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As more bulbs are added in parallel, the current strength will decrease OR. As more bulbs are added in parallel, the current strength will increase.

The terminal velocity as it falls through still air is 4.65154 in/s.

The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m

                                                                            = 3.175 × 10^-5 m

Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa

 So the formula for drag force is:

                Fd = 6πηrv

  where,  v is the velocity.

Now to attain terminal velocity acceleration must be zero.

            →  W = Fd

                ρVg = 6πrηv

                ρ × 4/3 πr³×g = 6πrηv

                           v = 2/9 × ρgr³/ η

                           v =  2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6

                           v = 0.1181  m/s

                           v = 4.65154 in/s

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Answer:6m/s

Explanation:as you can see before twenty seconds there was no change in speed,but between twenty to thirty seconds,the speed changed from 0m/s to 6m/s,so change in speed is 6m/s.

The speed of an object between 20 and 30 seconds shown in the graph is 70 m/s.

Given:

Time, ΔT = 30-20 = 10s

Acceleration, a = 7 m/s²

The speed can be computed from the acceleration and time. The standard unit of velocity is meters per second.

For the given case, the speed can be computed from the acceleration and time given in the graph.

The speed is given as:

a =  v/t

v = at

v = 7×10

v = 70 m/s

Hence, the speed of an object between 20 and 30 seconds shown in the graph is 70 m/s.

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Answer:

A

Explanation:

m1vi1 + m2vi2 = (m1+m2)vf

(0.5×3) + (1×0) = (1 + 0.5)vf

1.5=1.5vf

therefore final speed/velocity is 1m/s

m = mass

vi = velocity initial

vf = velocity final

If a star is moving towards Earth, shift towards the blue end of the spectrum, this is called blue shift. If the star is moving away from Earth the light from that star will be red and is called red shift .

The faster a star moves towards the earth, the more its light is shifted to higher frequencies. In contrast, if a star is moving away from the earth, its light is shifted to lower frequencies on the color spectrum

if a star is moving towards Earth, it appears to emit light that is shorter in wavelength compared to a source of light that isn't moving. Because shorter wavelengths correspond to a shift towards the blue end of the spectrum, this is called blue shift.

If the star is moving away from Earth, its light will lose energy to reach Earth, therefore the light from that star will be red and is called red shift

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Answer:

As a pendulum moves toward the equilibrium position, velocity increases and acceleration decreases. As the pendulum moves away from the equilibrium position, velocity decreases and acceleration increases.

Explanation:

Using the law of conservation of energy, we know that Em1=Em2.

Em1 (at the highest point) = Eg + Ek, where Ek is 0

Em2 (at the equilibrium point) = Eg +Ek, where Eg is 0

This makes sense. At the highest point, the pendulum is at its maximum height. At this point, however, it stops moving, so its velocity is 0. At the equilibrium point, the pendulum is at its lowest height (i.e. h=0). At this point, however, its moving at its maximum velocity. This velocity is constant, which means that acceleration is 0.

Answer:

1) Increases

2) Decreases

3) Decreases

4) Increases

5) Maximum

Explanation:

As a pendulum moves toward the equilibrium position, velocity

✔ increases

and acceleration

✔ decreases

. As the pendulum moves away from the equilibrium position, velocity

✔ decreases

and acceleration

✔ increases

. Velocity is at a

✔ maximum

when acceleration is zero.

Thinking about Planck's law, the Red star would give off the most orange light.

According to Planck's Law, distinct atoms and molecules can emit or take in power in discrete portions simplest. The smallest amount of strength that can be emitted or absorbed inside the form of electromagnetic radiation is called quantum.

Planck's Law describes the quantity of spectral radiance at a particular wavelength radiated through a black body in equilibrium. The equation is E=hv.

The floor temperature of a celeb determines the color of mild it emits. Blue stars are warmer than yellow stars, which are hotter than red stars. The bright orange celebrity Arcturus is particularly noteworthy for its massive right motion, The color is a characteristic of their floor temperatures.

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Fire spreading from a wall to a nearby couch due to radiant heat transfer is an example of heat reflectivity.

When sunlight and other light sources strike a material's surface, its reflectance is measured. This number can be used to characterize a surface's characteristics in terms of surface finish. Another name for reflection is reflectivity.

This is a measurement of the amount of energy that material reflects at a specific wavelength. A value between 0 and 1 can also be used to represent reflectivity (or a percentage between 0 and 100).

Sigma and other top businesses have created a range of other forms of heat reflective fabric in the 50 years after the creation of space blankets, including Fabric and aluminum foil laminates, fabric laminates with metalized thin films.

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In the writing of ionic chemical formulas the value of each ion's charge is crossed over in the crossover rule.

Rules for naming Ionic compounds

The oxidation state of each ion is also important, thus in the crossover rule, the value of each ion's charge is crossed over.

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The emf of the battery is 23.071 V.

What is emf?

The emf (electromotive force) is defined as the original potential applied across a circuit when there is no internal resistance.

The emf is given by the formula,

E=V+I*r

where E is the emf of the battery, V is the potential applied across the circuit, I is the current through the circuit and r is the internal resistance of the battery.

What is power?

The power is the product of the square of the current and the resistance. The formula of the power P for the internal resistance r is,

P=I^(2)*r

Given I=55.0 A and P=37 W, substitute I=55.0 A and P=37 W in the above formula and solve it to calculate r.

37 = (55.0)^2*r

r=37/ (55.0)^2

r=0.0122 ohm

Given V=22.4 V, substitute  I=55.0 A, r=0.0122 ohm, and V=22.4 V in the formula of emf to calculate the value of emf.

E=22.4+(55.0)*(0.0122)

E=23.071 V

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An array of this size can produce an average of 350-850 kWh of AC energy per month.

Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.

Solar panel systems are measured in terms of kW. A common size solar panel array is usually around 5kW. An array of this size can produce an average of 350-850 kWh of AC energy per month.

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C. The work done by the 5500.0 N force on the elevator is 275,000 J.

The work done by the 5500.0 N force on the elevator is calculated as follows;

W = Fd

where;

W = 5500 x 50

W = 275,000 J

Thus, the work done by the 5500.0 N force on the elevator is 275,000 J.

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The quantum theory opines that electron in atoms occur a discreet energy levels.

The quantum theory was initiated by the idea of Max plank. In this idea, energy was viewed as occurring in discrete amounts. This idea was first applied to the phenomenon of the black body radiation hence the Plank Equation; E = hf.

Now Neils Bohr pushed the idea further by putting forward the opinion that when an electron in atom is found in an orbit, it does not radiate energy. The atom was thus visualized as being composed of several energy levels and radiation can only occur when an electron moves from a higher to lower energy level.

This implies that the energy of each electron in an atom is quantized. Thus implies that it has a value which an integral multiple of a fundamental amount.

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The work done on the box is 350 Joule.

Work is done on an object when the displacement of the object is not perpendicular to the direction of the applied force. The unit of Work is Joule (J)

Given that 70N force pulls a box straight up 5 m above the ground.

Work is the product of force F and the distance S. That is,

W = F x S

Where

Substitute the two parameters into the formula above

W = 70 x 5

W = 350 J

Therefore, the work done on the box is 350 Joule.

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The free-fall acceleration on the second planet is one-fourth the value of the first planet.

Calculation:

Consider the mass of planet A to be, M

               the mass of planet B to be, Mₓ = M

               the radius of planet A to be, R₁

               the radius of planet B to be, R₂

The acceleration due to gravity on planet A's surface is given as:

g = GM/R₁²      - (1)

Similarly, the acceleration due to gravity on planet B's surface is given as:

g' = GM/R₂²                           [where, R₂ = 2R₁]

   = GM/4R₁²    -(2)

From equation 1 & 2, we get:

g/g' = GM/R₁² ÷ GM/4R₁²

g/g' = 4/1

Thus we get,

g' = 1/4 g

Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.

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Wave power involves  conversion of mechanical energy to electrical energy.

We know that energy conversion is part of the postulations of the first law of thermodynamics which states that energy can neither be created nor destroyed but can be transformed from one form to another.

Now, the wave power can convert the regular up and down movement of the ocean waves into a source of electricity. This implies that the energy that is taking place here is the conversion of mechanical energy to electrical energy.

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The car will halt at a minimum distance of 98.57 meters on a rainy day having a friction coefficient of 0.109.

Calculation of the minimum distance-

Provided that :

                                  = 52 x 0.278 m/s = 14.45 m/s

the regular force exerted on the car,

[tex]F_{N} = mg[/tex]

Along X-direction, the force is

[tex]F_{x} = ma_{x}[/tex]

Friction acts in the opposite way along the x-axis

[tex]-f_{friction} = ma_{x}[/tex]

⇒-μ[tex]F_{N} = ma_{x}[/tex]

⇒-μmg = [tex]ma_{x}[/tex]

⇒[tex]a_{x} =[/tex] μg

Utilizing the motion equation-

v² = u²+ 2 .a. s

The final speed, v=0 m/s

⇒0² = (14.45)² - 2 μg .s

⇒2 * 0.109 *9.8 *s = (14.45)² = 208.8

⇒s = 208.8 / 2.14 =  97.57 m

It is concluded that the car will halt at a minimum distance of 98.57 meters.

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Answer:q

Explanation:

There are different refractive errors that are common and some of them are:

This refers to the study of light phenomena that deflects when it passes through a medium in an oblique manner to another medium of a varying density.

Hence, we can see that there are everyday examples of refraction in simple terms which occurs and some of them are:

Hence, we can see that your question is incomplete, so I gave you a general overview to help you get a better understanding of the concept of refraction.

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Straight upward

the ball moves in the forward direction with your walking speed at all times. If you want the ball to land in your hand when it comes back down, you should toss the ball straight upward.

Projectile motion is the motion of an object thrown (projected) into the air.

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The distance between the drone and the car will be 20,3 m/s.

In physics, velocity is a quantity that identifies the displacement of a body in a given time. Thus, the average velocity measures in an average time interval, the speed of displacement of a body.

With that being said, Suppose that both car and drone starts from 0 and move towards north and east, respectively. So, after T time:

Distance covered by the car, [tex]y = 20.T.m[/tex]

Distance cover by the drone, [tex]x = 6.T.m[/tex]

Considering the elevations of 25m, the actual distance between them at any T instant:

[tex]A = \sqrt{(20T)^{2} } + (6T)^{2} +25^{2}[/tex]

Speed, [tex]V = \frac{ds}{dt} = \frac{[2(20T).20+2(6T).8}{\sqrt{(20.5)^{2}+(6T)^{2}+25^{2} } }[/tex]

[tex]V = 20,3 m/s[/tex]

So, the distance between the drone and the car will be 20,3 m/s.

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Answer:

20.3 m/s

Explanation:

dx / dt = 20 m / s

dy / dt = 6 m / s

dj / dt = ? when t = 5 s

The trick here is that the drone is flying at an elevation of 25 m.

x^2 + y^2 = j^2

Implicit Differentiation: 2x dx / dt + 2y dy / dt = 2j dj / dt

We are not given x and y values. Solve by d = vt. Distance = velocity * time

x = 20(5) = 100 m

y = 6 (5) = 30 m

Now we need to solve for j, but we need to solve the hypotenuse z of the right triangle first.

z = [tex]\sqrt{(100)^2 + (30)^2[/tex] ≈ 104.4 m

A mistake occurs when z is used as the distance between the drone and the car. Visualize the distance between the drone and the car as the right triangle where j is the hypotenuse, z is the x value, and 25 m is the y value.

j = [tex]\sqrt{(104.4)^2+(25)^2[/tex] ≈ 107.35 m

dj / dt = 1 / 2(107.35)((4000 + 360)) ≈ 20.3 m/s

P waves are faster than S waves and surface waves.

A surface wave in physics is a mechanical wave that travels at the interface of two different media. Gravity waves on the surface of liquids, like ocean waves, are an example that is frequently used. When two liquids with different densities come together, gravity waves can also form at that junction. Solid surfaces can experience elastic surface waves like Rayleigh or Love waves. The way that electromagnetic waves can be steered along a gradient in refractive index or at the boundary between two substances with varying dielectric constants is known as "surface wave" propagation. A guided wave that travels relatively close to the Earth's surface constitutes a ground wave in radio transmission.

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Answer:

gravity

Explanation:

gravity pulls anything with with weight towards the earth.

Answer

The reason why this occurs is because if there is any apparent wind being pushed towards the direction of the door, there will be an attempt of equalizing pressure and thus it will slam, or close very loudly when you even just push it shut with some effort.

Explanation

This has happened to me a variety of times, I would have the garage open, and it would be a little bit windy, and when I tried to close it, it would slam shut.

Airflow is a significant factor in the pressure appliance.

Your question at the end is correct (Differences in air pressure.)

Apologies for the late response, but I was interested in this as well.

The speed of Block A is 7.18 ft/s.

From energy conservation we know that the initial kinetic energy is equal to final kinetic energy.

Block A has weight of 60 lb.

Block B has weight of 10 lb.

In the question it is said that block A moves from rest at a distance of 5ft.

Relative motion constraint-

2sA + sB  =l

differentiating we get:

So,    2ΔsA + ΔsB  = 0

→  ΔsB = -2ΔsA

2 vA + vB  =0

→  vB = -2vA

Now applying principle of work and energy

TA0 +TBO + ΣwO-AB  =  TA+TB

1/2 mA v²A₀ + 1/2 mBv²B₀ + wAΔsA + wBΔsB = 1/2 mAv²A + 1/2 mBv²B

0 + 0 +6(5) - 10(10) = 1/2 (-60/32-2) v²A +1/2 (10/32.2) 2v²A

vA = 7.18 ft/s

So, the speed of block A is 7.18 ft/s.

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Thermal energy from the room-temperature water will continuously flow to the boiling water.

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Answer:

If you add the 2 velocity vectors you get the velocity of the third vector which is the (change in) velocity of the cue ball after striking the cushion

V * 2 * cos 45 = 4 * cos 45 = 2.83 m/s

Halo stars formed before disk stars and the protogalatic cloud(s) contained essentially no elements besides hydrogen and helium.

The hierarchical growth of huge galaxies like the Milky Way results in the natural by-product of extended star haloes. Our galaxy's star halo should contain traces of past merger events if this process is a significant contributor to the galaxy's expansion. However, it is difficult to reliably identify real halo stars. Aims. We have entered a new phase of galactic astronomy with the launch of the Gaia space telescope. Over two million stars the majority of which are in the solar neighbourhood have their locations, parallaxes, and proper motions listed in the initial Gaia data release. This sample will be expanded to include more than 1.5 billion stars in the second Gaia data release, of which 5 million will be fully phase-space characterized stars.

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Visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.

As the description itself says, visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.

Therefore, visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.

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The question you are looking for is given here:

Visualizing the body in the _____________ is significant because all observers have a common point of reference when describing and discussing its region.

The student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).

The total distance traveled by an object projected upward is calculated from third equation of motion a shown below.

v² = u² - 2gh

where;

at maximum height, the final velocity is zero, v = 0

0 = u² - 2gh

2gh = u²

h = u²/2g

The equation for the total distance an object has traveled during upward projection is "h = u²/2g".

d = (2vh)/g = (m/s x m) / (m/s²)  = (m²/s) / (m/s²) = m.s

Thus, the student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).

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