question is in the photo​

Answer:

i don't know

Step-by-step explanation:

Around my room before you came.

Answer: around my room before you came

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

120 divided by three equals fourty

Answer:

-2x-6

Step-by-step explanation:

Distribute -2x -2(3) = -2x-6

Answer:

Height of the building = 115.4 ft.

Step-by-step explanation:

Height of building = AB + 46.4 + CD + 30.5

By applying Pythagoras theorem in ΔABP,

(26)² = (10)²+ (AB)²

676 - 100 = AB²

AB² = 576

AB = 24 ft

By applying sine rule in ΔCDE,

cos(60°) = [tex]\frac{CD}{CE}[/tex]

CD = CE × [tex]\frac{1}{2}[/tex]

CD = [tex]\frac{29}{2}[/tex]

CD = 14.5 ft

Total Height = 24 + 46.4 + 14.5 + 30.5

                     = 115.4 ft

Answer:

19 girls snd 10 boys

Answer:

1. y = 32

2. x = 6

3. -33 = n

4. a = -15.6

Step-by-step explanation:

1.

y-23=55

 +23  +23          (23 cancels)

y = 32

2.

x - 14 = -8

 +14      +14           (-14 cancels)

   x = 6

3.

-15 = n + 18

    -18       -18          (18 cancels)

    -33 = n

4.

18.3 + a = 2.7

-18.3        -18.3        (18.3 cancels)

         a = -15.6

Answer:

She spends $36.53

Answer:

1:2

Step-by-step explanation:

Answer:

68

Step-by-step explanation:

Their are 77 total, 77-3= 74-4= 70-2= 68

Answer:

14r+11

Step-by-step explanation:

3+5r+9r+8

=11+14r

Answer:

B

Step-by-step explanation:

Answer with explanation:

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. = 14

Median or second quartile i.e. = 18

Third quartile or upper quartile i.e. =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. = 26

Median or second quartile i.e. = 30

Third quartile or upper quartile i.e. = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

   The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.

   And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e.

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

Hence, the number is : 1.5

Answer:

ive seen this before

Step-by-step explanation:

Answer:

2x(2a + b)

Step-by-step explanation:

4ax+ 2bx

= 2x (2a + b)

Answer:

The possible coordinates of point A are (-8,-4) or (-8,6)

Step-by-step explanation:

The distance between two points is given by the formula

[tex]d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }[/tex]

For point A [tex](x_{1} , y_{1})[/tex]; [tex]x_{1}= -8[/tex] and [tex]y_{1}[/tex] is unknown

For point B [tex](x_{2} , y_{2})[/tex]; (4,1) i.e [tex]x_{2}=4[/tex] and [tex]y_{2}=1[/tex]

and d = 13

Putting the values into the equation,

[tex]13= \sqrt{[(4-(-8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{[(4+8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{12^{2} + (1-y_{1})^{2} }\\13^{2} = 12^{2} + (1-y_{1})^{2} \\169 = 144 +(1-y_{1})^{2}\\169-144 = (1-y_{1})^{2}\\25 = 1 -2y_{1} +y_{1}^{2} \\y_{1}^{2} -2y_{1}+1-25 =0\\y_{1}^{2} -2y_{1}-24 =0\\y_{1}^{2} -6y_{1} + 4y_{1} -24 =0 \\y_{1}(y_{1}-6) +4(y_{1} -6) = 0\\(y_{1}+4)(y_{1}-6) =0\\(y_{1}+4)=0 or (y_{1}-6) =0[/tex]

[tex]y_{1}+4= 0[/tex] or [tex]y_{1}-6 =0[/tex]

[tex]y_{1} =-4[/tex] or [tex]y_{1} = 6[/tex]

Hence, the possible coordinates of point A are (-8,-4) or (-8,6)

Answer:

s< -7/11

Step-by-step explanation:

Answer:

A (3 Oranges For $1.02)

Step-by-step explanation:

3 Oranges for $1.02 is $0.34 for each Orange

4 Oranges For $1.52 is $0.38 for each Orange

6 Oranges for $2.46 is $0.41 for each Orange

5 Oranges for $1.75 is $0.35 for each Orange

Which Makes The First One The Cheapest Out Of All

Answer:

5.1

Step-by-step explanation:

hope it helps thank you

Answer:

y=-1/5x-1

Step-by-step explanation:

Answer:

4ft

Step-by-step explanation:

we will use the formula which states area of triangles is equal to base multiplied height divided by 2

base=5ft

height=8ft

area=5*8/2

=13/2

=6.5ft

this pic is not clear pls mention better next time I was confused what is 4ft and what is 8ft however if I have understood wrong I have also written the formula.

Answer: I need more to solve this

Step-by-step explanation:

Answer:

AB equals 4.535 (4.53478)

Answer:

B

Step-by-step explanation:

5/1 is not equal to 6/2 or 7/3 or 8/4

Answer:

The answer would be B instead of D

Answer:

for 3. the answer is 9

for 4. the answer is 12

Step-by-step explanation:

hope this helped!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

We are 95 percent confident that the mean word length for all papers submitted by students in humanities programs is between 20,995 words and 22,905 words

Step-by-step explanation:

The confidence interval is used to predict the mean for the entire humanities program, not just the sample.

Answer:

I think that the original price would be $30, but I'm not completely sure.

Step-by-step explanation:

Half (50%) of 40 would be 20, and half of 20 (25%) would be 10. Add 10 to 20 to get 30, because you are adding the %25 back to $20.

Hope this helps!

Answer:

$80

Step-by-step explanation:

25% = 1/4

To get original price multiply by 4:

$20 × 4 = $80

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:

1/2 M₀ = M₀ exp(12k)

for some decay constant k. Solve for this k :

1/2 = exp(12k)

ln(1/2) = 12k

k = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass M₀, the mass M remaining after time t is given by

M = M₀ exp(kt )

So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives

M = 590 exp(36k) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74