This problem is describing a system in which 100 kJ of energy is transferred from a cold reservior at 600 K to a hot one at 1050 K. This situation is opposed to the Clausius statement of the second law of thermodynamics, because it is widely known that heat is transferred from hot to cold systems.
However, we can calculate the total entropy change by using the following formula:
[tex]\Delta S =\Delta S _{Low}+\Delta S _{High}[/tex]
Which is broken down as follows:
[tex]\Delta S =\frac{-Q}{T_{Low}} + \frac{Q}{T_{High}}\\\\\\\Delta S =Q(\frac{-1}{T_{Low}} + \frac{1}{T_{High}})[/tex]
Since the heat is assumed to be equal for the both of them. Then, we plug in the given heat and temperatures to obtain:
[tex]\Delta S =100kJ(\frac{-1}{600K} + \frac{1}{1050K})\\\\\Delta S =-0.0714\frac{kJ}{K}[/tex]
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Ag+(aq)+e−→Ag(s)
How much time (in minutes) does it take to plate 19 g of silver using a current of 3.4 A ?
Answer:
Approximately [tex]83[/tex] minutes.
Explanation:
Look up the relative atomic mass of [tex]\rm Ag[/tex]: [tex]M({\rm Ag}) = 107.868\; \rm g \cdot mol^{-1}[/tex].[tex]\begin{aligned}Q &= e\, (n(e)) \\ &\approx 1.602 \times 10^{-19}\; \rm C \times 1.06 \times 10^{23} \\ &\approx 1.6987 \times 10^{4}\; \rm C \end{aligned}[/tex]/.
Avogadro's number: [tex]N_A \approx 6.02 \times 10^{23}\; \rm mol^{-1}[/tex].
Elementary charge: [tex]e \approx 1.602 \times 10^{-19}\; \rm C[/tex].
Calculate the quantity of [tex]\rm Ag[/tex] atoms to reduce:
[tex]\begin{aligned}& n({\rm Ag}) \\ &= \frac{m({\rm Ag})}{M({\rm Ag})} \\ &= \frac{19\; \rm g}{107.868\; \rm g \cdot mol^{-1}} \\ & \approx 0.176\; \rm mol\end{aligned}[/tex].
By the equation, it takes one electron to reduce every [tex]\rm Ag[/tex] atom. Thus, the number of electrons required to reduce [tex]0.176\; \rm mol[/tex] of [tex]\rm Ag\![/tex] atoms would be:
[tex]n(e) = n({\rm Ag}) \approx 0.176\; \rm mol[/tex].
[tex]\begin{aligned}N(e) &= n(e) \cdot N_{A}. \\ &\approx 0.176\; \rm mol \times 6.02 \times 10^{23}\; \rm mol^{-1} \\ & \approx 1.06 \times 10^{23}\end{aligned}[/tex].
Calculate the amount of charge (in coulombs) in that many electrons:
[tex]\begin{aligned}Q &= e\, (n(e)) \\ &\approx 1.602 \times 10^{-19}\; \rm C \times 1.06 \times 10^{23} \\ &\approx 16987.1 \; \rm C \end{aligned}[/tex].
A current of [tex]1\; \rm A[/tex] carries a charge of [tex]1\; \rm C[/tex] every second. Thus, the amount of time required for this current to carry that much electron would be:"
[tex]\begin{aligned}t &= \frac{Q}{I} \\ &\approx \frac{16987.1\; \rm C}{3.4\; \rm A} \\ &\approx 83.3\; \rm s \\ &\approx 5.00\times 10^{3}\; \rm s \\ &\approx 83\; \text{minutes} \end{aligned}[/tex].
formula of sodium bicarbonate
Answer:
NaHCO3
Explanation:
The three is small at the bottom at the end
What question would a student need to ask to form a compound with Group 16 nonmetals
A.
Will group 16 elements lose electrons to bond with group 2 in an XY format?
B.
Will group 16 elements gain electrons to bond with group 1 in an XY2 format?
C.
Will group 16 elements gain electrons to bond with group 2 in an XY format?
D.
Will group 16 elements lose electrons to bond with group 1 in an X2Y format?
Since nonmetals gain electrons, the correct question to ask about group 16 elements is; "Will group 16 elements gain electrons to bond with group 2 in an XY format?"
Group 16 elements are divalent and they form divalent negative ions. The periodic table is arranged in groups and periods. The elements in the same group have the same number of valence electrons. All elements in group 2 have six valence electrons.
If a wants to form a compound with the non metals of group 16, the correct question to ask is;"Will group 16 elements gain electrons to bond with group 2 in an XY format?"
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For the oxidation–reduction reaction equation
2Sc+3Br2⟶2ScBr3
indicate how many electrons are transferred in the formation of one formula unit of product.
In the formation of 1 formula unit of ScBr₃, 3 electrons are transferred.
Let's consider the following balanced redox reaction.
2 Sc + 3 Br₂ ⟶ 2 ScBr₃
We can identify both half-reactions.
Oxidation: 2 Sc ⟶ 2 Sc⁺³ + 6 e⁻
Reduction: 6 e⁻ + 3 Br₂ ⟶ 6 Br⁻
As we can see, 6 electrons are involved in the formation of 2 formula units of ScBr₃. Thus, 3 electrons are involved in the formation of 1 formula unit of ScBr₃.
In the formation of 1 formula unit of ScBr₃, 3 electrons are transferred.
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The structure of Disodium edta
Answer:
EDTA disodium salt | C10H14N2Na2O8
Explanation:
Determine how many grams of Al(OH)3 will be required to neutralize 216 mL of 0.367 M HCl according to the reaction:
3HCl + Al(OH)3 > AlCl3 + 3H20
mol = conc × v
= 0.367 × 0.216
= 0.0792 mol HCl
3 mol HCl = 1 mol Al(OH)3
0.0792 mol HCl = x
x = 0.0792/3 × 1
= 0.0264 mol Al(OH)3
Al(OH)3 = 27 + 3(16 +1) = 78 g/mol
mass = mol x molar mass
= 0.0264 × 78
= 2.0592 g
I don't know if it's correct
Yes thank you Great explanation
Answer:
you're welcome
pls help me right now
Answer:
LETTER
1. D. PURE SUBSTANCES CAN BE FURTHER BROKEN DOWN INTO SIMPLER SUBSTANCES.
2.A
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When two volumes of hydrogen gas react with one volume of oxygen gas, two
volumes of gaseous water are formed. Modify the diagram you made for #2 to
represent molecules of hydrogen, oxygen and water in this reaction
Complete and balance the following redox reaction in basic solution
Cr2O7^2-(aq) + Hg(l) ----> Hg^2+(aq) + Cr^3+(aq)
Answer:
balanced in ACID not BASE
Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O
Answer
Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O
Explanation:
Cr2O7^2-(aq) + Hg(l) ----> Hg^2+(aqH) + Cr^3+(aq)
add H^1+ (acid) to capture the O and make 7 water molecules
Cr2O7^2-(aq) + Hg(l) + H^1+ ----> Hg^2+(aqH) + Cr^3+(aq) + 7H2O
Cr goes from +6 to +3 by gaining 3 e
Hg goes from 0 to +2 by losing 2 e
we need 3 Hg for every 2 Cr
so
Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O
2 Cr on the right and left
Net 12 positive charges on the right and the left
3 Hg on the right and left
14 H on the right and left
the equation is balanced
we cannot balance the equation in a basic solution with OH^1-
we have plenty of O in the dichromate ion. we need to convert it to water which take free H^1+ from the acid
Brainliest fast before 5:35 no link no bot
Answer:
1.) 7
2.) 5
3.) stable
4.) 5A
5.) 5
6.) The properties would be more stable to property of phosphorous because same group and valenve electronics and they also have same chemical
Explanation:
The rest i dont know
A local water retention pond was found to have elevated mass concentration of mercury of 14 ng per liter. You would like to collect some mercury for your homemade perpetuum mobile machine. How many moles of mercury can you get you collect and process the entire volume of 1250 m3 of the water in the pond?
The number of moles of mercury can you get you collect and process the entire volume of 1250 m3 of the water in the pond is 8.7 × 10^-5 moles.
First, we must convert the concentration of mercury in the pond to molar concentration using the relation;
Mass concentration = Molar concentration × molar mass
Molar concentration = Mass concentration /molar mass
Molar mass of mercury = 201 g/mol
Molar concentration = 14 × 10^-9 g/201 g/mol = 6.97 × 10^-11 M
Volume of solution = 1250 m3 or 1250000 L
Number of moles = concentration × volume
Number of moles = 6.97 × 10^-11 M × 1250000 L
Number of moles = 8.7 × 10^-5 moles
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There are two valence electrons in a He atom. What is the average ionization energy of the two valence electrons in He
Answer:
A: Calcium is a group 2 element with two valence electrons. Therefore, it is very reactive and gives up electrons in chemical reactions. It is likely to react with an element with six valence electrons that “wants” to gain two electrons. This would be an element in group 6, such as oxygen.
Describing Chemical Reactions
Project: Modeling the Conservation of Mass
Answer:
Step 1: Prepare for the project.
a) Read the entire Student Guide before you begin this project.
b) If anything is unclear, be sure to ask your teacher for assistance before you begin.
c) Gather the materials you will need to complete this project.
Step 2: Review the chemical reaction.
a) The chemical reaction that you will model is shown below. Calcium oxide (CaO) is a white
solid with a crystalline structure. It is made by heating limestone, coral, sea shells, or chalk,
which are composed mainly of calcium carbonate (CaCO3). During the heating process,
carbon dioxide (CO2) is released and calcium oxide (CaO) is produced. Commercially,
calcium oxide is called lime. One of the oldest uses of lime is to make mortar, a substance
used in construction to secure bricks, stones, and blocks together.
CaCO3 CaO + CO2
Step 3: Build a model of the reactant.
a) Use gumdrops and toothpicks to build a model of CaCO3.
b) Select one color of gumdrop for calcium, a second color for carbon, and a third color for
oxygen. Be sure to include a key of your chosen color scheme with your model.
c) Use the periodic table to help you determine the number of bonds each atom will form.
Step 4: Build models of the products.
a) Use gumdrops and toothpicks to build a model of CaO and a model of CO2.
b) Be sure to use the same colors of gumdrops for calcium, carbon, and oxygen as you did in
Step 3. Include a key of your chosen color scheme with your models.
c) Use the periodic table to help you determine the number of bonds each atom will form.
Step 5: Type one to two paragraphs that describe your models and explain the conservation of
mass in the chemical reaction.
a) Create a new blank document. Type your name at the top.
b) Type one to two paragraphs that describe your models and relate them to the law of
conservation of mass. Your document should:
i. identify the names of the reactants and products in the reaction.
ii. identify the number of molecules that make up the reactants and products.
iii. identify the type and number of atoms in each molecule of the reactants and products.
iv. explain what happens during the chemical reaction.
v. explain how mass is conserved during the chemical reaction.
Step 6: Evaluate your project using this checklist.
If you can check each criterion below, you are ready to submit your project.
Did you create an accurate model of calcium carbonate (CaCO3)? Your model should include
the correct number of gumdrops for each element in calcium carbonate, consistent use of
colors for elements in calcium carbonate, and the correct number and placement of toothpicks
(bonds).
Did you create an accurate model of calcium oxide (CaO)? Your model should include the
correct number of gumdrops for each element in calcium oxide, consistent use of colors for
elements in calcium oxide, and the correct number and placement of toothpicks (bonds).
Did you create an accurate model of carbon dioxide (CO2)? Your model should include the
correct number of gumdrops for each element in carbon dioxide, consistent use of colors for
elements in carbon dioxide, and the correct number and placement of toothpicks (bonds).
Did you type one to two paragraphs that describe your models and relate them to the law of
conservation of mass? Your document should include the names of the reactants and
products in the reaction, the number of molecules that make up the reactants and products,
and the type and number of atoms in each molecule of the reactants and products. It should
also explain what happens during the chemical reaction and how mass is conserved during the reaction
Step 7: Revise and submit your project.
a) If you were unable to check off all of the requirements on the checklist, go back and make
b) When you have completed your project, submit your models to your teacher for grading.
c) Submit your document through the virtual classroom. Be sure that your name is on it.
Step 8: Clean up your workspace.
a) Clean up your workspace. Return any extra materials to your teacher and throw away any trash.
Explanation:
Br2(l) + 2Nal(aq) — 12(s) + 2NaBr(aq)
Which elements are oxidized and reduced in the reaction?
(1 point)
O Sodium (Na) is oxidized, and bromine (Br) is reduced.
O Bromine (Br) is oxidized, and iodine (1) is reduced.
O Bromine (Br) is oxidized, and sodium (Na) is reduced.
Olodine (I) is oxidized, and bromine (Br) is reduced.
Iodine (I) is oxidized, and bromine (Br) is reduced. The correct option is the last option - lodine (I) is oxidized, and bromine (Br) is reduced.
To determine which elements are oxidized and reduced,
First, we will define the terms Oxidation and Reduction
Oxidation is simply defined as the loss of electrons. It can also be defined as increase in oxidation number.
Reduction is defined as the gain of electrons. It can also be defined as decrease in oxidation number.
The given chemical equation is
Br₂(l) + 2NaI(aq) → I₂(s) + 2NaBr(aq)
Oxidation number of Bromine decreased from 0 to -1.
Therefore, Bromine is reduced.
Oxidation number of Iodine increased from -1 to 0.
Therefore, Iodine is oxidized.
Oxidation number of sodium did not change.
Therefore, Sodium is neither oxidized nor reduced.
Hence, Iodine (I) is oxidized, and bromine (Br) is reduced. The correct option is the last option - lodine (I) is oxidized, and bromine (Br) is reduced.
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What is the net charge of C
Explanation:
Sorry, I don't know, but I can tell you that when an atom, or a body, has the same amount of positive charges (protons) and negative charges (electrons), it is said to be electrically neutral. ... The net charge corresponds to the algebraic sum of all the charges that a body possesses.
Answer: Neutral carbon-12 (or any carbon atom) has 6 electrons with a total negative charge of 6e- orbiting a nucleus with a total positive charge of 6e+, so that the total net charge is zero. The nucleus is made up of 6 protons, each with a positive charge of e+, and 6 neutrons, each with zero charge.
Explanation:
What is the mass in grams of one mole of sulfur? (round to 3 sig figs)
Answer:
This tells you that one mole of sulfur atoms, S , has a mass of 32 g
What will happen to the temperature of an object if the kinetic energy of the particles increases?
The temperature of an object will increase if the kinetic energy of the particle increases.
Kinetic energy is an energy that is said to be in motion. According to the kinetic molecular theory of ideal gas, the particles of the gas are usually moving in constant random motion and they exert no force on each other.
Also, the temperature varies directly proportional to the average kinetic energy of the gas particles. As a result, when the kinetic energy of the particles increases, the temperature will also increase.
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A mixture of solids containing a ketone, a carboxylic acid, and an amine, are dissolved in DCM. What is the best way to begin an extraction to separate the amine from the mixture
There are different ways of extraction. The best way to begin an extraction to separate the amine from the mixture is to extract with dilute NaOH.
An acid-base extraction is often used in the extraction of carboxylic acids from the organic layer and thereafter into the aqueous layer.NaOH is known to be the most common compound that is used to convert a carboxylic acid into its more water-soluble ionic carboxylate form.
But if the mixture has a compound that you want, and that can react with NaOH, another milder base such as sodium bicarbonate is preferably used.
See full question below
A mixture of solids containing a ketone, a carboxylic acid, and an amine, are dissolved in DCM. What is the best way to begin an extraction in order to separate the carboxylic acid from the mixture?
A) Extract with dilute NaOH
B) Extract with dilute HCl
C) Extract with dichloromethane
D) Extract with water
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3.833 kJ of heat is required to convert a 36.8 g sample of ethyl
alcohol from the solid to liquid phase. What is the heat of
fusion of ethyl alcohol in J/g?
The heat of fusion of the given sample of the ethyl alcohol is 104.16 J/g.
The given parameters:
heat required to convert 36.8 g sample of ethyl alcohol, Q = 3.3833 kJmass of the ethyl alcohol, m = 36.8 gThe heat of fusion of the given sample of the ethyl alcohol converted from solid to liquid phase is calculated as follows;
[tex]H_f = \frac{Q}{m} \\\\H_f = \frac{3.833 \times 10^3\ J}{36.8 \ g} \\\\H_f = 104.16 \ J/g[/tex]
Thus, the heat of fusion of the given sample of the ethyl alcohol is 104.16 J/g.
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HELP PLEASE I NEED THIS
What is the lowest point of a wave called?
Amplitude
Crest
Frequency
Trough
Answer:
the lowest point of the wave is called Trough
Answer:
Trough is the correct answer
Explanation:
The highest part of the wave is called the crest. The lowest part is called the trough.
Pleeeeasee someone who’s good at chemistry?! 10 grade
ASAP
I’ll give points, just help please
Answer:
what's the question?
Explanation:
I'll help
Which of the following elements would be a +2 cation?
Vanadium (V)
Oxygen (0)
Helium (He)
Strontium (Sr)
Answer:
helium
Explanation:
What is the coefficient for O2 in the balanced version of the following chemical equation: C2H4+O2→CO2+H2O
Answer:
3
Explanation:
Here's the balanced equation;
C2H4 + 3O2 → 2CO2 + 2H2O
C ⇒2 C ⇒1 x 2 = 2
H ⇒4 H ⇒2 x 2 = 4
O ⇒3 x 2 = 6 O ⇒ (2 x 2) + (2 x 1) = 6
The coefficient that has been added as the coefficient to O2 is 3.
C2H4 + 3O2 → 2CO2 + 2H2O.
the given equation has 2oxygen atoms on the reactant side and 3 oxygen atoms on the product side
so to make it equal we have to add 3 as coefficient of O2 on the reactant side.
Therefore the correct answer to the equation C2H4 + 3O2 → 2CO2 + 2H2O is 3.
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In a constant-pressure calorimeter, 55.0 mL of 0.340 M Ba(OH), was added to 55.0 mL of 0.680 M HCI. The reaction caused the temperature of the solution to rise from 22.21 °C to 26.84 °C. If the solution has the same density and specific heat as water (1.00 g/mL and 4.184J/g • °C.) respectively), what is A4 for this reaction (per mole H,O produced)? Assume that the total volume is the sum of the individual volumes.
Answer:
Ba(OH)2 + 2 HCl → BaCl2 + 2 H2O
The reactants are present in equimolar amounts, so there is no excess or limiting reactants.
(0.0500 L) x (0.600 mol/L HCl) x (2 mol H2O / 2 mol HCl) = 0.0300 mol H2O
(4.184 J/g·°C) x (50.0 g + 50.0 g) x (25.82 - 21.73)°C = 1711.256 J
(1711.256 J) / (0.0300 mol H2O) = 57042 J/mol = 57.0 kJ/mol H2O
Explanation:
Why do we need to be more careful of how we use our water
Answer:
because water is actually a limited natural resource
Explanation:
although most of the earth is made up of water , dasalination plants are super expensive and hard to use. Thus slowly due to severely low rainfall over the years the earth is slowly depleting on levels of fresh water thats why we need to be careful how we use water :D !
Soldium and sulphur compound form formula
Answer:
Na2S
Explanation:
hope this helps
Write the balanced molecular chemical equation for the reaction in aqueous solution for ammonium sulfate and iron(II) chloride. If no reaction occurs, simply write only NR. ☐⁴⁻ ☐³⁻ ☐²⁻ ☐⁻ ☐⁺ ☐²⁺ ☐³⁺ ☐⁴⁺ 1 2 3 4 5 6 7 8 9 0 ☐₁ ☐₂ ☐₃ ☐₄ ☐₅ ☐₆ ☐₇ ☐₈ ☐₉ ☐₀ + ( ) → ⇌ (s) (l) (g) (aq) Ir N Fe O Am Cl NR S H Ch Reset
The balanced molecular chemical equation for the reaction is (NH4)2SO4(aq) + FeCl2(aq) -------> FeSO4(aq) + 2NH4Cl(aq).
The rule for writing a balanced chemical reaction equation is that the number of atom of each element on the right hand side must be the same as the number of atoms of the same element on the left hand side of the reaction equation. This is achieved by performing an atom count.
The balanced molecular chemical equation for the reaction in aqueous solution for ammonium sulfate and iron(II) chloride is;
(NH4)2SO4(aq) + FeCl2(aq) -------> FeSO4(aq) + 2NH4Cl(aq)
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So My friend has started her you know what and she scared to call her mom what should I do I'm sorry if this question is personal anything but I'm kind of confused cuz she's scared to call her mom her mom is gone so she needs some advice the best person who got the best answer will receive a brainly and 50 more points
Answer: so I was really scared to tell my mom and I was always thinking about how should I tell here but she should tell her mom an just said I think I started my thing her mom wont get mad she got it to and every girl goes thru that so your not alone
Explanation; she does not have to tell her mom but her mom could helpo her and give her tips
Answer:
Tell her to calm down and tell her mum because her mom knows better and would be able to put her through better than anyone could have ever.
A buffer was prepared by mixing 1.00 mole of ammonia and 1.00 mole of ammonium chloride to form an aqueous solution with a total volume of 1.00 liter. To 500 mL of this solution was added 30.0 mL of 1.00 M NaOH. What is the pH of this solution?
Answer:
Idek sorry
Explanation:
So sorry i think its 1.00