Plzz answer this question correctly

The frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

To find the answer, we need to know about the time of flight and range of projectile motion.

U= √{2.20×9.8/sin(73)} = 22.5m/s

= 2.73 s

Thus, we can conclude that the frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

Learn more about the range and time period of projectile motion here:

brainly.com/question/24136952

#SPJ1

Answer:

Every 15 minutes, remove the cover and check the temperatures of the samples using the three thermometers. Wait 30 seconds before recording the thermometer reading. Once the temperatures of the three samples are no more than a degree apart, record the temperatures.

(three 100-milliliter containers (each with a thermometer) in an ice bath inside an uncovered basin, with one container holding 50 grams of sand, one holding 50 grams of cold water, and one holding 100 grams of cold water)

Next, prepare the hot water.

-Fill each of the three 200-milliliter containers with 100 grams of hot tap water. Measure the mass using the mass scale.

(100 grams of hot water in a 200-milliliter container atop a mass scale)

-Prepare a hot-water bath by boiling water in a pot. Use the heat mitts to pour the hot water from the pot into the second tub. Fill the tub to a depth of about 2 inches. Carefully place the three containers of hot water into the bath without submerging them. Cover and wait for five minutes until the temperatures stabilize.

(three 200 mL containers (each holding 100 grams hot water) in a covered tub containing 2 inches of boiling water)

Prepare to mix the cold samples with hot water:

-Have three empty 300-milliliter mixing containers and three thermometers ready. Timing is important. Uncover the cold-water bath, and pour each cold sample into a different mixing container.

(three 300-milliliter containers (each with a thermometer), one holding 50 grams of sand, one holding 50 grams of cold water, and one holding 100 grams of cold water)

-Uncover the hot-water bath, and use a heat mitt to remove the three containers of hot water from the hot-water bath. Pour 100 grams of hot water into each mixing container.

(three 300 mL containers (each with a thermometer), one holding a 150-gram mixture of sand and hot water, one holding a 150-gram mixture of cold water and hot water, and one holding a 200-gram mixture of cold water and hot water)

Explanation:

A psychologist will need to have good linguistic intelligence in other to be successful.

This is referred to as a professional who specializes in the handling of mental health challenges in individuals.

It is best for such professional to have a good linguistic intelligence as the right words being said to the patient will solve the problem thereby bringing in more success.

Read more about Linguistic intelligence here https://brainly.com/question/15360566

#SPJ1

Answer:

B. Weight

Explanation:

Weight is the force of gravity exerted on a body

OR

It's the force exerted on a body by the influence of the earth's gravitational force

The two units for measuring the diameter of nucleus atom are femtometre and metre.

How do you measure the size of the nucleus ?

Nucleus size is expressed in fermi, often known as femtometers. between a lighter and a heavier nucleus. Despite its modest size, the nucleus contains the majority of an atom's mass. The weight or mass of the atom's nucleus and neutrons are determined by neutrons.

femtometre (fm), which equals [tex]10^{-15}[/tex] metre.

A nucleus' diameter largely depends as to how many particles it contains, from about 4 fm for a light nucleus like carbon to 15 fm for a heavy nucleus as lead.

Learn more about nucleus of an atom here :-

https://brainly.com/question/10658589

#SPJ1

According to mathematics, the planet's angle is stated as

dY=704 degrees.

We may demonstrate this by using Kepler's third law, which asserts that a planet's orbit squared is a function of cubed radius.

The equation for the period is often expressed numerically as

[tex](periodX / periodY)^2 = (radius X / radius Y)^3[/tex]

Therefore

(pX / pY)^2 = 4^3

(pX / pY)^2 = 64

[tex]\sqrt{(pX / pY )^2}= \sqrt{64}[/tex]

pX / pY=8

In conclusion, planet Y travels 8 times further than planet X does in the same amount of time since one orbit on planet X takes 8 times longer to complete.

planet Y travels ;

dY=8 * 88.0

dY= 704 degrees

Read more about Kepler's third rule

at brainly.com/question/1086445

#SPJ1

The correct option is D.   The initial momentum of the blue and green train combined during the collision is 200 kgm/s.

Apply the principle of conservation of linear momentum as follows;

Pi = m1v1 + m2v2

where;

Pi = (50 x 4) + 30(0)

Pi = 200 kgm/s

Thus, the initial momentum of the blue and green train combined is 200 kgm/s.

Learn more about momentum here: https://brainly.com/question/7538238

#SPJ1

The correct option is C.   Air resistance friction is not useful for an airplane because it slows it down.

Air resistance is the opposition to motion of an object caused by air flow.

High air resistance may cause turbulence during the motion of an air plane. This can lead to engine failure or some mishap during flight.

Air resistance is also a type of friction between air and another material such as airplane.

Friction between the air and the plane slows the airplane down. This is known as air resistance, or drag.

The faster an object travels through the air, the more it has to fight against drag.

Thus, air resistance friction is not useful for an airplane because it slows it down.

Learn more about air resistance here: https://brainly.com/question/1385438

#SPJ1

The minimum diameter of the steel wire is 7.58 mm.

Young's modulus = stress/strain

strain = e/l = (7.32 x 10⁻³ m) / (19.3 m) = 3.79 x 10⁻⁴

stress = Young's modulus  x  strain

stress = 200 x 10⁹ N/m²   x 3.79 x 10⁻⁴  = 7.59 x 10⁷ N/m²

stress = Force/Area

Area = Force/stress

Area = mg/stress

Area = (350 x 9.8) / (7.59 x 10⁷)

Area = 4.519 x 10⁻⁵ m²

Area = πd²/₄

πd²/₄ = 4.519 x 10⁻⁵ m²

πd² = 4(4.519 x 10⁻⁵)

d² = (4 x 4.519 x 10⁻⁵)/π

d² = 5.75 x 10⁻⁵

d = √(5.75 x 10⁻⁵)

d = 7.58 x 10⁻³ m

d = 7.58 mm

Thus, the minimum diameter of the steel wire is 7.58 mm.

Learn more about diameter here: https://brainly.com/question/390660

#SPJ1

The required horsepower engine is 32 horsepower.

The force of the 30 skiers is calculated as follows:

Mass of the skiers = 30 * 67kg = 2010 kg

Net force acting on the skiers along the x-axis

where f is the frictional force

The kinetic frictional force, f = μN

where

μ = The coefficient of the kinetic friction

N = normal reaction

Net force acting on the skiers along y axis, the

Fy = ma

N = mg cos θ

Substituting for N above

f = μk mg cos θ

Substituting for f in  (1)

F = mg sin θ + μk mg cos θ

F = mg(sinθ + μk cos θ)

Work done by the engine in pilling up the skiers, W = Fx

W = mg ( sinθ + μk cos θ)x

x = 300 m

W = (2010 kg) (9.81 m/s²) (sin 23° + (0.10) cos 23°) (300 m)

Work done, W = 2.86 * 10⁶ J

Time taken, t = 2.0 * 60sec = 120 s

1 horsepower = 746 W

Power = 2.86 * 10⁶/ 120 * 1/746

Power = 31.9 horsepower

In conclusion, the power of the engine is the ratio of the work done and time taken.

Learn more about power and work done at: https://brainly.com/question/1634438

#SPJ1

The density of the planet is determined as 1,974.26 kg/m³.

√(⁴/₃πGρ) = 2π/(2.35 x 3600)

where;

√(⁴/₃πGρ) = 2π/(2.35 x 3600)

√(⁴/₃πGρ) = 2π/8460

(⁴/₃πGρ)  = (2π/8460)²

⁴/₃πGρ = 4π²/(8460)²

ρ = 12π/(8460² x 4G)

ρ = (12π) / (8460² x 4 x 6.67 x 10⁻¹¹)

ρ = 1,974.26 kg/m³

Thus, the density of the planet is determined as 1,974.26 kg/m³.

Learn more about density here: https://brainly.com/question/6838128

#SPJ1

(a) The work done by the applied force is 26.65 J.

(b) The work done by the normal force exerted by the table is 0.

(c) The work done by the force of gravity is 0.

(d) The work done by the net force on the block is 26.65 J.

W = Fdcosθ

W = 14 x 2.1 x cos25

W = 26.65 J

W = Fₙd

W = mg cosθ x d

W = (2.5 x 9.8) x cos(90) x 2.1

W = 0 J

The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.

∑W = 0 + 26.65 J = 26.65 J

Thus, the work done by the applied force is 26.65 J.

The work done by the normal force exerted by the table is 0.

The work done by the force of gravity is 0.

The work done by the net force on the block is 26.65 J.

Learn more about work done here: https://brainly.com/question/8119756

#SPJ1

Answer: A train traveling initially at 16 m/s is under constant acceleration of 2 m/2. At a distance of 720m it will travel in 20 s, and the final velocity will be 56m/s.

Explanation: To find the answer, we need to know about uniformly accelerated motion.

                     [tex]u=16m/s\\a=2 m/s^2\\t=20s[/tex]

                      [tex]S=ut+\frac{1}{2}at^2[/tex]

                      [tex]S=(16*20)+\frac{2*20^2}{2} =720 m.[/tex]

                    [tex]v^2=u^2+2aS\\thus,\\v=\sqrt{u^2+2aS} =\sqrt{16^2+(2*2*720)} =56 m/s.[/tex]

Thus, we can conclude that, a train traveling initially at 16 m/s is under constant acceleration of 2 m/2. At a distance of 720m it will travel in 20 s, and the final velocity will be 56m/s.

Learn more about the uniformly accelerated motion here:

https://brainly.com/question/28105762

#SPJ4

A train experiencing constant acceleration of 2 m/s^2 is moving at an initial speed of 16 m/s. It will go 720 meters in 20 seconds, with a final velocity of 56 m/s.

Understanding uniformly accelerated motion is necessary in order to determine the solution.

                         [tex]S=ut+\frac{1}{2}at^2 \\S=720m\\where,\\u=16m/s, a=2m/s^2,t=20s[/tex]

                          [tex]v^2-u^2=2aS\\v=\sqrt{u^2+2aS} \\v=56m/s[/tex]

Thus, we may say that a train moving at 16 m/s initially experiences constant acceleration of 2 m/2. It will go 720 meters in 20 seconds, with a final velocity of 56 meters per second.

Learn more about uniformly accelerated motion here:

https://brainly.com/question/28105762

#SPJ1

The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

Apply the principle of conservation of energy,

E(up) - E(friction) = E(bottom)

mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²

[tex]v = \sqrt{2[\frac{mgd \ sin15 \ + \frac{1}{2}(M + m)u^2 \ -\mu (M + m)g cos\ 15 }{M + m}] }[/tex]

where;

u = √2gh

u = √(2gL sin15)

u = √(2 x 9.8 x 28 x sin 15)

u = 11.92 m/s

[tex]v = \sqrt{2[\frac{(30)(9.8)(70) \ sin15 \ + \frac{1}{2}(30 + 50)(11.92)^2 \ - 0.12 (30 + 50)9.8 cos\ 15 }{30 + 50}] }\\\\v = 16.52 \ m/s[/tex]

Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

Learn more about speed here: https://brainly.com/question/6504879

#SPJ1

The bigger object will move some distance because the initial and final momentum of the colliding particles are not zero.

The term momentum has to do with the product of mass and velocity. We know that during a collision, momentum is conserved. This implies that the momentum before collision is equal to the momentum after collision. Thus, the total momentum of the system is constant.

Given the fact that the initial and final momentum of the colliding particles are not zero, the  the big object is not going to stop immediately but must move some distance towards the smaller object.

Learn more about momentum:https://brainly.com/question/24030570

#SPJ1

The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

To find the answer, we need to know about the thermodynamic processes.

                                [tex]dU=dQ-dW[/tex]

                                  [tex]dU=0[/tex],

                             [tex]dU=C_pdT=0\\\\thus, dT=0\\\\or , T=constant\\\\i.e, T_1=T_2[/tex]

                          [tex]T_1=T_2=100^0C=373K[/tex]

                               [tex]W=RT*ln(\frac{V_2}{V_1} )=373R*ln(\frac{4}{\frac{4}{3} })\\ \\W=409.8R J[/tex]

Where, R is the universal gas constant.

Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

Learn more about thermodynamic processes here:

https://brainly.com/question/28067625

#SPJ1

The system's final temperature will be 373K, which is the same as its starting temperature. The system exerts 409.8R Joules of work.

We need to understand the thermodynamic processes in order to locate the solution.

                    [tex]dU=dQ-dW[/tex]     , It is 0 here.

                  [tex]dU=C_pdT=0\\dT=0\\T=constant\\T_1=T_2=373K[/tex]

As a result, the system's final temperature will be equal to its starting temperature.

                  [tex]W=RT ln(\frac{V_2}{V_1} )=373R*ln(3 )\\W=409.8R Joules[/tex]

R is the gaseous universal constant.

Thus, we can draw the conclusion that the system's end temperature will be 373K, the same as its starting temperature. The system exerts 409.8R Joules of work.

Learn more about the thermodynamic processes here:

https://brainly.com/question/28067625

#SPJ1

The speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.

v = √(GM/r)

where;

v = √(6.67 x 10⁻¹¹ x 5.98 x 10²⁴/3.57 x 6.37x 10³)

v = 1.32 x 10⁵ m/s

Thus, the speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.

Learn more about speed of satellite here: https://brainly.com/question/22247460

#SPJ1

Answer:

Wc = 7.84    weight of crown

Ww = 7.84 - 6.86 = .98       weight of water displaced

Density = 7.84 / .98 = 8     crown is 8 X that of water

Since gold has a density of 19.3 that of water the crown is certainly not 100 percent (if any) gold  

Answer:

See below

Explanation:

To change C to F°

  F = 9/5 C   + 32

     = 9/5 ( 45) + 32 = 113° F

To change F to C°   <= you could use the same equation...or re-earrange to:

C = 5/9 (F-32)

   = 5/9 ( 98.6 - 32) = 37° C

Similarly

100 C = 212 ° F

 to change C °  to  K    add 273.15   =  373.15 K    

A. The acceleration of the ball while it is in flight?

magnitude is 0 m/s² (magnitude is zero)

B. The velocity of the ball when it reaches its maximum height is 0 m/s (magnitude is zero)

C. The initial velocity of the ball 8.036 m/s upward

D. The maximum height reached by the ball is 3.29 m

Considering that the ball came to rest after 1.64s, it means the entire acceleration of the flight is zero as the ball was not moving in any form again.

At maximum height, the velocity of the ball is zero as it no longer has magnitude to keep going upwards. Hence the ball begins to ball down.

v = u - gt (since the ball is going against gravity)

0 = u - (9.8 × 0.82)

0 = u - 8.036

Collect like terms

u = 0 + 8.036

u = 8.036 m/s upward

h = ½gt²

h = ½ × 9.8 × 0.82²

h = 3.29 m

Learn more about motion under gravity:

https://brainly.com/question/20385439

#SPJ1

The period of M2, in years. is mathematically given as

T2= 134.3968years

M1 = 4.00 kg

M2 = 1.00 kg

T1 = 34.0 years.

Generally, the equation for is  mathematically given as

T2 = T1 (a2/a1)3/2

T2=  34.0  * (5/2)^{3/2}

T2= 134.3968years

In conclusion, the period of M2, in years

T2= 134.3968years

Read more about period

https://brainly.com/question/16061498

#SPJ1

Some of the techniques used by astronomers to determine the type of galaxy in which we live are:

This refers to the study of heavenly bodies and space and other things that space is made up of.

Hence, we can see that the reason why it is so difficult to determine the shape of our galaxy is that astronomers can only infer its presence from the motions of stars in the galaxy, and a precise shape is difficult to be determined.

Read more about astronomy here:

https://brainly.com/question/1141458

#SPJ1

The orbiting speed of the satellite orbiting around the planet Glob is 60.8m/s.

To find the answer, we need to know about the orbital velocity a satellite.

= 60.8m/s

Thus, we can conclude that the speed of the satellite orbiting the planet Glob is 60.8m/s.

Learn more about the orbital velocity here:

brainly.com/question/22247460

#SPJ1

Answer:

Yes.

Explanation:

When you move your hand from the cold water to the “warmer” (room temp) water, one hand feels warm.

As you move your hand from the warm water to the “colder” (room temp) water, that hand feels colder.

Although both hands experience the last bowl of water at the same temperature, your brain senses two

separate sensations. So the water feels “warm” or “cold” relative to the water your hand was in previously.

The greater the difference in temperature, the easier it is to sense a difference.

Answer: A treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the figure. The mass of the treasure chest is 75.6 kg. The tension in Rope A is 7.42x10^2 N, and the tension Rope B carries is 7.52x10^2 N. Then, the tension in rope C is 376N

Explanation: To find the correct answer, we have to know more about the Basic forces that acts upon a body.

                 [tex]T_A=7.42*10^2N\\T_B=7.54*10^2N[/tex]

                 [tex]T_C=T_B sin30\\thus,\\T_C=7.52*10^2*0.5=376N[/tex].

Thus, we can conclude that the tension in the rope c will be 376N.

Learn more about the basic forces on a body here:

https://brainly.com/question/28105672

#SPJ4

376N is the tension in rope C.

In order to determine the right response, we must have a better understanding of the fundamental forces that affect a body.

                              [tex]T_c=T_Bsin30\\T_c=7.52*10*2*0.5=376N[/tex]

Thus, we can infer that the rope's c tension will be 376N.

Learn more about the fundamental forces acting on a body here:

https://brainly.com/question/28105672

#SPJ1

The magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.

The acceleration of bock m2 is calculated from Net force exerted by the pulley.

F - T = m2a

F - m1a = m2a

F = m2a + m1a

F = a(m2 + m1)

a = F/(m1 + m2)

a = (0.03) / (0.04 + 0.02)

a = 0.5 m/s²

T = m1a

T = 0.04 x 0.5

T = 0.02 N

Thus, the magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.

Learn more about tension here: https://brainly.com/question/24994188

#SPJ1

(a) The  acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

(b) The velocity of the ball when it reaches its maximum height is zero.

(c) The initial velocity of the ball is 17.36 m/s.

(d) The maximum height it reaches is 15.36 m.

The acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

The velocity of the ball decreases as the ball moves upwards and eventually becomes zero at maximum height.

v = u - gt

at maximum height, final velocity, v = 0

0 = u - gt

u = gt

u = 9.81 x 1.77

u = 17.36 m/s

h = ut - ¹/₂gt

h = 17.36(1.77) - ¹/₂(9.81)(1.77²)

h = 15.36 m

Thus, the  acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

The velocity of the ball when it reaches its maximum height is zero.

The initial velocity of the ball is 17.36 m/s.

The maximum height it reaches is 15.36 m.

Learn more about maximum height here: https://brainly.com/question/12446886

#SPJ1

(a) The magnitude of the force that the magnetic field exerts on the loop is 0.042 N.

(b) The direction of the force that the magnetic field exerts on the loop will be out of the plane.

F = BIL

where;

emf = BVb

where;

emf = 2.6 x 3 x 0.018 = 0.1404 V

Current in the loop, I = emf/R = 0.1404/0.8 = 0.18 A

F = BIL

where;

F = 2.6 x 0.18 x 0.09 = 0.042 N

The direction of the force that the magnetic field exerts on the loop will be out of the plane.

Learn more about magnetic force here: https://brainly.com/question/13277365

#SPJ1

The kind of equation that can be used to differentiate the kind of separatrix that shows change on motion is

H = 2g/l.

A simple pendulum can be defined as the equipment that displays an oscillatory motion when a mass is tied on a rope and is suspended from it.

The various movements that occur using a simple pendulum is translational ( side to side) or continuous circle (oscillatory motion).

The equation that show that a change from one type of motion to another is H = 2g/l.

Learn more about motion here:

https://brainly.com/question/453639

#SPJ1