Question 1 of 10
Whích three factors are used to calculate gravitational potential energy?
A. The height of an object
B. The chemical formula for an object
O C. The density of an object
O D. The acceleration of an object due to gravity
O E. The mass of an object
F. The velocity of an object

Answers

Answer 1

Answer:

A., D., and E.

Explanation:

Gravitational potential energy is mgh, the values represented by answers E., D., and E., respectively.

Have a wonderful day!

Answer 2

Answer:

Im late. A D and E

Explanation:

The factors that affect an object's gravitational potential energy are its height relative to some reference point, its mass, and the strength of the gravitational field it is in. The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.


Related Questions

Explain why the following statement is either true or false: The idea that all matter consists of the elements was first introduced a few hundred years ago

Answers

So i say false because 500 years is more than a few years but i could be wrong. Because of Aristotle’s idea that al matter is made up of only four elements it was accepted for over 2000 years but only around 500 years ago did scientists start discovering all of the elements known today.

It is a true statement that the idea that all matter consists of elements was first introduced a few hundred years ago.

What is the matter?

Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

Individuals have believed that earth, air, water, and fire are the only four elements that make up matter for roughly two thousand years.

For more than two thousand years, Aristotle's theory that all matter is composed of just four elements was accepted, but only around 500 years ago did scientists begin to find all of the elements that are currently recognized.

Beginning around five hundred years ago, scientists started learning about all of the elements that are currently recognized.

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7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is
8.85 kg-m/s. What is the mass of the ball?

Answers

Answer:

Approximately [tex]1\; \rm kg[/tex]. (Assumption: [tex]g = 9.8\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Let the mass of this ball be [tex]x\; \rm kg[/tex].

Initial gravitational potential energy of this ball: [tex]m \cdot g \cdot h \approx (39.2\, x) \; \rm J[/tex].

Just before the ball hits the ground, all [tex](39.2\, x)\; \rm J[/tex] of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:

[tex]\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}[/tex].

Therefore, right before hitting the ground, the velocity of the ball would be:

[tex]\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}[/tex].

The momentum [tex]p[/tex] of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] would be [tex]p = m \cdot v[/tex]. Rewrite this equation to find an expression for mass [tex]m\![/tex] given velocity [tex]v\![/tex] and momentum [tex]p\![/tex]:

[tex]\displaystyle m = \frac{p}{v}[/tex].

Right before collision, the momentum of this ball is [tex]p = 8.85\; \rm kg \cdot m \cdot s^{-1}[/tex] while its velocity is [tex]v \approx 8.85\; \rm m \cdot s^{-1}[/tex]. Therefore, the mass of this ball would be:

[tex]\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}[/tex].



What is the net force of a scooter acting on the road with an impulse of 550 Ns for 10s.

Answers

Answer:

55N

Explanation:

Impulse is the product of Force and Time

Impulse = Force * Time

Given

Impulse = 550Ns

Time = 10s

Force = Impulse/Time

Force = 550/10

Force = 55N

Hence the net force on the scooter is 55N

When you push an object, it pushes back with an equal and opposite force

Answers

Answer:

I would say false

Explanation:

Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.

A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.

Answers

9.81m/s^2 x .27 = 2.6487m/s

The velocity of hitting the ground is 4.86 m/s and the velocity after hitting the ground is 4.53 m/s.

What is Velocity?

Velocity can be defined as the direction of movement of the body or object. Velocity is a vector quantity. It is the rate of change of displacement.

Given data,

Initial velocity when dropped(u)=0 m/s

Distance traveled(s)=1.21 m/s

Distance traveled after leave the ground(s1) = 1.05 ms

According to third law of motion,

v² = u² + 2gs

Initial velocity u=0

v² = 2gs or v = [tex]\sqrt{2gs}[/tex]

​by putting the value of s

v (hitting) = √(2 × 9.8 × 1.21) = [tex]\sqrt{23.71}[/tex] = 4.86m/s

After leaving ground at 1.21 m final velocity will be zero

So, velocity just after left the ground will be

2 = √(2 × 9.8 × 1.05) = [tex]\sqrt{20.58}[/tex] = 4.53m/s

So, velocity of hitting the ground is 4.86 m/s and after hitting is 4.53 m/s.

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An ice skater accelerates backward for 5.0 second to final speed of 12m/s. If the acceleration backward was at a a rate of 1.5m/s2 what was the skater's initial speed

Answers

Answer:

Initial velocity, U = 4.5m/s

Explanation:

Given the following data;

Final velocity, v = 12m/s

Time, t = 5 seconds

Acceleration, a = 1.5m/s²

To find the initial velocity, we would use the first equation of motion.

[tex] V = U + at[/tex]

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

12 = U + 1.5*5

12 = U + 7.5

U = 12 - 7.5

Initial velocity, U = 4.5m/s

How do limiting factors impact Pacific Coast organisms?

Answers

Answer:

Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration. When organisms face limiting factors, they show logistic growth (S-shaped curve, curve B: Figure below). ... Limiting factors determine the carrying capacity of a population.

Explanation:

walks 5 meters in 5 seconds what is the average speed

Answers

Answer:

10 is the speed

Explanation:

this is y

its in the pic plz help

Answers

Answer:

Hand soap: basic

chocolate milk: neutral

apple juice: acidic

shampoo: acidic

mouthwash: acidic

tap water: basic

Explanation:

Check your PH scale

1-6 = acidic

7 = neutral

8-14 = basic

The air pressure inside a car tire is

3.00 atm, and it creates 41,500 N

of force pushing out on the tire.

What is the surface area of the

inside of the tire?

(Unit = m^2)

Answers

Answer:

[tex]A=0.136\ m^2[/tex]

Explanation:

The air pressure inside a car tire is 3 atm = 303975 Pa

The force of 41,500 N  of force pushing out on the tire.

We need to find the surface area of the inside of the tire. The pressure acting on an object is given by :

[tex]P=\dfrac{F}{A}\\\\A=\dfrac{F}{P}\\\\A=\dfrac{41500}{303975}\\\\A=0.136\ m^2[/tex]

So, the surface area of the inside of the tire is [tex]0.136\ m^2[/tex].

If a 5.5 kg object experiences 15 N of force for .15 seconds what is the speed change

Answers

The speed change : Δv = 0.41 m/s

Further explanation

Given

mass = 5.5 kg

Force = 15 N

time = 0.15 s

Required

the speed change

Solution

Newton 2nd's law

Impulse and momentum

F = m.a

F = m . Δv/t

F.t = m.Δv

Input the value :

15 N x 0.15 s = 5.5 kg x Δv

Δv = 0.41 m/s

An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?

Answers

Answer:

i. 15.6 m/s

ii. I = 1.44 KNs

Explanation:

The impulse, I, on a body is the product of force applied on it and the time it acts.

i.e I = F x t

Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.

i. mass, m, of the player = 92 kg

initial velocity of the player, u = 9.4 m/s

final velocity of the player, v = 6.2 m/s

Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.

So that,

change in velocity of the player = final velocity - initial velocity

                                          = 6.2 - (-9.4)

                                         = 6.2 + 9.4

                                         = 15.6 m/s

change in velocity of the player is 15.6 m/s

ii. Impulse, I = m(v - u)

                    = 92 x 15.6

                    = 1435.2

Impulse on the player is 1.44 KNs.

2. What is the y-component of a 95.3 N force that is exerted at 57.1

degree to the horizontal, *

Answers

Answer: 80N

Explanation:

The y-component would be the magnitude of the force multiplied by the sine of the angle.

[tex]95.3*\sin(57.1)=80N[/tex]

The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.

What is Force?

Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.

It can be expressed as:

F = m a

Where, F= Force

m= mass of the object

a= acceleration

In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,

so, For x component [tex]F_x[/tex] = Fcosθ

For y component [tex]F_y[/tex] = F sinθ

Given, F= 95.3 N ; θ= 57.1 °

[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]

Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.

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The planet Jupiter has much more mass than Earth. What would happen to an astronaut who landed on Jupiter

A. The astronaut would weigh somewhat less on Jupiter than on Earth

B. The astronaut would have the same weight on Jupiter as on Earth

C. The astronaut would be weightless on Jupiter

D. The astronaut would weigh mire on Jupiter than on Earth

Answers

Answer:

A. The astronaut would way somewhat less

The planet Jupiter has much more mass than Earth, is an astronaut who landed on Jupiter would weigh more on Jupiter than on Earth. Thus, the correct option is D.

What is Jupiter?

Jupiter is a planet of the Solar system of the Milkyway galaxy. It is made up of mostly hydrogen and helium gas. The temperature on this planet is extremely hot and an astronaut landing on this planet will experience free-floating in mid-Jupiter with no way of escaping.

Jupiter has more mass than that of the Earth thus, it exerts greater gravitational force than the Earth, and the weight is equal to the product of the mass and the gravitational acceleration. So, the mass of an astronaut will remain constant when he or she move from earth to jupiter however the weight of the astronaut will increase on jupiter.

Therefore, the correct option is D.

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How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?

Answers

Explanation:

Hey there!

Given that 4kg ball struck by 12 N force.

So, we need acceleration.

Force = Mass × Acceleration

And, so

Acceleration = Force / Mass.

Acceleration = 12/4

Acceleration is equal to 3m/s² in SI units.

Hope it helps :)

A 9 V battery produces a current of 18 amps. What is the resistance?

Answers

[tex]\bf{ \underline{Given:- }}[/tex]

[tex] \sf• \: Battery \: Voltage \: (V) = 9 \: v[/tex]

[tex] \sf• \: Current \: (I) = 18 \: Amps.[/tex]

[tex] \\ [/tex]

[tex]\bf{ \underline{To \:  Find :- }}[/tex]

[tex] \sf• \: The \: Resistance. [/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{Solution :- }}[/tex]

[tex] \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}[/tex]

[tex] \rightarrow \sf R = \frac{9}{18} [/tex]

[tex] \rightarrow \sf R = \frac{1}{2}[/tex]

[tex] \rightarrow \sf R = 0.5[/tex]

[tex] \\ [/tex]

[tex] \bf \purple{Therefore, \: the \: \: resistance \: \: is \: \: 0.5 \: Ω \: .}[/tex]

A book of mass 1.5 ,kg exerted a downward force on the table
What is the direction of this second force?

Answers

Answer:

up ward force it is balanced by dow ward force

An element has a charge of -3, has 8 protons, 11 neutrons, and electrons

Word Bank:
12 5 11 8 13
pls help

Answers

Question isn’t clear
If it’s asking the no of electrons then -
No of electrons =no of protons in an atom of a element ....therefore there are 11 electrons

If you have observed something about the world and want to


investigate it further, what are you seeking to do?


a Do background research


b Construct a hypothesis


C Ask a question


d Report the results

Answers

Answer: a

Explanation: :)

scientific notation

1. 0,000034
2. 0,0054
3. 346574
4. 0,00125
5. 348954

Answers

Answer:

1. 3.4 x10^-5

2. 5.4 x10^-3

3. 346574

4. 12.5x10^-4

5. 348954

Hope this helps, please mark me brainliest if it does! :)

Comparing the Motion of Two Cars
Position vs Time
for Two Cars
D
Which statements describe the motion of car A and car
B? Check all that apply.
Car A and car B are both moving toward the origin.
Car A and car B are moving in opposite directions,
Car Ais moving faster than car B.
Car A and car B started at the same location.
Car A and car B are moving toward each other until
they cross over.
B
Position (m)
Time (s)

Answers

B, C, E

Hope this helps

no one can answer

why electrons are negetive? ​

Answers

Answer:

they're negative bc a proton is positive. a proton attracts an electron by the fact that opposite charges attract each other, while two electrons repel each other. Thus it shows that polarity of the charge on an electron and a proton is opposite.

Explanation:

Formula for angular acceleration

Answers

Answer:

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Explanation:

The angular acceleration is given by the relation as follows :

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Where

[tex]\omega_i\ and\ \omega_f[/tex] are the initial and final angular velocities

t is time

The SI unit of angular acceleration is rad/s². Hence, this is the required solution.

You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.


a)How long after it is launched does the walnut reach the ground?

b)How far does the walnut travel horizontally from launch point to landing point?

c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.

Answers

Answer:

a.3.51s

b.33.8m

c. 9.64,-22.9

Explanation:

(a) The time taken be "3.5083 sec".

(b) The distance will be "33.82 m".

(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".

Velocity and Direction

According to the question,

Speed, V₀x = 15 Cos (50.0°)

                   = 9.64 m/s

            V₀y = 15 Sin (50.0°)

                   = 11.49 m/s

Vertical displacement = -20.0 m

(a) We know the relation between displacement, time and acceleration

→  y = vt + [tex]\frac{1}{2}[/tex]at²

By substituting the values,

→ -20.0 = 11.49 t - 4.9 t²

  4.9 t² - 11.49 t - 20.0 = 0

                                   t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]

                                     = [tex]\frac{11.49 + 22.89}{9.8}[/tex]

                                     = 3.5083 sec

(b) We know the formula,

Distance = Speed × Time

or,

→ X = 9.64 t

      = 9.64 × 3.5083

      = 33.82 m

(c) Again by using the above relation, we get

    Vx = V₀x

          = 9.64 m/s

    Vy = V₀y - gt

By substituting the values,

          = 11.49 - 9.8 × 3.5083

          = 11.49 - 34.38

          = -22.89 m/s

Thus the response above is correct.

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A hockey puck that has a mass of 0.170 kg travels with a speed of 42.0 m/s.

What is the momentum of the puck?

Answers

Answer:

Momentum = 7.14 Kgm/s

Explanation:

Given the following data;

Mass = 0.170 kg

Velocity = 42m/s

To find the momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

Substituting into the equation, we have;

Momentum = 0.170 * 42

Momentum = 7.14kgm/s

Therefore, the momentum of the honey puck is 7.14 Kgm/s.

A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5.40 m and friction is ignored, what is the kinetic energy of the fish when it hits the water?

Answers

Here we go.
My abbreviations; KE = Kinetic Energy; GPE = Gravitational Potential Energy.

So first off, we know the fish has KE right when the bird releases it. Why? Because it has horizontal velocity after released! So let’s calculate it:
KE = 1/2(m)(V)^2
KE = 1/2(2)(18)^2
KE = 324 J

Nice!
We also know that the fish has GPE at its maximum height before release:
GPE = mgh
GPE = (2)(9.81)(5.40)
GPE = 105.95 J

Now, based on the *queue dramatic voice* LAW OF CONSERVATION OF ENERGY, we know all of the initial energy of the fish will be equal to the amount of final energy. And since the only form of energy when it hits the water is KE, we can write:
KEi + GPEi = KEf
(Remember - we found the initial energies before!)
(324) + (105.95) = KEf
KEf = 429.95J
And that’s you’re final answer! Notice how this value is MORE than the initial KE from before (324 J) - this is because all of the initial GPE from before was transformed into more KE as the fish fell (h decreased) and sped up (V increased).

If this helped please like it and comment!

3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?| I

Answers

Answer:

2.18 m/s.

Explanation:

need help someone please

Answers

Answer:

C would be the correct answer.

27. Julie and Ashwin were doing an experiment in the classroom. They
each had to move a 15 kg box. Julie was able to move her box, but
Ashwin was only able to move his after removing half the items in the
box. Which is true regarding the force he applies after removing the
items from the box?
a
He has to apply more force to lift the box
because the mass is greater.
b
He has to apply less force to lift the box
because the mass has decreased.
С
He has to apply a different type of force after
changing the mass.
d
He has to apply the same amount of force to
the box to overcome gravity.

Answers

Answer:

b. He has to apply less force to lift the box because the mass has decreased.

Explanation: i just took a ck12 test and it was right lol

Which of the following represents a chemical change?
A. Melting
of ice to water.
B. Combustion of a firecracker
C. Salt dissolves in water
D. The iron stretched into wires-ductile and iron pounded into sheets-malleable.

Answers

The answer is B! Good Luck!!
I think it’s D In my opinion
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