QUESTIONS ARE DOWN BELOW!!! ALL HELP WILL BE APPRECIATED AND I WILL TRY TO MARK BRAINLIEST (IF I CAN)

Answer:

About 71.77 degrees

Step-by-step explanation:

The starting leg is 2.3 km and the finishing leg is 6.2 km.

Using the law of cosines C^2 = A^2 + B^2 -2AB*cos(c) where A = 2.3 km, B = 6.2 km, C = 5.9 km, and angle c is the opposite angle to side C, we get:

5.9^2 = 2.3^2 + 6.2^2 -2(2.3)(6.2)*cos(c)

cos(c) = -(5.9^2 - 2.3^2 - 6.2^2)/(2*2.3*6.2)

c = 71.77 degrees

Answer:

72°

Step-by-step explanation:

when we have all the sides and need an angle, we use the law of cosine (the extended Pythagoras) :

c² = a² + b² - 2ab×cos(C)

where c is the side opposite of the angle C.

so, since the starting leg is 2.3 km, and the finishing leg is 6.2 km, we know that 5.9 km is the side opposite of the angle between the starting and finishing legs.

so, we have

5.9² = 2.3² + 6.2² - 2×2.3×6.2×cos(C)

34.81 = 5.29 + 38.44 - 28.52×cos(C)

-8.92 = -28.52×cos(C)

cos(C) = -8.92/-28.52 = 0.312762973...

C = 71.77418076...° ≈ 72°

Step-by-step explanation:

asleep percentage :- ( 8h /24h ) 100 % = 33.33%

awake percentage :- ( 16h / 24h ) 100 % = 66.67%

Answer:

The answer to your question is C. There a specific quantifiable target that we are interested in or trying to predict.

Step-by-step explanation:

I hope this helps and have a good day!

The smallest possible value of N is 23.

According to the statement

we have given that the sequence {1,2,3.....n}

and the sum is 241. we have to find the smallest value of n.

So, for this purpose we use summation formula of an arithmetic sequence

Sn = n /2 ( a1 +an )

Put the values in it then.

Note that the sum of the first 21 integers  is   21 * 22 /2  =  231...this isn't large enough as compare to given value.

And the sum of the first  22 integers  =   22 * 23 / 2  =   253

So    253 - 241  =  12 = omitted sum.....  

but  the sum of two consecutive integers must be odd

And......the sum of the first 23 integers is  23 * 24 / 2  = 276

So.......276 - 241   =  35    = omitted sum

So....the   consecutive integers omitted must be  17  and 18

So....... the smallest value of n  is   23

So, The smallest possible value of N is 23.

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The probability that battery lasts more than 3 years is [tex]e^{-0.6 }[/tex].

Parameter of Exponential Distribution

It is given that the average lifespan of the car battery = 5 years

⇒ μ = 5

And, we have to find the probability that the car battery lasts more than 3 years.

Now, the relation between the parameter of exponential distribution, λ and average, μ is given as,

1/ λ = μ

⇒ λ = 1/5

Calculating the Probability

The probability for the car battery to lasts more than 3 years is given by P(N>3). Here, N is the lifespan of the car battery.

P(N>3) = 1 - P(N≤3)

P(N>3) = 1-F(4)

Here, F is the exponential distribution  for the lifespan of the car battery.

P(N>3) = 1-(1-e^(-λn))

P(N>3) = [tex]e^{-3/5}[/tex]

Thus, the required probability is,

P(N>3) = [tex]e^{-0.6 }[/tex]

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Henry was 40 feet away from his original starting point. Using Pythagorean's theorem it is calculated.

The theorem says that,

In a right-angled triangle, the sum of squares of the lengths of two arms (opposite and adjacent sides) is equal to the square of the hypotenuse.

I.e, Consider a right-angled triangle ΔABC, where AC is the hypotenuse side of the triangle. So, according to the theory,

AC² = AB² + BC²

It is given that,

Henry walked on a flat field,

9 meters - towards the north

24 feet - towards the east

9 meters + 32 feet - towards the south

This can be shown in the diagram below.

In the diagram, the distance from the starting point is X, and the last point is  S.

To find the distance between these two points, a line is joined as shown in the diagram. Thus, it is formed as a right-angled triangle.

So, according to the Pythagorean theorem,

XS² = (24)² + (32)²

(here 32 feet is the only distance from the assumed point to the endpoint)

⇒ XS² = 1600 = 40²

∴ XS = 40 feet

So, Henry is 40 feet away from the original starting point.

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The geometric modeling is analyzed below.

Basic shapes are generally created using points, lines, circles, and triangles. Some basic shapes are rectangles, ellipses, triangles, and curves.

In geometric modeling, we make a cad model of parts for virtual analysis. By geometric modeling, one can model, and perform CAE analysis to optimize the product.

The best part is the period of doing all this is very small compared to practical manufacturing and looking at the product. In CAD one can very quickly alter the design and come up with new concepts in a very small span of time.

Here chances of error can be shorted easily and there is no wastage of material hence cost saving is there compared to practically manufacturing the part and altering it.

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Answer:

Gradient: 5

y-intercept: (0, 15)

Step-by-step explanation:

The gradient is usually just the same as the slope, so if we write the equation in slope-intercept form, y = 5x+15, the coefficient of x value (5) is the slope. The y-intercept is when x equals 0. Plug that in to get y = 15.

Using the concept of vertical and horizontal asymptotes, it is found that the function will have a horizontal asymptote at y = 2 and a vertical asymptote at x = 1 for a = -1 and m = 1.

In this problem, the function is:

[tex]f(x) = \frac{2x^m}{x + a}[/tex]

It has a vertical asymptote at x = 1, hence:

x + a = 0

1 + a = 0

a = -1

It has a horizontal asymptote at y = 2, hence:

[tex]\lim_{x \rightarrow \infty} f(x) = 2[/tex]

[tex]\lim_{x \rightarrow \infty} \frac{2x^m}{x + a} = 2[/tex]

[tex]\lim_{x \rightarrow \infty} \frac{2x^m}{x} = 2[/tex]

[tex]2^{m-1} = 2[/tex]

Then, since we want to simplify, the exponents at the numerator and the denominator have to be equal, hence m = 1.

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The addition of the polynomials [tex]2x^3+4x-6[/tex] and [tex]3x^3-8x+7[/tex] in the proper location on the grid is [tex]5x^3-4x+1[/tex]

How to find the addition of two polynomials is proper location on the grid ?

Polynomials addition in proper location means add the coefficient of same power of variable

So the addition of polynomials like this

[tex]2x^3+4x-6+3x^3-8x+7[/tex]

[tex]2x^3+3x^3=5x^3\\4x-8x=-4x\\-6+7=1[/tex]

The addition of the polynomials is [tex]2x^3+4x-6+ 3x^3-8x+7=5x^3-4x+1[/tex]

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The multiplicative inverse of -13/14 as in the task content is; -14/13.

The multiplicative inverse of a number x is given as; 1/x.

On this same note, it follows that since, the number whose multiplicative inverse is to be found is: -13/14, the multiplicative inverse is; -14/13.

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Answer:

x^7y^9

Step-by-step explanation:

Remembering the laws of indices and applying BODMAS

(x^6y^8)^3/x^2y^2

(x^6 * y^8)^3/x^2 * y^2

opening bracket

we get;

x^6+3 * y^8+3/x^2 * y^2

x^9 * y^11/x^2 * y^2

Applying law of indices at which when the values are the same during division we pick one coefficient and minus the power

therefore;

x^9-2 * y^11-2

x^7 * y^9

=x^7y^9

Answer:

x=7

Step-by-step explanation:

The angle of a straight line is 180 degrees, so let's just say the other angle to the right of 15x+34 is "a" that means that 15x + 34 + A = 180, and since the sum of interior angles of a triangle is 180 degrees, that means that 29 + A + 12x + 26 = 180, and we can define A using this equation in terms of x.

Original equation (sum of interior angles)

A + 29 + 12x + 26 = 180

Combine like terms

A + 12x + 55 = 180

Subtract 12x and 55 from both sides

A = -12x + 125

Original equation (since a line is 180 degrees)

15x + 34 + A = 180

Substitute -12x + 125 as A

15x + 34 + (-12x + 125) = 180

Combine like terms

3x + 159 = 180

Subtract 159 from both sides

3x = 21

Divide both sides by 3

x = 7

Answer:

  2.0 km

Step-by-step explanation:

The Law of Cosines can be used to find the third side of a triangle in which two sides and the angle between them are given.

The law of cosines tells us ...

  c² = a² +b² -2ab·cos(C)

Using the given values, we have ...

  c² = 4.2² +4.5² -2(4.2)(4.5)cos(26°)

Simplifying the equation, we get ...

  c² = 37.89 -37.8cos(26°) ≈ 3.91559

  c ≈ 1.979 . . . . km

The width of the strait is about 2.0 km.

IfIf AD BD, the following relationships that can be proved and why is: D. ΔACD ΔBCD, because of SAS.

The relationship that can be proved is ΔACD ΔBCD, because of SAS.

The reason is that m<CDA=M<CDB=90°

CD=CD

AD=BD

Hence, ΔACD=ΔBCD because of SAS. SAS congruence can tend to be proved when the length of the two side correspond and when  the angle between the two side is equal.

Therefore the correct option is D.

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Total number of teams are 10

An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation is one that includes a variable, such as x.

As given in the problem,

total number of students in class=30

now professor want to create study teams .

one team consist of 3 members,

lets suppose professor will form n teams

So,

3×n=30

solve this equation to get value of n

n=30÷3

n=10 teams

hence total number of teams are 10 .

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The set  (x1,x2)+(y1,y2)=(x1-x2, y1+y2) is not a vector space.

A set is a vector space if it satisfy all the addition operation axiom and scalar multiplication axiom.

Addition operation:

Commutativity -

(x1, x2) + (y1, y2) equals  (x1 - x2,  y1 + y2) equals  (y1, y2) + (x1, x2)

Associativity -

(x1, x2) plus ((y1, y2) plus (z1, z2)) = (x1, x2) + (z1 + y1, z2 + y2) = (x1+ y1 + z1, x2 + y2 + z2) =

((x1, x2)   + (y1, y2)) + (z1, z2)

Zero element -

(0, 0)  → (x1, x2) + (0, 0) = (x1, x2)

Inverse element -

(x1, x2)  adding (-x1, -x2) = (0, 0)

Scalar multiplication:

Compatibility -

a(b (x, y)) = a(bx, 0) = (abx, 0) = b(ax, 0) = b(a(x, y))

Identity element -

1(x, y) = (x, 0) ≠ (x, y)     [Identity element doesn’t exist for this operation.)

Distributivity law -

a((x1, x2) + (y1, y2)) = a(x1 + y1, x2 + y2) = (a(x1 + y1), 0) = a(x1, x2) + a(y1, y2)

Distributivity law -

(a + b)(x, y) = ((a + b)x, 0) = (ax, 0) + (bx, 0) = a(x, y) + b(x, y)

The scalar multiplication postulate is not fulfilled in this space (this operation does not have the identity element). It is therefore not a vector space.

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The height of squared pyramid is [tex]\frac{1}{3}h[/tex] unit.

A cube is a solid three-dimensional object with six square faces or sides, three of which meet at each vertex. One of the five Platonic solids, the cube is the only regular hexahedron. It contains 8 vertices, 6 faces, and 12 edges.

Volume of cube [tex]= (side)^3 \ unit^3[/tex]

Given the height of cube is [tex]h[/tex] unit.

Volume of cube is [tex]h^3 \ unit^3[/tex]

Let the height of squared pyramid is [tex]x[/tex] unit

Volume of squared pyramid is [tex]\frac{1}{3} h^{2} \times x \ unit^3[/tex]

According to the question, we have

Volume of cube = [tex]6 \times[/tex] volume of squared pyramid

[tex]\Rightarrow h^3=6 \times \frac{1}{3}h^2 \times x\\\Rightarrow h^3=2 \ h^2 \times x\\\Rightarrow h=2x\\\Rightarrow x= \frac{1}{2}h[/tex]

Therefore, the height of squared pyramid is [tex]\frac{1}{3}h[/tex] unit.

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Answer:

6

Step-by-step explanation:

Substituting in n = 2,

[tex]\frac{3(2)^{2}}{2}=6[/tex]

The function that could represent the price tag's height relative to the table top is  h(t) = 4sin (22) +4

The question is incomplete because the options are not given and hence the correct option is shown below

Which function could represent the price tag's height relative to the table top, h(t), after it has been rolling for e seconds?

A n(t) = 2008(832) +2

B. h(t) =-2005(522) +2

C h(t) = –2sin(572) +2

D. h(t) = 4sin (22) +4

Given diameter is 4 inches and the time given is  5 seconds and

the number of rotations given is 4

We need to find the function that could represent the price tag's height relative to the table top .

Diameter = 4

So, Radius will be D/2 = 4/2

Radius=2

time given is  5 seconds and

the number of rotations given is 4

So ,   5/4 = 2π/w

Therefore ,

W = 8π / 5

Therefore

h(t) = h(t) = 4sin (22) +4

Hence The function that could represent the price tag's height relative to the table top is  h(t) = 4sin (22) +4

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The simplified form of the expression [5.5(x+6 1/2)-(x+9 1/3)-(19-x)] is 11x/2 + 89/12

Given the expression;

5.5(x+6 1/2) - (x+9 1/3) - (19-x)

First, we convert 6 1/2, 9 1/3 and 5.5 to an improper fraction

6 1/2 = 13/2, 9 1/3 = 28/3 and 5.5 = 11/2

So, we have

(11/2)( x + 13/2 ) - ( x + 28/3 ) - ( 19 - x )

Next, we remove the parentheses

11x/2 + 143/4 - x - 28/3 - 19 + x

11x/2 + 143/4 - 28/3 - 19

11x/2 + 317/12 - 19

11x/2 + 89/12

Therefore, the simplified form of the expression [5.5(x+6 1/2)-(x+9 1/3)-(19-x)] is 11x/2 + 89/12.

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The rate at which the distance between the top of the ladder and the ground at that instant is decreasing at 42 meters per minute.

Given length of ladder 39 m and the rate at which the wall is increasing is 101, the bottom of the ladder is 36 m from the wall.

Let bottom is x and the length of wall be y.

We have to find the rate at which the distance between the top of the ladder and the ground at that instant.

we have to find dy/dt.

We have to apply pythagoras theorem first.

[tex]x^{2} +y^{2} =39^{2}[/tex]---------------1

[tex]x^{2} +y^{2} =1521[/tex]

put the value of x=36 in the above equation

[tex]36^{2} +y^{2} =1521[/tex]

[tex]y^{2} =225[/tex]

y=15 m

We have to find the derivative of equation 1 with respect to t.

2x*dx/dt+2y*dy/dt=0

Because it is given that bottom is increasing at 101 meters per minute so dx/dt=101

2x*101+2y*dy/dt=0

put the value of y=15

2x*101+2*15*dy/dt=0

2x*101+2*15*dy/dt=0

dy/dt=-3030/2*36

dy/dt=-42.08

Hence the rate at which the rate at which the top of the ladder and the ground at that instant is decreasing at 42 meters per minute.

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Question is wrong so it includes ladder length be 39 meters and the rate of increasing of bottom of ladder from bottom of wall is 101 meters per minute and the bottomis 36 m from the wall.

Let [tex]a,b,c[/tex] denote the amounts (in liters) of the 20%, 30%, and 60% acid solutions, respectively. These quantities then contain [tex]0.20a[/tex], [tex]0.30b[/tex], and [tex]0.60c[/tex] liters of acid.

The chemist wants to end up with a total volume of 54 liters, so

[tex]a + b + c = 54[/tex]

and a concentration of 45% acid. This comes out to 0.45×54 = 24.3 total liters of acid, so

[tex]0.20a + 0.30b + 0.60c = 24.3[/tex]

He will also use twice as much of the 60% solution as the 30% solution, so

[tex]c = 2b[/tex]

Substitute this into the first two equations and solve for [tex]a,b[/tex].

[tex]\begin{cases} a + 3b = 54 \\ 0.20a + 1.50b = 24.3 \end{cases}[/tex]

Eliminating [tex]b[/tex], we have

[tex](a + 3b) - 2 (0.20a + 1.50b) = 54 - 2(24.3) \implies 0.60a = 5.4 \implies \boxed{a = 9}[/tex]

Solve for [tex]b[/tex].

[tex]9+3b=54 \implies 3b=45 \implies \boxed{b=15}[/tex]

Solve for [tex]c[/tex].

[tex]c = 2(15) \implies \boxed{c=30}[/tex]

a = 9, b = 15 and c = 30 liters of each solution should be used.

According to the question:

Let a, b, and c stand for the relative volumes (in liters) of the 20 percent, 30 percent, and 60 percent acid solutions. The amount of acid in these amounts is 0.20a, 0.30b, and 0.60c liters.

a+b+c = 54 because the chemist wishes to have a final volume of 54 liters.

and a concentration of 45% acid. This comes out to 0.45×54 = 24.3 total liters of acid, so

0.20a + 0.30b + 0.60c = 24.3

Additionally, he will consume twice as much of the 60% solution as the 30% solution, thus c = 2b.

Substitute this into the first two equations and solve for a,b

a + 3b = 54

0.20a + 1.50b = 24.3

[tex](a+3 b)-2(0.20 a+1.50 b)=54-2(24.3) \\0.60 a=5.4[/tex]

a = 9.

9+3b = 54

3b = 45

b = 15.

c = 2(15)

c = 30.

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Answer:4

Step-by-step explanation: 32\8 = 4

Answer:

The solution for the expression is choice D 26√5 +2√10

Step-by-step explanation:

Hello!

First, apply distributive law: a(b+c)= ab+ac

The equation models the amount of gas left in the car as Phan drives, and how many gallons of gasoline does it take to fill her tank is g = 3h + 3; 12 gallon

Check all equation

g = 18 – 2h; 18 gallons

= 18 - 2(3)

= 18 - 6

= 12

g = 18 – 2h; 16 gallons

= 18 - 2(3)

= 18 - 6

= 12

g = 3h + 3; 30 gallons

= 3(3) + 3

= 9 + 3

= 12

g = 3h + 3; 12 gallon

= 3(3) + 3

= 9 + 3

= 12

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The correct option is (b) h=0.5cos([tex]\pi[/tex]/6t)+9.5.

The equations can be used to model the height as a function of time, t, in hours is h=0.5cos([tex]\pi[/tex]/6t)+9.5.

The following is a presentation of the cosine function's generic form;

y =  a + cos(bx - c) + d

amplitude = a

b = cycle speed

Calculation for the model height;

The height, h (feet) of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet.

Obtain amplitude 'a' as

[tex]\begin{aligned}a &=\frac{\text { Maximum value }-\text { Minimum value }}{2} \\a &=\frac{10-9}{2} \\a &=\frac{1}{2} \\a &=0.5\end{aligned}[/tex]

The time 'T' is calculated as-

[tex]\begin{aligned}&\mathrm{T}=\frac{2 \pi}{\mathrm{b}} \\&12=\frac{2 \pi}{\mathrm{b}} \\&\mathrm{b}=\frac{2 \pi}{12} \\&\mathrm{~b}=\frac{\pi}{6}\end{aligned}[/tex]

Now, calculate 'd'

[tex]\begin{aligned}&\mathrm{d}=\frac{\text { Maximum value }+\text { Minimum value }}{2} \\&\mathrm{~d}=\frac{10+9}{2} \\&\mathrm{~d}=\frac{19}{2} \\&\mathrm{~d}=9.5\end{aligned}[/tex]

Therefore, with the height as a function of time, t, expressed in hours, can be modeled by the following equations:

h=0.5cos([tex]\pi[/tex]/6t)+9.5

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The complete question is-

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m.

A. h=0.5cos([tex]\pi[/tex]/12t)+9.5

B. h=0.5cos([tex]\pi[/tex]/6t)+9.5

C. h=cos([tex]\pi[/tex]/12t)+9

D. h=cos([tex]\pi[/tex]/6t)+9

Answer:

[tex]d=\frac{t}{12}+\frac{4}{3}[/tex]

Step-by-step explanation:

The average rate of change is (10-6)/(104-56) = 1/12.

So, the equation is of the form d = t/12 + c for some constant c.

Substituting in d=6 and t=56 gives that c=4/3.

So, the equation is

[tex]d=\frac{t}{12}+\frac{4}{3}[/tex]