PLEASE HELP!!!



What are some compound machines that are used today?

Answers

Answer 1

Answer:

Examples of compound machines include bicycles, cars, scissors, and fishing rods with reels. Compound machines generally have lower efficiency but greater mechanical advantage than simple machines

Brilianst

Answer 2

Answer:

screws, inclined planes , etc

Explanation:

no explanation needed


Related Questions

Why is fluorine more chemically reactive than nitrogen

Answers

Answer:

Me encanta el pollo, de todos modos, un día que es hoy, por cierto, fui a la tierra de los pollos y caminé en México, ¿sabías que es mi sueño? ¿Olvidé que mi nombre es jemma y me gusta caminar? párrafo así que nos vemos

Explanation:

Answer:

Fluorine needs to gain only 1 electron to have a full octet, while nitrogen needs to gain 3.

A woman stands still holding a 350 Newton bag (about 80 pounds) 2 meters off the ground. How much work does the woman do?

Answers

Answer:

700 Joules

Explanation:

What we know:

Force = 350 Newton

Distance = 2 meters

Work = ?

The formula for work is:

Work = force x distance

Plugging values into equation:

Work = 350 Newtons x 2 meters

Work = 700 Joules

I had the same question on the homework assignment with the answers provided:

a) It depends on how long she holds the bag

b) 350 Joules

c) none

d) 350 Newtons

The final answer would be c) none. The work done is 700 Joules. Hope this helps!

a sports car has a mass of 1300kg.Starting from the rest the car generates a force of 4400 N.The frictional force opposing this motion is 280 N.What is the car’s acceleration

Answers

since the car moves, the force needed to move is greater than the frictional forces opposing it

a = 3.17m/s²

The acceleration of the car with a mass of 1300 kg which starts from rest generating a force of 4400 N and having a frictional force of 280 N is 3.17 m/s²

We'll begin by calculating the net force acting on the car. This can be obtained as follow:

Force (F) = 4400 N

Frictional force (Fբ) = 280 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 4400 – 280

Fₙ = 4120 N

Thus, the net force acting on the car is 4120 N

Finally, we shall determine the acceleration of the car. This can be obtained as follow:

Mass (m) = 1300 Kg

Net force (F) = 4120 N

Acceleration (a) =?

Force = Mass × Acceleration

4120 = 1300 × a

Divide both side by 1300

[tex]a = \frac{4120}{1300}\\\\[/tex]

a = 3.17 m/s²

Therefore, the acceleration of the car is 3.17 m/s².

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In which scenario is the greatest amount of work done on a wagon?

A force of 55 N moves it 8 m.
A force of 60 N moves it 6 m.
A force of 50 N moves it 5 m.
A force of 40 N moves it 10 m.

Answers

Answer:

The first scenario!

Explanation:

W=F*d

a) 55*8= 440J

b) 60*6= 360J

c) 50*5= 250J

d) 40*10= 400J

The scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.

What is Work done?

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied and d is distance travelled.

From the question;

A force of 55 N moves it 8 m

W = 55N×8m = 440N.m

A force of 60 N moves it 6 m.

W = 60N×6m = 360N.m

A force of 50 N moves it 5 m.

W = 50N×5m = 250N

A force of 40 N moves it 10 m.

W = 40N×10m = 400N.m

Therefore, the scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.

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Gravity does not actually "pull" objects at
all, rather gravity is a result of the warping.
or curving, of

A Stars and planets
B. The solar system
C Spacetime
D. Any object

Answers

I believe it’s (D. Any object)

What is sin for the given right triangle?
8.6 meters
5 meters

6.99 meters
A. l0.71
B. 0.81
C. 0.58
D. 1.72

Answers

Answer:

C

Explanation:

sin of a right triangle is opposite divided by hypotenuse

in this case, that is 5/8.6 = 0.581395349

you can easily remember the trig functions with this acronym:

SOH-CAH-TOA

S: Sine

O: Opposite

H: Hypotenuse

C: Cosine

A: Adjacent

H: Hypotenuse

T: Tangent

O: Opposite

A: Adjacent

Explanation:

sin = Mp /0P

sin = 5/8,6

sin = 0,58

Lichen grows on the surface of hornblende granite and causes it to breakdown at a faster rate. This is an example of. _______ Weathering

Answers

Answer:

Chemical.

Explanation:

Weathering can be defined as the physical and chemical breakdown of rock into smaller pieces called sediment. Weathering can be classified into two categories namely;

I. Physical weathering : it is the process of breaking rocks into pieces without affecting its chemical composition e.g temperature, abrasion and frost action.

II. Chemical weathering : it is the process of breaking rocks into pieces by chemical action which leads to changes in its chemical composition e.g carbonation, hydration, plant acid and oxidation.

In this scenario, Lichen grows on the surface of hornblende granite and causes it to breakdown at a faster rate. Thus, this is an example of chemical weathering

a wave of frequency 10hz forms a stationary wave pattern in a medium where the velocity is 30cm/s. the distance between adjacent nodes is?​

Answers

Answer:

The ans is 1 not 2

Explanation:

The distance between two adjacent node in a stationary wave is half wavelength π/2 and not full wavelength as in π,so when solving we got 2cm as the wavelength since they ask the dist. Also adjacent nodes you will divide it by 2 and the ans will give u 1cm.

Hope this helps.

student c precise or accurate darts

Answers

Answer:

i don't get it

Explanation:

? provide answers pls

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.250 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.960 m above the floor. (a) Calculate his velocity (in m/s) when he leaves the floor. 4.33 Correct: Your answer is correct. m/s (b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.250 m.

Answers

Answer:

a. 3.73 m/s b. 27.8 m/s²

Explanation:

(a) Calculate his velocity (in m/s) when he leaves the floor.

Using the conservation of energy principles,

Potential energy gained by basketball player = kinetic energy loss of basket ball player

So, ΔU + ΔK = 0

ΔU = -ΔK

mg(h' - h) = -1/2m(v'² - v²)

g(h' - h) = -1/2(v'² - v²) where g = acceleration due to gravity = 9.8 m/s², h' = 0.960 m, h = 0.250 m, v' =0 m/s (since the basketball player momentarily stops at h' = 0.960 m) and v = velocity with which the basketball player leaves the floor

Substituting the values of the variables into the equation, we have

9.8 m/s²(0.960 m - 0.250 m) = -1/2((0 m/s)² - v²)

9.8 m/s²(0.710 m) = -1/2(-v²)

6.958 m²/s² = v²/2

v² = 2 × 6.958 m²/s²

v² = 13.916 m²/s²

v = √(13.916 m²/s²)

v = 3.73 m/s

(b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.250 m.

Using v² = u² + 2as where u = initial speed of basketball player before lengthening = 0 m/s, v = final speed of basketball player after lengthening = 3.73 m/s, a = acceleration during lengthening and s = distance moved during lengthening = 0.250 m

So, making, a subject of the formula, we have

a = (v² - u²)/2s

Substituting the values of the variables into the equation, we have

a = ((3.73 m/s)² - (0 m/s)²)/(2 × 0.250 m)

a = (13.913 m²/s² - 0 m²/s²)/(0.50 m)

a = 13.913 m²/s²/(0.50 m)

a = 27.83 m/s²

a ≅ 27.8 m/s²

TAKING 100 PONTS!!! PLEASE SOMEONE HELP.JUST LOOK THE PICTURE​

Answers

Explanation:

oh no i hope i dont fall and the  i agree with the other dude

Answer: Okay, thanks I really appreciate the generosity.

Waves are ?
that can travel through matter.

Answers

Answer:

A wave can be thought of as a disturbance or oscillation that travels through space-time, accompanied by a transfer of energy. The direction a wave propagates is perpendicular to the direction it oscillates for transverse waves. A wave does not move mass in the direction of propagation; it transfers energy.

A city near the ocean experiences thunderstorms on a frequent basis. Which of these is the BEST explanation for this?

A.
The interactions of the waves with the landmass change the air pressure to cause thunderstorms.

B.
The cold fronts that form only over coastal areas cause thunderstorms.

C.
The amount of sunshine received by coastal areas causes thunderstorms.

D.
The uneven heating of land and water in coastal areas creates fronts that cause thunderstorms.

Answers

Answer:

d

Explanation:

The uneven heating of land and water in coastal areas creates fronts that cause thunderstorms. So, option D is correct.

What is meant by heat energy ?

Heat energy of a system is defined as the energy transferred between the molecules due to the temperature difference between them. Heat energy is the energy responsible for the temperature of the molecules.

Here,

A city near the ocean experiences thunderstorms on a frequent basis. This is because,

The atmosphere near to the land is highly humid and warm and thus creates a relatively low pressure in the land. In order to balance the pressure variation the air from the oceans make movements towards the land, and as a result, sea breeze are formed. During the evenings when the water in the ocean is more warm and when land begins to cool, the air from land rushes towards the sea, in order to balance the pressure variation occurred here. This makes the air above the ocean highly humid and thus would lead to the formation of thunderstorms.

Hence,

The uneven heating of land and water in coastal areas creates fronts that cause thunderstorms.

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HELP
HELP
SORRY TO BEG :/
HELP ASAP :) PLZ

Answers

Answer:

It's b because he discovered galaxies .

Object 1 has a momentum of 10 kg m/s and Object 2 has a momentum of 25 kg m/s. Will it be easier to change the direction of movement of Object 1 or of Object 2?

Answers

Answer:

I think its object 1

Explanation:

Because the object that has more weight has a greater momentum and the lightest object that has a less momentum will be easier to change because its lighter.

Is the speed of light constant throughout the universe.?

Answers

Answer:

It is a basic postulate of the theory of relativity that the speed of light is constant. This can be broken down into two parts: The speed of light is independent of the motion of the observer. The speed of light does not vary with time or place.

Explanation:

When an object is raised vertically, work is done against __________. What one word completes the sentence?

please help quickly!!

Answers

Gravity Gravitational Force of Gravity

When an object is raised vertically, work is done against _gravitational force _________

What is gravitational force ?

The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface is called gravitational force .

On every body there is a force acting named  gravitational force which attracts the body downward .

If a object / body is thrown up it always comes downward if only gravitational force is acting on it which act due to earth's gravity .

When an object is raised vertically, work is done against _gravitational force _________

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What is the gravitational potential energy of an object that has a mass of 8 kg and is 11.2 meters above Earth? Round your answer the nearest whole number.
A. 878 J
B. 30 J
C. 680 J

Answers

Answer:
A.
Explanation:
GPE= ham
GPE= (8)(11.2)(9.8)
GPE= 878.08
round it up
878 J

if you ride a bike at 2 km/h and travel a total distance of 20km, how long willnit takr ( in second) you to teach your destination

Answers

Time = (20 km) x (1 hr/2 km) x (3,600 sec/hr)

Time = (20 x 1 x 3,600 km-hr-sec) / (2 km-hr)

Time = (20 x 1 x 3,600 / 2) (km-hr-sec / km-hr)

Time = 36,000 seconds

(That's 10 hours.)

3. What is the power of a derby race car that uses a 50 N force to travel 20 meters in 10 seconds?
A. 1000 W
B. 100 W
C. 80 W

Answers

I think it is B. 100 W


When you are doing either a chest or a bounce pass where are your thumbs at the end of the
motion?

Answers

Answer:

yes

Explanation:

You are riding in the passenger seat of a car as it goes around a tight turn. You slide across the seat to the passenger side door. Which statement below properly describes what is happening? a. You are exerting a centripetal force on the door. b. The door and seat are exerting a centripetal force on you that balances the centrifugal force of the turn. c. The car seat exerts a centripetal force on you, but not enough to keep you in place, so the door exerts the rest. d. The centrifugal force is greater than the force of friction between you and the seat, so you slide outward.

Answers

Answer:

Explanation:

answer C looks good

there isn't really a "centrifugal " force. :/    when we are pushed "back" in a car seat.. it's not because there is a force pushing us backwards... but a force pushing us forwards.. just like when turning too,   a force pushes us into the corner,  not a force pushing out of the corner.  :)  

Problem 05.086 - Water pumped from a lower reservoir to a higher reservoir Water is pumped from a lower reservoir to a higher reservoir by a pump that provides 21 kW of useful mechanical power to the water. The free surface of the upper reservoir is 45 m higher than the surface of the lower reservoir. If the flow rate of water is measured to be 0.03 m3/s, determine the irreversible head loss of the system and the lost mechanical power during this process. Take the density of water to be 1000 kg/m3. The irreversible head loss of the system is 26.35 m. The lost mechanical power in this process is kW.

Answers

Answer:

Lost Mechanical Power = 7.7565 KW

Head Loss = 26.35 m

Explanation:

First, we will find the useful mechanical power used to transport water to the higher reservoir:

[tex]P_{useful} = \rho ghV[/tex]

where,

P_useful = Useful mechanical Power = ?

ρ = density of water = 1000 kg/m³

g = acceleration due to gravity = 9.81 m/s²

h = height = 45 m

V = Volume flow rate = 0.03 m³/s

Therefore,

[tex]P_{useful} = (1000\ kg/m^3)(9.81\ m/s^2)(45\ m)(0.03\ m^3/s)\\P_{useful} = 13243.5\ W = 13.2435\ KW[/tex]

Now, the lost mechanical power will be:

[tex]Lost\ Mechanical\ Power = Total\ Mechanical\ Power - Useful\ power\\Lost\ Mechanical\ Power = 21\ KW - 13.2435\ KW\\[/tex]

Lost Mechanical Power = 7.7565 KW

Now, for the head loss:

[tex]Lost\ Mechanical\ Power = \rho g(Head\ Loss)V\\Head\ Loss = \frac{Lost\ Mechanical\ Power}{\rho gV} \\\\Head\ Loss = \frac{7756.5\ W}{(1000\ kg/m^3)(9.81\ m/s^2)(0.03\ m^3/s)} \\[/tex]

Head Loss = 26.35 m

pls help its already late lol

Answers

Answer:

Temperature

Explanation:

Answer:

Gravity

Explanation:

Gravity has nothing to do with weather. Temperature means hot or cold, water is rain and thunder, and wind is if it's in the winter or something like that

Find the momentum of a 15 kg object traveling at 7 m/s

What is the momentum?

What equation did you use to solve?

Answers

Answer:

105 kg*m/s

Explanation:

p=mv

momentum=mass*velocity

momentum=15kg*7m/s

momentum=105kg*m/s

During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapults that are made with surgical hose mounted on a window frame. A balloon filled with dyed water is placed in a pouch attached to the hose, which is then stretched through the width of the room. Assume that the stretching of the hose obeys Hooke's law with a spring constant of 112 N/m. If the hose is stretched by 4.70 m and then released, how much work does the force from the hose do on the balloon in the pouch by the time the hose reaches its relaxed length

Answers

Answer:

1237 J

Explanation:

The work done by the hose on the balloon is the work done by a spring which is

W = 1/2k(x₀² - x₁²) where k = spring constant = 112 N/m, x₀ = 4.70 m and x₁ = 0 m.

Substituting the values of the variables into the equation, we have

W = 1/2k(x₀² - x₁²)

W = 1/2 × 112 N/m((4.70 m)² - (0 m)²)

W = 56 N/m(22.09 m² - 0 m²)

W = 56 N/m(22.09 m²)

W = 1237.04 J

W ≅ 1237 J

What variables affect density weight,conductivity,color,volume, or mass

Answers

Answer:

Density is affected by volume and mass.

Explanation:

Density is defined as the quantity of mass per unit of volume, or expressed mathematically, d = m/v.

Define speed and what is it’s SI unit.

Answers

Speed can be thought of as the rate at which an object covers distance. ... Speed has the dimensions of distance divided by time. The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour........?
Speed is the rate at which someone or something is able to move or operate. Moreover, the SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour.

PLEASE HELP ME WITH THIS ONE QUESTION

Which pendulum would have the highest frequency?

1) 1 kg mass and 0.5-meter length

2) 0.5 kg mass and 0.75-meter length

3) 0.5 kg mass and 1-meter length

4) 1 kg mass and 0.75-meter length

Answers

Answer:

B is the Answer

Follow me please

Mark brainliest

Answer:

The answer is A

Explanation:

This is because f = 1/T,

or frequency equals 1 over period, T

Since the highest T would be the answer with the greatest length and mass does not matter the answer would be c IF they were asking for the highest period.

F is found by 1 over T so the greatest F would be the smallest number, Hence answer A

Please Mark me brainiest

In 1976, a 53 kg helicopter was built in Denmark. Suppose this helicopter flew east with a speed of 60.0 m/s and the total momentum of the helicopter and pilot was 7,200 kg∙m/s to the east. What was the mass of the pilot?

Answers

Answer:

67 kg.

Explanation:

From the question,

Total momentum = (mass of the pilot+ mass of the helicopter)×velocity.

I = (m+M)v............................... Equation 1

Where I = Total momentum of the pilot and the helicopter, m = mass of the pilot, M = mass of the helicopter, v = velocity.

make m the subject of the equation

m = (I/v)-M.............................. Equation 2

Given: I = 7200 kg.m/s, v = 60 m/s, M = 53 kg.

Substitute these values into equation 2

m = (7200/60)-53

m = 120-53

m = 67 kg.

Hence the mass of the pilot is 67 kg

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