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according to the ____ rule, elements tend to react until they have the same electron configuration as a _____. _____, found on the left of the _____, tend to lose electrons and from ____. _____ tend gain electrons to form _____.

Answer:

correct answer is sodium

Explanation:

element is most active in this question is sodium please make me Brilliant to this correct answer

The stoichiometric coefficient in front of the oxygen ([tex]O_{2}[/tex]) in the balanced version of the reaction will be 6.

The number that must be present before the atoms, molecules, or ions is known as the stoichiometric coefficient. Fractions, as well as whole numbers, can be used as stoichiometric coefficients. Essentially, the coefficients assist us in determining the mole ratio of reactants to products.

The balanced chemical reaction will be

[tex]C_{4} H_{8} +6O_{2}[/tex] → [tex]4CO_{2} +4H_{2} O[/tex]

It can be seen that the stoichiometric coefficient in front of oxygen is 6.

Therefore, stoichiometric coefficient in front of oxygen will be 6.

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Answer:

A

Explanation:

looking at both equity

and mortgage bond fixtures

I would rather say secured bond fit into not being backed by any specific collateral

Answer:

the effect of leaving the following substances in humid air is

ii) sulphate

The incorrect rule for assigning oxidation numbers is Hydrogen is usually –1.

Hydrogen is usually +1

Oxidation numbers can be defined as that number which is assigned to an element in chemical reaction which represents the number of electrons lost or gained.

So therefore, the incorrect rule for assigning oxidation numbers is Hydrogen is usually –1.

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Answer:

B: Oxygen is usually –2.

Explanation:

Organic chemistry is defined as the study of compounds containing carbon element .

In an organic chemistry, we study about structure, properties , composition, reaction and preparation of carbon congaing compounds.The organic compound is contains mainly carbon and hydrogen and other elements. The other elements in organic compounds are nitrogen, oxygen,sulfur, phosphorus, halogen and etc.

Organic chemistry is also refer as carbon chemistry .The carbon element is important because it is center elements of living organism and it is very basic for all live in the earth. By studying about organic chemistry , scientist get to know about human body and living organism.

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Answer: the answer is not c

Explanation: I don't know the correct answer, but I took the test and I know it is not c

Answer:

b is the answer

Explanation:

bc i said so

Answer:

The pool cannot be neutralized with only vinegar.

Explanation:

The pool's [OH] concentration is 1.0x101mol/L. You must determine the volume of the pool in order to determine how many moles of OH there are in the solution:

r2h = V(pool)

Where h is the depth of the pool, which is equal to 10 meters, and r is the radius,

V(pool) = π (6m)

V(pool) = 2*10 = 1131 m3.

As 1m³ = 1000L

The pool holds 1131m3 x (1000L / 1m3) = 1131000L.

And the OH moles are:

The pool has 131100 moles of OH, or 1.0x101mol per liter times 1131000 liters.

The following is how H+ neutralizes OH:

OH⁻ + H⁺ → H₂O

In order to neutralize the pool, 131100 moles of H+ must be added.

H+ levels in vinegar with a pH of 2 are as follows:

[H+] = -log pH

2 = -log [H⁺]

1x10⁻²M = [H⁺]

Only 4x102 moles of [H+] make up 4L. As necessary, 131100 moles of H⁺:

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Despite the fact that viruses and ambient bacteria found indoors could both be mesophiles, at 37 degrees Celsius, the temperature of the human body, pathogens would develop more quickly than environmental strains.

A virus would be an infectious submicroscopic creature that only reproduces inside of live cells.

Although bacteria may survive at higher and lower temperatures than humans, they thrive in an environment which really is warm, wet, protein-rich, and pH neutral as well as slightly acidic.

Therefore, Despite the fact that viruses and ambient bacteria found indoors could both be mesophiles, at 37 degrees Celsius, the temperature of the human body, pathogens would develop more quickly than environmental strains.

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NaBrO₃ (sodium bromate) is an ionic compound. It consists of a metal (sodium, Na) and a polyatomic ion (bromate, BrO₃⁻).

Ionic compounds are compounds composed of positive and negative ions held together by electrostatic forces. They are formed through the transfer of electrons between atoms, resulting in the formation of positively charged cations and negatively charged anions.

In an ionic compound, the cations are typically metal ions, while the anions are usually nonmetal ions or polyatomic ions. The transfer of electrons occurs from the metal atom(s) to the nonmetal atom(s), resulting in the formation of a crystal lattice structure.

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A reasonable explanation for the disappearance of these fish is the high acidity affecting fish metabolism.

pH is a very important parameter to consider, as it has a direct effect on the metabolism and physiological processes of fish and other aquatic organisms. The pH tolerance range for fish is between 4.0 and 9.0, while the ideal index is between 6.5 and 8.0

With this information, we can conclude that The various fish species differ in terms of the best pH. The pH range between 6.5 – 9.0 is generally recommended for freshwater species. For marine species, the most recommended PH range is between 7.8-8.4.

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For the mentioned reaction, the balanced chemical equation is:

KBr (aq) + AgNO3 (s) → KNO3 (aq) + AgBr(s)

The number written in front of the ion, atoms, and molecules in a chemical reaction so that each of the elements on both the sides of reactants and products of the equation gets balanced is known as the stoichiometric coefficient.

From the mentioned balanced equation, the stoichiometric coefficient before KBr is 1, AgNO3 is 1, KNO3 is 1, as well as before AgBr is also 1. Thus, it is clear that 1 mole of potassium bromide reacts with 1 mole of silver nitrate to produce 1 mole of potassium nitrate and 1 mole of silver bromide.

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The balanced molecular equation for this reaction is

2HCl(aq) + Ba(OH)2(aq) ===> BaCl2(aq) + 2H2O(l).

The neutralization of hydrochloric acid and barium hydroxide.

Molecular formula for hydrochloric acid is HCl and barium hydroxide is Ba(OH)2.

Hydrochloric acid and barium hydroxide is aqueous in nature.

HCl have one H+ ion and barium hydroxide has two hydroxide (OH) group.

So, it will take two HCl to neutralize one Ba(OH)2.

Hence, equation for this reaction is

2HCl(aq) + Ba(OH)2(aq) ===> BaCl2(aq) + 2H2O(l).

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Answer:

50.0 °C

Explanation:

If all other variables are being held constant, you can find the temperature using Guy-Lussac's Law. The equation looks like this:

P₁ / T₁ = P₂ / T₂

In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. You can find the missing temperature (T₂) by plugging the given values into the equation and simplifying.

P₁ = 405 pKa                    P₂ = 1013 pKa

T₁ = 20 °C                         T₂ = ? °C

P₁ / T₁ = P₂ / T₂                                              <----- Guy-Lussac's Law

405 pKa / 20 °C = 1013 pKa / T₂                  <----- Insert values

20.25 = 1013 pKa / T₂                                   <----- Divide 20 from 405

20.25 x T₂ = 1013 pKa                                  <----- Multiply both sides by T₂

T₂ = 50.0 °C                                                  <----- Divide both sides by 20.25

If not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

The concentration is the amount of substance that is present in solution. We know that we can not measure the concentration unless all of the solute have been dissolved in the solution.

Thus, if not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

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As per ideal gas equation ,

 [tex]C_{3}H_{6}[/tex] Volume   = 11.56 L

[tex]CO_{2\\}[/tex] volume =  8.62L

What is Ideal gas equation?

PV = nRT

[tex]C_{3} H_{6}[/tex] gas burns in air according to following equation:

[tex]2C_{3}H_{6}[/tex] + [tex]9O_{2}[/tex] → [tex]6CO_{2}[/tex] + [tex]6H_{2} O[/tex]

Volume of [tex]C_{3} H_{6}[/tex] produced;

Step 1 : Calculate the moles of [tex]H_{2} O[/tex]

PV = nRT

n = PV / RT

n = 0.762 × 34.7 / 0.08206 × 302.55

n = 1.065 mol

Step 2: Calculate the moles of [tex]C_{3} H_{6}[/tex]

1.065 mol [tex]H_{2} O[/tex]× 2 mol [tex]C_{3} H_{6\\}[/tex] / 6 mol [tex]H_{2} O[/tex]

= 0.355 mol

Step 3 : Calculate new volume

V = 0.355 × 0.08206 × 302.55 / 0.762

V = 11.56 L

Volume of [tex]CO_{2}[/tex] produced;

Step 1: Calculate the moles of [tex]O_{2}[/tex]

18.7g [tex]O_{2}[/tex] × 1 mol [tex]O_{2}[/tex] / 32 g [tex]O_{2}[/tex]

= 0.58 mol

Step 2: calculate the moles of [tex]CO_{2}[/tex]

0.58 mol × 6mol [tex]CO_{2}[/tex] / 9 mol [tex]O_{2}[/tex]

= 0.38 mol

Step3: convert mol to litres

0.38 × 22.7L / 1mol [tex]CO_{2}[/tex]          [22.7L = 1mol]

= 8.62 L

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Answer:

The three-point test

Explanation:

The three-point test refers to a ground test utilizing an auxiliary current electrode and an auxiliary potential electrode.

Taking into account the reaction stoichiometry, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

In first place, the balanced reaction is:

CH₄ + 2 O₂  → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 16 grams of CH₄ reacts with 64 grams of O₂, 8.50 grams of CH₄ reacts with how much mass of O₂?

[tex]mass of O_{2} =\frac{8.50 grams of CH_{4}x64 grams of O_{2} }{16grams of CH_{4}}[/tex]

mass of O₂= 34 grams

But 34 grams of O₂ are not available, 15.9 grams are available. Since you have less mass than you need to react with 8.50 grams of CH₄, O₂ will be the limiting reagent.

The following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44 grams of CO₂, 15.9 grams of O₂ form how much mass of CO₂?

[tex]mass of CO_{2} =\frac{15.9 grams of O_{2}x44 grams of CO_{2} }{64grams of O_{2}}[/tex]

mass of CO₂= 10.93 grams

Then, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

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Answer:

0.01 moles NaCl

Explanation:

It seems that the given volumes are unnecessary information.

To find the moles NaCl, you need to convert moles HCl and NaOH to moles NaCl via the balanced chemical equation. Specifically, you need to use the mole-to-mole ratio made up of the reaction coefficients. The reason why you need to convert both reactants is because you have not been given a limiting reagent. The smallest amount of moles NaCl calculated will be the final answer.

The balanced reaction:

HCl + NaOH -----> NaCl + H₂O

0.1 moles HCl         1 mole NaCl
----------------------  x  ----------------------  =  0.1 moles NaCl
                                  1 mole HCl

 0.01 moles NaOH           1 mole NaCl
-----------------------------  x  -----------------------  =  0.01 moles NaCl
                                         1 mole NaOH

NaOH produces the smallest amount of product. This means it is completely used up before HCl runs out. Therefore, NaOH is the limiting reagent and 0.01 moles NaCl are actually produced.

Answer:

D.) K, Mn, As, Ar

Explanation:

The metalloids are located in the p-block on the periodic table and have a ladder-like arrangement.

The most commonly recognized metalloids are:

boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te)

Answer:

larger the intermolecular forces in a compound, the slower its evaporation rate

Explanation:

socratic

When the system turns pink, then the end point has been attained.

The end point or the equivalence point is the time when the reactants have undergone transformation in accordance with the reaction equation. The reaction in this case is; HCl + NaOH -----> NaCl + H2O.

We know that phenolphthalein is colorless in acid but red in a base. The color at end point is pink. Thus, when the system turns pink, then the end point has been attained.

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Answer:

which one is isn't the one that is wrong

Explanation:

bang bang chocho train

Answer:

.577 atm

Explanation:

P1 V1  = P2 V2

RE-ARRANGE TO     P2 = P1 V1 / V2

Sub in the given values

  P2 = 1.15 * .414 / .825 = .577 atm

From the stoichiometry of the reaction, carbon is in excess and 5.856 g s left over.

The reaction can be written as; 4C(s) + 5H2(g) -----> C4H10(g)

Number of moles of C =  13.45 g/1 2g/mol = 1.12 moles

If 1 mole of hydrogen occupies 22.4 L

x moles of hydrogen occupies  17.65 L

x = 0.79 moles

Now;

4 moles of carbon reacts with 5 moles of hydrogen

1.12 moles of carbon reacts with  1.12 moles * 5 moles/4 moles

= 1.4 moles of hydrogen

Hence hydrogen is the limiting reactant here and carbon is in excess.

If 4 moles of carbon reacts with 5 moles of hydrogen

x moles of carbon reacts with 0.79 moles of hydrogen

x = 0.632 moles

Number of moles of carbon unreacted =  1.12 moles -  0.632 moles

= 0.488 moles

Mass of carbon unreacted = 0.488 moles * 12 g/mol

= 5.856 g

Volume of butane produced is obtained from;

5 moles of hydrogen produces 1 mole of butane

0.79 moles of hydrogen produces 0.79 moles *  1 mole/ 5 moles

= 0.158 moles

1 mole of butane occupies 22.4 L

0.158 moles of butane occupies 0.158 moles * 22.4 L/ 1 mole

= 3.53 L

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The concentration of the acetic acid before titration is 0.128M

For weak acid and strong base titration-

Moles of acetic acid =  moles of NaOH

Given concentration of NaOH = 0.1067M

Volume of NaOH = 30.07ml = 0.03007L

Using the formula, Concentration = Moles/Volume

Moles of NaOH = concentration X volume = 0.1067 X 0.03007 = 0.0032

Therefore, moles of acetic acid  = 0.0032mole

Using the formula, Concentration = Moles/Volume

Concentration of acetic acid =  0.0032/0.025 = 0.128M

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Control rods in a nuclear reactor control a chain reaction by absorbing neutrons. Option C

The control rods are rods that are inserted into the nuclear reactor in order to absorb the neutrons thereby preventing the nuclear reaction from going out of hand.

Hence, control rods in a nuclear reactor control a chain reaction by absorbing neutrons. Option C

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The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.

The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.

To find the change in energy use this expression:

q = n ΔH

where

q = Energy change

n = number of moles

ΔH = Molar enthalpy

Number of moles (n) = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

                                  = [tex]\frac{78.0\ g}{200\ \text{g/mol}}[/tex]

                                  = 0.39 mol

Now put the values in above formula we get

q = n ΔH

  = 0.39 mol × 2.29 kJ/mol

  = 0.89 kJ

Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.

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Answer:

the smoke one

Explanation:

it can be made aware of and people can raise money to stop it/ help it

Ionization of Gold:

The maximum wavelength of light that will ionize gold is 134.5 x 10 ⁻⁴m  

Calculation:

1 mole requires = 890.1kJ = 8.901×10⁵ J

The energy needed to ionize a single atom = Divide it by Avogadro's number (6.0221409×10²³)

Thus, 1 atom requires = 8.901×10⁵ J / 6.0221409×10²³ J

                                    =  1.478×10⁻¹⁸ J

The Energy of photon = E = hc/λ   where,

h =  Planck constant (6.626070040Ă—10â’34 Js)

λ =  the wavelength

c = the speed of light

Putting the values:

E = 1.478×10⁻¹⁸ J

h =6.63x10⁻³⁴ Js

c = 3 x 10⁸ m/s

λ = ?

λ = hc/E

  = (6.63x10⁻³⁴ x 3 x 10⁸ ) / 1.478×10⁻¹⁸

  = 134.5 x 10 ⁻⁴m  

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