Explanation:
A student is preparing to take a bath when she realizes that the hot water tap is not working.
The student goes to the kitchen and prepares 10 L of 100 degree Celsius water to mix with 10 L of 10 degree Celsius water. What will be the final temperature of the bath water?
Using the relation, Heat lost = Heat gained (assuming no heat is lost to the surroundings).
Heat lost by hot water = heat gained by cold water
Using the formula of heat, Q = mcΔT
where m = mass of water, c = specific heat capacity of water, ΔT = temperature difference
mass of water = density * volume (density of water = 1 kg/L)
mass of hot water, m₁ = 1 kg/L * 10 L = 10 kg;
mass of cold water, m₂ = 1 kg/L * 10 L = 10 kg;
specific heat capacity of water, c = 4200 j/kg
Let the final temperature of the mixture be T
-m₁cΔT₁ = m₂cΔT₂ ( since heat is lost by the hot water)
-m₁ΔT₁ = m₂ΔT₂
-10 * (T- 100) = 10 * (T - 10)
-10T + 1000 = 10T - 100
20T = 1100
T = 1100/20
T = 55°C
Therefore, the final temperature of the bath water will be 55°C
Epidemiologists sometimes us computers and artificial intelligence (AI) to help them analyze data. Why would this be helpful?
A gas has an initial volume of 24.6 L at a pressure of 1.90 atm and a temperature of 335 K. The pressure of the gas increases to 3.50 atm, and the volume of the gas increases to 31.3 L. What is the final temperature of the gas? 143 K 231 K 485 K 785 K
Answer:
the final temperature of the gas is 785.18 K
Explanation:
The computation of the final temperature of the gas is shown below:
Here we apply the gas law
= PV ÷ T
Given that
P1 = 1.9 atm
V1 = 24.6 L
T1 = 335 K
P2 = 3.5 atm
V2 = 31.3 L
T2 = ?
Now
P1V1 ÷ T1 = P2V2 ÷ T2
(1.9 × 24.6) ÷ 335 = (3.5 × 31.3)/T2
T2 = 785.18 K
hence, the final temperature of the gas is 785.18 K
Answer: D
Explanation: edge
pls qmp
What is the purpose of the lab, the importance of the topic, and the question you are trying to answer?
Energy
Answer: I put the importance of the lab in the topic is to find how dense an object is and if it can sink or float and it's important to answer the question so you can also find mass and volume.
Explanation: I dunno haha...
what is the momentum of a 1550kg car that is traveling 38.0 m/s?
Answer:
p = 58,900 kg m/s
Explanation:
p = m × v
p = 1,550 × 38.0
p = 58,900 kg m/s
neon has 10 electrons, 2 in the inner level and 8 in it's outermost level. how many valence electrons do neon atoms have?
Answer:
It's very simple- 8 valence electrons
Answer:
it's 8
Explanation:
that the answer for the question
OK so big sich. here so #relationships #BFGF
W. T. F does roly polying someone mean
Someone told me it means in a relationship that its when someone is dating someone but they find someone they also like but not fully dating them so its not 100% cheating so W T F DOES IT MEAN
Answer:
I have know idea what that means lol.
Thanks for the free points. Hope you have a fantastic rest of your life!
why does a bowling ball and a father fall at the same speed while in a vacuum?
PLZ NEED HELP
Answer:
there is no drag in a vacuum (why is father in a vaccum)
Explanation:
there is nothing to hit and slow the object other than gravity like dust or air
Need help please !!!! Hurry
Answer:
4
Explanation:
Waves that are squished have higher frequency. It has short wavelength.
Answer:
4
Explanation:
frequency and wavelength are inverses, so since this has the smallest wavelength it has the highest frequency. The smaller the wavelength, the more waves (more/high frequency) fit in a certain area in comparison to larger wavelengths fit fewer waves (less frequent).
Rae has just heard a loud crash from her garage. The impact of the sound wave bouncing against her eardrum sets off a chain reaction through the three tiny bones in the middle ear, called the:
Answer:
Hammer
Anvil
Stirrup
Explanation:
The three tiny bones in the ear drum are:
Hammer, this is also known as malleus and it is attached to the eardrum
Anvil, this is also called incus and it found with the chain of bones in the middle ear.
Stirrup, also known as stapes and it attached to the membrane covered opening that connects the middle ear with the inner ear.
A solid wooden cube, 30cm on each side can be totally submerged in water if it is pushed downward with a force of 54N. What is the density of the wood?
Answer:
the density of the wooden cube is 204.1 kg/m³
Explanation:
Given;
applied force, F = 54 N
length of each side of the solid wooden cube, L = 30 cm = 0.3 m
mass of the wooden cube is calculated as;
F = mg
m = F/g
m = 54/9.8
m = 5.51 kg
The volume of the wooden cube is calculated as;
V = L³
V = (0.3)³
V = 0.027 m³
The density of the wooden cube is calculated as;
ρ = m/V
ρ = (5.51 kg) / (0.027 m³)
ρ = 204.1 kg/m³
Therefore, the density of the wooden cube is 204.1 kg/m³
Describa con sus palabras que fue lo que descubrio galileo en su legendario experimento en la torre inclinada de pisa
Answer:
En 1589 Galileo realizó un experimento lanzando dos bolas de diferentes masas desde la famosa Torre Inclinada de Pisa para demostrar que el tiempo de caída es independiente de la masa de la bola. A través de este experimento, Galileo descubrió que los cuerpos caían casi simultáneamente, refutando la teoría de Aristóteles de que la tasa de caída era proporcional a la masa del cuerpo.
Debido a la imperfección de los equipo de medición de esa época, la caída libre de los cuerpos era casi imposible de estudiar. En busca de una forma de reducir la velocidad de movimiento, Galileo reemplazó la caída libre por rodar sobre una superficie inclinada, donde había velocidades y resistencia del aire significativamente más bajas. Se notó que con el tiempo, la velocidad del movimiento aumenta: los cuerpos se mueven con aceleración. Se concluyó que la velocidad y la aceleración no dependen ni de la masa ni del material de la pelota.