Please match the correct type of reaction to its name.

Answer:

D 27.74%

Explanation:

Percent composition of Magnesium (Mg) in Magnesium Phosphate compound ie Mg3(PO4)2 = 27.74%

Answer:

The answer is D

Explanation:

I took the test

Answer:

Below 7

Explanation:

The equivalence point, or stoichiometric point, of a chemical reaction is the point at which chemically equivalent quantities of reactants have been mixed(Wikipedia).

For a strong acid-weak base titration, the pH at the equivalence point is usually below 7. This owes to the fact that a conjugate acid  is produced in the course of the reaction which interacts with water to produce hydronium (H3O+) ions.

Answer:

7

Explanation:

i did my research and from what i found its 7.

Answer:

[tex]1.2x10^{24}g[/tex]

Explanation:

Hello!

In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:

[tex]\frac{2.00g}{1nail}[/tex]

Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:

[tex]6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g[/tex]

Best regards!

Answer:

Burning of fossil fuels

Cutting of tress

Also CO2 is produce in industries like cement manufacturing.

Explanation:

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

[tex]7.5+50=57.5\ \text{g}[/tex]

Products

[tex]57.5\ \text{g}[/tex]

The data is consistent with the law of conservation of matter.

Reactants

[tex]50+243=293\ \text{g}[/tex]

Products

[tex]206+97=303\ \text{g}[/tex]

The data is not consistent with the law of conservation of matter.

Reactant

[tex]17.7+34.7=52.4\ \text{g}[/tex]

Products

[tex]62.4\ \text{g}[/tex]

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

7.5 ppm

Given

1000 g of water

0.0075g of Ca²⁺ ion

Required

the concentration in ppm by mass of Ca²⁺

Solution

ppm = part per million

solvent = water ⇒ ppm = 1 mg/L(water density is 1 kg / L) or mg/kg

Convert g to mg of  Ca²⁺ ion :

0.0075 g = 7.5 x 10⁻³ g = 7.5 mg

Convert g to kg of water :

1000 g = 1 kg water

So the concentration of Ca²⁺ ion :

= 7.5 mg / 1 kg

= 7.5 ppm

Answer:

8.397J/mol is the activation energy for the reaction

Explanation:

The graphical form of Arrhenius equation is:

ln k = -Ea/R*(1/T)+lnA

Where k is activation energy

Ea is activation energy

R is gas constant (8.314J/molK)

T is absolute temperature

And A is the pre-exponential factor.

The slope of the plot is -Ea/R:

-Ea/R = -1.01x10⁴K

-Ea/8.314J/molK = -1.01x10⁴K

Ea = -1.01x10⁴K*8.314J/molK

Ea = 8.397J/mol is the activation energy for the reaction

Answer:

tree

Explanation:

so easy and obvious

Answer: C6H12O6 is formed by a covalent bond, the rest of the options are formed by ionic bonds.

Answer:

used by plants to make protein

Explanation:

so B

400 Joules

Work done is measured in Joules (J) remember that

Answer:400 joules

wut do u need

Explanation:

Answer:

1.403x10²⁴ molecules

Explanation:

In order to calculate how many molecules of CO₂ are there in 102.5 g of the compound, we first convert grams to moles using its molar mass:

Now we convert moles into molecules using Avogadro's number:

Answer:

5.80200 Kg / L

Explanation:

Explanation:

A. AgNO3 + KCl --> AgCl + KNO3

Reaction is already balanced.

Type = Double Replacement

B. H2O + SO3 --> H2SO4

Reaction is already balanced.

Type = Synthesis

C. KI + Cl2 --> KCl + I2

Balanced Equation = 2KI + Cl2 --> 2KCl + I2

Type = Single Replacement

D. NaHCO3 --> Na2CO3 + H2O + CO2

Balanced Equation = 2NaHCO3 --> Na2CO3 + H2O + CO2

Type = Decomposition

E. Zn + HCl  --> ZnCl2 + H2

Balanced Equation = Zn + 2HCl  --> ZnCl2 + H2

Type = Single Replacement

F. BaCl2 + Na2SO4 --> BaSO4 + NaCl

Balanced Equation =  BaCl2 + Na2SO4 → 2NaCl + BaSO4  

Type = Double Replacement

G. C3H8 + O2 --> CO2 + H2O

Balanced Equation =  C3H8 + 5O2 → 3CO2 + 4H2O  

Type = Single Replacement

H. Al + CuCl2 --> AlCl3 + Cu

Balanced Equation =   2Al + 3CuCl2 → 2AlCl3 + 3Cu  

Type = Single Replacement

Mass of iron(ll) oxide= 616.608 g

Given

Reaction

2Fe+O2 -->2FeO

479.6 grams of iron

Required

mass of iron(ll) oxide

Solution

mol of iron :

= mass : Ar Fe

= 479.6 g : 56 g/mol

= 8.564

From the equation, mol FeO :

= 2/2 x mol Fe

= 2/2 x 8.564

= 8.564 moles

Mass of iron(ll) oxide :

= mol x MW

= 8.564 x 72 g/mol

= 616.608 g

rise and cold air

it doesn't fall cause I already fall inlove with levi

Answer:

c). their home was destroyed by the government

Explanation:

yan po ang Tama sure ako sa sagot ko.

Answer:

Empirical formula = CH₃O

Molecular formula = C₂H₆O₂

Explanation:

The empirical formula is the simplest whole-number ratio of atoms present in a molecule. To find the ratio of atoms we must find the moles of C, H and O. With the molar mass we can find the molecular formula:

Moles C = Moles CO₂:

12.65g * (1mol / 44.01g) = 0.2874 moles of C * 12.01g/mol = 3.452g C

Moles H = 1/2 moles H₂O:

7.768g * (1mol / 18.015g) = 0.4312 moles of H₂O * 2 = 0.8624 moles H * 1.008g/mol = 0.869g H

Moles O:

Mass O = 8.919g - 0.869g H - 3.452g C = 4.598g O * (1mol / 16g) = 0.2874 moles of O

Ratio of atoms -Dividing in the lower number of moles-:

C = 0.2874 mol C / 0.2874 mol = 1

H = 0.8624 mol H / 0.2874 mol = 3

O = 0.2874 mol O / 0.2874 mol = 1

The molar mass of this formula is:

1C = 12.01g/mol

3H = 3*1.008g/mol = 3.024g/mol

1O = 16g/mol

12.01+3.024+16 = 31.034g/mol

Twice this formula gives the molecular formula = 31.034g/mol*2 = 62.068g/mol ≅ the molar mass of the compound. That means molecular formula of the compound is:

Answer:

[tex]C_4H_8O_2[/tex]

Explanation:

Hello!

In this case, since the combustion of this compound has only one source of carbon, the carbon dioxide, we can compute both mass and moles of carbon in 4.401 grams of CO2:

[tex]n_C = 4.401gCO_2*\frac{1molCO_2}{44.01gCO_2}* \frac{1molC}{1molCO_2} =0.1molC\\\\m_C = 0.1molC*\frac{12.01gC}{1molC} = 1.201gC[/tex]

Next, we do the same for hydrogen in water, as the only source of this atom in the products:

[tex]n_H = 1.802gH_2O*\frac{1molH_2O}{18.02gH_2O}* \frac{2molH}{1molH_2O} =0.2molH\\\\m_H = 0.2molC*\frac{1.01gH}{1molH} = 0.202gH[/tex]

Thus, we compute the mass and then the moles of oxygen considering the 2.203-g sample of dioxane:

[tex]m_O = 2.203g-m_C-m_H=2.203g-1.202g-0.202g = 0.799gO\\\\n_O =0.799gO*\frac{1molO}{16.0gO} =0.05molO[/tex]

Next, we divide the moles of C, H and O by the moles of O as the fewest in the molecule to find their subscripts in the empirical formula:

[tex]C:\frac{0.1mol}{0.050mol}=2 \\\\H:\frac{0.202mol}{0.050mol} =4\\\\O:\frac{0.050}{0.050}=1 \\\\[/tex]

[tex]C_2H_4O[/tex]

Whose molar mass is 44.1 g/mol. Thus, since the molar mass of the compound is 88.1 g/mol, we see a factor of 2 by which the empirical formula should be multiplied to get the molecular one, therefore, we obtain:

[tex]C_4H_8O_2[/tex]

Best regards!

Answer:

Septic tanks.

Explanation:

Wastewater typically refers to a body of water that has been contaminated through human use in homes, offices, schools, businesses, etc. Wastewater are meant to be disposed in accordance with the local regulations and standards because they are unhygienic for human consumption or use.

Generally, many homes use a floor drain in their bathrooms and toilets to remove wastewater in order to mitigate stagnation and to improve hygiene. A floor drain can be defined as a material installed on floors for the continuous removal of any stagnant wastewater in buildings.

Wastewater flows into a septic tank once it is released into a floor drain or from the water closet through the use of a pipe such as a polyvinyl chloride (PVC) pipe, which directly connects the to the septic tank.

It is used by nearly one-third of the U.S. population, septic tanks are frequent sources of biological contamination, such as fecal bacteria and virus contamination, of water supplies, and often the owners of these systems dispose of detergents, nitrates, chlorides, and solvents in the system leading to potential downstream contamination if not managed properly.

Hence, the wastewater and biological contamination should be removed from septic tanks when they are filled up through the use of a pump.

Sulfur act as a reducing agent and chlorine acts as an oxidizing agent.

The charge is based on the number of electrons assigned to an atom as compared to the neutral atom

Given reaction:-

[tex]S+Cl_2 \rightarrow SCl_2[/tex]

The oxidation state of sulfur in the left side is 0, but in right side is +2. So, sulfur is oxidized. The oxidation number of Cl in the reactant side is 0 and n the product side is -1. So, Cl acts as oxidizing agent.

To know more about:-

brainly.com/question/13182308

Answer:

The element is a nonmetal

Explanation:

Elements are broadly classified into metals and non metals. Metals conduct electricity while non metals do not conduct electricity.

If we look at this scenario described in the question, we can easily decipher that the element is a nonmetal because the LED stays dark. The LED should have been lit if electricity was passed through the element in question.

Hence, the element is a non metal.

Answer:

20 mole of co2

Explanation:

I hope this helps

Answer: Theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]

[tex]\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles[/tex]

The balanced chemical equation is:  

[tex]2S+3O_2\rightarrow 2SO_3[/tex]  

According to stoichiometry :

2 moles of [tex]S[/tex] produce =  3 moles of [tex]SO_3[/tex]

Thus 0.28 moles of [tex]S[/tex] will produce=[tex]\frac{3}{2}\times 0.28=0.42moles[/tex]  of [tex]SO_3[/tex]  

Mass of [tex]SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g[/tex]

Thus theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g

Answer:

6.76 mol/L

Explanation:

A chemist prepares a solution 0.607 kg of calcium bromide by measuring out of calcium bromide into a 450. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's calcium bromide solution. Be sure your answer has the correct number of significant digits.

Step 1: Given data

Step 2: Calculate the moles of solute

The molar mass of calcium bromide is 199.89 g/mol.

607 g × 1 mol/199.89 g = 3.04 mol

Step 3: Convert "V" to liters

We will use the conversion factor 1 L = 1000 mL.

450. mL × 1 L/1000 mL = 0.450 L

Step 4: Calculate the concentration of calcium bromide in mol/L

[CaBr₂] = 3.04 mol/0.450 L = 6.76 mol/L