PLEASEEE HELPPPP!!!!! ASAP!
King and his friend went to a restaurant for dinner. King ordered a half pound burger and a milkshake. The burger contained 25 grams of total fat. If the recommended daily allowance of total fat for a 2,000 calories diet is 62 grams, what percent of the daily allowance did King have when he ate his burger? Show your work and round to the nearest tenth.

Answers

Answer 1

Answer:

  40.3%

Step-by-step explanation:

You want to know the percentage of a 62 gram allowance of fat is represented by a burger with 25 grams of fat.

Percentage

The fraction can be converted to a percentage by multiplying by 100%.

  burger/allowance = (25 g)/(62 g) × 100% = 40.3%

King has 40.3% of his daily allowance for fat when he ate his burger.

PLEASEEE HELPPPP!!!!! ASAP!King And His Friend Went To A Restaurant For Dinner. King Ordered A Half Pound

Related Questions

Rewrite without absolute value for the given condition: |(square root 2) +3 -5|

Answers

Answer: We can simplify the expression inside the absolute value first:

|(sqrt(2) + 3 - 5)|

= |(sqrt(2) - 2)|

Since sqrt(2) > 2, we know that sqrt(2) - 2 is negative. Therefore, we can rewrite the absolute value as a negative:

|sqrt(2) - 2| = -(sqrt(2) - 2)

So the expression without absolute value is:

-(sqrt(2) - 2)

Step-by-step explanation:

10 POINTS NEED HELP ASAP!!!! PLEASE HELP ME FIND THE AREA AND THE PERIMETER!!

Answers

The area of the composite shape using the area formula for the different shapes is 460.48ft².

What are composite shapes?

The area of composite shapes refers to the space occupied by any composite shape. A composite shape is a shape that is made by connecting a few polygons to form the required shape.

These figures or shapes can be built from a wide range of shapes, such as triangles, squares, quadrilaterals, etc. Divide a composite item into basic forms such a square, triangle, rectangle, or hexagon to get its area.

Now in the question,

First let us find the area of the semi-circle.

Area of semi-circle = πr²/2

= [3.14 × (16/2) ²]/2

= (3.14 × 8²)/2

= 200.96/2

= 100.48ft²

Now coming to the rectangle,

area of the rectangle = l × b

= 20 × 15

= 300ft²

Now for calculating the area of the triangle,

area = 1/2 × b × h

= 1/2 × 12 × 10

= 60ft²

Therefore, the area of the total figure = 100.48 + 300 + 60 = 460.48ft².

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Find the surface area of the figure on the right.

Answers

The fig's right side of total surface = 42yds.

What is surface area?

A solid object's surface area is a measurement of the total area that the surface of the object takes up.

The definition of arc length for one-dimensional curves and the definition of surface area for polyhedra (i.e., objects with flat polygonal faces), where the surface area is the sum of the areas of its faces, are both much simpler mathematical concepts than the definition of surface area when there are curved surfaces.

A smooth surface's surface area is determined using its representation as a parametric surface, such as a sphere.

This definition of surface area uses partial derivatives and double integration and is based on techniques used in infinitesimal calculus.

Henri Lebesgue and Hermann Minkowski at the turn of the century sought a general definition of surface area.

According to our question-

(17+17+8)yds

42yds

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under the normal distribution, if the mean of the distribution of raw scores is equal to 100, then its equivalent z-score is equal to

Answers

The equivalent z-score for a raw score of 115 under a normal distribution with a mean of 100 and a standard deviation of 15 is 1.

Under the normal distribution, if the mean of the distribution of raw scores is equal to 100 and the standard deviation is known, we can use the z-score formula to calculate the equivalent z-score for any given raw score.

The z-score formula is given by:

z = (x - μ) / σ

where x is the raw score, μ is the mean of the distribution, σ is the standard deviation of the distribution, and z is the corresponding z-score.

Since the mean of the distribution is 100, we have μ = 100. To calculate the z-score, we need to know the standard deviation of the distribution or have information about the distance of the raw score from the mean in terms of standard deviations.

If we assume that the standard deviation is 15, which is a common value used in educational testing, and the raw score is 115, then the corresponding z-score would be:

z = (115 - 100) / 15 = 1

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Just need to answer to this geometry question, Its a throw back for me.

Answers

As the triangles are similar to each other, using congruent theorem, we get the value of side JK = 63.8.

What are similar triangles?

Comparable triangles are those that resemble one another but may not be precisely the same size. Comparable items are those that share the same shape but differ in size.

This shows that when shapes are amplified or demagnified, they superimpose one another. This feature of similar shapes is often known as "similarity".

As per the triangles,

Let JK be = x.

GF/GH = JI/JK

⇒ 11/18 = 36 /x

⇒ x = 36 × 18/11

⇒ x = 63.8.

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Find, correct to four decimal places, the length of the curve of intersection of the cylinder4x^2 + y^2 = 4and the planex + y + z = 6

Answers

The length of the curve of intersection, correct to four decimal places, is 27.7128 units.

To find the length of the curve of intersection, we need to first parameterize the curve.

From the equation of the cylinder, we have:

4x² + y² = 4

Dividing both sides by 4, we get:

x²/1 + y²/4 = 1

This is the equation of an ellipse centered at the origin with semi-major axis a=1 and semi-minor axis b=2.

From the equation of the plane, we have:

x + y + z = 6

Solving for z, we get:

z = 6 - x - y

So the equation of the curve of intersection is:

r(t) = <t, 2sin(t), 6-t-2sin(t)>

where 0 <= t <= 2π.

To find the length of the curve, we need to integrate the magnitude of its derivative with respect to t:

L = ∫√(dx/dt)² + (dy/dt)² + (dz/dt)² dt

Taking the derivative of r(t), we get:

r'(t) = <1, 2cos(t), -1-2cos(t)>

So the magnitude of r'(t) is:

|r'(t)| = √(1² + (2cos(t))² + (-1-2cos(t))²) = √(9+9cos(t)²)

Therefore, the length of the curve is:

L = ∫_0⁽²π⁾ √(9+9cos(t)²) dt

This integral can be solved using the substitution u = tan(t/2), which gives:

L = 18∫_0∞ 1/√(1+u²) du

This integral can be evaluated using trig substitution, letting u = tanθ, which gives:

L = 18∫_0⁽π/²⁾ secθ dθ = 18 ln|sec(π/4)+tan(π/4)| = 18 ln(1+√2)

Using a calculator, we get:

L ≈ 27.7128

Therefore, the length of the curve of intersection, correct to four decimal places, is 27.7128 units.

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Trigonometric Functions

pls help and be sure to show all your work !! the second pic is the graph that needs to be plotted for the first question.

Answers

A) Values of y will be 1, 0, -1, 0, 1

B) and C) plot the values as shown in below figure.

Define the term Trigonometric Function?

Trigonometric functions are a set of mathematical functions that relate the angles and sides of right triangles.

A) for f(x) = cos x; the values of x-y chart are:

  x                   y = f(x)

  0                      1

  [tex]\frac{\pi }{2}[/tex]                      0

  [tex]\pi[/tex]                      -1

  [tex]\frac{3\pi }{2}[/tex]                     0

  [tex]2\pi[/tex]                     1

B) the points are plotted as given figure below.

C) Connects the dots to show the graph of y = cos x; sown in figure below please check it.

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4^(-x)=1/256
I believe it is x=4, but I need how to work it out pls thxxx

Answers

Answer:

x = 4

Step-by-step explanation:

using the rule of exponents

• [tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] , then

[tex]4^{-x}[/tex] = [tex]\frac{1}{4^{x} }[/tex]

and 256 = [tex]4^{4}[/tex]

then

[tex]\frac{1}{4^{x} }[/tex] = [tex]\frac{1}{4^{4} }[/tex]

so

[tex]4^{x}[/tex] = [tex]4^{4}[/tex]

since bases on both sides are equal, bot 4 then equate exponents

x = 4

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Similar shapes are shapes whose lengths are in equivalent ratio. [tex]\Delta ABC[/tex] and [tex]\Delta DE[/tex][tex]F[/tex] are similar because the side lengths of both triangles are in equivalent ratio (refer to attachment)

Step 1: Draw a random triangle [tex]\Delta ABC[/tex]

The lengths of two sides and an angle are:

[tex]AB=10[/tex]

[tex]BC=6[/tex]

[tex]\angle C=90^o[/tex]

Step 2: Draw and measure the length of DE

[tex]DE=15[/tex]

Step 3: Calculate the ratio

The corresponding line segment to DE is line segment AB.

So, the ratio (k) is:

[tex]k=\dfrac{DE}{AB}[/tex]

[tex]k=\dfrac{15}{10}[/tex]

[tex]k=1.5[/tex]

Step 4: Multiply the ratio by the other line segment in step 1

In (1), we have:

[tex]BC=6[/tex]

So:

[tex]EF=k\times BC[/tex]

[tex]EF=1.5\times6[/tex]

[tex]EF=9[/tex]

Step 5: Draw a circle with center F and radius EF  

The center of the circle is point F and the radius of the circle is 9 units

Step 6: Draw a ray from the center (i.e. point F) to DE

Refer to the attached image for

Triangle ABCTriangle DEFCircle with center F and radius 9Ray from F to DE

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let z be a standard normal random variable. find the values of a such that p({z > 1.35}) or {z > 2.34})

Answers

The values of a such that p({z > 1.35}) or {z > 2.34}) is 0.0981.

Let z be a standard normal random variable.

The standard normal distribution is a probability distribution that is symmetric around a mean of zero and has a standard deviation of one. It is also referred to as the Gaussian distribution or the normal distribution. This distribution is commonly used in the field of statistics to measure the likelihood of certain outcomes.

We have to determine the values of a such that p({z > 1.35}) or {z > 2.34}).

p(z > 1.35) + p(z > 2.34) = p(z > a)

After using the standard normal distribution table.

0.0885 + 0.0096 = p(z > a)

p(z > a) = 0.0981

p(z > 1.29) = 0.0981

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A home has gone up in value over several
decades and is now worth 1354% of its
original sale price of $23,000. What is the
value now?

Answers

Answer:

$31,142

Step-by-step explanation:

To convert a percentage into a decimal, you move the decimal two places to the left. 1354% converted into a decimal is 13.54.

$23,000 * 13.54 = $31,142

You run 3 laps around a rectangular field. The field is 100 meters long and 97 meters wide. How many meters do you run?

Answers

The distance around the rectangular field can be calculated using the formula:

distance = 2(length + width)

In this case, the length is 100 meters and the width is 97 meters. So the distance around the field is:

distance = 2(100 + 97) = 2(197) = 394 meters

Since you run 3 laps around the field, the total distance you run is:

total distance = 3 × distance around the field
total distance = 3 × 394 meters
total distance = 1182 meters

Therefore, you run 1182 meters in total.

what is the range of function m?

Answers

The range of the function m is [1, ∞). Thus, B is correct option.

What are a function's range and domain?

The dοmain οf a functiοn is the cοllectiοn οf values that can be plugged intο it. This set represents the x values in a functiοn like f. (x). A functiοn's range is the set οf values that the functiοn can take οn. This is the set οf values returned by the functiοn when we enter an x value.

Tο determine the range οf functiοn m, we must first determine the set οf all pοssible functiοn οutput values.

Looking at the function graph, we can see that the lowest point is (3, 1) and the highest point is (∞, ∞).

As a result, the function m has a range of [1, ∞).

We can write: in interval notation:

m ∈ [1, ∞) range.

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Desmond makes online purchase of R395 from Lineup store . he gets 46 and half % discount due to loyality points. calculate the amount of discount Desmond receive​

Answers

Desmοnd receives a discοunt οf R183.675. We can rοund this tο R183.18 οr R183.18, depending οn the desired level οf precisiοn.

What is discοunt?

We all are eager abοut availing discοunts, but we barely knοw hοw we get these discοunts. There is a prοper way tο calculate discοunt and that we dο by using a discοunt fοrmula. The discοunt rate fοrmula can either be extracted by subtracting the selling price οf the prοduct frοm its marked price οr by multiplying the discοunt rate οffered and the marked price οf the prοduct. In terms οf Mathematics, the fοrmula fοr discοunt is represented as belοw,

Accοrding tο given infοrmatiοn,

Tο calculate the discοunt Desmοnd receives, we first need tο find 53.5% οf the οriginal price. We can dο this by multiplying the οriginal price by 0.535:

R395 x 0.535 = R211.325

Sο, Desmοnd pays R211.325 fοr his purchase after the discοunt.

Tο find the amοunt οf discοunt, we need tο subtract the discοunted price frοm the οriginal price:

R395 - R211.325 = R183.675

Therefοre, Desmοnd receives a discοunt οf R183.675. We can rοund this tο R183.18 οr R183.18, depending οn the desired level οf precisiοn.

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Bill buys candy that costs $5 per pound. He will spend at least $40 on candy. What are the possible numbers of pounds he will buy? Use p for the number of pounds Bill will buy. Write your answer as an inequality solved for p.

Answers

Answer: 5p = 40

Step-by-step explanation:

5 X p = 40

5/5 40/5

p = 8

how do you simplify 7/8 + 3/4?

Answers

Answer:

13/8

Step-by-step explanation:

You first find the lcm of 8 and 4 which is 8

Then make a dividing line (/) with the lcm as the numerator.

After which you start diviing the lcm by each denominator of the two terms, and then multiplying with their numerators:

8/8 x 7 + 8/4 x 3 all over the lcm which is 8

(1 x 7 + 2 x 3)/8

(7 + 6)/8

13/8

A company's website states their oven temperatures
display may vary up to 35 degrees higher or lower than the temperature being
produced. Based on this statement, which of the following can represent an
oven's actual temperature, t, if it is displaying a temperature of 350 degrees?
x + 350 = 35
x - 350 =35
x + 35 = 350
x-35 = 350
x≤ 315 and x ≥ 385
315 ≤ x ≤ 385
-∞0 ≤x≤ ∞0

Answers

Answer:

The correct answer is:

315 ≤ t ≤ 385

This is because the oven temperature display can vary up to 35 degrees higher or lower than the actual temperature being produced. Therefore, the actual temperature (t) could be 35 degrees higher or lower than the displayed temperature (350 degrees), resulting in a range of possible temperatures from 315 to 385 degrees.

the simplest form of the expression sqr3-sqr6/sqr3+sqr6?

Answers

Answer:

1 - [tex]\frac{2\sqrt{2} }{3}[/tex]

Step-by-step explanation:

[tex]\frac{\sqrt{3}-\sqrt{6} }{\sqrt{3}+\sqrt{6} }[/tex]

rationalise the denominator by multiplying the numerator and denominator by the conjugate of the denominator.

the conjugate of [tex]\sqrt{3}[/tex] + [tex]\sqrt{6}[/tex] is [tex]\sqrt{3}[/tex] - [tex]\sqrt{6}[/tex]

= [tex]\frac{(\sqrt{3}-\sqrt{6})(\sqrt{3}-\sqrt{6}) }{(\sqrt{3}+\sqrt{6})(\sqrt{3}-\sqrt{6}) }[/tex] ← expand numerator/ denominator using FOIL

= [tex]\frac{3-\sqrt{18}-\sqrt{18}+6 }{3-\sqrt{18}+\sqrt{18}+6 }[/tex]

= [tex]\frac{9-2\sqrt{18} }{3+6}[/tex]

= [tex]\frac{9-2(3\sqrt{2}) }{9}[/tex]

= [tex]\frac{9-6\sqrt{2} }{9}[/tex]

= [tex]\frac{9}{9}[/tex] - [tex]\frac{6\sqrt{2} }{9}[/tex]

= 1 - [tex]\frac{2\sqrt{2} }{3}[/tex]

a coin is toosed and a number cube is rolled. sketch a list or tree digrams to represnts the sample space

Answers

The first of these two events is the number displayed on the cube. The result of the coin toss is the second. There should be two columns in this tree, one for each occurrence.

a list or tree digrams to represnts the sample space in the given below figure . Observe the first column first. Let the number cube's result be. The following six values are possible:. Six branches, one for each outcome, result from that proceed to the following column. Let the result of the coin toss be. There would always be two possible results for, regardless of the number obtained for.

The first of these two events is the number displayed on the cube. The result of the coin toss is the second. There should be two columns in this tree, one for each occurrence.

Observe the first column first. Let N represent the number cube's result. Six values are possible: 1, 2, 3, 4, 5, and 6. Six branches, one for each outcome, result from that. proceed to the following column. Let the result of the coin toss be. There would always be two possible results for, regardless of the number obtained for.

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the actual question is :

The number cube is rolled and a coin is tossed . How can you sketch a tree diagram to represent the sample space ?

Given x-intercepts of (-1,0), (6, 0) and point (-2, 2) that lies on the
quadratic graph, which equation below represents the correct quadratic
equation in standard form?

Answers

Answer:

y = (-1/3)x^2 - 2x + 5/3

Step-by-step explanation:

To find the quadratic equation that passes through these points, we can start by using the standard form of a quadratic equation:

y = ax^2 + bx + c

We know that the graph passes through the point (-2,2), so we can substitute these values into the equation:

2 = a(-2)^2 + b(-2) + c

Simplifying this equation, we get:

4a - 2b + c = 2

We also know that the graph has x-intercepts at (-1,0) and (6,0). This means that when x = -1 and x = 6, the value of y (i.e., the height of the graph) is 0. We can use these two points to write two more equations:

0 = a(-1)^2 + b(-1) + c

0 = a(6)^2 + b(6) + c

Simplifying these equations, we get:

a - b + c = 0

36a + 6b + c = 0

Now we have a system of three equations:

4a - 2b + c = 2

a - b + c = 0

36a + 6b + c = 0

We can solve for a, b, and c using any method of solving systems of equations. One way is to use substitution:

From the second equation, we get:

c = b - a

Substituting this into the other two equations, we get:

4a - 2b + (b - a) = 2

36a + 6b + (b - a) = 0

Simplifying these equations, we get:

3a - b = 1

35a + 7b = -b

Multiplying the first equation by 7 and adding it to the second equation, we eliminate b:

21a = -7

a = -1/3

Substituting this value of a into the first equation, we can solve for b:

4(-1/3) - 2b + (b - (-1/3)) = 2

-4/3 - b + b + 1/3 = 2

b = -2

Finally, we can use either of the first two equations to solve for c:

c = a - b = (-1/3) - (-2) = 5/3

So the quadratic equation in standard form is:

y = (-1/3)x^2 - 2x + 5/3

Find the associated z-score or scores that represent the following standard normal areas(hint use the excel function =NORM.S.INV()
A. Middle 50 percent


B. Lowest 5 percent


C. Middle 90%

Answer all questions please(URGENT

Answers

The z-scores that represent the middle 50% of the standard normal distribution are between -0.6745 and 0.6745, the lowest 5% of the standard normal distribution is -1.645, and the 90% of the standard normal distribution is between -1.645 and 1.645.

What is the definition of standard normal variation?

The mean and variance of a standard normal distribution are both 0. A z distribution is another name for this.

Yes, here are the z-scores for the given standard normal areas:

A. Middle 50%: The area between the 25th and 75th percentiles corresponds to the middle 50% of the standard normal distribution. Using Excel's NORM.S.INV() function, we can calculate the z-scores that correspond to those percentiles as follows:

-0.6745 is the z-score corresponding to the 25th percentile.

The 75th percentile z-score is 0.6745.

As a result, the z-scores representing the middle 50% of the standard normal distribution range between -0.6745 and 0.6745.

B. Lowest 5%: The area to the left of the 5th percentile corresponds to the lowest 5% of the standard normal distribution. Using Excel's NORM.S.INV() function, we can calculate the z-score that corresponds to that percentile as follows:

The z-score associated with the fifth percentile is -1.645.

As a result, the z-score representing the bottom 5% of the standard normal distribution is -1.645.

C. Middle 90%: The area between the 5th and 95th percentiles corresponds to the middle 90% of the standard normal distribution. Using Excel's NORM.S.INV() function, we can calculate the z-scores that correspond to those percentiles as follows:

The z-score associated with the fifth percentile is -1.645.

The z-score associated with the 95th percentile is 1.645.

As a result, the z-scores representing the middle 90% of the standard normal distribution range between -1.645 and 1.645.

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Calculate the following limits?

Answers

The answer of the given question based on the limits the answers are as follows, (a)  lim f(x) = 1 , (b)  lim f(x) = 3 , (c)  lim f(x) = 3.

What is Graph?

A graph is  visual representation of data that shows the relationship between two or more variables. Graphs can be used to display  wide variety of information, including numerical data, functions, and networks. The most common types of graphs like line graphs, bar graphs, scatter plots, and pie charts.

Graphs are widely used in many fields, like science, economics, engineering, and social sciences, to help people understand and analyze complex data. They are  powerful tool for visualizing trends, patterns, and relationships, and are often used to communicate findings to wider audience.

a) The limit of f(x) as x approaches 2 from the left:

We can see from the graph that as x approaches 2 from the left, f(x) approaches 1. Therefore, we can write:

lim f(x) = 1

x→2-

b) The limit of f(x) as x approaches 2 from the right:

Similarly, as x approaches 2 from the right, f(x) approaches 3. Therefore:

lim f(x) = 3

x→2+

c) The limit of f(x) as x approaches 2:

Since the limit from the left and the limit from the right exist and are equal, we can say that the limit of f(x) as x approaches 2 exists and equals the common value of the left and right limits. Therefore:

lim f(x) = 3

x→2

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Find the equation of the tangent through the point (2,-2) to the hyperbola x² + y² = 16​

Answers

Answer: y = -x

Step-by-step explanation:

The equation of the hyperbola is x² - y² = 16.

Taking the derivative of the equation with respect to x, we get:

2x - 2yy' = 0

y' = x / y

At the point (2,-2), we have x = 2 and y = -2. Thus, the slope of the tangent is:

y' = 2 / (-2) = -1

So, the equation of the tangent through the point (2,-2) is:

y + 2 = -1(x - 2)

y + 2 = -x + 2

y = -x

find a parameterization of each of the following surfaces, in terms of sines, cosines, and hyperbolic sines and cosines

Answers

Parameterizing a surface over a rectangle Parameterizing the surface z = x²+2y² over the rectangular region R defined by -3 ≤ x ≤ 3, −1 ≤ y ≤ 1 are falls under the range of R.

Let's start by expressing x and y as functions of u and v. Since x varies between -3 and 3 over R, we can use the following parameterization for x:

x = u

where u varies between -3 and 3. Similarly, since y varies between -1 and 1 over R, we can use the following parameterization for y:

y = v

where v varies between -1 and 1.

Next, we can use these parameterizations for x and y to express z as a function of u and v. Substituting x = u and y = v into the equation z = x² + 2y², we get:

z = u² + 2v²

So, the parameterization of the surface z = x² + 2y² over the rectangular region R is given by:

x = u, y = v, z = u² + 2v²

where -3 ≤ u ≤ 3 and -1 ≤ v ≤ 1.

The parameterization allows us to study various properties of the surface z = x² + 2y² over the rectangular region R.

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Complete Question:

Parameterizing a surface over a rectangle Parameterizing the surface z = x²+2y² over the rectangular region R defined by -3 ≤ x ≤ 3, −1 ≤ y ≤ 1.

1. Solve. 4x+4=4
O 1
0 0
O 3
O
-3

Answers

4x+4=4 /-4
4x=0 /:4
x=0

Answer:

x = 0

Step-by-step explanation:

4x+4 = 4

Subtract 4 from both sides:-

4x+4-4 = 4-4

4x = 0

Divide both sides by 4:-

4x/4 = 0/4

x = 0

Let f(x)=-3x-1 and g(x)=x - 4 Find (fxg)(-1).​

Answers

The value of the equation (fxg)(-1) is 10.

What is Equation?

An equation is a mathematical statement that shows that two expressions are equal. It usually includes variables, which are represented by letters or symbols, and constants, which are fixed values.

What are the different types of Equations?

There are several types of equations in mathematics. Here are some of the most common types:

Linear equation: An equation of the form "ax + b = c", where "a", "b", and "c" are constants and "x" is the variable. The graph of a linear equation is a straight line.Quadratic equation: An equation of the form "ax² + bx + c = 0", where "a", "b", and "c" are constants and "x" is the variable. The graph of a quadratic equation is a parabola.

Cubic equation: An equation of the form "ax³ + bx² + cx + d = 0", where "a", "b", "c", and "d" are constants and "x" is the variable. The graph of a cubic equation is a curve that can have one or two humps.

In the given question,

To find (f x g)(-1), we need to evaluate the product of f(-1) and g(-1).

First, we find f(-1):

f(-1) = -3(-1) - 1 = 2

Next, we find g(-1):

g(-1) = -1 - 4 = -5

Now, we can find the product (f x g)(-1):

(f x g)(-1) = f(-1) x g(-1) = 2 x (-5) = -10

Therefore, (f x g)(-1) = -10.

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TRUE/FALSE. When calculating probabilities, combinations and permutations are used to find the number of outcomes in a sample space.

Answers

TRUE. Combinations and permutations are used in probability calculations to determine the number of possible outcomes in a sample space.

When calculating probabilities, combinations and permutations are used to find the number of outcomes in a sample space. Why?

When order is important, permutations are utilized, and when order is not important, combinations are used. The formula P(n,r) = n!/(n-r)!, where n! signifies the factorial of n, and the expression C(n,r) = n!/r!(n-r)!, give the number of permutations of n items taken r at a time and the number of combinations of n objects taken r at a time, respectively.

It is possible to count the number of ways that a subset of items can be chosen from a larger set using both permutations and combinations. These ideas are crucial for estimating probabilities because they let us know how many different outcomes could satisfy a certain condition.

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Locate the absolute extrema of the function on the closed interval

Answers

Answer:

The absolute extrema is minimum at (-1, 2/9)

Step-by-step explanation:

Absolute extrema is a logical point that shows whether a the curve function is maximum or minimum.

Forexample a curve in the image attached. A, B and C are points of absolute maxima or absolute maximum. and P and Q are points of absolute minima or minimum.

Remember A, B, C, P, Q are critical points or stationary points.

How do we find absolute extrema?

The find the sign of the second derivative of the function.

From the question;

[tex]{ \sf{g(x) = \sqrt[3]{x} }} \\ \\ { \sf{g(x) = {x}^{ \frac{1}{3} } }} \\ [/tex]

Find the first derivative of g(x)

[tex]{ \sf{g {}^{l}(x) = \frac{1}{3} {x}^{ - \frac{2}{3} } }} \\ [/tex]

Find the second derivative;

[tex]{ \sf{g {}^{ll} (x) = ( \frac{1}{3} \times - \frac{2}{3}) {x}^{( - \frac{2}{3} - 1) } }} \\ \\ { \sf{g {ll}^{(x)} = - \frac{2}{9} {x}^{ - \frac{5}{3} } }}[/tex]

Then substitute for x as -1 from [-1, 1]

[tex]{ \sf{g {}^{ll}(x) = - \frac{2}{9} ( - 1) {}^{ - \frac{5}{3} } }} \\ \\ = \frac{ - 2}{9} \times - 1 \\ \\ = \frac{2}{9} [/tex]

Since the sign of the result is positive, the absolute extrema is minimum

Pleasee help!
Highlight the vertex, and name the angle on the image below

Answers

Answer:

Highlight "x" then it's an acute angle

Step-by-step explanation:

Suppose we want to choose 2 letters, without replacement, from the 3 letters A, B, and C.

Answers

The numbers of ways in which we can select the letters without replacement are: a. order relevant - 6 ways. b. order not relevant- 3 ways.

What are combinations and permutations?

Both permutations and combinations count the number of possible ways to select a particular number of things from a bigger collection of options. The distinction is that whereas combinations ignore the order of the components, permutations do. In other words, combinations don't care about the order in which the elements are selected, but permutations require arranging the components in a certain sequence.

Given that, we want to choose 2 letters, without replacement.

a. When the order is relevant we have the following choices:

3 options for the first letter and 2 options for the second letter, that is:

3 x 2 = 6 ways

b. If the order is not relevant we use combinations:

n C r = n! / (r! (n-r)!)

3 C 2 = 3! / (2! (3-2)!) = 3

Hence, the numbers of ways in which we can select the letters are: a. order relevant - 6 ways. b. order not relevant- 3 ways.

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The complete question is:

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